Title: A Mathematical Model of Motion
1A Mathematical Model of Motion
25.1 Graphing Motion in One Dimension
- Interpret graphs of position versus time for a
moving object to determine the velocity of the
object - Describe in words the information presented in
graphs and draw graphs from descriptions of
motion - Write equations that describe the position of an
object moving at constant velocity
3Parts of a Graph
- X-axis
- Y-axis
- All axes must be labeled with appropriate units,
and values.
45.1 Position vs. Time
- The x-axis is always time
- The y-axis is always position
- The slope of the line indicates the velocity of
the object. - Slope (y2-y1)/(x2-x1)
- d1-d0/t1-t0
- ?d/?t
5Steepness of slope on Position-Time graph
- Slope is related to velocity
- Steep slope higher velocity
- Shallow slope less velocity
6Uniform Motion
- Uniform motion is defined as equal displacements
occurring during successive equal time periods
(sometimes called constant velocity) - Straight lines on position-time graphs mean
uniform motion.
7Given below is a diagram of a ball rolling along
a table. Strobe pictures reveal the position of
the object at regular intervals of time, in this
case, once each 0.1 seconds. Â
Notice that the ball covers an equal distance
between flashes. Let's assume this distance
equals 20 cm and display the ball's behavior on a
graph plotting its x-position versus time.
8The slope of this line would equal 20 cm divided
by 0.1 sec or 200 cm/sec. This represents the
ball's average velocity as it moves across the
table. Since the ball is moving in a positive
direction its velocity is positive. That is, the
ball's velocity is a vector quantity possessing
both magnitude (200 cm/sec) and direction
(positive).
9Different Position. Vs. Time graphs
Accelerated Motion
Uniform Motion
Constant positive velocity (zero acceleration)
Increasing positive velocity (positive
acceleration)
Constant negative velocity (zero acceleration)
Decreasing negative velocity (positive
acceleration)
10Different Position. Vs. Time
Changing slope means changing velocity!!!!!!
Increasing negative slope ??
Decreasing negative slope ??
11A Starts at home (origin) and goes forward
slowly B Not moving (position remains constant
as time progresses) C Turns around and goes in
the other direction quickly, passing up home
12During which intervals was he traveling in a
positive direction? During which intervals was he
traveling in a negative direction? During which
interval was he resting in a negative
location? During which interval was he resting in
a positive location? During which two intervals
did he travel at the same speed? A) 0 to 2 sec B)
2 to 5 sec C) 5 to 6 sec D)6 to 7 sec E) 7 to
9 sec F)9 to 11 sec
13Graphing w/ Acceleration
x
A Start from rest south of home increase speed
gradually B Pass home gradually slow to a stop
(still moving north) C Turn around gradually
speed back up again heading south D Continue
heading south gradually slow to a stop near the
starting point
14You try it..
- Using the Position-time graph given to you, write
a one or two paragraph story that describes the
motion illustrated. - You need to describe the specific motion for each
of the steps (a-f) - You will be graded upon your ability to correctly
describe the motion for each step.
15Tangent Lines
x
t
On a position vs. time graph
SLOPE VELOCITY
Positive Positive
Negative Negative
Zero Zero
SLOPE SPEED
Steep Fast
Gentle Slow
Flat Zero
16Increasing Decreasing
Increasing
Decreasing
On a position vs. time graph Increasing means
moving forward (positive direction). Decreasing
means moving backwards (negative direction).
17Concavity
On a position vs. time graph Concave up means
positive acceleration. Concave down means
negative acceleration.
18Special Points
Q
R
P
S
Inflection Pt. P, R Change of concavity, change of acceleration
Peak or Valley Q Turning point, change of positive velocity to negative
Time Axis Intercept P, S Times when you are at home, or at origin
195.2 Graphing Velocity in One Dimension
- Determine, from a graph of velocity versus time,
the velocity of an object at a specific time - Interpret a v-t graph to find the time at which
an object has a specific velocity - Calculate the displacement of an object from the
area under a v-t graph
205.2 Velocity vs. Time
- X-axis is the time
- Y-axis is the velocity
- Slope of the line the acceleration
21Different Velocity-time graphs
22Different Velocity-time graphs
23Velocity vs. Time
- Horizontal lines constant velocity
- Sloped line changing velocity
- Steeper greater change in velocity per second
- Negative slope deceleration
24Acceleration vs. Time
- Time is on the x-axis
- Acceleration is on the y-axis
- Shows how acceleration changes over a period of
time. - Often a horizontal line.
