Title: Water,%20Water%20Everywhere
1Water, Water Everywhere
2Water as Liquid - Rainwater
3Water as Solid - Iceberg
4Snow and Snow Flakes
5Water Vapor (Steam)
6Water Cycle
7Water Cycle
8Water Molecule
9Hydrogen Bonding in Water
10What Makes Soils Rocks Have Different Colors
11Where does Chemistry fit in?
- Chemistry is about the study of matters and the
changes they undergo. - Chemistry probes the fundamental units of matter
in order to understand how and why they are what
they are. - Chemists always ask questions and try to find the
answers.
12The Central Science
- Chemistry is regarded as the central science.
- Chemistry is essential in understanding the
various aspects of living and non-living things - It is essential in understanding natural and
unnatural processes of nature.
13What is Matter?
- The materials of the universe
- ? anything that has mass and occupies space
14What Type of Change?
- Physical or Chemical processes
- Physical Change
- A process that alters the state of a substance,
but not its fundamental composition. - Chemical Change
- A process that alters the fundamental
composition of the substance and, therefore, its
identity.
15The Scientific Approach
- Making Observations/collecting Data
- Formulating Hypotheses
- Testing the Hypotheses
- Revising the Hypothesis
- Summarizing Hypotheses into a Theory
- Summarizing observations or natural behavior into
a Scientific Law
16Steps in the scientific Method?
- Identify the Problems and ask Questions
- Develop a Hypothesis based on observations
- Test The Hypothesis
- (Design Perform Experiments)
- Collect more Data
- Analyze Results
- Make a Conclusion
- Suggest further studies on the subject.
17Definitions of Terms in Scientific Methods
- Hypothesis-
- a plausible or logical statement that attempts
to explain the observation or data. - Theory -
- a set of (tested) hypotheses that explain a
certain behavior of nature. - Scientific Law -
- a concise statement about a natural phenomenon
or behavior.
18Measurements
- The Number System
- Decimal Numbers
- 384,400
- 0.08206
- Scientific Notations
- 3.844 x 105
- 8.206 x 10-2
19Units of Measurements
- Units give meaning to numbers.
- Without Unit With Units
- 384,400 ? 384,400 km (very far)
- 384,400 cm (not very far)
- 0.08206 ? 0.08206 L.atm/(K.mol)
- 144 ? 144 eggs
20English Units
- Mass ounce (oz.), pound (lb.), ton
- Length inches, feet, yards, miles
- Volume pints, quarts, gallons, in3, ft3, etc.
- Area acre, hectare, in2, ft2, yd2, mi2.
21Metric Units
- Mass milligram (mg), gram (g), kilogram (kg),
- Length cm, m, km, mm, mm, nm,
- Area cm2, m2, km2
- Volume mL(cm3), dL, L,, m3.
22SI Units
- Mass kilogram (kg)
- Length meter (m)
- Area square meter (m2)
- Volume cubic meter (m3)
- Temperature Kelvin (K)
- Energy Joule (J)
- Charge Coulomb (C)
- Time second (s)
23Prefixes in the Metric System
- Prefix Symbol 10n Decimal Forms
- Giga G 109 1,000,000,000
- Mega M 106 1,000,000
- kilo k 103 1,000
- deci d 10-1 0.1
- centi c 10-2 0.01
- milli m 10-3 0.001
- micro m 10-6 0.000,001
- nano n 10-9 0.000,000,001
-
24Accuracy and Precisionin Measurements
- Accuracy
- The agreement of an experimental value with the
true or accepted value - Precision
- The reproducibility of measurements of the same
type
25Accuracy and Precision
26Errors in Measurements
- Random errors
- values have equal chances of being high or low
- may be minimize by taking the average of several
measurements of the same kind - Systematic errors
- Errors due to faulty instruments
- Reading is either higher or lower than the
correct value by a fixed amount - Weighing by differences can eliminate systematic
errors of the faulty instruments.
27Significant Figures
- All non-zero digits
- Example 453.6 has 4 significant figures.
- Captive zeros
- Example 1.079 has 4 significant figures.
- Trailing zeros if the decimal point is shown
- Example 1080 has 3 significant figures, but
1080. or 1.080 x 103 has 4 significant figures. - Leading zeros are not significant figures
- Example 0.02050 has 4 significant figures
28How many significant figures?
- 0.00239
- 0.01950
- 1.00 x 10-3
- 100.40
- 168,000
- 0.082060
- 144 eggs in a carton
- Express one thousand as a value with two
significant figures.
