Title: Physics 207, Lecture 16, Oct. 29
1Physics 207, Lecture 16, Oct. 29
- Agenda Chapter 13
- Center of Mass
- Torque
- Moment of Inertia
- Rotational Energy
- Rotational Momentum
- Assignment
- Wednesday is an exam review session, Exam will be
held in rooms B102 B130 in Van Vleck at 715 PM - MP Homework 7, Ch. 11, 5 problems,
- NOTE Due Wednesday at 4 PM
- MP Homework 7A, Ch. 13, 5 problems, available soon
2Chap. 13 Rotational Dynamics
- Up until now rotation has been only in terms of
circular motion with ac v2 / R and aT d
v / dt - Rotation is common in the world around us.
- Many ideas developed for translational motion are
transferable.
3Conservation of angular momentum has consequences
How does one describe rotation (magnitude and
direction)?
4Rotational Dynamics A childs toy, a physics
playground or a students nightmare
- A merry-go-round is spinning and we run and jump
on it. What does it do? - We are standing on the rim and our friends spin
it faster. What happens to us? - We are standing on the rim a walk towards the
center. Does anything change?
5Rotational Variables
- Rotation about a fixed axis
- Consider a disk rotating aboutan axis through
its center - How do we describe the motion
- (Analogous to the linear case )
6Rotational Variables...
- Recall At a point a distance R away from the
axis of rotation, the tangential motion - x ? R
- v ? R
- a ? R
7Summary (with comparison to 1-D kinematics)
And for a point at a distance R from the rotation
axis
x R ????????????v ? R ??????????a ? R
8Lecture 15, Exercise 5Rotational Definitions
- A friend at a party (perhaps a little tipsy) sees
a disk spinning and says Ooh, look! Theres a
wheel with a negative w and positive a! - Which of the following is a true statement about
the wheel?
- The wheel is spinning counter-clockwise and
slowing down. - The wheel is spinning counter-clockwise and
speeding up. - The wheel is spinning clockwise and slowing down.
- The wheel is spinning clockwise and speeding up
9Lecture 15, Exercise 5Rotational Definitions
- A goofy friend sees a disk spinning and says
Ooh, look! Theres a wheel with a negative w and
with antiparallel w and a! - Which of the following is a true statement about
the wheel?
(A) The wheel is spinning counter-clockwise and
slowing down. (B) The wheel is spinning
counter-clockwise and speeding up. (C) The wheel
is spinning clockwise and slowing down. (D) The
wheel is spinning clockwise and speeding up
10Example Wheel And Rope
- A wheel with radius r 0.4 m rotates freely
about a fixed axle. There is a rope wound around
the wheel. - Starting from rest at t 0, the rope is
pulled such that it has a constant acceleration a
4m/s2. - How many revolutions has the wheel made after
10 seconds? - (One revolution 2? radians)
11Example Wheel And Rope
- A wheel with radius r 0.4 m rotates freely
about a fixed axle. There is a rope wound around
the wheel. Starting from rest at t 0, the rope
is pulled such that it has a constant
acceleration a 4 m/s2. How many revolutions
has the wheel made after 10 seconds?
(One revolution 2? radians) - Revolutions R (q - q0) / 2p and a a r
- q q0 w0 t ½ a t2 ?
- R (q - q0) / 2p 0 ½ (a/r) t2 / 2p
- R (0.5 x 10 x 100) / 6.28
12System of Particles (Distributed Mass)
- Until now, we have considered the behavior of
very simple systems (one or two masses). - But real objects have distributed mass !
- For example, consider a simple rotating disk and
2 equal mass m plugs at distances r and 2r. - Compare the velocities and kinetic energies at
these two points.
w
1
2
13System of Particles (Distributed Mass)
- An extended solid object (like a disk) can be
thought of as a collection of parts. - The motion of each little part depends on where
it is in the object! - The rotation axis matters too!
1 K ½ m v2 ½ m (w r)2
w
2 K ½ m (2v)2 ½ m (w 2r)2
14System of Particles Center of Mass
- If an object is not held then it rotates about
the center of mass. - Center of mass Where the system is balanced !
