Title: Module 8: Gases
1Module 8 Gases
- By Alyssa Jean-Mary
- Source Modular Study Guide for First Semester
Chemistry by Anthony J. Papaps and Marta E.
Goicoechea-Pappas
2Substances that Exist as Gases
- All the elements and some common compounds that
exist as gases under standard laboratory
conditions (T 25C and P 760 torr) are listed
in the table above.
3Properties of Gases
- Compressibility a gas can be compressed into
smaller volumes in other words, the density of
a gas can be increased by applying pressure (but
if too much pressure is applied, the gas will
become a liquid or a solid) - Indefinite shape of volume a gas fits the
container it is in - Expansion a gas expands without limit, until it
completely and uniformly fills the volume of the
container it is in - Mixibility or diffusion gases diffuse into each
other completely in other words, they can mix
together easily - Low density the density of a gas is small it
is expressed in g/L - The average kinetic energy (KE) of gaseous
molecules is directly proportional to absolute
temperature of these molecules - KE a T (K).
Thus, if the temperature is the same, the kinetic
energy of different gas molecules is also the
same. - The terms to describe the amounts and properties
of gases are - T temperature (expressed in Kelvin (K))
- P pressure
- V volume
- n number of moles
4Characteristics of Ideal Gases
- The equations in this module apply only to ideal
gases or to gases who behave very similarly to
ideal gases - The characteristics of an ideal gas are
- It has a negligible volume
- It has no attractive forces between molecules
- It undergoes elastic collisions
- Real gases can behave as ideal gases by avoiding
the following - extremely low temperatures
- very small volumes
- very high pressures
5Pressure
- Pressure is force per unit area
- Common units of pressure
- atmosphere (atm)
- torr
- millimeters of mercury (mmHg)
- pascal (Pa)
- bar
- The following equalities allow conversion between
units of pressure - 1.00 atm 760 torr 760 mmHg 1.01 x 105 Pa
1.01 bar - At sea level, the pressure is 760 torr (1 atm)
- Below sea level, it is greater than this
- Above sea level, it is lower than this
- A barometer is a device that is used to measure
pressure - The pressure of the atmosphere is equal to the
height of the mercury Patm h (mmHg) - A manometer is a partially filled glass tube of
mercury, with one arm open to the atmosphere
(side P1) and the other arm (side P2) attached to
a gas tank - The pressure of the gas in the tank is equal to
the pressure of the atmosphere plus the
difference in the height of the mercury on the
two sides Pgas P1 ?h
6Examples Using a Manometer
- What is the pressure (in Pascals) of a gas if the
difference in the height of mercury from one arm
to the other in a manometer is 45mm and the
pressure of the atmosphere is 1.03atm?
7Standard Temperature and Pressure (STP) and
Standard Molar Volume
- STP (standard temperature and pressure)
- T 0.00C (273.15K)
- P 1 atm (760 torr)
- At STP, 1 mol of an ideal gas occupies 22.4L
8Gas Laws
- Boyles Law volume is indirectly proportional to
pressure, keeping temperature and number of moles
constant - V a 1/P (at constant T and n) - For example, if the volume is doubled, and the
temperature and the number of moles are kept
constant, the pressure is cut in half - Charles Law volume is directly proportional to
absolute temperature, keeping pressure and number
of moles constant V a T (K) (at constant P and
n) - For example, if the volume is doubled, and the
pressure and the number of moles are kept
constant, the temperature (in K) is also doubled - Avogadros Law volume is directly proportional
to the number of moles, keeping the pressure and
temperature constant V a n (at constant T and
P) - For example, if the volume is doubled, and the
pressure and the temperature are kept constant,
the number of moles is also doubled
9Examples Using the Gas Laws
- Example 1 If the volume of a gas is 50mL, what
happens to this volume if - at constant temperature and number of moles, the
pressure is increased from 2atm to 6atm? - at constant temperature and number of moles, the
pressure is decreased from 8atm to 4atm? - at constant pressure and number of moles, the
temperature is increased from 55K to 110K? - at constant temperature and number of moles, the
pressure is decreased from 255K to 85K? - at constant temperature and pressure, the number
of moles is increased from 1mol to 4mol? - at constant temperature and pressure, the number
of moles is decreased from 8mol to 2mol? - Example 2 If there are 4.0g of Lithium and 2.0g
of Helium, which occupies the larger volume at
STP?
10Combined Gas Laws
- (P1V1 / n1T1) (P2V2 / n2T2)
- If one of the terms is constant, it is eliminated
from both sides of the equation for example - If n is constant, (P1V1 / T1) (P2V2 / T2)
- If n and T are constant, (P1V1) (P2V2)
- Units used for this equation
- Pressure (P) and Volume (V) can be in any unit as
long as P1 and P2 have the same units V1 and V2
have the same units - Temperature (T1 and T2) must have the units of
Kelvin (K)
11Examples Using the Combined Gas Laws
- Example 1 If a sample of oxygen has a volume of
45.2L, a pressure of 2.6atm, and a temperature of
33C, what volume will it occupy at STP? - Example 2 If the pressure of a gas at 56C is
cut in half and its volume is tripled, what will
the resulting temperature be? - Example 3 If a gas has a pressure of 250torr and
a volume of 67mL, what will the new volume (in L)
be if the pressure increased to 0.658atm if the
temperature is held constant?
