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The Law of Sines

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The Law of Sines x 15ft 15 65 B A C We can find the area of a triangle if we are given any two sides of a triangle and the measure of the included angle. – PowerPoint PPT presentation

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Title: The Law of Sines


1
Chapter 14.1
  • The Law of Sines

2
We know that Trigonometry can help us solve
right triangles. But not all triangles are right
triangles. Fortunately, Trigonometry can help us
solve non-right triangles as well. Non-right
triangles are know as oblique triangles. There
are two categories of oblique trianglesacute and
obtuse.
3
Acute Triangles
In an acute triangle, each of the angles is less
than 90º.
4
Obtuse Triangles
In an obtuse triangle, one of the angles is
obtuse (between 90º and 180º). Can there be two
obtuse angles in a triangle?
Of course not!
5
Law of Sines

6
The Law of Sines is used when we know any two
angles and one side or when we know two sides and
an angle opposite one of those sides.
7
There are two cases where one side and two angles
are known ASA or SAA
8
Disclaimer Do not assume that any
triangles are drawn to scale.
9
Lets do an example involving ASA. From the
model, we need to determine a, b, and ? using
the law of sines.
10
First off, 42º 61º ? 180º so that ?
77º. (Knowledge of two angles yields the third!)
11
Now by the law of sines, we have the following
relationships
12
Lets solve for our unknowns
13
Now, an example involving SAA From the model, we
need to determine a, b, and ? using the law of
sines. Note ? 110º 40º 180º so that ?
30º
b
a
14
By the law of sines, we have the following
relationships
15
Therefore,
16
The Ambiguous Case SSA In this case, you may
have information that results in one triangle,
two triangles, or no triangles.
17
Example 1 of SSA Two sides and an angle
opposite one of the sides are given. Lets try
to solve this triangle.
18
By the law of sines,
19
Thus,
Therefore, there is no value for ? that exists!
No triangle is possible!
20
Example 2 of SSA
Two sides and an angle opposite one of the sides
are given. Lets try to solve this triangle.
21
By the law of sines,
22
So that,
Interesting! Lets see if one or both of these
angle measures makes sense.
23
Case 1 Case 2
Both triangles are valid! Therefore, we have two
possible cases to solve.
24
Finish Case 1
25
Finish Case 2
26
Wrapping it up, here are our two solutions
27
Example 3 of SSA
Two sides and an angle opposite one of the sides
are given. Lets try to solve this triangle.
28
By the law of sines,
29
(No Transcript)
30
Note Only one is legitimate!
31
Thus, we have only one triangle.
Now lets find b.
32
By the law of sines,
33
Finally, we have
34
Example Finding the Height of a Telephone Pole

35
The Area of a TriangleUsing Trigonometry
We can find the area of a triangle if we are
given any two sides of a triangle and the measure
of the included angle. (SAS)
36
Example Find the area of given a 32 m, b 9
m, and
37
Homework pg. 891 893 11 47 e.o.o. and
46, 50, 53, 55
  • Now go and practice. Remember, practice makes
    perfect!
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