Title: The Law of Sines
1The Law of Sines
2Law of Sines
- If A, B, and C are the measures of the angles of
a triangle, and a, b, and c are the lengths of
the sides opposite these angles, then -
- The ratio of the length of the side of any
triangle to the sine of the angle opposite that
side is the same for all three sides of the
triangle.
3Text Example
- Solve triangle ABC if A 50º, C 33.5º, and b
76.
Solution We begin by drawing a picture of
triangle ABC and labeling it with the given
information. The figure shows the triangle that
we must solve. We begin by finding B.
4Solve triangle ABC if A 50º, C 33.5º, and b
76.
Text Example cont.
Solution Keep in mind that we must be given one
of the three ratios to apply the Law of Sines. In
this example, we are given that b 76 and we
found that B 96.5º. Thus, we use the ratio
b/sin B, or 76/sin96.5º, to find the other two
sides. Use the Law of Sines to find a and c.
Find a Find c
The solution is B 96.5º, a ? 59, and c ? 42.
5Example
- Solve the triangle shown with A36º, B88º and
c29 feet.
Solution
A36º, B88º so 180-88-3656º C56º
6The Ambiguous Case (SSA)
Consider a triangle in which a, b, and A are
given. This information may result in
No Triangle One Right Triangle
Two Triangles One
Triangle
7One Solution
- Solve the triangle shown with A43º, a81 and
b62.
149 43 gt 180. Thus there is only 1 solution.
8Two Solutions
- Solve the triangle shown with X40º, x54 and
z62.
132 40 lt 180, so we have 2 solutions!
9No Solution
- Solve the triangle shown with A75º, a51 and
b71.
No Solution!
10Area of An Oblique Triangle
- The area of a triangle equals one-half the
product of the lengths of two sides times the
sine of their included angle. In the following
figure, this wording can be expressed by the
formulas
11Text Example
- Find the area of a triangle having two sides of
lengths 24 meters and 10 meters and an included
angle of 62º.
12Example
- Find the area of a triangle having two sides of
lengths 12 ft. and 20 ft. and an included angle
of 57º.
Solution