Title: Simple Harmonic Motion
1Simple Harmonic Motion
- Holt Physics
- Pages 438 - 451
2Distinguish simple harmonic motion from other
forms of periodic motion.
- Periodic motion is motion in which a body moves
repeatedly over the same path in equal time
intervals. - Examples uniform circular motion and simple
harmonic motion.
3Contd
- Simple Harmonic Motion (SHM) is a special type of
periodic motion in which an object moves back and
forth, along a straight line or arc. - Examples pendulum, swings, vibrating spring,
piston in an engine. - In SHM, we ignore the effects of friction.
- Friction damps or slows down the motion of the
particles. If we included the affect of friction
then its called damped harmonic motion.
4Contd
- For instance a person oscillating on a bungee
cord would experience damped harmonic motion.
Over time the amplitude of the oscillation
changes due to the energy lost to friction. - http//departments.weber.edu/physics/amiri/directo
r/DCRfiles/Energy/bungee4s.dcr
5State the conditions necessary for simple
harmonic motion.
- A spring wants to stay at its equilibrium or
resting position. - However, if a distorting force pulls down on the
spring (when hanging an object from the spring,
the distorting force is the weight of the
object), the spring stretches to a point below
the equilibrium position. - The spring then creates a restoring force, which
tries to bring the spring back to the equilibrium
position.
6Contd
- The distorting force and the restoring force are
equal in magnitude and opposite in direction. - FNET and the acceleration are always directed
toward the equilibrium position.
7Contd
- Applet showing the forces, displacement, and
velocity of an object oscillating on a spring. - https//ngsir.netfirms.com/englishhtm/SpringSHM.ht
m
8Displacement Velocity Acceleration
9Contd
- at equilibrium
- speed or velocity is at a maximum
- displacement (x) is zero
- acceleration is zero
- FNET is zero (magnitude of Restoring Force
magnitude of Distorting Force which is the
weight) - object continues to move due to inertia
10Contd
- at endpoints
- speed or velocity is zero
- displacement (x) is at a maximum equal to the
amplitude - acceleration is at a maximum
- restoring force is at a maximum
- F -kx (hooks law)
- FNET is at a maximum
11State Hookes law and apply it to the solution of
problems.
- Hookes Law relates the distorting force and the
restoring force of a spring to the displacement
from equilibrium.
12Contd
- F restoring force in Newtons
- k spring constant or force constant (stiffness
of a spring) in Newtons per meter (N/m) - x displacement from equilibrium in meters
- The distorting force is equal in magnitude but
opposite in direction to the restoring force.
13The spring shown to the right has an unstretched
length of 3 cm. When a 2 kg object is hung from
the spring, it comes to rest at the 7 cm mark.
What is the spring constant of this spring? 490
N/m What direction is the restoring force? upward
14Calculate the frequency and period of any simple
harmonic motion.
- T period (time required for a complete
vibration) in seconds - f frequency in vibrations / second or Hertz
15- A particle is moving in simple harmonic motion
with a frequency of 10 Hz. - What is its period?
- 0.1 sec
- How many complete oscillations does it make in
one minute? - 600 oscilations
16Relate uniform circular motion to simple harmonic
motion.
- The reference circle relates uniform circular
motion to SHM. - The shadow of an object moving in uniform
circular motion acts like SHM. - The speed of an object moving in uniform circular
motion may be constant but the shadow wont move
at a constant speed. - The speed at the endpoints is zero and a maximum
in the middle. - The shadow only shows one component of the motion.
17Contd
- Applet showing the forces, displacement, and
velocity of an object oscillating on a spring and
an object in uniform circular motion. - http//www.physics.uoguelph.ca/tutorials/shm/phase
0.html
18Identify the positions of and calculate the
maximum velocity and maximum accelerations of a
particle in simple harmonic motion.
- The acceleration is a maximum at the endpoints
and zero at the midpoint. - The acceleration is directly proportional to the
displacement, x. - The radius of the reference circle is equal to
the amplitude. - The force and acceleration are always directed
toward the midpoint.