29Rounding off Calculated values
- In Multiplications and Divisions
- Round off the final answer so that it has the
same number of significant figures as the one
with the least significant figures. -
- Examples
- (a) 9.546 x 3.12 29.8 (round off from
29.78352) - (b) 9.546/2.5 3.8 (round off from 3.8184)
- (c) (9.546 x 3.12)/2.5 12 (round off from
11.913408) -
30Rounding off Calculated values
- In Additions and Subtractions
- Round off the final answer so that it has the
same number of digits after the decimal point as
the data value with the least number of such
digits. - Examples
- (a) 53.6 7.265 60.9 (round off from 60.865)
- (b) 53.6 7.265 46.3 (round off from 46.335)
- (c) 41 7.265 5.5 43 (round off from 42.765)
31Mean, Median Standard Deviation
- Mean average
- Example
- Consider the following temperature values
- 20.4oC, 20.6oC, 20.3oC, 20.5oC, 20.4oC, and
20.2oC - (Is there any outlying value that we can throw
away?) - No outlying value, the mean temperature is
- (20.4 20.6 20.3 20.5 20.4 20.2) 6
20.4oC
32Mean, Median Standard Deviation
- Median
- the middle value (for odd number samples) or
- average of two middle values (for even number)
- when values are arranged in ascending or
descending order. - For the following temperatures
- 20.4oC, 20.6oC, 20.3oC, 20.5oC, 20.4oC, and
20.2oC, - the median 20.4oC
33Mean, Median Standard Deviation
- Standard Deviation, S
- (for n lt 10, Xi sample value mean
value) - Note calculated value for std. deviation should
have one significant figure only. -
- For above temperatures, S 0.1 Mean 20.4
0.1 oC
34Calculating Mean Value
- Consider the following masses of pennies (in
grams) - 2.48, 2.50, 2.52, 2.49, 2.50, 3.02, 2.49, and
2.51 - Is there outlying value?
- Yes 3.02 does not belong in the group can be
discarded - Outlying values should not be included when
calculating the mean, median, or standard
deviation. - Average (mean) mass of pennies is,
- (2.48 2.50 2.52 2.49 2.50 2.49 2.51)
7 2.50 g
35Calculating Standard Deviation
- _________________________
- -0.02 0.0004
- -0.00 0.0000
- 0.02 0.0004
- -0.01 0.0001
- 0.00 0.0000
- -0.01 0.0001
- 0.01 0.0001___
- Sum 0.0011
- ------------------------------------------
36Mean and Standard Deviation
- The correct mean value that is consistent with
the precision is expressed as follows - 2.50 0.01
37Using Q-test to retain or reject questionable
values
- Calculate Qcalc. as follows
- Qcalc.
- Compare Qcalc with Qtab from Table-2 at the
chosen confidence level for the matching sample
size - If Qcalc lt Qtab, the questionable value is
retained - If Qcalc gt Qtab, the questionable value is can
rejected.
38Rejection Quotient
- Rejection quotient, Qtab, at 90 confidence level
-
- Sample size Qtab ___
- 4 0.76
- 5 0.64
- 6 0.56
- 7 0.51
- 8 0.47
- 9 0.44
- 10 0.41
-
39Performing Q-test on Sample Data
- Consider the following set of data values
- 0.5230, 0.5325, 0.5560, 0.5250, 0.5180, and
0.5270 - Two questionable values are 0.5180 0.5560 (the
lowest and highest values in the group) - Perform Q-test at 90 confidence level on 0.5180
- Qcalc. 0.13 lt 0.56
- (limit at 90 confidence level for sample size of
6) - We keep 0.5180.
40Performing Q-test on questionable value
- Calculate rejection quotient for 0.5560
- Qcalc. 0.618 gt 0.56
- (limit at 90 confidence level for a sample of 6
is 0.56) - We reject 0.5560.
41Calculate the mean using acceptable values
- Re-write the mean value to be consistent with the
precision - Mean 0.526 0.005
42Calculating Standard Deviation
- ???????????????
