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Title: Plant


1
Plant Electrical Distribution Systems
  • Module ENGE 303
  • H.Gallagher_at_gcal.ac.uk
  • hugo_at_logis-tech.co.uk
  • Tel No 0141 331 .
  • Room M
  • Week 1

2
Recommended Text
  • J.O Bird, Electrical Circuit Theory and
    Technology, Revised edition
  • (Chapters 7, 8, 9)
  • T.Floyd, Electronic Fundamentals, Circuits,
    Devices and Applications, 6th Edition
  • (Chapter 7)

3
Magnetismand Electromagnetism
4
The Magnetic Field
  • A permanent magnet has a magnetic field
    surrounding it.
  • Consists of lines of force that radiate from the
    north pole to the south pole and back to the
    north pole through the magnetic material.

5
Figure 1 Magnetic lines of force around a bar
magnet.
6
The Magnetic Field
  • Consists of lines of force, (or flux lines), that
    radiate from the north pole (N) to the south pole
    (S) and back to the N. pole through the magnetic
    material.
  • The many lines surround the magnet in 3
    dimensions.
  • Lines shrink to the smallest possible size and
    blend together- although they do not touch.
  • Forms a continuous magnetic field surrounding the
    magnet.

7
Figure 2 Magnetic attraction and repulsion
8
Fig. 3 Effect of (a) nonmagnetic and (b)
magnetic materials on a magnetic field.
9
Magnetic Flux, F
  • The group of force lines going from the N. pole
    to the S. pole of a magnet is called the magnetic
    flux, symbolized by F (phi).
  • No. of lines of force in a magnetic field
    determines the value of the flux.
  • The more lines of force, the greater the flux and
    the stronger the magnetic field.
  • Unit of magnetic flux is the weber (Wb)
  • One weber 108 lines.

10
Magnetic Flux Density, (B)
  • Is the amount of flux per unit area perpendicular
    to the magnetic field.
  • Its symbol is B, and its unit is the tesla (T).
  • One tesla one weber/square meter (Wb/m2).
  • The following expresses the flux density
  • B F
  • A
  • F is the flux, A is the c.s.a in square meters
    (m2) of the magnetic field.

11
The Gauss
  • The tesla (T) is the SI unit for flux density,
    another unit called the gauss, from the CGS
    (centimeter-gram-second) system, is sometimes
    used (104 gauss 1T).
  • The instrument used to measure flux density is
    the gaussmeter.

12
Example 1
  • Find the flux density in a magnetic field in
    which the flux in 0.1m2 is 800µWb.
  • Solution
  • B F/A
  • 800µWb/0.1m2
  • 8000µT

13
Example 2
  • A magnetic pole face has a rectangular section
    having dimensions 200 mm by 100 mm. If the total
    flux emerging from the pole is 150 µ Wb.
    Calculate the flux density.
  • Solution
  • F 150 µ Wb 150 x 10-6 Wb
  • c.s.a 200 x 100 20000 mm2 20000 x 10-6 m2
  • Flux Density, B F/A
  • 150 x 10-6/20000
    x 10-6
  • 0.0075 T or 7.5mT

14
How Materials Become Magnetised
  • Ferromagnetic materials become magnetised when
    placed in the magnetic field of a magnet.
  • We have all seen a permanent magnet pick up paper
    clips, nails, or iron filings.
  • Objects becomes magnetised under the influence of
    the permanent magnetic field and becomes
    attracted to the magnet.
  • When removed from the magnetic field, object
    tends to lose its magnetism.
  • Ferromagnetic materials have minute magnetic
    domains created within their atomic structure by
    the orbital motion and spin of electrons.
  • These domains can be viewed as very small bar
    magnets with N. and S. poles.

15
Figure 4 Magnetic domains in (a) an
unmagnetized and in (b) a magnetised material.
16
Figure 5 Operation of a magnetic switch
Application Example
17
Figure 6 Connection of a typical perimeter alarm
system
18
Quiz 1
  • When the North poles of two magnets are placed
    close together, do they repel or attract each
    other?
  • Ans The North Poles repel
  • What is magnetic flux?
  • Ans Magnetic flux is the group of lines of force
    that make up a magnetic field.
  • What is the flux density when F 4.5µWb and A
    5 x 10-3 m2?
  • Ans B F/A 900µT

19
Electromagnetism
  • Is the production of a magnetic field by current
    in a conductor.
  • Many types of useful devices such as tape
    recorders, electric motors, speakers, solenoids,
    and relays are based on electromagnetism.

