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Particles in Motion

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Particles in Motion ... II Pressure = N * mv Therefore Px = 1/3 mv2N Go to a Maxwellian speed distribution: The Maxwell-Boltzmann Distribution Let Then This ... – PowerPoint PPT presentation

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Title: Particles in Motion


1
Particles in Motion
2
Velocities and Speeds of Particles
The Maxwell-Boltzmann Distribution
  • Consider a Cartesian system with orthogonal axes
    (x,y,z)
  • N(vx)dvx number of particles having a velocity
    component along the x axis between vx and vxdvx
  • N Total Number of particles
  • m mass of the particle
  • Then

3
Continuing
Let
Then
This is just a gaussian.
4
Gaussians
  • Generally a gaussian is
  • The center is at x 0 and the amplitude is A
  • To move the center -a(x-x0)2
  • FWHM y A/2 (but remember to double!)
  • This is the Formal Gaussian Probability
    Distribution where s is the standard deviation

5
Continuing some more
The y,z contributions are
The fraction with components along the respective
axes vxdvx, vydvy, vzdvz
6
Summation and Normalization
Probability Distributions Integrate to 1
Or
The normalization on the gaussians is a Now
consider the speeds of the particles gt
v2 vx2 vy2 vz2 Let us go to a spherical
coordinate system gt dvxdvydvz ? 4pv2dv
7
The Speed Distribution
Note that a is just the most probable speed
NB Velocities are normally distributed but the
speeds are not!
8
Gas Pressure
Another way to do it!
  • Pressure rate of momentum transfer normal to
    surface
  • Consider a 3d orthogonal axis system
  • If the particles are confined to move along axes,
    then 1/6 are moving along any one axis at a
    single time (on the average)
  • Let the speed be v
  • The number crossing a unit area per second on any
    axis is Nx 1/6 Nv and Nx- 1/6 Nv.
  • Therefore the total number of crossings is 1/3 Nv

9
Gas Pressure II
Now use the Maxwell Boltzman Distribution
  • Pressure N mv
  • Therefore Px 1/3 mv2N
  • Go to a Maxwellian speed distribution

One can either invoke the Perfect Gas Law or one
can derive the Perfect Gas Law!
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