- Building a mobile is an exercise in finding
- centers of mass.
mobile
15System of Particles Center of Mass
- How do we describe the position of a system
made up of many parts ? - Define the Center of Mass (average position)
- For a collection of N individual pointlike
particles whose masses and positions we know
RCM
m2
m1
r2
r1
y
x
(In this case, N 2)
16Sample calculation
- Consider the following mass distribution
XCM (m x 0 2m x 12 m x 24 )/4m meters YCM
(m x 0 2m x 12 m x 0 )/4m meters XCM 12
meters YCM 6 meters
17System of Particles Center of Mass
- For a continuous solid, convert sums to an
integral.
dm
r
y
where dm is an infinitesimal mass element.
x
18Rotational Dynamics What makes it spin?
A force applied at a distance from the rotation
axis
- Torque is the rotational equivalent of force
- Torque has units of kg m2/s2 (kg m/s2) m N m
- A constant torque gives constant angular
acceleration iff the mass distribution and the
axis of rotation remain constant.
19Lecture 16, Exercise 1Torque
- In which of the cases shown below is the torque
provided by the applied force about the rotation
axis biggest? In both cases the magnitude and
direction of the applied force is the same. - Remember torque requires F, r and sin q
- or the tangential force component times
perpendicular distance
- Case 1
- Case 2
- Same
20Lecture 16, Exercise 1Torque
- In which of the cases shown below is the torque
provided by the applied force about the rotation
axis biggest? In both cases the magnitude and
direction of the applied force is the same. - Remember torque requires F, r and sin f
- or the tangential force component times
perpendicular distance
L
F
F
(A) case 1 (B) case 2 (C) same
L
axis
case 1
case 2
21Rotational Dynamics What makes it spin?
A force applied at a distance from the rotation
axis
- Torque is the rotational equivalent of force
- Torque has units of kg m2/s2 (kg m/s2) m N m
?TOT r FTang r m a
r m r a m r2 a
For every little part of the wheel
22 ?TOT m r2 a and inertia
- The further a mass is away from this axis the
greater the inertia (resistance) to rotation
- This is the rotational version of FTOT ma
- Moment of inertia, I m r2 , (here I is just a
point on the wheel) is the rotational equivalent
of mass. - If I is big, more torque is required to achieve
a given angular acceleration.
23Calculating Moment of Inertia
- where r is the distance from the mass
to the axis of rotation.
Example Calculate the moment of inertia of four
point masses (m) on the corners of a square whose
sides have length L, about a perpendicular axis
through the center of the square
m
m
L
m
m
24Calculating Moment of Inertia...
- For a single object, I depends on the rotation
axis! - Example I1 4 m R2 4 m (21/2 L / 2)2
I1 2mL2
I 2mL2
I2 mL2
m
m
L
m
m
25Lecture 16, Exercise 2Moment of Inertia
- A triangular shape is made from identical balls
and identical rigid, massless rods as shown. The
moment of inertia about the a, b, and c axes is
Ia, Ib, and Ic respectively. - Which of the following is correct
(A) Ia gt Ib gt Ic (B) Ia gt Ic gt Ib (C)
Ib gt Ia gt Ic
26Lecture 16, Home Exercise Moment of Inertia
- Ia 2 m (2L)2 Ib 3 m L2 Ic m (2L)2
-
- Which of the following is correct
a
(A) Ia gt Ib gt Ic (B) Ia gt Ic gt Ib (C)
Ib gt Ia gt Ic
L
b
L
c
27Calculating Moment of Inertia...
- For a discrete collection of point masses we
found - For a continuous solid object we have to add up
the mr2 contribution for every infinitesimal mass
element dm. - An integral is required to find I
dm
r
28Moments of Inertia
- Some examples of I for solid objects
- Solid disk or cylinder of mass M and radius
R, about perpendicular axis through its center. - I ½ M R2
29Moments of Inertia...
- Some examples of I for solid objects
Solid sphere of mass M and radius R, about an
axis through its center. I 2/5 M R2
R
Thin spherical shell of mass M and radius R,
about an axis through its center. Use the table
R
See Table 13.3, Moments of Inertia
30Moments of Inertia
- Some examples of I for solid objects
Thin hoop (or cylinder) of mass M and radius R,
about an axis through it center, perpendicular
to the plane of the hoop is just MR2
R
R
Thin hoop of mass M and radius R, about an axis
through a diameter.
