Title: The Failure of the Tacoma Narrows Bridge
1The Failure of the Tacoma Narrows Bridge
By Thomas Fein Advisor Dr. Jyoti Champanerkar
2Brief History of the Bridge
- Built in Washington State
- Construction started in November of 1938.
- Completed on July 1, 1940.
- Third Largest Suspension Bridge of its time.
- Total Length1524 m (5000ft)
- Length of Center Span854 m (2800 ft)
- Width 11.9 m (39 ft, two lanes)
- Cost 6.4M (90M in Todays Dollars)
3Behavior of the Bridge on the Day of Collapse
- Amplitude of Oscillations were about 5 feet
- Frequency of oscillations were 38 cycles per
minute - Vertical Oscillation of approximately 12 to14
cycles per second - Instantaneous change from vertical to torsional
motion
4Classic Explanation for CollapseResonance
- What is Resonace-The increase in amplitude of
oscillation of an electric or mechanical system
exposed to a periodic force whose frequency is
equal or very close to the natural undamped
frequency of the system. - Resonance fails to account to change from
vertical to torsional motion - Also fails to account for vertical oscillation of
bridge due to a single gust of wind
5Outline
- Derive a mechanical model of the Bridge
- Choose Physical Constants for the differential
equations based on Historical Data - Compare the linear and nonlinear models
- Explain the instantaneous change from vertical to
torsional oscillation by analyzing nonlinear model
6Modeling the Bridge
7Energy Equations from Bridge Model
- Potential Energy-energy associated with position
- Kinetic Energy-energy of motion
- Potential Energy ky2/2, where kspring constant
and y is the extended distance of the spring - Kinetic Energy(1/6)mL2(? ) 2, where a rod of
mass m and length 2L rotates about its center of
gravity (cg) with angular velocity ?
8Energy Equations Continued
- Let ?angle of the rod from horizontal and
ydownward distance of the cg of the from the
unloaded state (dashed lines) - Let y be the positive part of y
- Gravitational Potential Energy is mgy
- Extension of One Spring is (y-l sin ?) and the
other is (y l sin ?) - Total PE(k/2) (y-l sin ?) (y l sin
?)2-mgy - Total KEm y2 /2 (1/6)mL2(? ) 2
9Model Continued
(1/3)ml2? (kl) cos ? (y- L sin ?) - (y L
sin ?) y -k (y- L sin ?) - (y L sin ?)
mg Solving for ? and y adding a small
viscous damping term d? to the first equation
and dy to the second. Also, we are adding a
forcing term, f(t) to the second equation. ? -
d? (3k/m L) cos ? (y- L sin ?) - (y L sin
?) f(t) y - dy -(k/m) (y- L sin ?)
(y L sin ?) g Assuming cables never lose
tension ? - d? (6k/m)cos ? sin ? f(t) y
- dy - (2k/m)y g
10Numerical Experiment Comparison of the Linear
and Non-linear Models
- The nonlinear model ( for torsion) is
- ? (-.01)? (6k/m)cos ? sin ? f(t)
- Choosing Physical Constants
-
- Letting K1000 and m2500, f(t) ?sin(µt) and
.01 for the viscous damping terms. µ will be
taken from 1.2 to 1.6. -
- ? (-.01)? (2.4)cos ? sin ? ? sin(µt)
- For small ?, we let sin ? ? and cos ?1. Thus,
the linearized version of the equation is - ? (- .01)? (2.4)? ? sin(µt)
11- Large torsional Push- ICs ? (0) 1.2 and ? (0)
0 with µ1.2 and ?0.06 - The linear model (Top) has settled down to an
oscillation of 3 degrees. - The nonlinear model (Bottom) has settled into
large amplitude periodic oscillation of about one
radian.
12- µ1.2 and ?.06
- Small initial conditions ,?(0)1.2 and ?(0)0.
Similar to linear model from previous graph (Top) - Large torsional push combined with the same small
torsional forcing term results in a large
amplitude oscillation. (Bottom) - ConclusionNonlinear Model can have different
responses to same forcing term depending on
whether or not there is a single push
13- Increase µ 1.3 but decrease ? to 0.02 produces
an oscillation of 1 degrees in the linear model.
Here the linear model settles down to near
equilibrium (Bottom) - Nonlinear model,-with its large initial push-
produces a large torsional oscillation. - The period is 4.83 which is somewhat above that
observed when the bridge started its torsional
oscillation.
14- µ is increased to 1.4-same results.
- Period is reduced to 4.5 which is much closer to
the reported 4.3. - Similar result if µ is increased to 1.5.
- Results vanish until integral multiples of µ are
reached.
15- Historical Observation- vertical motions that
came before the torsional ones had a frequency of
about 40 per minute( µ near 4). - When the initial conditions are large or small
combined with a forcing term of ? sin (4t) the
results in either a small linear response or a
large nonlinear response respectively.
16- Compare the transient behavior for the nonlinear
(correct) model and the linear model. - Different initial conditions are used and the
forcing term, when used, takes the form ?
sin(1.2t). - Figure Below- Large Initial Push and No Forcing
Term. There is very little difference as both
models settle back to equilibrium.
17- Now, a forcing term is introduced, ?.05 but with
initial conditions at equilibrium. - As seen in Figure below, the results for both
models are again similar.
18- In Figure Below both effects are combined.
- As predicted by the Principle of Superposition,
the linear system (top) dies out. - The nonlinear model goes into large torsional
oscillation, eventually settling down to a large
periodic motion.
19- The sensitivity of the nonlinear system to the
amplitude of the forcing term is exhibited in the
Figure below. - If ? is reduced from 0.05 (top) to 0.04 (bottom)
the motion is reduced to near-equilibrium.
20The Transition to Torsional Motion
- Investigate initial value problem for nonlinear
system if cables lose tension briefly - Start with large vertical push y(0)26 and tiny
torsional forcing - As seen in figure below, the cables lose tension
for about 2 periods but torsional motions are
around zero.
21Vertical and Torsional Responses to large push
(y(0)26) in vertical direction
22The Transition to Torsional Motion
- Repeat Experiment but change y(0)31.
- At first almost no torsional oscillations then it
instantaneously approaches 1 radian - With no torsional forcing term, the motion is
damped and settles down to near equilibrium
23Vertical and Torsional Responses to large push
(y(0)31) in vertical direction
24- Repeat Experiment with tiny displacement ? (0)
.001 and no torsional forcing term. - Results Below- Again, no torsional oscillation
for a while, then and instantaneous jump to large
torsional oscillation up to around 1 radian - With no torsional forcing term, oscillation dies
down due to damping.
25- Now, we combine a small periodic forcing term and
a large vertical push. - Results- A quick transition to large torsional
oscillation as the vertical oscillation is damped
away.
26Conclusion
- Linearizing for small oscillations was a good
approximation but for large oscillations it
should be categorized as an error. - The error of treating cables, in both their
loaded and unloaded state, as springs that obey
Hookes law was corrected. - Most important conclusion-Within frequencies
corresponding to those of the bridge, the final
oscillations produced by the nonlinear model can
be both very large or very small.
27- Thank You For Your Time.
- Questions?