20
Fig. 7 Magnetic field around a current-carrying
conductor
21
Figure 8 Visible effects of an electromagnetic
field
22
Fig. 9 Magnetic lines of force around a
current-carrying conductor
23
Fig. 10 Illustration of right-hand rule
24
Electromagnetic Properties
  • Permeability (µ)
  • The Relative Permeability (µr)
  • Reluctance, S (RM)

25
Permeability (µ)
  • Ease with which a magnetic field can be
    established in a given material is measured by
    the permeability of that material.
  • Higher the permeability, a magnetic field can be
    established easier
  • Symbol µ its value varies depending on material.
  • µo, permeability of a vacuum is 4p X 10-7 Wb/At.m
    (weber/ampere-turn.meter) and is used as a
    reference.
  • Ferromagnetic materials typically have
  • permeabilities hundreds of times larger than that
    of a vacuum
  • include iron, steel, and their alloys.

26
The Relative Permeability
  • (µr) of a material is the ratio of its absolute
    permeability (µ) to the permeability of a vacuum
    (µo).
  • Since µr is a ratio, it has no units.
  • µr µ
  • µo

27
Reluctance (S)
  • Opposition to the establishment of a magnetic
    field in a material is called reluctance (S).
  • Value of reluctance is directly proportional to
    the length (L) of the magnetic path, and
    inversely proportional to the permeability (µ)
    and to the c.s.a. (A) of the material
  • S L/µA (At/Wb)

28
Example 2
  • What is the reluctance of a material that has a
    length of 0.05 m, a cross-sectional area of 0.012
    m2, and a permeability of 3500 µWb/At.m?
  • Solution
  • S L/ µA
  • 0.05/ (3500 x 10-6 Wb/At.m) (0.012m2)
  • 1190 At/Wb

29
Magnetomotive Force (mmf)
  • Current in a conductor produces a magnetic field.
  • Force that produces the magnetic field is called
    the magnetomotive force (mmf).
  • Unit of mmf, (At), is established on the basis of
    the current in a single loop (turn) of wire.
  • Formula for mmf is
  • Fm NI
  • Fm is the magnetomotive force, N is the no. of
    turns of wire, I is the current in amperes.

30
Figure 11 A basic magnetic circuit
31
Ohm's law for magnetic circuits
  • The amount of flux depends on the magnitude of
    the mmf and on the reluctance of the material, as
    expressed by
  • F Fm
  • R

32
Example 3
  • How much flux is established in the magnetic path
    of Fig. 12 if the reluctance of the material is
    0.28 X 105 At/WB?

Figure 12
33
Solution to Example 3
  • F Fm/R NI/R (5 t) (3 A)
  • 0.28 X 105 At/Wb
  • 5.36 X 10-4 Wb
  • 536µWb

34
Example 4
  • There are two amperes of current through a wire
    with 5 turns.
  • (a) What is the mmf?
  • (b) What is the reluctance of the circuit if the
    flux is 250 µWb?
  • Solution
  • (a) N 5 and I 2A
  • Fm NI (5t)(2A) 10 At
  • (b) R Fm/F 10At/250µWb
  • 0.04 X 106 At/Wb
  • 4.0 X 104 At/Wb

35
The Electromagnet
  • A basic electromagnet is simply a coil of wire
    wound around a core material that can be easily
    magnetised.
  • The shape of the electromagnet can be designed
    for various applications.

36
Figure 13 Reversing the current in the coil
causes the electromagnetic field to reverse.
37
Figure 14 Read/write function on a magnetic
surface.
Application Examples
38
The Magneto Optical Disk
  • Uses an electromagnet and laser beams to read and
    write (record) data on a magnetic surface.
  • Formatted in tracks and sectors similar to
    magnetic floppy disks and hard disks.
  • Laser beam precisely directed to an extremely
    small spot
  • Capable of storing much more data than standard
    magnetic hard disks.