31Rotation Kinetic Energy
- Consider the simple rotating system shown below.
(Assume the masses are attached to the rotation
axis by massless rigid rods). - The kinetic energy of this system will be the sum
of the kinetic energy of each piece - K ½ m1v12 ½ m2v22 ½ m3v32 ½ m4v42
m4
m1
r1
?
r4
r2
m3
r3
m2
32Rotation Kinetic Energy
- Notice that v1 w r1 , v2 w r2 , v3 w r3 ,
v4 w r4 - So we can rewrite the summation
-
- We recognize the quantity, moment of inertia or
I, and write
33Lecture 16, Exercise 2Rotational Kinetic Energy
- We have two balls of the same mass. Ball 1 is
attached to a 0.1 m long rope. It spins around at
2 revolutions per second. Ball 2 is on a 0.2 m
long rope. It spins around at 2 revolutions per
second. - What is the ratio of the kinetic energy
- of Ball 2 to that of Ball 1 ?
- ¼
- ½
- 1
- 2
- 4
34Lecture 16, Exercise 2Rotational Kinetic Energy
- K2/K1 ½ m wr22 / ½ m wr12 0.22 / 0.12 4
- What is the ratio of the kinetic energy of Ball 2
to that of Ball 1 ? - (A) 1/4 (B) 1/2 (C) 1 (D) 2 (E)
4
35Rotation Kinetic Energy...
- The kinetic energy of a rotating system looks
similar to that of a point particle - Point Particle Rotating System
v is linear velocity m is the mass.
? is angular velocity I is the moment of
inertia about the rotation axis.
36Moment of Inertia and Rotational Energy
- Notice that the moment of inertia I depends on
the distribution of mass in the system. - The further the mass is from the rotation axis,
the bigger the moment of inertia. - For a given object, the moment of inertia depends
on where we choose the rotation axis (unlike the
center of mass). - In rotational dynamics, the moment of inertia I
appears in the same way that mass m does in
linear dynamics !
37Work (in rotational motion)
- Consider the work done by a force F acting on an
object constrained to move around a fixed axis.
For an infinitesimal angular displacement d?
where dr R d? - ?dW FTangential dr
- dW (FTangential R) d?
- ?dW ? d? (and with a constant torque)
- We can integrate this to find W ? ?
(?f-ti) ? - Analogue of W F ?r
- W will be negative if ? and ? have opposite sign
!
axis of rotation
38Work Kinetic Energy
- Recall the Work Kinetic-Energy Theorem ?K
WNET - This is true in general, and hence applies to
rotational motion as well as linear motion. - So for an object that rotates about a fixed axis
39Lecture 16, Home exercise Work Energy
- Strings are wrapped around the circumference of
two solid disks and pulled with identical forces
for the same linear distance. Disk 1 has a
bigger radius, but both are identical material
(i.e. their density r M/V is the same). Both
disks rotate freely around axes though their
centers, and start at rest. - Which disk has the biggest angular velocity
after the pull?
W ? ? F d ½ I w2 (A) Disk 1 (B) Disk
2 (C) Same
w2
w1
F
F
start
d
finish
40Lecture 16, Home exercise Work Energy
- Strings are wrapped around the circumference of
two solid disks and pulled with identical forces
for the same linear distance. Disk 1 has a
bigger radius, but both are identical material
(i.e. their density r M/V is the same). Both
disks rotate freely around axes though their
centers, and start at rest. - Which disk has the biggest angular velocity
after the pull?
W F d ½ I1 w12 ½ I2 w22 w1 (I2 / I1)½ w2
and I2 lt I1 (A) Disk 1 (B) Disk 2 (C) Same
w2
w1
F
F
start
d
finish
41Example Rotating Rod
- A uniform rod of length L0.5 m and mass m1 kg
is free to rotate on a frictionless pin passing
through one end as in the Figure. The rod is
released from rest in the horizontal position.
What is - (A) its angular speed when it reaches the lowest
point ? - (B) its initial angular acceleration ?
- (C) initial linear acceleration of its free end
?
42Example Rotating Rod
- A uniform rod of length L0.5 m and mass m1 kg
is free to rotate on a frictionless hinge passing
through one end as shown. The rod is released
from rest in the horizontal position. What is - (B) its initial angular acceleration ?
