Title: Review of Relative Density Principles
1Review of Relative Density Principles
- Relative Density principles apply to compaction
of relatively clean, coarse-grained soils. - Relatively clean usually taken to be less 12 or
less finer than the 200 sieve. - Important for compaction study of filters
2Objectives
- Explain basic principles of compacting clean
sands and gravels - Understand basic tests to obtain reference
densities. - Use 1 point compaction test in design and quality
control
- Summarize minimum and maximum index density tests
- Detail the importance of water content in
compacting clean sands and gravels
3Review of Compaction Principles
- Compaction Tests are not commonly performed on
soils with 12 or fewer fines - Small percentage of fines means soils cannot
easily hold water to examine range of water and
effect on dry density
4Review of Compaction Principles
- Compaction tests performed on clean sands may
have this appearance
Dr density
w
5Compacting Clean Sands
- Clean sands are compacted most easily at either
very dry or very wet water contents - At intermediate water contents, capillary
stresses in voids resist compaction - Bulking is term for this phenomenon
6Compacting Clean Sands
- Vibration most effective energy for sands
- Use smooth-wheeled vibratory roller
7Relative Density
- Alternative to traditional compaction test is
relative density tests - Minimum Index Density
- Maximum Index Density
- Relative Density
8Minimum Index Density
- Minimum index density of clean sand is that
resulting from very loosely filling a steel mold.
ASTM Method D4254
Sand dropped no more than 1
9Minimum Index Density
- After filling the mold, excess soil is carefully
screed off. The volume of this mold is 0.1 ft3.
Knowing the weight of soil in the mold, the dry
density is easily computed
10Maximum Index Density
- Example Minimum dry density 96 pcf
- Maximum index density of clean sand results from
vibration at high amplitude on vibratory table
for 10 minutes. ASTM D4253 - Example Maximum dry density 117.5 pcf
11Maximum Index Density
Weight on sample inside sleeve
Vibratory table
12Maximum Index Density
Weight on sample inside sleeve
Vibratory table
13Maximum Index Density
Sample densified by vibration
Measure D height to determine new gd
Plate on which weight sits during vibration
14Void Ratio and Dry Density
- The void Ratio is calculated for each state of
denseness of sample. - Maximum void ratio occurs at minimum index
density - For Example Min.gd 96.0 pcf - Minimum void ratio occurs at maximum index
density For Example Maximum gd 110.0 pcf
15Minimum and Maximum Void Ratios
- First Calculate void ratio at Minimum gd
- Next Calculate void ratio at Maximum gd
16Relative Density Equation
Diagram below illustrates a relative density of
about 40
emeasured
emax
emin
?d measured
?dmax
?d min
increasing density
17Calculate Void Ratio of Compacted Sand
- Now, assume that the density of this sand was
measured in a compacted fill and it was 102.5
pcf. Calculate a value for relative density of
the fill. First, calculate the void ratio of the
fill
18Compute Relative Density
- Now, use the values of void ratio in the relative
density equation
19Compute Relative Density
- Relative Density Equation(rewritten in dry
density terms) - Solve for Example
?
20Fort Worth Relative Density Study
- NRCS lab in Fort Worth studied 28 filter sands
and used some published data - Minimum and Maximum Index Densities were
performed on each sample - A 1 point dry Standard Proctor energy mold was
also prepared for each sample. - Values of 50 and 70 relative density were
plotted against the 1 point Proctor value
2170 Relative Density vs. 1 Point Proctor
2270 Relative Density vs. 1 Point Proctor
- Conclusion is that the field 1 point Proctor dry
test is about equal to 70 relative density
2350 Relative Density vs. 1 Point Proctor
2450 Relative Density vs. 1 Point Proctor
- Conclusion is that the 95 of the field 1 point
Proctor dry test is about equal to 50 relative
density
25Relative Density Estimates from FW SML Study
gD70 1.075 x gd 1pt -9.61, for RD70 and gd
1pt in lb/ft3 gD50 1.07 x gd 1pt - 12.5,
for RD50 and gd 1pt in lb/ft3
26Relative Density Estimates from FW SML Study
- Example Relative Density Estimates
- Given 1 Point Proctor Testgd 105.5 pcf
- Estimate 70 and 50 Relative Density
- Given that measured gd is 98.7, evaluate state of
compaction of sand.
27Review of Relative Density
- Class Problem - Relative Density
- A soils minimum index density is 96.5 pcf and
its maximum index density is 111.5 pcf. The Gs
value is 2.65 - Calculate the emin and emax
- Compute the void ratio and dry density
corresponding to a relative density value of 70
28Class Problem Solution
- Given Minimum index density is 96.5 pcf
- Maximum index density is 111.5 pcf.
29Class Problem Solution
- Now, substitue a value for RD of 70() in the
relative density equation
30Class Problem Solution
- Solving and Rearranging the equation
31Class Problem Solution
- Now, calculate a value for dry density at this
void ratio
- Summary - The dry density corresponding to 70()
relative density for this sample is 106.5 pcf
32Other information on Relative Density
33Other information on Relative Density
Chart is for silty sands (SM)
34Class Problem
- Given that the water content of a silty sand that
was obtained from a saturated zone of a channel
bank measured 24.5 percent - What is the estimated relative density of the
sand?
35Class Problem Solution
- Reading from the chart, the estimated Rd value is
about 42 percent.