Title: Bell Ringer
1Bell Ringer
When 6.58 g SO3 and 1.64 g H2O react, what is the
expected yield of sulfuric acid? If the actual
yield is 7.99 g sulfuric acid, what is the
percent yield?
SO3
H2O
H2SO4
1 mol SO3
1 mol H2SO4
98.09 g H2SO4
6.58 g SO3
x
x
x
80.07 g SO3
1 mol SO3
1 mol H2SO4
8.06 g H2SO4
1 mol H2O
1 mol H2SO4
98.09 g H2SO4
1.64 g H2O
x
x
x
18.02 g H2O
1 mol H2O
1 mol H2SO4
8.93 g H2SO4
2Bell Ringer
When 6.58 g SO3 and 1.64 g H2O react, what is the
expected yield of sulfuric acid? If the actual
yield is 7.99 g sulfuric acid, what is the
percent yield?
SO3
H2O
H2SO4
Info weve learned
Theoretical Yield 8.06 g H2SO4
7.99 g H2SO4
99.1
8.06 g H2SO4
3Limiting Factors Percent Yield Quiz
Good Luck!!
4Homework Answers
- D
- A
- C
- B
- A
- C
- C
- A
- B
- D
- 11. Mass-mass
- 12. Mass-volume
- 13. Mole-mole
- 14. Limiting reactant
- 15. Volume-volume
- 0.52 mol PBr3
- 0.13 mol Na
- 50 g NaClO3
- 23. 5000 g HCl
- 4770 g H2O
- 27. 98 g AgCl 120 g AgNO3
- 29. 700 g CO2 500 g O2
- 31. 89.6 L H2
- 33. 234 g ZnSO4
- 35. 7.75 L O2
- 39. 8.06 g H2SO4 99.1
5Stoichiometry Review
6Types of Stoichiometry Problems
- Mole-Mole
- Mass-Mole
- Mass-Mass
- Mass-Volume
- Volume-Mass
- Volume-Volume
- Limiting Reactant
- Percent Yield
7Types of Stoichiometry Problems
- Mole-Mole
- Mass-Mole
- Mass-Mass
- Mass-Volume
- Volume-Mass
- Volume-Volume
- Limiting Reactant
- Percent Yield
8Mole-Mole Problems
- 1 conversion step
- Given moles A
- Required moles B
- Convert moles A to moles B using mole ratio.
- The mole ratio is used in EVERY STOICHIOMETRY
PROBLEM. EVER. I PROMISE.
How many moles of water can be formed from 0.5
mol H2?
2 mol H2O
0.5 mol H2
0.5 mol H2O
x
2 mol H2
9Types of Stoichiometry Problems
- Mole-Mole
- Mass-Mole
- Mass-Mass
- Mass-Volume
- Volume-Mass
- Volume-Volume
- Limiting Reactant
- Percent Yield
10Mass-Mole Problems
- 2 conversion steps
- Given mass A
- Required moles B
- Step 1 convert grams A to moles A using
Periodic Table - Step 2 convert moles A to moles B using mole
ratio
How many moles of water can be formed from 48.0 g
O2?
2 mol H2O
1 mol O2
48.0 g O2
3.00 mol H2O
x
x
1 mol O2
32.00 g O2
11Types of Stoichiometry Problems
- Mole-Mole
- Mass-Mole
- Mass-Mass
- Mass-Volume
- Volume-Mass
- Volume-Volume
- Limiting Reactant
- Percent Yield
12Mass-Mass Problems
- 3 conversion steps
- Given mass A
- Required mass B
- Step 1 convert grams A to moles A using
Periodic Table - Step 2 convert moles A to moles B using mole
ratio - Step 3 convert moles B to grams B using
Periodic Table
How many grams of water can be formed from 48.0 g
O2?
2 mol H2O
1 mol O2
18.02 g H2O
48.0 g O2
54.1 g H2O
x
x
x
1 mol O2
32.00 g O2
1 mol H2O
13Types of Stoichiometry Problems
- Mole-Mole
- Mass-Mole
- Mass-Mass
- Mass-Volume
- Volume-Mass
- Volume-Volume
- Limiting Reactant
- Percent Yield
14Mass-Volume Problems
- 3 4 conversion steps
- Given mass A
- Required volume B
- Step 1 convert grams A to moles A using
Periodic Table - Step 2 convert moles A to moles B using mole
ratio - Step 3 convert moles B to liters B
How many liters of oxygen are necessary to create
48.0 g H2O?