39
Figure 15 Basic concept of the magneto-optical
disk.
40
Electromagnetic Devices
  • Magnetic disk/tape read/write head
  • Magneto-optical disk
  • Transformer
  • Solenoid
  • Relay
  • Speaker

41
The Solenoid
  • Is a type of electromagnetic device that has a
    movable iron core called a plunger.
  • Movement of this iron core depends on both an
    electromagnetic field and a mechanical spring
    force.

42
Figure 16 Basic solenoid structure.
43
Figure 17 Basic solenoid operation
44
The Relay
  • Differs from solenoids in that the
    electromagnetic action is used to open or close
    electrical contacts rather than to provide
    mechanical movement.

45
Fig. 18 Basic structure of a single-pole-double-th
row relay
46
Reed Relay
  • like the armature relay, uses an electromagnetic
    coil.
  • Contacts are thin reeds of magnetic material and
    are usually located inside the coil.

47
Figure 20 Basic structure of a reed relay
48
Example 5
  • With the aid of a sketch, explain the operation
    of the electromagnetic relay.
  • Also provide an example of an application of this
    type of device?
  • Solution
  • Reference should be made to the reed relay and
    /or the armature relay.
  • electromagnetic action is used to open or close
    electrical contacts
  • unenergised/energised
  • Structure
  • Symbol

49
The Speaker
  • Permanent-magnet speakers are commonly used and
    their operation is based on the principle of
    electromagnetism.
  • Constructed with a permanent magnet and an
    electromagnet.
  • Cone of the speaker consists of a paper-like
    diaphragm to which is attached a hollow cylinder
    with a coil around it, forming an electromagnet.

50
Figure 21 Basic speaker operation
51
Fig. 22 The speaker converts audio signal
voltages into sound waves.
52
Meter Movement
  • d'Arsonval meter movement is the most common type
    used in analog multimeters.
  • In this type of meter movement, the pointer is
    deflected in proportion to the amount of current
    through a coil.

53
Figure 23 The basic dArsonval meter movement
54
Fig. 24 When the electromagnetic field interacts
with the permanent magnetic field, forces are
exerted on the rotating coil assembly, causing it
to move clockwise and thus deflecting the pointer.
55
Magnetising Force (H)
  • Magnetizing force in a material is defined to be
    the
  • magnetomotive force (Fm) per unit length (L)
    of the material.
  • Unit of magnetizing force (H) is ampere-turns per
    meter (At/m).
  • H Fm
  • L
  • Where, Fm NI.
  • Note
  • Magnetising force depends on the no. of turns (N)
    of the coil of
  • wire, the current (I) through the coil, and
    the length (L) of the material.
  • It does not depend on the type of material.

56
Magnetising Force (H)
  • Since F Fm/R, as Fm increases, the flux
    increases.
  • Also, magnetising force (H) increases.
  • Recall that flux density (B) is the flux per
    unit c.s.a. (B F/A), so B is also proportional
    to H.
  • Curve showing how these two quantities (B H)
    are related is called the B-H curve (hysteresis
    curve).

57
Fig. 25 Parameters that determine the magnetising
force (H) and the flux density (B).
58
The Hysteresis Curve
  • Hysteresis is a characteristic of a magnetic
    material whereby a change in magnetisation lags
    the application of a magnetising force.
  • Magnetising force (H) can be increased or
    decreased by varying the current through the coil
    of wire (reversed by reversing the voltage
    polarity across the coil).

59
Fig 26 Development of a magnetic hysteresis curve
60
Fig 26(g) Complete B-H Curve The Hysteresis
Curve
61
Example 6
  • A mild steel ring of c.s.a. 4 cm has a radial
    air-gap of 3 mm cut into it. If the mean length
    of the mild steel path is 300 mm.
  • Calculate the magnetomotive force to
  • produce a flux of 0.48 mWb.
  • (Use B-H curve on page 78)

62
Solution to Example 6
  • Two parts to the circuit - mild steel and the
    air-gap
  • For the mild steel
  • B F/A
  • 0.48 x 10-3 /4 x 10-4 1.2
    T
  • (From B-H curve for mild steel on p78)
  • when B 1.2 T, H 1800 A/m (or close)
  • Hence, m.m.f. for the mild steel
  • Hl (1800)(300 x 10-3) 540 A

