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Center of Mass and Linear Momentum

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Title: Center of Mass and Linear Momentum


1
Chapter 9 Center of Mass and Linear Momentum
2
  • Linear momentum
  • Linear momentum (or, simply momentum) of a
    point-like object (particle) is
  • SI unit of linear momentum is kgm/s
  • Momentum is a vector, its direction coincides
    with the direction of velocity

3
  • Newtons Second Law revisited
  • Originally, Newton formulated his Second Law in
    a more general form
  • The rate of change of the momentum of an object
    is equal to the net force acting on the object
  • For a constant mass

4
  • Center of mass
  • In a certain reference frame we consider a
    system of particles, each of which can be
    described by a mass and a position vector
  • For this system we can define a center of mass

5
  • Center of mass of two particles
  • A system consists of two particles on the x axis
  • Then the center of mass is
  • Changing the reference frame

6
  • Newtons Second Law for a system of particles
  • For a system of particles, the center of mass is
  • Then

7
  • Newtons Second Law for a system of particles
  • From the previous slide
  • Here is a resultant force on particle i
  • According to the Newtons Third Law, the forces
    that particles of the system exert on each other
    (internal forces) should cancel
  • Here is the net force of all external
    forces that act on the system (assuming the mass
    of the system does not change)

8
Newtons Second Law for a system of particles
9
  • Linear momentum for a system of particles
  • We define a total momentum of a system as
  • Using the definition of the center of mass
  • The linear momentum of a system of particles is
    equal to the product of the total mass of the
    system and the velocity of the center of mass

10
  • Linear momentum for a system of particles
  • Total momentum of a system
  • Taking a time derivative
  • Alternative form of the Newtons Second Law for
    a system of particles

11
  • Conservation of linear momentum
  • From the Newtons Second Law
  • If the net force acting on a system is zero,
    then
  • If no net external force acts on a system of
    particles, the total linear momentum of the
    system is conserved (constant)
  • This rule applies independently to all components

12
  • Center of mass of a rigid body
  • For a system of individual particles we have
  • For a rigid body (continuous assembly of matter)
    with volume V and density ?(V) we generalize a
    definition of a center of mass

13
Chapter 9 Problem 82
14
  • Impulse
  • During a collision, an object is acted upon by a
    force exerted on it by other objects
    participating in the collision
  • We define impulse as
  • Then (momentum-impulse theorem)

15
  • Elastic and inelastic collisions
  • During a collision, the total linear momentum is
    always conserved if the system is isolated (no
    external force)
  • It may not necessarily apply to the total
    kinetic energy
  • If the total kinetic energy is conserved during
    the collision, then such a collision is called
    elastic
  • If the total kinetic energy is not conserved
    during the collision, then such a collision is
    called inelastic
  • If the total kinetic energy loss during the
    collision is a maximum (the objects stick
    together), then such a collision is called
    completely inelastic

16
Elastic collision in 1D
17
  • Elastic collision in 1D stationary target
  • Stationary target v2i 0
  • Then

18
Chapter 9 Problem 58
19
Completely inelastic collision in 1D
20
Chapter 9 Problem 62
21
  • Answers to the even-numbered problems
  • Chapter 9
  • Problem 2
  • -1.50 m
  • (b) -1.43 m

22
Answers to the even-numbered problems Chapter 9
Problem 10 6.2 m
23
Answers to the even-numbered problems Chapter 9
Problem 18 4.9 kg m/s
24
  • Answers to the even-numbered problems
  • Chapter 9
  • Problem 26
  • 42 N s
  • (b) 2.1 kN

25
Answers to the even-numbered problems Chapter 9
Problem 46 3.1 102 m/s
26
  • Answers to the even-numbered problems
  • Chapter 9
  • Problem 66
  • (10 m/s)i (15 m/s)j
  • (b) -500 J

27
  • Answers to the even-numbered problems
  • Chapter 9
  • Problem 70
  • 2.7
  • (b) 7.4
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