19The mass on the end of a spring (which stretches
linearly) is in equilibrium as shown. It is
pulled down so that the pointer is opposite the
11 cm mark and then released. What is the
amplitude of the vibration? 4 cm What two places
will the restoring force be greatest? 11 cm and 3
cm Where will the restoring force be least? 7 cm
20- Where is the speed greatest?
- 7 cm
- What two places is the speed least?
- 3 cm and 11 cm
- Where is the magnitude of the displacement
greatest? - 3 cm and 11 cm
- Where is the displacement least?
- 7 cm
- Where is the magnitude of the acceleration
greatest? - 3 cm and 11 cm
- Where is the acceleration least?
- 7 cm
- Where is the elastic potential energy the
greatest? - Where is the kinetic energy the greatest?
21Contd
- Remember that in uniform circular motion, the
velocity is calculated using
In SHM, the maximum velocity would be equal to
the velocity of the object in uniform circular
motion. The radius of the circle correlates to
the Amplitude (A) in SHM.
22Contd
- Remember that in uniform circular motion, the
centripetal acceleration is calculated using
In SHM, the maximum acceleration would be equal
to the acceleration of the object in uniform
circular motion. The radius of the circle
correlates to the Amplitude (A) in SHM.
23- A mass hanging on a spring oscillates with an
amplitude of 10 cm and a period of 2 seconds.
What is the maximum speed of the object and where
does it occur? - 0.314 m/s at equilibrium
- What is the minimum speed of the object and where
does it occur? - 0 m/s at the end points.
- What is its maximum acceleration?
- 0.987 m/s2 at the end points
24- An object moving is simple harmonic motion can be
located using - A is amplitude
- f is frequency
- x is displacement from equilibrium
- ? is angular velocity
25- The mass on the end of a spring (which stretches
linearly) is in equilibrium as shown. - It is pulled down so that the pointer is
opposite the 11 cm mark and then released. A
spring vibrates in SHM according to the equation
x 4 cospt. - How many complete vibrations does it make in 10
seconds? - 5 vibrations
26- The elastic potential energy content of the
system is
So the maximum elastic potential energy is stored
at the end points of the oscillations where the
displacement is equal to the amplitude of the
vibration
At the end point, the object is not moving so
there is no kinetic energy. Therefore the total
energy content of the system is equal to
27- A mass on a spring oscillates horizontally on a
frictionless table with an amplitude of A. In
terms of Eo (total mechanical energy of the
system) when the mass is at A, Us ______ and K
_________. - Us Eo and K 0
- When the mass is at 0.5 A, then Us __________
and K _________. - Us 0.25 Eo and K 0.75Eo
- When the mass is at the equilibrium position,
then Us _________ and K ________ - Us 0 and K Eo
28- A 2 kg object is attached to a spring of force
constant k 500 N / m. The spring is then
stretched 3 cm from the equilibrium position and
released. What is the maximum kinetic energy of
this system? - 0.225 J
- What is the maximum velocity it will attain?
- 0.47 m/s
29Contd
- T period (s)
- m mass (kg)
- k spring constant (N/m)
30- You want a mass that, when hung on the end of the
spring, oscillates with a period of 3 seconds.
If the spring constant is 5 N/m, the mass should
be _______. - 1.14 kg
31- The period for a mass vibrating on very stiff
springs (large values of k) will be (larger /
smaller) compared to the same mass vibrating on a
less stiff spring. - Smaller
- If the value of k halves, the period will be
______ times as long.
32Relate the motion of a simple pendulum to simple
harmonic motion.
- A pendulum is a type of SHM.
- A simple pendulum is a small, dense mass
suspended by a cord of negligible mass. - The period of the pendulum is directly
proportional to the square root of the length and
inversely proportional to the square root of the
acceleration due to gravity.
33Contd
- T period (s)
- l length (m)
- g acceleration due to gravity (m/s2)
34- A pendulum has a period of 2 seconds here on the
surface of the earth. That pendulum is taken to
the moon where the acceleration due to gravity is
1/6 as much. What is the period of the pendulum
on the moon? - Squareroot of 6 times as much or 4.9 seconds.