63
Solution to Example 6 (cont.d)
  • For the air-gap
  • The flux density will be the same in the air-gap
    as in the mild steel, i.e. 1.2 T
  • For air, B µ0H from which,
  • H B/µ0
  • 1.2T/4p x 10-7
  • 954930 A/m
  • Hence the m.m.f. for the air-gap Hl

  • (954930)(3 ? 10-3)

  • 2865 A
  • Total m.m.f. to produce a flux of 0.48 mWb
  • 540
    2865 3405 A

64
Materials with a low Retentivity
  • Do not retain a magnetic field very well while
    those with high retentivities exhibit values of
    BR very close to the saturation value of B.
  • Retentivity in a magnetic material can be an
    advantage or a disadvantage.
  • In permanent magnets and memory cores high
    retentivity is required.
  • In ac motors retentivity is undesirable

65
Electromagnetic Induction
  • Relative motion between a conductor and a
    magnetic field, a voltage is produced across the
    conductor.
  • Resulting voltage is an induced voltage.
  • Transformers, electrical generators, electrical
    motors, and many other devices possible.

66
Relative Motion
  • When a wire is moved across a magnetic field,
    there is a relative motion between the wire and
    the magnetic field.
  • Likewise, when a magnetic field is moved past a
    stationary wire, there is also relative motion.
  • In either case, this relative motion results in
    an induced voltage (vind) .

67
Fig. 27 Relative motion between a wire and a
magnetic field
68
Fig. 28 Polarity of induced voltage depends on
direction of motion.
69
Fig. 29 Induced current (iind) in a load as the
wire moves through the magnetic field.
70
Fig. 30 Forces on a current-carrying conductor in
a magnetic field (motor action).
71
Faradays Law
  • Michael Faraday discovered the principle of
    electromagnetic induction in 1831.
  • Faraday's two observations
  • (1) The amount of voltage induced in a coil is
    directly proportional to the rate of change of
    the magnetic field w.r.t. the coil.
  • (2) The amount of voltage induced in a coil is
    directly proportional to the no. of turns of wire
    in the coil.

72
Fig. 31 A demonstration of Faradays first
observation The amount of induced voltage is
directly proportional to the rate of change of
the magnetic field w.r.t. the coil.
73
Fig. 32 A demonstration of Faradays second
observation The amount of induced voltage is
directly proportional to the no. of turns in the
coil
74
Faradays Law
  • The voltage induced across a coil of wire equals
    the number of turns in the coil times the rate of
    change of the magnetic flux.

75
Lenzs Law
  • Defines the polarity or direction of the induced
    voltage.
  • When the current through a coil changes, the
    polarity of the induced voltage created by the
    changing magnetic field is such that it always
    opposes the change in current that caused it.

76
Applications of Electromagnetic Induction
  • an automotive crankshaft position sensor
  • dc generator.

77
Automotive Crankshaft Position Sensor
  • An interesting automotive application is a type
    of engine sensor that detects the crankshaft
    position directly using electromagnetic
    induction.
  • The electronic engine controller in many
    automobiles uses the position of the crankshaft
  • to set ignition timing
  • adjust the fuel control system.

78
Fig. 33 A crankshaft position sensor that
produces a voltage when a tab passes through the
air gap of the magnet.
79
Fig. 34 As the tab passes through the air gap of
the magnet, the coil senses a change in the
magnetic field, and a voltage is induced.
80
Fig. 35 A simplified dc generator
81
Fig. 36 End view of wire loop cutting through the
magnetic field
82
Fig. 37 Operation of a basic dc generator
83
Fig. 38 Induced voltage over three rotations of
the wire loop in the dc generator.
84
Fig. 39 The induced voltage for a two-loop
generator. There is much less variation in the
induced voltage.
85
Example 7
  • A conductor 30 cm long is situated at
    right-angles to a magnetic field. Calculate the
    strength of the magnetic field if a current of 15
    A in the conductor produces a force on it of 3.6
    N.
  • Solution
  • L 0.3 m, I 15 A and F 3.6 N
  • F B I L gt B F / I L 3.6 / 15 x 0.3
  • 0.80
    T

86
Example 8
  • Find the emf in a coil of 200 turns when there is
    a change of flux of 30 mWb linking it in 40 ms.
  • Solution
  • ?? 30 x 10-3 Wb
  • ?t 40 x 10-3 s

Induced emf, E
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