- 1. For forces you need to locate the Center of
Mass - CM is at L/2 ( halfway ) and put in the Force on
a FBD - 2. The hinge changes everything!
S F 0 occurs only at the hinge
but tz I az r F sin 90 at the center of
mass and (ICM m(L/2)2) az (L/2) mg and solve
for az
mg
43Example Rotating Rod
- A uniform rod of length L0.5 m and mass m1 kg
is free to rotate on a frictionless hinge passing
through one end as shown. The rod is released
from rest in the horizontal position. What is - (C) initial linear acceleration of its free end
? - 1. For forces you need to locate the Center of
Mass - CM is at L/2 ( halfway ) and put in the Force on
a FBD - 2. The hinge changes everything!
a a L
mg
44Example Rotating Rod
- A uniform rod of length L0.5 m and mass m1 kg
is free to rotate on a frictionless hinge passing
through one end as shown. The rod is released
from rest in the horizontal position. What is - (A) its angular speed when it reaches the lowest
point ? - 1. For forces you need to locate the Center of
Mass - CM is at L/2 ( halfway ) and use the Work-Energy
Theorem - 2. The hinge changes everything!
L
W mgh ½ I w2
m
W mgL/2 ½ (ICM m (L/2)2) w2 and solve for
w
mg
L/2
mg
45Connection with CM motion
- If an object of mass M is moving linearly at
velocity VCM without rotating then its kinetic
energy is
- If an object of moment of inertia ICM is rotating
in place about its center of mass at angular
velocity w then its kinetic energy is
- What if the object is both moving linearly and
rotating?
46Connection with CM motion...
- So for a solid object which rotates about its
center of mass and whose CM is moving
VCM
?
47Rolling Motion
- Now consider a cylinder rolling at a constant
speed.
VCM
CM
The cylinder is rotating about CM and its CM is
moving at constant speed (VCM). Thus its total
kinetic energy is given by
48Lecture 16, Example The YoYo
- A solid uniform disk yoyo of radium R and mass M
starts from rest, unrolls, and falls a distance
h. - (1) What is the angular acceleration?
- (2) What will be the linear velocity of the
center of mass after it falls h meters? - (3) What is the tension on the cord ?
T
w
M
h
49Lecture 16, Example The YoYo
- A solid uniform disk yoyo of radium R and mass M
starts from rest, unrolls, and falls a distance
h. - Conceptual Exercise
- Which of the following pictures correctly
represents the yoyo after it falls a height h? - (A) (B) (C)
h
50Lecture 16, Example The YoYo
- A solid uniform disk yoyo of radium R and mass M
starts from rest, unrolls, and falls a distance
h. - Conceptual Exercise
- Which of the following pictures correctly
represents the yoyo after it falls a height h? - (A) (B) No Fx, no ax (C)
T
w0
M
h
h
Mg
51Lecture 16, Example The YoYo
- A solid uniform disk yoyo of radium R and mass M
starts from rest, unrolls, and falls a distance
h. - (1) What is the angular acceleration?
- (2) What will be the linear velocity of the
center of mass after it falls h meters? - (3) What is the tension on the cord ?
T
Choose a point and calculate the torque
St I az Mg R T0 ( ½ MR2 MR2 ) az
Mg R az Mg /(3/2 MR) 2 g / (3R)
w
M
X
h
52Lecture 16, Example The YoYo
- A solid uniform disk yoyo of radium R and mass M
starts from rest, unrolls, and falls a distance
h. - (1) What is the angular acceleration?
- (2) What will be the linear velocity of the
center of mass after it falls h meters? - (3) What is the tension on the cord ?
- az Mg /(3/2 MR) 2 g / (3R)
- and aCM az R 2g/3 (down)
- Can use kinetics or work energy
- Mgh ½ mv2 ½ ICM w2
- Mgh ½ Mv2 ½ ( ½ MR2) (v/R)2
- gh ¾ v2 ? v 2 (gh/3)½
T
w
M
X
h
53Lecture 16, Example The YoYo
- A solid uniform disk yoyo of radium R and mass M
starts from rest, unrolls, and falls a distance
h. - (1) What is the angular acceleration?
- (2) What will be the linear velocity of the
center of mass after it falls h meters? - (3) What is the tension on the cord ?
