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CELEBRITY CHEMIST of THE DAY

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Title: CELEBRITY CHEMIST of THE DAY


1
CELEBRITY CHEMIST of THE DAY
2
MOLE CONCEPT
Unit of measure for matter
  • Number of particles in one mole Avogadros
    number 6.02 X 10 23
  • 602 000 000 000 000 000 000 000

3
How many molecules are present in 4 moles of H2O?
How many atoms are present?
  • SOLUTION
  • One mole of any substance contains 6.02 X 10 23
    particles, therefore
  • (4 moles) 6.02 X 10 23 2.41 X 10 24 molecules
  • mole
  • Since there are 3 atoms per H2O molecule,
  • the total number of atoms is
  • (3 atoms) 2.41 X 10 24 molecules 7.23 X 10 24
    atoms
  • molecule

4
MOLAR MASS
  • Mass of one mole mass of one atom/molecule
    expressed in grams rather than atomic mass unit
    (amu)
  • 1 amu based on 1/12 the mass of C-12 (most
    common carbon isotope)
  • Example
  • 1 atom of He 4 amus
  • 1 mole of He 4 grams
  • 1 molecule of O2 2 x 16 amus/O 32 amus
  • 1 mole of O2 32 grams

5
FORMULA
  • GIVEN WEIGHT
  • MOLAR MASS

NUMBER OF MOLES

GW MM
n

6
How many moles of carbon atoms are contained in 4
g of carbon?
  • The atomic mass of carbon is 12 amu, therefore
    the molar mass of carbon is 12 grams.
  • 4 g X 1 mole 0.333 mole C
  • 12 g

CONVERSION FACTOR (from periodic table)
7
2. How many moles of water are there in 36 g of
water?
  • SOLUTION
  • The molecular mass of H2O is 18 amu.
  • The molar mass of H2O is 18 g.
  • 36 g X 1 mole 2 moles H2O
  • 18 g

8
3. Calculate the mass of aluminum carbonate
(Al2(CO3)3) in 5.85 moles of the compound.
  • In Al2(CO3)3 , there are 2 Al, 3 C and 9 O
  • Formula mass (2 X 27 g/Al)
  • (3 X 12 g/C) (9 X 16 g/O) 234 g
  • Molar mass 234 g
  • Mass of Al2(CO3)3 5.85 moles X 234 g 1369 g

9
MOLAR VOLUME
  • Volume of one mole of solid and liquids varies
    from one substance to another based on their
    density
  • Example
  • 1 mole of H2O (density 1.00 g/mL) has a mass
    of 18 grams and will therefore occupy 18 mL
  • 1 mole of NaCl (density 2.165 g/mL) has a mass
    58 g
  • (Na 23 g Cl 35 g) and would occupy a
    volume of 26.8 mL (58 g /2.165 g/mL)
  • Volume of one mole of gas equal to 22.4 liters
    at standard temperature (0oC) and pressure (1 atm
    or 760 mm Hg) (STP)
  • 1 mole of O2 gas 22.4 L at STP
  • 1 mole of He 22.4 L at STP

10
How many moles of nitrogen are present in 4.48
liters of nitrogen at STP?
  • Since there are 22.4 liters of any gas at STP,
    the solution is
  • 4.48 L X 1 mole 0.2 moles N2
  • 22.4 L

CONVERSION FACTOR
11
PERCENT COMPOSITION
  • Percent by mass of each element present in the
    compound.

by mass of each element
Total mass of element X 100 Total mass of
compound

12
What is the percentage composition of H2O?
H in H2O
2 X 1 g x 100 18 g
11.11

O in H2O
1 X 16 g x 100 18 g
88.89

TO CHECK 100.00
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