Title: Animal Environment
1Animal Environment Heat Flow
- BSE 2294 Animal Structures and Environments
- S. Christian Mariger Ph.D. Susan W. Gay Ph.D.
2Environmental Fundamentals
- Environment is the total of all external
conditions that effect the development, response
and growth of plants and animals. - Physical factors
- Social factors
- Thermal factors
- Ventilation is the method of environmental
modification for agricultural structures.
3Physical Factors
- Space
- Lighting
- Sound
- Gasses
- Equipment
4Social Factors
- Number of animals to a pen
- Behavior
5Thermal Factors
- Air temperature
- Relative humidity
- Air movement
- Radiation (one type of heat transfer)
6Environmental Factors
- Influence
- Animal health
- Breeding
- Production efficiency
- Product quality
- Human health
- Equipment service life
- Building material longevity
7Heating and Ventilation Terms
- Heat the energy transferred from a warmer body
to a colder body because of the temperature
difference - Temperature is a measure of a bodys ability to
transfer or receive heat from matter in contact
with it. - Ambient temperature - the temperature of the
medium surrounding a body - British Thermal Unit (Btu) the quantity of heat
required to raise one pound of water one F
8Heating and Ventilation Terms
- Calorie the quantity of heat required to raise
one gram of water one C - Specific heat is the quantity of heat required
to raise one pound of material one F (Units
Btu/lb-F) - Sensible heat is a measure of the energy that
accompanies temperature change - Latent heat is the heat energy absorbed or
released when a material changes phase (ice to
water for example)
9Sensible and latent heat to change one lb of
water from ice to steam
qs Mcv?T
10Sensible latent heat example
- Given a 20 cubic foot water trough that was
allowed to freeze to 28 F how many Btu will be
required to thaw and warm the water to 40 F.
11Sensible latent heat example
- Find lbs of water.
- ?H2O 62.4 lb/ft3
- 20 ft3 x 62.4 lb/ft3 1,248 lbs
12Sensible latent heat example
- Find sensible heat required (Btu) to raise the
temp from 28 F to 32 F. - Specific heat of ice 0.56 Btu/lb - 1 F
- 1,248 lbs x 0.56 Btu/lb - 1 F 699 Btu - 1 F
- (32 F 28 F) x 699 Btu - 1 F 2,796 Btu
13Sensible latent heat example
- Find the latent heat of fusion for the water.
- Latent heat of fusion H2O 144 Btu/lb
- 1,248 lbs x 144 Btu/lb 179,712 Btu
14Sensible latent heat example
- Find sensible heat required to raise the temp
from 32 F to 40 F. - Specific heat of water 1.0 Btu/lb - 1 F
- 1,248 lbs x 1.0 Btu/lb - 1 F 1,248 Btu - 1 F
- (40 F 32 F) x 1,248 Btu - 1 F 9,984 Btu
15Sensible latent heat example
- Sum the Btus to find the energy required to
raise the temp from 32 F to 40 F. - (32 F 28 F) 2,796 Btu
- Latent heat of fusion 179,712 Btu
- (40 F 32 F) 9,984 Btu
- Total 192,492 Btu
16Types of Heat Transfer
17Conduction
- Conduction the exchange of heat between
contacting bodies that are at different
temperatures or transfer of energy through a
material as a result of a temperature gradient.
Conduction is often a heat loss factor as well as
a heating factor!
18Conduction heat flow
- q AK (T1 T2) / L
- A cross-sectional area of the surface
- K thermal conductivity
- L thickness of the material
- T1 T2 ?T change in temperature
- q (A/R) ?T
- R thermal resistance (L/K)
19Conduction example
- Determine the heat transfer through a wall
composed of two sheets of ½ plywood (R 0.62)
and 3 ½ of batt insulation (R 11).