- aCM az R -2g/3
- MaCM - 2Mg/3 T Mg
- T Mg/3
- or from torques
- I az TR ½ MR2 (2g/3R)
- T Mg/3
T
w
M
X
h
54Rolling Motion
- Again consider a cylinder rolling at a constant
speed.
2VCM
CM
VCM
55Example Rolling Motion
- A cylinder is about to roll down an inclined
plane. What is its speed at the bottom of the
plane ?
56Example Rolling Motion
- A cylinder is about to roll down an inclined
plane. What is its speed at the bottom of the
plane ? - Use Work-Energy theorem
Mgh ½ Mv2 ½ ICM w2 Mgh ½ Mv2 ½ (½ M R2
)(v/R)2 ¾ Mv2 v 2(gh/3)½
57Rolling Motion
- Now consider a cylinder rolling at a constant
speed.
VCM
CM
The cylinder is rotating about CM and its CM is
moving at constant speed (VCM). Thus its total
kinetic energy is given by
58 Motion
- Again consider a cylinder rolling at a constant
speed.
Both with VTang VCM
Rotation only VTang wR
Sliding only
2VCM
VCM
CM
CM
CM
VCM
59Angular Momentum
- We have shown that for a system of particles,
- momentum
-
- is conserved if
- What is the rotational equivalent of this?
- angular momentum
- is conserved if
-
60Example Two Disks
- A disk of mass M and radius R rotates around the
z axis with angular velocity ?0. A second
identical disk, initially not rotating, is
dropped on top of the first. There is friction
between the disks, and eventually they rotate
together with angular velocity ?F.
?0
61Example Two Disks
- A disk of mass M and radius R rotates around the
z axis with initial angular velocity ?0. A
second identical disk, at rest, is dropped on top
of the first. There is friction between the
disks, and eventually they rotate together with
angular velocity ?F.
No External Torque so Lz is constant Li Lf ?
I wi i I wf ? ½ mR2 w0 ½ 2mR2 wf
62Lecture 16, Oct. 29
- Assignment
- Wednesday is an exam review session, Exam will be
held in rooms B102 B130 in Van Vleck at 715 PM - MP Homework 7, Ch. 11, 5 problems,
- NOTE Due Wednesday at 4 PM
- MP Homework 7A, Ch. 13, 5 problems, available
soon
63Angular MomentumDefinitions Derivations
p mv
- We have shown that for a system of particles
- Momentum is conserved if
- What is the rotational equivalent of this?
-
- The rotational analog of force F is torque ?
- Define the rotational analog of momentum p to be
angular momentum, L or
64Recall from Chapter 9 Linear Momentum
- Definition For a single particle, the momentum
p is defined as
p mv
(p is a vector since v is a vector)
So px mvx etc.
F ma
- Units of linear momentum are kg m/s.
65Linear Momentum and Angular Momentum
F ma
- Units of angular momentum are kg m2/s.
66Putting it all together
- In the absence of external torques
Total angular momentum is conserved
67Angular momentum of a rigid bodyabout a fixed
axis
- Consider a rigid distribution of point particles
rotating in the x-y plane around the z axis, as
shown below. The total angular momentum around
the origin is the sum of the angular momentum of
each particle
(since ri , vi , are perpendicular)
v1
We see that L is in the z direction.
m2
Using vi ? ri , we get
r2
r1
i
v2
r3
v3
m3
68Example Two Disks
- A disk of mass M and radius R rotates around the
z axis with angular velocity ?0. A second
identical disk, initially not rotating, is
dropped on top of the first. There is friction
between the disks, and eventually they rotate
together with angular velocity ?F.
?0
69Example Two Disks
- A disk of mass M and radius R rotates around the
z axis with initial angular velocity ?0. A
second identical disk, at rest, is dropped on top
of the first. There is friction between the
disks, and eventually they rotate together with
angular velocity ?F.
No External Torque so Lz is constant Li Lf ?
I wi i I wf ? ½ mR2 w0 ½ 2mR2 wf
70DemonstrationConservation of Angular Momentum
z
Arm
Arm
?B
LA LB
IA IB
wA wB
No External Torque so Lz is constant even if
internal work done.
71DemonstrationConservation of Angular Momentum
z
Arm
Arm
?B
?A
IAwA LA LB IBwB
IA lt IB wA gt wB ½ IAwA2 gt ½
IB wB2 (work needs to be done)
No External Torque so Lz is constant even if
internal work done.
