Law of Sines - PowerPoint PPT Presentation

1 / 14
About This Presentation
Title:

Law of Sines

Description:

MATH 109 - Precalculus S ... most triangles will not be right triangles Thus we need a method to apply to find side lengths and angles of other types of triangles ... – PowerPoint PPT presentation

Number of Views:131
Avg rating:3.0/5.0
Slides: 15
Provided by: Lab
Category:
Tags: law | math | sines | triangles | types

less

Transcript and Presenter's Notes

Title: Law of Sines


1
Law of Sines
  • MATH 109 - Precalculus
  • S. Rook

2
Overview
  • Section 6.1 in the textbook
  • Law of Sines

3
Law of Sines
4
Oblique Triangles
  • Oblique Triangle a triangle containing no right
    angles
  • All of the triangles we have studied thus far
    have been right triangles
  • We can apply SOHCAHTOA only to right triangles
  • Naturally most triangles will not be right
    triangles
  • Thus we need a method to apply to find side
    lengths and angles of other types of triangles

5
Four Cases for Oblique Triangles
  • By definition a triangle has three sides and
    three angles for a total of 6 components
  • We can find the measure of all sides and all
    angles if we know AT LEAST 3 of these components
  • Broken down into four cases
  • AAS or ASA
  • Measure of two angles and the length of any side
  • SSA
  • Length of two sides and the measure of the angle
    opposite one of two known sides
  • Known as the ambiguous case because none, one, or
    two triangles could be possible

6
Four Cases for Oblique Triangles (Continued)
  • SSS
  • Length of all three sides
  • SAS
  • Length of two sides and the measure of the angle
    opposite the third (possibly unknown) side
  • AAA is NOT a case because there are an infinite
    number of triangles that can be drawn
  • Recall that the largest side is opposite the
    largest and angle, but there is no limitation on
    the length of the side!

7
Law of Sines
  • The first two cases (AAS/ASA and SSA) are covered
    by the Law of Sines
  • i.e. the ratio of the measure of any side of a
    triangle to its corresponding angle yields the
    same constant value
  • This constant value is different for each
    triangle
  • The Law of Sines can be proved by dropping an
    altitude from an oblique triangle and using
    trigonometric functions with the right angle
  • See page 489
  • ALWAYS draw the triangle!

8
Law of Sines AAS/ASA (Example)
  • Ex 1 Use the Law of Sines to solve the triangle
    round answers to two decimal places
  • a) A 102.4, C 16.7, a 21.6
  • b) A 55, B 42, c ¾

9
SSA the Ambiguous Case
  • Occurs when we know the length of two sides and
    the measure of the angle opposite one of two
    known sides
  • e.g. a, b, A and b, c, C are SSA cases
  • e.g. a, b, C and b, c, A are NOT (they are SAS
    cases)
  • To solve the SSA case
  • Use the Law of Sines to calculate the missing
    angle across from one of the known sides
  • There are three possible cases

10
SSA the Ambiguous Case (Continued)
  • Let A be the missing angle across from one of the
    known sides and B be the measure of the known
    angle
  • Case I sin A gt 1
  • e.g. sin A 1.3511
  • Recall the domain for the inverse sine -1 x
    1
  • NO triangle exists
  • Recall that the sine is positive in both Q I and
    Q II and how to use reference angles to obtain
    the angle in Q II
  • Case II (180 A) B 180
  • i.e. the measure of the possible second angle
    yields a second triangle with contradictory
    dimensions
  • ONE triangle exists

11
SSA the Ambiguous Case (Continued)
  • Case III (180 A) B lt 180
  • i.e. the measure of the possible second angle
    yields a second triangle with feasible dimensions
  • TWO triangles exist

12
SSA the Ambiguous Case (Example)
  • Ex 2 Use the Law of Sines to solve for all
    solutions round to two decimal places
  • a) A 54, a 7, b 10
  • b) A 98, a 10, b 3
  • c) C 27.83, c 347, b 425
  • d) B 58, b 11.4, c 12.8

13
Law of Sines Application (Example)
  • Ex 3 A bridge is to be built across a small
    lake from a gazebo to a dock (see figure on page
    437). The bearing from the gazebo to the dock is
    S 41 W. From a tree 100 meters away from the
    gazebo, the bearings to the gazebo and dock are S
    74 E and S 28 E respectively. Find the length
    of the bridge.

14
Summary
  • After studying these slides, you should be able
    to
  • Apply the Law of Sines in solving for the
    components of a triangle or in an application
    problem
  • Additional Practice
  • See the list of suggested problems for 6.1
  • Next lesson
  • Law of Cosines (Section 6.2)
Write a Comment
User Comments (0)
About PowerShow.com