Title: EE%20369%20POWER%20SYSTEM%20ANALYSIS
1EE 369POWER SYSTEM ANALYSIS
- Lecture 5
- Development of Transmission Line Models
- Tom Overbye and Ross Baldick
2Reading
- For lectures 5 through 7 read Chapter 4
- we will not be covering sections 4.7, 4.11, and
4.12 in detail. - HW 4 is 2.31, 2.48, 4.8, 4.10, 4.12, 4.13, 4.15,
4.19, 4.20, 4.22, 4.24, 4.25 (assume Cardinal
conductor and look up GMR in Table A.4), due
Thursday 9/22. - HW 5 is Problems 4.1, 4.3, 4.6, 4.26, 4.33, 4.36,
4.38, 4.49, 5.2, 5.4, 5.7, 5.9 due Thursday
9/29. - Mid-term I is Thursday, October 13, covering up
to and including material in HW 5.
3Substation Bus
4Inductance Example
- Calculate the inductance of an N turn coil wound
tightly on a toroidal iron core that has a radius
of R and a cross-sectional area of A. Assume - 1) all flux is within the coil
- 2) all flux links each turn
- 3) Radius of each turn is negligible compared to R
Circular path G of radius R within the iron core
encloses all N turns of the coil and hence links
total enclosed current of Ie NI. Since the
radius of each turn is negligible compared to R,
all circular paths within the iron core have
radius approximately equal to R.
5Inductance Example, contd
6Inductance of a Single Wire
- To develop models of transmission lines, we first
need to determine the inductance of a single,
infinitely long wire. To do this we need to
determine the wires total flux linkage,
including - 1. flux linkages outside of the wire
- 2. flux linkages within the wire
- Well assume that the current density within the
wire is uniform and that the wire is solid with a
radius of r. - In fact, current density is non-uniform, and
conductor is stranded, so our calculations will
be approximate.
7Flux Linkages outside of the wire
8Flux Linkages outside, contd
9Flux linkages inside of wire
10Flux linkages inside, contd
Wire cross section
11Line Total Flux Inductance
12Inductance Simplification
13Two Conductor Line Inductance
- Key problem with the previous derivation is we
assumed no return path for the current. Now
consider the case of two wires, each carrying the
same current I, but in opposite directions
assume the wires are separated by distance D.
To determine the inductance of each conductor we
integrate as before. However now we get
some field cancellation.
Creates a clockwise field
Creates counter- clockwise field
14Two Conductor Case, contd
Key Point Flux linkage due to currents in each
conductor tend to cancel out. Use superposition
to get total flux linkage.
Left Current
Right Current
15Two Conductor Inductance
16Many-Conductor Case
Now assume we now have n conductors, with the
k-th conductor having current ik, and arranged in
some specified geometry. Wed like to find flux
linkages of each conductor.
Each conductors flux linkage, lk, depends upon
its own current and the current in all the
other conductors.
For example, to derive the flux linkage for
conductor 1, l1, well be integrating from
conductor 1 (at origin) to the right along the
x-axis.
17Many-Conductor Case, contd
Rk is the distance from con- ductor k to point c.
Wed like to integrate the flux crossing between
b to c. But the flux crossing between a and c
is easier to calculate and provides a very good
approximation of l1k. Point a is at distance d1k
from conductor k.
At point b the net contribution to l1 from ik ,
l1k, is zero.
18Many-Conductor Case, contd
19Many-Conductor Case, contd
20Symmetric Line Spacing 69 kV
21Line Inductance Example
Calculate the reactance for a balanced 3f,
60Hz transmission line with a conductor geometry
of an equilateral triangle with D 5m, r
1.24cm (Rookconductor) and a length of 5 miles.
22Line Inductance Example, contd
23Line Inductance Example, contd
24Conductor Bundling
To increase the capacity of high voltage
transmission lines it is very common to use a
number of conductors per phase. This is known
as conductor bundling. Typical values are two
conductors for 345 kV lines, three for 500 kV
and four for 765 kV.
25Bundled Conductor Flux Linkages
- For the line shown on the left,
- define dij as the distance between
- conductors i and j.
- We can then determine lk for conductor k.
- Assuming ¼ of the phase current flows
- in each of the four conductors in
- a given phase bundle, then for conductor 1
26Bundled Conductors, contd
27Bundled Conductors, contd
28Inductance of Bundle
29Inductance of Bundle, contd
30Bundle Inductance Example
Consider the previous example of the three
phases symmetrically spaced 5 meters apart using
wire with a radius of r 1.24 cm. Except now
assume each phase has 4 conductors in a square
bundle, spaced 0.25 meters apart. What is the
new inductance per meter?
31Transmission Tower Configurations
- The problem with the line analysis weve done so
far is we have assumed a symmetrical tower
configuration. - Such a tower configuration is seldom practical.
- Therefore in
- general Dab ?
- Dac ? Dbc
- Unless something
- was done this would
- result in unbalanced
- Phases.
Typical Transmission Tower Configuration
32Transposition
- To keep system balanced, over the length of a
transmission line the conductors are rotated so
each phase occupies each position on tower for an
equal distance. - This is known as transposition.
Aerial or side view of conductor positions over
the length of the transmission line.
33Line Transposition Example
34Line Transposition Example
35Transposition Impact on Flux Linkages
a phase in position 1
a phase in position 3
a phase in position 2
36Transposition Impact, contd
37Inductance of Transposed Line
38Inductance with Bundling
39Inductance Example
- Calculate the per phase inductance and reactance
of a balanced 3?, 60 Hz, line with - horizontal phase spacing of 10m
- using three conductor bundling with a spacing
between conductors in the bundle of 0.3m. - Assume the line is uniformly transposed and the
conductors have a 1cm radius.
40Inductance Example