Inside temp 80 F
Outside temp 20 F
Assume the cross-sectional area A is 1ft2
20Conduction example
- Find RT for the wall
- Material 1 ½ plywood R 0.62
- Material 2 3 ½ batt insulation R 11.00
- Material 3 ½ plywood R 0.62
- RT 12.24
21Conduction example
- Find q for the wall
- q (A/RT) x (Tinside Toutside)
- q (1ft2/12.24) x (80 20) 4.90 Btu/Hour
22Heat conduction for a building (qb)
- Calculate the conduction (q) for each building
component - Ceilings qc - Windows qwi
- Doors qd - Walls qw
- Etc.
- Add all the conductions to find the conduction
for the building (qb)
qb qc qwi qd qw q...... (in Btu/hr)
23Conduction temperature change
- We can also calculate the temperature from one
side to the next for each layer in the wall. - Determine the temperatures at points 2 and 3.
- Where T1 T2 (q/A) R
R1 0.62
R3 0.62
R2 11
T1 80 F
T4 20 F
T2 ?
T3 ?
24Conduction temperature change
- Temp at point 2
- T2 T1 (q/A) R1
- T2 80 F (4.9/1) x 0.62 77 F
- Temp at point 3
- T3 T2 (q/A) R2 .
- T3 77 F (4.9/1) x 11.0 23 F
25Convection
- Heat transferred to or from a body by mass
movement of either a liquid or a gas
26Convection
- Convection is often used for interior heating
27Radiation
- The exchange of thermal energy between objects by
electromagnetic waves. - Radiant energy is transferred between two bodies
in both directions, not just from warmer to
cooler.
28Radiation
- Here is an example of infra red (IR) radiation
being used in an interior heating application
29Typical Environmental Effects (dairy cattle
example)
30Heat stress occurs in animals when their heat
gain is greater than their heat loss.
Body heat Metabolism Physical activity Performanc
e Environment Radiation (sun) Convection
(air) Conduction (resting surface)
31Heat stress has a severe impact on cow
performance and health.
Increases Respiration rate Sweating Water
intake Decreases Dry matter intake Feed passage
rate Blood flow to internal organs Milk
production Reproduction performance
32Cows are much more comfortable at cooler
temperatures than humans.
Thermal comfort zone 41 77 F Lower critical
temperature Neonatal calves 55 F Mature cows 13
F Upper critical temperature 77 78 F
33Animals can lose heat by sensible or latent heat
losses.
Sensible heat Conduction (direct
contact) Convection (air movement) Radiation
(line of sight) Latent heat Evaporation (phase
change)
34As air temperatures increase, animals cannot lose
as much sensible heat, so they pant and sweat
(evaporation).
Direct radiation
Indirect radiation
Convection
Indirect radiation
Digestive heat
Conduction
35As relative humidity rises, an animal losses less
heat by evaporation.
Evaporation (from skin)
Evaporation (respiratory tract)
36Relative Humidity ()
80
100
20
40
60
0
72
No Stress
80
Mild Stress
90
Heat Stress
Temperature (F)
Severe Stress
100
110
Dead Cows
120
37How can you tell if a cow is suffering from heat
stress?
Rectal temperatures Above 102.5 F Respiration
rates gt 80 breaths per minute Decreases in Dry
matter intake Milk production
38How can heat stress be managed?
Shade Air exchange Air velocity Water
39Shade lowers the solar heat load from direct and,
sometimes, indirect radiation.
40Good air exchange or ventilation of confinement
housing is essential to animal comfort.
Removes Hot, moist air Increases Convective
heat loss Recommended 1000 cfm per cow
41Cows cooling ability is improved by increasing
the air velocity over the animals skin.
Removes Hot, moist air in contact with the
animal Turbulence Disrupt the boundary layer
Recommended 220 to 440 fpm (2.5 to 5 mph)
42Water improves animal cooling through
evaporation.
Watering locations Increase in hot
weather Sprinkling systems Wet cows
hide Increase direct evaporation Evaporative
cooling pads Cools air directly Cows cooled by
convection
43Thermal effects on other species
44Heat Balance
45Heat balance
- To maintain constant room temperature, heat
produced by the animals and heaters must equal
the heat lost through the building structure and
by ventilation. - Heat gain (Qh) Heat loss (QT)
- Qf Qs Qvent Qb
46Heat removed by ventilation (Qvent)
- Ventilation removes heat by replacing warm in
side air with cold outside air. - If humidity is constant we know the specific heat
of air. - If we also know the difference between the
outside temp and the inside temp (?t) - If we also know how much air is being exchanged
in Cubic Feet/Minute (cfm) - Then we can calculate the heat removed by
ventilation.
