Title: Theoretical genetics
1Theoretical genetics
2Important definitions
- Genotype- the alleles possesed by an organism
- Phenotype- all the characteristics of an
organism. - Dominant allele- an allele which has the same
effect on the phenotype whether it is present in
the homozoygous or heterozygous state - Recessive allele- an allele which only has an
effect on the phenotype when present in the
homozygous state
3Important definitions
- Codominant alleles- alleles which only has an
effect on the phenotype when present in
heterozygous but a greater effect in homozygous
individuals. - Locus- The particular position of a gene on
homologous chromosomes. - Homozygous- two identical alleles of a gene
- Heterozygous- having two different alleles of a
gene - Carrier- an individual that has a recessive
allele of a gene that does not have an effect on
the phenotype - Test cross- testing a suspected heterozygote by
crossing with a known homozygous recessive.
4Construction of Punnett grids
- Way of finding he expected ratio of the
offspring, giving certain parental phenotypes
5Punnett grids
- Example using characteristics used by Mendel
- He study the size of pea plants and found that
tall is dominant over short - Lets start with two pure breeding (homozygous)
plants with contrasting traits (tall and short) - F1 generation will have the dominant phenotype
tall but will be heterozygous.
Phenotypes Corresponding genotypes
Tall TT or Tt
Short tt
T T
Tt Tt
Tt Tt
t t
6Punnett grids
T t
- IF the F1 generation self fertilized we will
obtained F2 - ¾ tall
- ¼ short
- 31
- 1TT2Tt1tt
TT Tt
Tt tt
T t
7Lets practice
- IF a tall garden pea is crossed with a dwarf
garden pea, the F1 are all tall. Predict the
result of self fertilization of the F1, using a
Punnett square.
8Pedigree chart
- Used to show the inheritance of certain traits
over several generations of humans - Example Queen Victoria hemophilic condition
- Males are normal or affected
- Females normal or carriers
- Hemophilia allele is homozygous lethal as well as
sex linked since it is carried on the X
chromosome - Males can be XHY (normal) or XhY (affected)
- Females can be XHXH (normal) or XHXh (carrier)
9Queen Victoria and hemophilia
Affected male
Affected female
Normal female
Normal male
Victoria Albert
Victoria Edward Alice Alfred
Helena Louise Arthur Leopold
Beatrice
George V
3
Irene Frederick Alexandra
NicholasII
George VI
Duke of Windsor
3
Alexis
Elizabeth Margaret
10Multiple alleles
- Some genes have more than two alleles
- Multiple alleles can be found in blood groups
11ABO blood groups
- Based on 4 different phenotypes (ABAB and O)
- Caused by different combinations of 3 different
alleles
Phenotypes Genotypes
A IAIA or IAi
B IBIB or IBi
AB IAIB
0 ii
12ABO blood groups
- Using a Punnett Grid work out the possible
combinations of blood groups of a male with blood
group B and a female with blood group - Using a Punnett Grid explain why a female with
blood group O and a male with blood group AB
cannot have children with either pf the parents
blood group.
13How sex chromosomes determine gender
- Gender determination
- Decided by sex chromosomes
- Females has two X chromosomes
- Males have one X and one Y chromosome
14Genes in X and Y chromosomes
- The X chromosome is relatively large
- Y chromosome is much smaller
- Several genes are located on the X chromosome
- Sex linked examples
- Colorblindness
- hemophilia
- Few genes on the Y
- Hairy ears
15Define sex linkage and state two examples
- Genes carried on the sex chromosomes, most often
on the X chromosome. - Examples
- Color blindness
- Certain colors cannot be distinguished, and is
most commonly due to an inherited condition.
Red/Green color blindness is by far the most
common form, about 99, and causes problems in
distinguishing reds and greens. Another color
deficiency Blue/Yellow also exists, but is rare
and there is no commonly available test for it. - Depending on just which figures you believe,
color blindness seems to occur in about 8 - 12
of males of European origin and about one-half of
1 of females. Total color blindness (seeing in
only shades of gray) is extremely rare. - There is no treatment for color blindness, nor is
it usually the cause of any significant
disability.
16Define sex linkage and state two examples
- Hemophilia
- Blood condition in which an essential clotting
factor is either partly or completely missing. - This causes a person with hemophilia to bleed for
longer than normal. - Cuts and grazes are not great problems as a
little pressure and a plaster are usually enough
to stop bleeding. - The main problem is internal bleeding into
joints, muscles and soft tissues. - Hemophilia is a lifelong inherited genetic
condition, which affects females as carriers and
males who inherit the condition.
17Human females can be homozygous, hetero with
respect to sex linked genes
- Human males cannot be heterozygous since they
only have one copy of one allele - Example
- Colorblindness
Existing alleles XB for normal vision Xb for colorblindness
A female can be XBXB or XBXb XbXb
A male can be XBY XbY
18Human females can be homozygous, hetero with
respect to sex linked genes
Existing alleles XH for normal Xh for hemophilia
A female can be XHXH or XHXh XhXh (not exist)
A male can be XHY XhY
- Homozygous lethal
- Female carriers are heterozygous for X linked
recessive alleles - They will not show the disease but can pass it on
to the next generation
19Explain that female carriers are heterozygous for
X-linked recessive alleles
- Heterozygous females for sex linked traits
- Are said to be carriers
- They will not show the disease
- Can pass the disease to the next generation
20Calculate and predict the genotypic and
phenotypic ratios of monohybrid crosses
- Monohybrid crosses
- Involves the cross between two individuals to
study the inheritance of one gene - Example
- Character Tongue Rolling
- Gene R
- Alleles R, r
- Genotypes RR, Rr, rr
- Phenotypes rollers, non rollers
- Cross
- Heterozygous X Heterozygous
- Rr X Rr
- Gametes R, r X R, r
- Punnett square
R r
RR Rr
Rr rr
R r
Ratio 31
21Calculate and predict the genotypic and
phenotypic ratios of monohybrid crosses
- In your notebooks calculate the genotypic and
phenotypic ratios of a cross between a
heterozygous tongue roller and a recessive
individual for tongue rolling
22Calculations and codominance
- Type pf inheritance in which the two alleles of
the gene are equally dominant and so they are
both expressed in the heterozygous genotype. - Alleles
- R red
- W white
- RR red
- WW white
- RW- pink
23Calculations and codominance
- The two alleles are equally dominant
- This kind of inheritance produces more variation.
- Example
- Phenotypes of parents Red X White
- Genotypes of parents RR X WW
- Gametes R and W
- F1- RW all pink
- Perform a self cross between the F1 generation
24Deduce the genotypes or phenotypes of individuals
in pedigree charts
- Go to page 434-435.
- Answer exercises 2 and 4