48.0 g H2O
1 mol O2
1 mol H2O
22.4 L O2
29.8 L O2
x
x
x
2 mol H2O
18.02 g H2O
1 mol O2
15Types of Stoichiometry Problems
- Mole-Mole
- Mass-Mole
- Mass-Mass
- Mass-Volume
- Volume-Mass
- Volume-Volume
- Limiting Reactant
- Percent Yield
16Volume-Mass Problems
- 3 4 conversion steps
- Given volume A
- Required mass B
- Step 1 convert liters A to moles A
- Step 2 convert moles A to moles B using mole
ratio - Step 3 convert moles B to grams B using
Periodic Table
How many grams of water are formed by reacting
36.0 L O2?
36.0 L O2
2 mol H2O
1 mol O2
18.02 g H2O
58.7 g H2O
x
x
x
1 mol O2
22.4L O2
1 mol H2O
17Types of Stoichiometry Problems
- Mole-Mole
- Mass-Mole
- Mass-Mass
- Mass-Volume
- Volume-Mass
- Volume-Volume
- Limiting Reactant
- Percent Yield
18Volume-Volume Problems
- 3 5 conversion steps
- Given volume A
- Required volume B
- Step 1 convert liters A to moles A
- Step 2 convert moles A to moles B using mole
ratio - Step 3 convert moles B to liters B
How many liters of H2 are required to react with
5.0 L O2?
5.0 L O2
2 mol H2
1 mol O2
22.4 L H2
10. L H2
x
x
x
1 mol O2
22.4 L O2
1 mol H2
19Types of Stoichiometry Problems
- Mole-Mole
- Mass-Mole
- Mass-Mass
- Mass-Volume
- Volume-Mass
- Volume-Volume
- Limiting Reactant
- Percent Yield
20Limiting Reactant Problems
- Quantities are given for each reactant.
- 2 parallel equations
- Solve each equation for product desired and
determine limiting reactant. - Use Limiting Reactant to solve for amount or
excess reactant used. - Subtract amount excess reactant used from amount
given to determine how much is left over.
21Limiting Reactant Problems
If you start with 10.0 g of O2 and 5.00 g H2 how
much water would be formed? Which would be your
limiting factor? How much of the excess reagent
would there be?
1 mol O2
2 mol H2O
18.02 g H2O
10.0 g O2
x
x
x
32.00 g O2
1 mol O2
1 mol H2O
LIMITING REACTANT
11.3 g H2O
THEORETICAL YIELD
5.00 g H2
1 mol H2
2 mol H2O
18.02 g H2O
x
x
x
2.02 g H2
2 mol H2
1 mol H2O
EXCESS REACTANT
44.06 g H2O
22Limiting Reactant Problems
2 H2
O2
2 H2O
If you start with 10.0 g of O2 and 5.00 g H2 how
much water would be formed? Which would be your
limiting factor? How much of the excess reagent
would there be?
Info we know so far Limiting Reactant
O2 Excess Reactant H2
2 mol H2
1 mol O2
2.02 g H2
10.0 g O2
x
x
x
1 mol O2
32.00 g O2
1 mol H2
1.26 g H2
USED
5.00 g H2 1.26 g H2
3.74 g H2
LEFT OVER
23Types of Stoichiometry Problems
- Mole-Mole
- Mass-Mole
- Mass-Mass
- Mass-Volume
- Volume-Mass
- Volume-Volume
- Limiting Reactant
- Percent Yield
24Percent Yield Problems
- Critical Information
- Theoretical Yield
- Actual Yield
- Percent Yield
Determine the actual yield of a reaction between
6.25 g H2 and excess O2 that has a 85 percent
yield.
6.25 g H2
1 mol H2
2 mol H2O
18.02 g H2O
x
x
x
2.02 g H2
2 mol H2
1 mol H2O
55.6 g H2O
THEORETICAL YIELD
?
85
100
x
55.6 g H2O
ACTUAL YIELD 47.3 g H2O
25Homework Answers
- D
- A
- C
- B
- A
- C
- C
- A
- B
- D
- 11. Mass-mass
- 12. Mass-volume
- 13. Mole-mole
- 14. Limiting reactant
- 15. Volume-volume
- 0.52 mol PBr3
- 0.13 mol Na
- 50 g NaClO3
- 23. 5000 g HCl
- 4770 g H2O
- 27. 98 g AgCl 120 g AgNO3
- 29. 700 g CO2 500 g O2
- 31. 89.6 L H2
- 33. 234 g ZnSO4
- 35. 7.75 L O2
- 39. 8.06 g H2SO4 99.1