47Heat removed by ventilation (Qvent)
- Qvent (1.1)(Fan rate cfm)(?t)
48Ventilation (Qvent) example
- A building is ventilated at 1,200 cfm. The inside
temperature is 65 F and the outside temperature
is 15 F. Determine the rate of heat removal.
49Ventilation (Qvent) example
- (Qvent) (1.1) (fan rate) (Ti To)
- (Qvent) (1.1) (1,200) (65 15)
- (Qvent) 66,000 Btu/hour
50Heat lost through the structure (Qb)
- We have discussed heat lost through structure in
terms of thermal resistance (R) and thermal
conductivity (K). - Q AK (T1 T2) / L
- A cross-sectional area of the surface
- K thermal conductivity
- L thickness of the material
- T1 T2 ?t change in temperature
- Q (A/R) ?t
- R thermal resistance (L/K)
- Qb qc qwi qd qw q......
51Heat gain (Qh)
- Heat gain in an animal structure comes from two
major sources - Supplemental heat (Qf) the heat provided by
various heaters. - Animal sensible heat (Qs) the heat the animals
give up to the environment. - Conduction
- Convection
- Radiation
- Evaporation (latent heat of vaporization)
52Animal sensible heat (Qs)
- Assumptions
- air velocity 20-30 fpm
- humidity 50
- surface temp of walls are equal to air temp
53Forced ventilation example
- Fifty (50) pigs in the growing stage (100 lbs)
are housed at a temperature of 60 F. The cold
weather ventilation rate (To 20 F) is 7 cfm
for each animal. The total heat loss for the
structure QB 14,000 Btu/hour and the animal
sensible heat Qs 375 Btu / hour / head. Will
supplemental heat (Qf) be required for this
structure, if so how much?
54Forced ventilation example
- Find the required ventilation
- ( animals) x (cfm/animal) fan rate
- fan rate (50) x (7 cfm) 350 cfm
55Forced ventilation example
- Find the heat removed by ventilation (Qvent)
- Qvent (1.1) (fan rate) (?t)
- Qvent (1.1) (350) (60 20)
- Qvent 15,400 Btu/hour
56Forced ventilation example
- Find the total heat loss (QT)
- (QT) Qvent QB
- (QT) 15,400 Btu/hour 14,000 Btu/hour
- (QT) 29,400 Btu/hour
57Forced ventilation example
- Find animal sensible heat (Qs)
- (Qs) ( animals) (Btu/hour head)
- (Qs) (50) (375) 18,750 Btu/hour
58Forced ventilation example
- If Qf Qs Qvent QB then
- Find the supplemental heat (Qf)
- (Qf) Qvent QB Qs
- OR
- (Qf) QT Qs
- (Qf) 29,400 Btu/hour - 18,750 Btu/hour
- (Qf) 10,650 Btu/hour
59Moisture Balance
60What about moisture?
- As ventilating air moves through a structure it
evaporates moisture from the floor, pits and
other wet surfaces. - As animals breath, moisture is lost from their
respiratory system to the air. - To maintain a desirable temperature, enough
moisture must be removed to keep the relative
humidity below 70
61Moisture balance
- To maintain a constant rate of moisture
- Moisture Loss Moisture production
- The moisture holding capacity of air nearly
doubles with each 20 F increase in temperature!
62Where does the moisture come from?
- Incoming air
- Animal waste
- Animal respiration
- Feed and water
63Swine ventilation rates
64Air tempering systems
- Tempering warms or cools air before it enters the
animal housing portion of a structure.
65Air tempering systems
- Tempering systems include
- air make-up systems
- air blending systems
- heat exchangers
- solar collectors
- earth tubes
- evaporative coolers
66Air pre-heating
67Air blending
68Heat exchangers
69Solar collectors
70Earth tubes
71Evaporative cooling