25All 3 Graphs
v
t
a
t
26Real life
Note how the v graph is pointy and the a
graph skips. In real life, the blue points would
be smooth curves and the orange segments would be
connected. In our class, however, well only
deal with constant acceleration.
v
t
a
t
27Constant Rightward Velocity
28Constant Leftward Velocity
29Constant Rightward Acceleration
30Constant Leftward Acceleration
31Leftward Velocity with Rightward Acceleration
32Graph Practice
Try making all three graphs for the following
scenario 1. Newberry starts out north of home.
At time zero hes driving a cement mixer south
very fast at a constant speed. 2. He
accidentally runs over an innocent moose crossing
the road, so he slows to a stop to check on the
poor moose. 3. He pauses for a while until he
determines the moose is squashed flat and deader
than a doornail. 4. Fleeing the scene of the
crime, Newberry takes off again in the same
direction, speeding up quickly. 5. When his
conscience gets the better of him, he slows,
turns around, and returns to the crash site.
33Area Underneath v-t Graph
- If you calculate the area underneath a v-t graph,
you would multiply height X width. - Because height is actually velocity and width is
actually time, area underneath the graph is equal
to - Velocity X time or
- Vt
34- Remember that Velocity ?d
- ?t
- Rearranging, we get ?d velocity X ?t
- So.the area underneath a velocity-time graph is
equal to the displacement during that time
period.
35Area
Note that, here, the areas are about equal, so
even though a significant distance may have been
covered, the displacement is about zero, meaning
the stopping point was near the starting point.
The position graph shows this as well.
36Velocity vs. Time
- The area under a velocity time graph indicates
the displacement during that time period. - Remember that the slope of the line indicates the
acceleration. - The smaller the time units the more
instantaneous is the acceleration at that
particular time. - If velocity is not uniform, or is changing, the
acceleration will be changing, and cannot be
determined for an instant, so you can only find
average acceleration
375.3 Acceleration
- Determine from the curves on a velocity-time
graph both the constant and instantaneous
acceleration - Determine the sign of acceleration using a v-t
graph and a motion diagram - Calculate the velocity and the displacement of an
object undergoing constant acceleration
385.3 Acceleration
- Like speed or velocity, acceleration is a rate of
change, defined as the rate of change of velocity - Average Acceleration change in velocity
-
Elapsed time
Units of acceleration?
39Rearrangement of the equation
40Finally
- This equation is to be used to find (final)
velocity of an accelerating object. You can use
it if there is or is not a beginning velocity
41Displacement under Constant Acceleration
- Remember that displacement under constant
velocity was
?d vt or d1 d0 vt
- With acceleration, there is no one single
instantaneous v to use, but we could use an
average velocity of an accelerating object.
42Average velocity of an accelerating object would
simply be ½ of sum of beginning and ending
velocities
Average velocity of an accelerating object
V ½ (v0 v1)
43So.
Key equation
44Some other equations
2
This equation is to be used to find final
position when there is an initial velocity, but
velocity at time t1 is not known.
45If no time is known, use this to find final
position.