72Angular Momentum Conservation
- A freely moving particle has a well defined
angular momentum about any given axis. - If no torques are acting on the particle, its
angular momentum remains constant (i.e., will be
conserved). - In the example below, the direction of L is along
the z axis, and its magnitude is given by LZ pd
mvd.
y
x
d
v
m
73Example Bullet hitting stick
- A uniform stick of mass M and length D is pivoted
at the center. A bullet of mass m is shot through
the stick at a point halfway between the pivot
and the end. The initial speed of the bullet is
v1, and the final speed is v2. - What is the angular speed ?F of the stick after
the collision? (Ignore gravity)
M
D
?F
m
D/4
v1
v2
before
after
74Example Bullet hitting stick
- What is the angular speed ?F of the stick after
the collision? (Ignore gravity). - Process (1) Define system (2) Identify
Conditions - (1) System bullet and stick (No Ext. torque, L
is constant) - (2) Momentum is conserved (Istick I MD2/12 )
- Linit Lbullet Lstick m v1 D/4 0 Lfinal
m v2 D/4 I wf
M
D
?F
m
D/4
v1
v2
before
after
75Example Throwing ball from stool
- A student sits on a stool, initially at rest, but
which is free to rotate. The moment of inertia
of the student plus the stool is I. They throw a
heavy ball of mass M with speed v such that its
velocity vector moves a distance d from the axis
of rotation. - What is the angular speed ?F of the
student-stool system after they throw the ball ? -
M
v
d
?F
I
I
Top view before after
76Example Throwing ball from stool
- What is the angular speed ?F of the student-stool
system after they throw the ball ? - Process (1) Define system (2) Identify
Conditions - (1) System student, stool and ball (No Ext.
torque, L is constant) - (2) Momentum is conserved
- Linit 0 Lfinal m v d I wf
M
v
d
?F
I
I
Top view before after
77An example Neutron Star rotation
Neutron star with a mass of 1.5 solar masses has
a diameter of 11 km. Our sun rotates about once
every 37 days wf / wi Ii / If ri2 / rf2
(7x105 km)2/(11 km)2 4 x 109 gives millisecond
periods!
period of pulsar is 1.187911164 s
78Angular Momentum as a Fundamental Quantity
- The concept of angular momentum is also valid on
a submicroscopic scale - Angular momentum has been used in the development
of modern theories of atomic, molecular and
nuclear physics - In these systems, the angular momentum has been
found to be a fundamental quantity - Fundamental here means that it is an intrinsic
property of these objects
79Fundamental Angular Momentum
- Angular momentum has discrete values
- These discrete values are multiples of a
fundamental unit of angular momentum - The fundamental unit of angular momentum is h-bar
- Where h is called Plancks constant
80Intrinsic Angular Momentum
photon
81Angular Momentum of a Molecule
- Consider the molecule as a rigid rotor, with the
two atoms separated by a fixed distance - The rotation occurs about the center of mass in
the plane of the page with a speed of
82Angular Momentum of a Molecule (It heats the
water in a microwave over)
E h2/(8p2I) J (J1) J 0, 1, 2, .
83Center of Mass Example Astronauts Rope
- Two astronauts are initially at rest in outer
space and 20 meters apart. The one on the right
has 1.5 times the mass of the other (as shown).
The 1.5 m astronaut wants to get back to the ship
but his jet pack is broken. There happens to be
a rope connected between the two. The heavier
astronaut starts pulling in the rope. - (1) Does he/she get back to the ship ?
- (2) Does he/she meet the other astronaut ?
M 1.5m
m
84Example Astronauts Rope
- There is no external force so if the larger
astronaut pulls on the rope he will create an
impulse that accelerates him/her to the left and
the small astronaut to the right. The larger
ones velocity will be less than the smaller
ones so he/she doesnt let go of the rope they
will either collide (elastically or
inelastically) and thus never make it.
85Example Astronauts Rope
- (2) However if the larger astronaut lets go of
the rope he will get to the ship. (Too bad for
the smaller astronaut!) - In all cases the center of mass will remain fixed
because they are initially at rest and there is
no external force. - To find the position where they meet all we need
do is find the Center of Mass