- 0.5230 -0.0028 7.8 x 10-6
- 0.5325 0.0067 4.5 x 10-5
- 0.5250 -0.0008 6.4 x 10-7
- 0.5180 -0.0078 6.1 x 10-5
- 0.7270 0.0012 1.4 x 10-6
- S 1.16 x 10-4
43Mean value must be consistent with the precision
- Standard deviation
- should have one significant digit only
- It shows where the uncertainty appears in mean
value - That is, which digit on the mean contains error
- The mean value should be rounded off at the digit
where it becomes uncertain. - Thus, the mean consistent with the precision will
be - 0.526 0.005
- (the mean value is precise up to the third
decimal place)
44Problem Solving by Dimensional Analysis
- Value sought value given x conversion factor(s)
- Example
- How many kilometers is 25 miles? (1 mi. 1.609
km) - Value sought ? km value given 25 miles
- conversion factor 1 mi. 1.609 km
- ? km 25 mi. x (1.609 km/1 mi.) 40. km
45Unit Conversions
- (1) Express 26 miles per gallon (mpg) to
kilometers per liter (kmpL). - (1 mile 1.609 km and 1 gallon 3.7854 L)
- (Answer 11 kmpL)
- (2) If the speed of light is 3.00 x 108 m/s, what
is the speed in miles per hour (mph)? - (1 km 1000 m and 1 hour 3600 s)
- (Answer 6.71 x 108)
46Temperature
- Temperature scales
- Celsius (oC)
- Fahrenheit (oF)
- Kelvin (K)
- Reference temperatures freezing and boiling
point of water - Tf 0 oC 32 oF 273.15 K
- Tb 100 oC 212 oF 373.15 K
47Temperature Conversion
- Fahrenheit to Celsius
- (T oF 32 oF) x (5oC/9oF) T oC
- Example converting 98.6oF to oC
- (98.6 oF 32 oF) x (5oC/9oF) 37.0 oC
48Temperature Conversion
- Celsius to Fahrenheit
- ToC x (9oF/5oC) 32 oF T oF
- Example converting 25.0oC to oF
- 25.0 oC x (9oF/5oC) 32 oF 77.0 oF
49Temperature Conversion
- Celsius to Kelvin T oC 273.15 T K
- Kelvin to Celsius T K 273.15 T oC
- Examples
- 25.0 oC to Kelvin 25.0 273.15 298.2 K
- 310. K to oC 310. 273.15 27 oC
50Temperature Conversion
- 1) What is the temperature of 65.0 oF expressed
in degrees Celsius and in Kelvin? - (Answer 18.3 oC 291.5 K)
- 2) A newly invented thermometer has a T-scale
that ranges from -50 T to 300 T. On this
thermometer, the freezing point of water is -20 T
and its boiling point is 230 T. Find a formula
that would enable you to convert a T-scale
temperature to degrees Celsius. What is the
temperature of 92.5 T in Celsius? - (Answer 45.0 oC)
51Density
- Density Mass/Volume
- (Mass Volume x density Volume
mass/density) - Units g/mL or g/cm3 (for liquids or solids)
- g/L (for gases)
- SI unit kg/m3
- Examples density of water 1.00 g/mL (1.00
g/cm3) - in SI unit 1.00 x 103 kg/m3
52Determining Volumes
- Rectangular objects V length x width x
thickness - Cylindrical objects V pr2l (or pr2h)
- Spherical objects V (4/3)pr3
- Liquid displacement method
- the volume of object submerged in a liquid is
equal to the volume of liquid displaced by the
object. -
53Density Determination
- Example-1
- A cylindrical metal rod that is 1.00 m long and
a diameter of 1.50 cm weighs 477.0 grams. What is
the density of metal? - Volume p(1.50 cm)2 x 100. cm 177 cm3
- Density 477.0 g/177 cm3 2.70 g/cm3
54Density Determination
- Example-2
- A 100-mL graduated cylinder is filled with 35.0
mL of water. When a 45.0-g sample of zinc pellets
is poured into the graduate, the water level
rises to 41.3 mL. Calculate the density of zinc. - Volume of zinc pellets 41.3 mL 35.0 mL 6.3
mL - Density of zinc 45.0 g/6.3 mL 7.1 g/mL (7.1
g/cm3)
55Density Calculation 1
- The mass of an empty flask is 64.25 g. When
filled with water, the combined mass of flask and
water is 91.75 g. However, when the flask is
filled with an alcohol sample the combined mass
is found to be 85.90 g. If we assume that the
density of water is 1.00 g/mL, what is the
density of the alcohol sample? - (Answer 0.787 g/mL)
56Density Calculation 2
- A 50-mL graduated cylinder weighs 41.30 g when
empty. When filled with 30.0 mL of water, the
combined mass is 71.25 g. A piece of metal is
dropped into the water in the graduate, which
causes the water level rises to 36.9 mL. The
combined mass of graduate, water and metal is
132.65 g. Calculate the densities of water and
metal. - (Answer 0.998 g/mL and 8.9 g/mL, respectively)
57Classification of Matter
58Classification of Matter
- Mixture matter with variable composition
- Homogeneous mixture
- One that has a uniform appearance and
composition throughout the mixture - Heterogeneous mixture
- One that has neither uniform appearance or
composition the appearance and composition in
one part of the mixture may differ from the other
part - Substance matter with a fixed composition
59Substances
- Element
- Composed of only one type of atoms it cannot
be further reduced to simpler forms. - Compound
- Composed of at least two different types of
atoms combined chemically in a fixed ratio it
may be broken down into simpler forms (or reduced
to the elements)
60Physical Changes
- Examples
- melting,
- freezing,
- evaporation,
- condensation,
- sublimation,
- dissolution.
61Chemical Changes
- Examples
- combustion (burning),
- decomposition,
- chemical combination (synthesis),
- fermentation,
- corrosion,
- oxidation and reduction,
- (any chemical reactions)
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