2
2
46Finding final velocity if no time is known
2
2
47The equations of importance
482
2
2
2
2
49Practical Application Velocity/Position/Time
equations
- Calculation of arrival times/schedules of
aircraft/trains (including vectors) - GPS technology (arrival time of signal/distance
to satellite) - Military targeting/delivery
- Calculation of Mass movement (glaciers/faults)
- Ultrasound (speed of sound) (babies/concrete/metal
s) Sonar (Sound Navigation and Ranging) - Auto accident reconstruction
- Explosives (rate of burn/expansion rates/timing
with det. cord)
505.4 Free Fall
- Recognize the meaning of the acceleration due to
gravity - Define the magnitude of the acceleration due to
gravity as a positive quantity and determine the
sign of the acceleration relative to the chosen
coordinate system - Use the motion equations to solve problems
involving freely falling objects
51Freefall
- Defined as the motion of an object if the only
force acting on it is gravity. - No friction, no air resistance, no drag
52Acceleration Due to Gravity
- Galileo Galilei recognized about 400 years ago
that, to understand the motion of falling
objects, the effects of air or water would have
to be ignored. - As a result, we will investigate falling, but
only as a result of one force, gravity.
Galileo Galilei 1564-1642
53Galileos Ramps
- Because gravity causes objects to move very fast,
and because the time-keepers available to Galileo
were limited, Galileo used ramps with moveable
bells to slow down falling objects for accurate
timing.
54Galileos Ramps
55Galileos Ramps
- To keep accurate time, Galileo used a water
clock. - For the measurement of time, he employed a large
vessel of water placed in an elevated position
to the bottom of this vessel was soldered a pipe
of small diameter giving a thin jet of water,
which he collected in a small glass during the
time of each descent... the water thus collected
was weighed, after each descent, on a very
accurate balance the difference and ratios of
these weights gave us the differences and ratios
of the times...
56(No Transcript)
57Displacements of Falling Objects
- Looking at his results, Galileo realized that a
falling ( or rolling downhill) object would have
displacements that increased as a function of the
square of the time, or t2 - Another way to look at it, the velocity of an
object increased as a function of the square of
time, multiplied by some constant.
58- Galileo also found that all objects, no matter
what slope of ramp he rolled them down, and as
long as the ramps were all the same height, would
reach the bottom with the same velocity.
59Galileos Finding
- Galileo found that, neglecting friction, all
freely falling objects have the same
acceleration.
60Hippo Ping Pong Ball
In a vacuum, all bodies fall at the same rate.
If a hippo and a ping pong ball were dropped from
a helicopter in a vacuum (assuming the copter
could fly without air), theyd land at the same
time.
When theres no air resistance, size and shape
matter not!
61Proving Galileo Correct
Galileo could not produce a vacuum to prove his
ideas. That came later with the invention of a
vacuum machine, and the demonstration with a
guinea feather and gold coin dropped in a vacuum.
62Guinea Feather and Coin/NASA demonstrations
63Acceleration Due to Gravity
- Galileo calculated that all freely falling
objects accelerate at a rate of -
9.8 m/s2
This value, as an acceleration, is known as g
64Acceleration Due to Gravity
- Because this value is an acceleration value, it
can be used to calculate displacements or
velocities using the acceleration equations
learned earlier. Just substitute g for the a
65Example problem
- A brick is dropped from a high building.
- What is its velocity after 4.0 sec.?
- How far does the brick fall during this time?
66The Churchs opposition to new thought
- Church leaders of the time held the same views as
Aristotle, the great philosopher. - Aristotle thought that objects of different mass
would fall at different ratesmakes sense
huh?????? - All objects have their natural position. Rocks
fall faster than feathers, so it only made sense
(to him) - Galileo, in attempting to convince church leaders
that the natural position view was incorrect,
considered two rocks of different mass.
67Falling Rock Conundrum
- Galileo presented this in his book Dialogue
Concerning the Two Chief World Systems(1632) as a
discussion between Simplicio (as played by a
church leader) and Salviati (as played by
Galileo) - Two rocks of different masses are dropped
- Massive rock falls faster???
68Rocks continued
- Now consider the two rocks held together by a
length of string. - If the smaller rock were to fall slower, it would
impede the rate at which both rocks would fall. - But the two rocks together would actually have
more mass, and should therefore fall faster. - A conundrum????? The previously held views could
not have been correct.
69- Galileo had data which proved Aristotle and the
church wrong, but church leaders were hardly
moved in their position that all objects have
their correct position in the world - Furthermore, the use of Simplicio (or simpleton)
as the head of the church in his dialog, was a
direct insult to the church leaders themselves.