Title: Power Electronics Lecture (5)
1Power ElectronicsLecture (5)
- Prof. Mohammed Zeki Khedher
- Department of Electrical Engineering
- University of Jordan
1
2Diode Circuits or Uncontrolled Rectifier
- Rectification The process of converting the
alternating voltages and currents to direct
currents
3Single-phase half-wave diode rectifier with
resistive load.
4the load and diode currents
5Performance Parameters
rectification effeciency
form factor
ripple factor
6 7Transformer Utilization Factor
8Crest Factor
9Example 1 The rectifier shown in Figure has a
pure resistive load of R Determine (a) The
efficiency, (b) Form factor (c) Ripple factor (d)
Peak inverse voltage (PIV) of diode D1.
.
It is clear from the Figure that the PIV is
10- VA VsIs 0.707 Vm x 0.5 Vm /R
- TUF Pdc/VsIs (0.318)2 / (0.707 x 0.5)
- 0.286
- CF Is-peak/ Is 1/0.5 2
- PF Pac/VA 0.52 / (0.707X0.5) 0.707
11The main disadvantages of half wave rectifier
are
- High ripple factor,
- Low rectification efficiency,
- Low transformer utilization factor, and,
- DC saturation of transformer secondary winding.
12Half wave Rectifier with a Battery
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