Title: Lecture 10
1Lecture 10 Axial compressors 2
- Blade design
- Preliminary design of a seven stage compressor
- choice of rotational speed and annulus dimension
- estimation of the number of stages and stage by
stage design - variation of air angles from root to tip
- Compressibility effects in axial compressors
- Problem 5.1
2Blade design
- We want
- blade must achieve required turning at maximum
efficiency over a range of rotational speeds - Correlated experiments are very valuable to
estimate performance - tests on single blades (effect of adjacent blades
must be estimated) - tests on rows of blades - so called cascades
- Linear cascades (rectilinear cascade).
Mechanically simpler than annular to build. Flow
patterns are simpler to interpret. More frequent.
- Annular. Many root tip ratios would be required.
Does not satisfactorily reproduce flow in actual
compressor
Annular cascade
Linear cascade
3Blade design
- For a test camber angle ?, chord c and pitch s
will be fixed and the stagger angle ? is changed
by the turn table. - Pressures and velocities are measured downstream
and upstream by traversing instruments
4Blade design
- Measurements are recorded as pressure losses and
deflection - Incidence is varied by turning the turn-table
- Mean deflection and loss are computed
5Blade design
- Selecting more than 80 of stall deflection means
risk of stalling at part load - Select
- Stall reached when loss is twice of minimum loss
- e is dependent mainly on s/c and a2 for a given
cascade. Thus, data can be reduced into one
diagram
6Blade design
- Air angles decided from design
- Pitch/Chord from Fig. 5-26
- Blade heigth from area requirement.
- Assume h/c (methods for selecting h/c are
discussed in section 5.9 which is less relevant
to course) - s, c and h/c will then be known
- The blade outlet angle is determined from air
outlet angle and empirical rule for deviation. - Assume camber-line shape (for instance circular
arc)
7Rotational speed and annulus dimensions
- Compressor for low cost, turbojet
- Design point specification
- rc 4.15, m 20 kg/s, T3 1100 K
- No inlet guide vanes (a10.0)
- Annulus dimension? Assume values on
- blade tip speed range 350-450 m/s. Values close
to 350 m/s will limit stress problems - axial velocity range 150-200 m/s. Try 150 m/s
to reduce difficulties associated with shock
losses - root-tip ratio range 0.4-0.6
- You should know that these ranges represent
typical values that you can assume on exam.
8Annulus dimension
Continuity gives the compressor inlet area
9Annulus dimension
A single stage turbine can designed to drive
this compressor if a rotational speed of 250
rev/s is chosen (Chapter 7). N 250 rev/s gives
Considering the relatively low Ut centrifugal
stresses in the root will not be critical and the
choice of a root-tip ratio of 0.5 will be
considered a good starting point for the design.
Recall the approximative formula
10Annulus dimension
- A check on the tip Mach number gives
This is a suitable level of Mach number.
Relative Mach numbers over about 1.2-1.3 would
require supercritical (controlled diffusion
blading). Too low values would result in a low
stage temperature rise.
- The compressor exit temperature is estimated
assuming a polytropic efficiency, ? c,polytropic,
of 90, which gives the exit area
11Annulus dimension
- The blade height at exit can now be calculated
12Estimation of the number of stages
- Assumed polytropic efficiency gave
- Reasonable stage temperature rises are 10-30 K.
Up to 45 is possible for high-performance
transonic stages. Let us estimate what we could
get in our case
- We have derived the stage temperature rise as
13Estimation of the number of stages
- An overestimation of the temperature rise is
obtained for a de Haller number equal to the
minimum allowable limit 0.72
- Which gives a rotor blade outlet angle
- Setting the work done factor ? 1.0 yields
- We could not expect to achieve the design target
unless we use
- Since 6 is close to achievable aerodynamic
limits, seven is a reasonable assumption!
14Design goal
- Stage 1 and stage 7 are somewhat less loaded to
allow for - Stage 1 highest Mach numbers occur in first
stage rotor tip gt difficult aerodynamic design.
Inlet distortion of flow may be substantial. Less
aerodynamic loading may alleviate these
difficulties - Stage 7 it is desirable to have an axial flow
exiting the stator of the last stage gt a higher
deflection is necessary in this stage which may
be easier to design for if a reduction in goal
temperature rise is allowed for - This gives the following design criteria
(assuming a typical work done distribution)
15Stage-by-stage design - Stage 1
- The change in whirl velocity for the first stage
is
- A check on the de Haller number giveswhich is
satisfactory. The diffusion factors will be
checked at a later stage.
16Stage-by-stage design Stage 1
- For small pressure ratios isentropic and
polytropic efficiencies are close to equal.
Approximate the isentropic stage efficiency to be
0.90. This gives the stage pressure rise as
- We have finally to choose a 3. Since a 1 in stage
2 will equal a 3 in stage 1, this will be done as
part of the design process for the second stage.
17Stage-by-stage design Stage 2
- Since we do not know a1 for the second stage we
need further design requirements. We will use the
degree of reaction. The degree of reaction for
the first stage is (a3 in first stage is 11.06
degrees. cos(11.06) 0.981)
- Since the root-tip ratio of the first stage is
the lowest, the greatest difficulties with low
degrees of reaction will be experienced in the
first stage rotor. Thus, a good margin to 0.50
has to be accepted.
