Finding Small Two-Qubit Circuits - PowerPoint PPT Presentation

About This Presentation
Title:

Finding Small Two-Qubit Circuits

Description:

DARPA DARPA Finding Small Two-Qubit Circuits Vivek V. Shende Igor L. Markov Stephen S. Bullock – PowerPoint PPT presentation

Number of Views:80
Avg rating:3.0/5.0
Slides: 23
Provided by: umichEdu7
Category:
Tags: circuits | finding | qubit | two

less

Transcript and Presenter's Notes

Title: Finding Small Two-Qubit Circuits


1
Finding Small Two-Qubit Circuits
  • Vivek V. Shende
  • Igor L. Markov
  • Stephen S. Bullock

2
Outline
  • Motivation
  • Background
  • One Qubit Rotations
  • Two Qubit Entanglement
  • Our Results

3
We Can Find
  • A one-CNOT circuit to prepare a given 2-qubit
    pure state from 0?.
  • A two-CNOT circuit to simulate a given 2-qubit
    unitary operator up to relative phase.
  • A CNOT-optimal circuit, using at most three
    CNOTs, to simulate a given 2-qubit unitary
    operator.

4
We Can Find
  • (If possible) A time, t, for a given Hamiltonian,
    H, such that eiHt, is a CNOT, up to 1-qubit
    gates.
  • We can also find the 1-qubit gates.
  • An eighteen-CNOT circuit to simulate a given
    three-qubit unitary operator.
  • (If a conjecture in Barenco et. Al. 95 holds)

5
1-Qubit Rotations
A. Barenco et al., Elementary Gates For Quantum
Computation, PRA 52, 1995.
  • We use the following 1-qubit gates
  • Any 1-qubit operator can be written as RzRyRz,
    RxRzRx, RxRyRz, etc.
  • Three gates needed to simulate a generic operator
    in SU(2), since dim SU(2) 3

6
2-Qubit Entanglement
S. Hill, K. Wooters, Entanglement of a Pair of
Quantum Bits, PRL 78, 1997.
  • For a two-qubit state vector, f?, TFAE
  • f? is not entangled, ie, f? f1?f0?
  • ?0f? ?3f? - ?1f? ?2f? 0
  • fTsy?2 f 0
  • If u ? U(4) satisfies uTsy?2u sy?2
  • (uf)Tsy?2 uf fTuTsy?2 uf fTsy?2f
  • Thus u cannot introduce entanglement
  • Hence is a wire swap followed by local unitaries
  • u (a ? b)(wire swap), then det(a ? b) 1
  • If det(u) 1, then u a ? b for a,b ? SU(2)

7
The Magic Basis
S. Hill, K. Wooters, Entanglement of a Pair of
Quantum Bits, PRL 78, 1997.
  • EET sy?2 iff E-1SU(2)?2E SO(4)
  • Proof
  • u ? SU(2) iff uTsy?2u sy?2
  • Equivalently, (E-1uE)T(E-1uE) 1
  • Hence u ? SU(2) iff E-1uE ? SO(4)
  • And such E ? U(4) exist

8
The Makhlin Invariants
Yu. Makhlin, Nonlocal Properties of Two-qubit
Gates and Mixed States and Optimization of
Quantum Computations, QIP 1, p. 243, 2002.
  • For u,v ? SU(4), sy?2uTsy?2u and sy?2vTsy?2v have
    the same spectra iff there exist a,b,c,d ?SU(2)
    s.t.
  • Proof
  • In the Magic Basis, this says that UUT is similar
    to VVT iff there exist A,B ? SO(4) such that U
    AVB
  • Write UUT A-1VVTA. Since UUT, VVT are
    symmetric, can choose A ? SO(4).
  • Then U-1A-1V is in SO(4) and AU(U-1A-1V) V.

9
How many gates does it take
  • to simulate a generic 2-qubit operator (up to
    global phase)?

10
18 Gates Suffice
  • Any 2-qubit operator can be simulated by a
    circuit of the form
  • Proof Compute invariants

11
18 Gates Are Necessary
  • Need 15 of the 1-parameter gates since SU(4) is
    15-dimensional
  • Need 3 CNOTs to prevent cancellation

a
c
Rx
Rx
Ry
Rz
Ry
Rz
b
d
12
How many CNOTs does it take
  • to simulate a given
  • two-qubit operator?

13
How to count CNOTs
  • For u in SU(4), let ?(u) uTsy?2usy?2
  • Then u can be simulated using
  • 1-qubit gates at most three CNOTs
  • 1-qubit gates two CNOTs iff tr?(u) is real
  • 1-qubit gates one CNOT iff ?(u)? ?i, ?(u)2 -1
  • 1-qubit gates and a wire swap iff ?(u) ?i
  • Only 1-qubit gates iff ?(u) ?1
  • Proof Compute invariants

14
Examples
  • Any u in SO(4) can be simulated by two CNOTs and
    some 1-qubit gates
  • The wire swap needs three CNOTs
  • The two-qubit QFT needs at least three CNOTs and
    three 1-qubit gates

15
How many CNOTs does it take
  • to simulate a given two-qubit operator up to
    relative phase?

16
Simulation up to Relative Phase
  • Two CNOTs are sufficient
  • Proof for any u ? SU(4), can find a diagonal d
    such that tr?(du) is real.
  • Useful because measurement in the computational
    basis kills relative phase

17
Can I Simulate the CNOT
  • by appropriately timing a given Hamiltonian?

18
Simulating CNOT
  • Given a Hamiltonian, H, want to determine a time,
    t, for which eiHt differs from CNOT by 1-qubit
    gates
  • Compute ?(eiHt) for various values of t

19
Application CNOT in the presence of noise
  • Fact can time H sx?sx to implement up to CNOT
    1-qubit gates
  • Add a noise term, eg., (0.42) I?sz
  • Numerical tests yield t0.80587

20
Conclusions
  • We can find small (often optimal) circuits for
    2-qubit operators

21
The End
22
Useful fact about sy
Write a Comment
User Comments (0)
About PowerShow.com