Title: Kjemisk reaksjonsteknikk
1- Lecture 2
- Kjemisk reaksjonsteknikk
- Review of Lecture 1 and 2 (chapter 1 and 2)
- Rate Laws
- Reaction Orders
- Arrhenius Equation
- Activation Energy
- Effect of Temperature
2General Mole Balance
- General Mole Balance on System Volume V
2
3Reactor Mole Balance Summary
The GMBE applied to the four major reactor types
(and the general reaction A?B)
Reactor Differential Algebraic Integral
3
4Reactor Mole Balances in terms of conversion
FAFA0-FA0XFA0(1-X)
Reactor Differential Algebraic Integral
X
4
5Reactor Mole Balances in terms of residence time
and conversion
FACAFV , CACA0(1-X), tV/ FV
Batch reactor
X
CSTR
PFR
5
6Two types of problems
- Design problem Design a reactor to achieve
certain conversion - Operating problem in a existing reactor to find
conversion or the residence time to reach the
certain conversion
Levenspiel Plots
PFR
CSTR
7Reactors in Series
8PFR vs CSTR in series
..
Is the PFR always better than the CSTR in terms
of reactor size to achieve a identical
conversion?
9Reactors in Series
Only valid if there are no side streams
9
10Reactors in Series
Exothermic reaction in an adiabatic reactor
How can we minimize the reaction size?
10
11Basic Definitions
- Homogeneous reactions involve only one phase
- Heterogeneous reactions involve more than one
phase, and reactions occur at interfaces of two
phases - Irreversible reactions occur at only one
direction - Reversible reactions occur at both directions,
depending one the approach to equilibrium - Molecularity of the reaction is the number of the
atoms, ions or molecules involved in a reaction
step. Unimolecular, bimolecular and termolecular
refer to reactions involving one, two and three
atoms or molecules in one reaction step,
respectively - Elementary reaction involves only one bond
breaking or formation - Non-elementary reaction could involve multi
elementary reaction steps
12Kinetics
13Kinetics - Power Law Model
A reactor follows an elementary rate law if the
reaction orders just happens to agree with the
stoichiometric coefficients for the reaction as
written. e.g. If the above reaction follows an
elementary rate law 2nd order in A, 1st order in
B, overall third order
13
14 "Everyone has Problems -but Chemists have Solutions"
Chemical Engineers have Simple Solutions !!!
15Example Ammonia decomposition
- 2NH33H2N2 11 kJ/mol
-
- The kinetic study was performed in a fixed bed
reactor (6 mm diameter) on Fe/Al2O3 catalysts at
atmospheric pressure and total flow of 100 ml/min
with Ar as the balance. 100 mg catalysts mixed
with 1 g SiC were loaded in the reactor. - FNH3.s (ml/min)
20 40 80 - FAr,s (ml/min)
80 60 20 - XNH3
0.050 0.051 0.050 - Can we determine the reactor order? (n0,1,2 ? )
- How can we reduce the conversion from 5.0 to
2.5
16Relative Rates of Reaction
16
17Relative Rates of Reaction
17
182AB?3C
- Second Order in A
- Zero Order in B
- Overall Second Order
18
19Reversible Reaction
This equation is thermodynamically consistent.
19
20Reversible Reaction
Reaction is First Order in A Second Order
in B Overall third Order
20
2121
22Arrhenius Equation
k is the specific reaction rate (constant) and is
given by the Arrhenius Equation. where
Svante August Arrhenius was a Swedish scientist,
received the Nobel Prize for Chemistry in 1903
22
23Arrhenius Equation
where E Activation energy (cal/mol) R Gas
constant (cal/molK) T Temperature (K) A
Frequency factor (same units as rate constant
k) (units of A, and k, depend on overall reaction
order)
23
24Reaction Coordinate
The activation energy can be thought of as a
barrier to the reaction. One way to view the
barrier to a reaction is through the reaction
coordinates. These coordinates denote the energy
of the system as a function of progress along the
reaction path. For the reaction
The reaction coordinate is
Transition state theory
24
25Why is there an Activation Energy?
We see that for the reaction to occur, the
reactants must overcome an energy barrier or
activation energy EA. The energy to overcome
their barrier comes from the transfer to the
kinetic energy from molecular collisions and
internal energy (e.g. Vibrational Energy).
- The molecules need energy to disort or stretch
their bonds in order to break them and thus form
new bonds - As the reacting molecules come close together
they must overcome both stearic and electron
repulsion forces in order to react.
25
26(No Transcript)
27(No Transcript)
28Collision probability
29One such distribution of energies is in the
following figure
29
30Rate expression Gas phase reaction
AB 2C
31Rate expression Catalysed reaction