Title: Vibrations: a special class of motion
1Vibrations a special class of motion
Oscillatory in time Displacement cos
(frequency t)
We have already examined vibrations in some
examples of dynamical systems Two-story
building Pendulum Systems that vibrate (nearly
everything) are often subjected to time-dependent
applied forces. The response of the system
includes the phenomenon of resonance, in which
the amplitude of the response becomes very large.
Resonance must be controlled for both good
and bad applications of vibrating
systems. Vibrations as a class of motion
therefore merits special, focused attention
Multi-story Building
Ear Drum
2Desirable Vibrations
MRI
Time keeping
Atomic Force Microscopy
Ultrasound
3Undesirable Vibrations
Tacoma Narrows Bridge (1940)
See videos on YouTube and a long one
on http//www.archive.org/details/SF121
4Earthquake-induced Vibrational Failure Kobe,
Japan 1995 Sichuan Province, China, 2008
5Vibration Control and Isolation
6Low Tech Solution Railway Suspension Bridge,
Niagara Falls 1860
7Scope of Vibrations Lectures
FREE Vibration provide initial conditions and
let system respond
Undamped
First Simplest system one degree of
freedom Then Vibration of systems (multiple
degrees of freedom)
Damped
8Scope of Lectures
FORCED Vibrations Continuous forcing of the
system by an oscillating force or motion
9All these pictures of springs But pictorial
examples dont have any springs Why ?
Many objects/structures behave like springs i.e.
Displacement is proportional to Force F -kx
Static measurement of deflections and forces can
be used to measure the effective spring constant
10Result is some curve
11Why is it always linear? When no forces are
exerted on a material, the atoms adjust
themselves to minimize the potential energy of
the material If the potential energy is a smooth
function of atom positions, then at the minimum
the energy must vary quadratically, not linearly
For a conservative system, force is the
derivative (gradient) of the energy, so
When you stretch a material, you are directly
measuring the atomic springs
12Bending instead of stretching
h
b
Displacement versus Force is still linear
13Equation of Motion for Free Vibrations One
Degree of Freedom ( one coordinate of motion)
Equation of Motion
or
14Pendulum
We derived the equation of motion for the angle ?
previously
L
For small ?ltlt1
m
Same form as before
15How about something a bit more complicated
16A case of rotational oscillations
17Always the Same Equation of Motion
Mass m on a spring
Pendulum
Two-mass/Pulley system
Rotating bar
Equation of Motion always of the form
M mass-like quantity K spring-like
quantity x position-like variable
18Frequency the system wants to vibrate at if left
alone (unforced)
19Solve the Equation of Motion
Homogeneous 2nd order, linear, ordinary
differential equation with constant coefficients
Solutions for x(t) are
20Solution for Vibratory Motion
The two constants C1 and C2 are fully determined
by specifying the two initial conditions x(t0)
and dx/dt at t0
First, rewrite, using
21(Amplitude)
(phase angle)
22All systems have one (or more) Natural Frequency
of Vibration ?n Frequency at which the system
will oscillate when left on its own (no damping,
no forcing)
Motion is always described as
Systems differ in what x measures, and the
starting conditions (leading to amplitude X and
phase ?)
23Static measurement of deflections and forces can
reveal the effective spring constant
Man, mass 90kg steps on end
If he initiates an oscillation, what would period
of oscillation be?
(neglect mass of diving board)
24Combining Springs
Springs in Series
(equivalent spring)
x
What quantity is the same in both springs? Force
or displacement?
Force
25Combining Springs
Springs in Parallel
(equivalent spring)
x
What quantity is the same in both springs? Force
or displacement?
Displacement
26Are series these two springs in serial or
parallel?
27Oscillation does not depend on equilibrium
position
Sloped
28Strategy for Problem Solving
Draw F.B.D.
Very straightforward the subtleties are in
getting the initial conditions and the
equilibrium position, but these come from other
considerations
29Example (useless, but illustrates the main
points)
3kg blob of putty dropped 2m onto initially
stationary 28kg block. Block supported by four
springs with k800N/m
Find x(t) (measured from initial position of
block)
After impact, have a 31kg mass bouncing on four
parallel springs
1. FBD
303. Natural Frequency
5. Apply initial conditions
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