18Stage-by-stage design
- Due to the increase in root-tip ratio for the
second stage we hope to be able to use a ? of
0.70
- Solving the two simultaneous equations for ß 1
and ß 2 gives
- a 1 and a 2 are then obtained from (obtaining a
1 means that the design of the first stage is
complete)
19Stage-by-stage design - Stage 1
- The design of the first stage is now complete
- The de Haller number in thestator is
20Stage-by-stage design Stage 2
- The stage pressure rise of stage 2 becomes
- We have finally to choose a 3. Since a 1 in stage
3 will equal a 3 in stage 2, this will be done as
part of the design process for the third stage.
21Stage-by-stage design Stage 3
- Due to the further decrease in root-tip ratio to
the third stage we hope to be able to use a ? of
0.50
- Solving the two simultaneous equations for ß 1
and ß 2 gives ß 151.24 and ß 228.00. This
gives a to low de Haller number which can be
dealt with by reducing the temperature increase
over the stage to 24K. Repeating the calculation
gives
- which is produces an ok de Haller number. a 1
and a 2 are obtained from symmetry which is
obtained when ? 0.50.
22Stage-by-stage design - Stage 2
- The design of the second stage is now complete
- The de Haller number in thestator is
23Stage-by-stage design Stage 3
- The stage pressure rise of stage 3 becomes
- We have finally to choose a 3. Since a 1 in stage
4 will equal a 3 in stage 3, this will be done as
part of the design process for the fourth.
24Stage-by-stage design Stage 4,5 and 6
- We maintain ? of 0.50 for stage 4, 5 and 6
- Since ? is 0.83 for the remaining stages, the
stages 4, 5 and 6 are all designed with the same
angles. Again the stage temperature rise is
reduced to 24 K to maintain the de Haller number
at an high enough number. Solving the two
equations give
25Stage-by-stage design - Stage 3
- The design of the third stage is now complete
- The de Haller number in thestator is
26Stage-by-stage design stage 4,5,6
- The stage pressure rise and exit temperature and
pressure of stages 4,5,6 become
- Stage 4, 5 and 6 are repeating stages, except for
the stator outlet angle of stage 6 which is
governed by the design of stage 7.
27Stage-by-stage design - Stage 4,5,6
- The design of stages 4,5 and 6 are now complete
- The de Haller number for thestators are
28Stage-by-stage design stage 7
- We maintain ? of 0.50 for stage 7
- The pressure ratio of the seventh stage is set by
the overall requirement of an rc 4.15. The
stage inlet pressure is 3.56 bar, which gives the
required pressure ratio and temperature increase
according to
29Stage-by-stage design - Stage 7
- The design of stage 7 is now complete
- Exit guide vanes can be incorporated to
straighten flow before it enters the burner
30Annulus shape
- The main types of annulus designs exists
- Constant mean diameter
- Constant outer diameter
- Constant inner diameter
- Constant outer diameter
- Mean blade speed increases with stage number
- Less deflection required gt de Haller number will
be greater - U1 and U2 will not be the same!!! It will be
necessary to use
31Variations from root to tip
- Calculate angles at root, mid and tip using the
free vortex design principle, i.e. - Cwr constant
- The requirement is satisfied at inlet since Cw 0
(no IGV) - Blade speed at root, mean and tip are
32Variations from root to tip
- Cw velocities are computed using the whirl
velocity at the mid, Cw2,m 76.9 m/s together
with the free vortex condition. - Cwr constant
- The root and tip radii will have changed due to
the increase in density of the gas. Compute the
exit area according to
- Which gives the blade height, root and tip radii
33Variations from root to tip
- The rotor exit tip and root radii are assumed to
be the average of the stage exit and inlet radii
- The free vortex condition gives
34Variations from root to tip
- The stator inlet angles a 2,r , a 2,m , a 2,t
and rotor exit angles ß 2,r , ß 2,m , ß 2,t are
obtained from
- Note the necessary radial blade twist for air
and blade angles to agreee - The reaction at the root is 0.697. The high
value at the mean radius ensured a high enough
value at the root - Where do the highest stator Mach numbers occur
??
35Compressibility effects
- Fan tip Mach numbers of more than 1.5 are today
frequent in high bypass ratio turbofans - At some free-stream Mach number a local Mach
number exceeding 1.0 will occur over the blade - This Mach number is called the criticalMach
number Mcr. - A turbulent boundary layer will separate if the
pressure rise across the shock exceeds that for
a normal shock with an upstream Mach number of
1.3 (Schlichting 1979). Keep this in mind!!!
36Effect of Mach number on losses
- As the Mach number passes the critical Mach
number - minimum loss increases and the range of
incidence for which losses are acceptable is
drastically reduced - Simplified shock model
- The turning determines the Mach number at
station B (Prandtl-Meyer relations - Appendix
A.8 - you may skip that section). The more
turning the higher the Mach number - Shock loss Normal shock loss taken at
averageMach number at A and B. - Why less loaded first stage in example
- Less loaded first stage gt less turning gt
reduced shock losses
37Supercritical design - Mrel gt 1.3
- How would you design a blade operating at Mach
number 1.6 remembering that - A turbulent boundary layer will separate if the
pressure rise across the shock exceeds that for
a normal shock with an upstream Mach number of
1.3 (Schlichting 1979)
38Supercritical blading
Concave portion gt supercritical
diffusion Concave section after entrance region
39Supercritical blading
40Learning goals
- Know how to determine a multistage compressor
design for a certain specification. - This includes making assumptions design
parameters - Have an understanding of how compressor design
must be adjusted for high Mach number effects.