12Ideal Gas Equation
- PV nRT
- R gas constant 0.0821 (Latm)/(moleK) 62.4
(Ltorr)/(moleK)
13Examples Using the Ideal Gas Equation
- Example 1 If 2.6g of nitrogen gas at 23C has a
volume of 55mL, what is its pressure (in mmHg)? - Example 2 If 0.556mol of neon gas has a volume
of 25L and a pressure of 4.1atm, what is its
temperature (in C)?
14Molar Mass and Density of Gases
- The ideal gas equation (PV nRT) can be
rewritten to include molar mass (M) - Since n g/M, PV (g/M)RT
- The ideal gas equation (PV nRT), rewritten to
include molar mass (PV (g/M)RT), can be
rewritten to find density - Since d m/V g/V, d PM/RT
15Examples of Calculating Molar Mass and Density
- Example 1 If 5.62g of a gas has a pressure of
55torr, a volume of 60mL, and a temperature of
75C, what the molar mass of this gas? - Example 2 What is the density of argon at STP?
16Daltons Law of Partial Pressures 1
- At constant volume and temperature, the total
pressure exerted by a mixture of ideal gases is
equal to the sum of the partial pressures of
these gases - PT PA PB PC
- where PT total pressure, PA partial pressure
of gas A, PB partial pressure of gas B, PC
partial pressure of gas C - Using the ideal gas equation (PV nRT) and
solving for P (P nRT/V), with V and T being
constant (along with R), PT nART/V nBRT/V
nCRT/V , but since T and V are constant (along
with R), PT (nA nB nC )(RT/V) - where nA number of moles of gas A, nB number
of moles of gas B, nC number of moles of gas C
17Daltons Law of Partial Pressures Relationship
Between Total Pressure and Individual Partial
Pressures
- If a sample contains gases A and B
- If PA is divided by PT
- PA/PT (nART/V) / ((nAnB)RT/V), but since T and
V, along with R, are constant, they cancel out,
so PA/PT nA/(nAnB) XA, where XA is the mole
fraction of A - A mole fraction is the ratio of moles of one
component in a sample to the number of total
moles in the sample. A mole fraction is a
dimensionless quantity (i.e. it has no units). A
mole fraction can be any number between 0 and 1,
but the sum of all the mole fractions in a sample
must be equal to 1, so, if there are just two
components present (gases A and B), XA XB 1 - By rearranging PA/PT nA/(nAnB) XA, the
partial pressure of A can be found PA
(nA/(nAnB))PT XAPT using this same method,
the partial pressure of B can also be found PB
(nB/(nAnB))PT XBPT - So, in this sample of gases A and B, the
following equation can be used to find the total
pressure of the sample PT PA PB
(nAnB)(RT/V) XAPT XBPT
18Daltons Law of Partial Pressures Insoluble Gases
- Gases that are insoluble in water and that dont
react with water can be collected over water. - The partial pressure that a gas (for example,
water vapor) exerts above its liquid is called
its vapor pressure. Each liquid has its own
characteristic vapor pressures that vary with
temperature. - When a gas is collected over water, there is
water vapor present along with the gas above the
water, so, at atmospheric pressure, with PT
atmospheric pressure, PT Pgas Pwater, and,
solving for Pgas, Pgas PT Pwater
19Examples Using Daltons Law of Partial Pressures
- Example 1 If a 25.0L flask contains 4.3g of
oxygen gas and 2.6g of nitrogen gas at 35C, - What is the total pressure (in atm) inside the
flask? - What is the partial pressure of each component in
the mixture? - What is the mole fraction of each component in
the mixture? - Example 2 If 253mL of a sample of oxygen gas are
collected over water at 31C and 750.3torr, how
many moles of oxygen are present in the sample?
20Grahams Law Diffusion and Effusion of Gases
- Diffusion the intermingling of gases
- Effusion the leaking out of a gas through a
small hole or orifice - RateA/RateB v(MB/MA)
- where RateA rate of effusion of gas A, RateB
rate of effusion of gas B, MB molar mass of gas
B, MA molar mass of gas A - Rate Volume/time, so units mL/sec, L/min, etc.
21Examples Using Grahams Law
- Example 1 What is the ratio of effusion of O2 to
H2? - Example 2 If O2 effuses 5 times faster than an
unknown gas, what is the molar mass of the gas? - Example 3 If O2 effuses at a rate of 25.5 L/min,
at what rate (in L/min) does N2 effuse?
22Stoichiometry in Reactions Involving Gases
Gay-Lussacs Law (Law of Combining Volumes)
- At constant temperature and pressure, the volumes
of reacting gases can be expressed using the same
simple whole number ratio used for expressing
moles of reacting gases, meaning that V is
directly proportional to n, if temperature and
pressure are constant - V a n (at constant T and
P). So, just as moles can be converted using the
coefficients in a balanced chemical equation, so
can volumes. - If the reaction is performed at STP, 1 mole
22.4 L.
23Examples of Solving Stoichiometry Problems Using
Gay-Lussacs Law
- Example 1 Consider the following balanced
chemical equation - 3 H2 (g) N2 (g) ? 2 NH3 (g)
- If 25.0L of H2 reacts with excess N2 at constant
temperature and pressure, how many liters of NH3
are produced? - If 7.66g of N2 reacts with excess H2 at STP, how
many liters of NH3 are produced?
24Stoichiometry in Reactions Involving Gases Using
the Ideal Gas Equation
- The concept map below represents the possible
steps to solve a stoichiometry problem. Which
steps are used depends on the information given
in the problem and the information that needs to
be solved for in the problem.
25Examples of Solving Stoichiometry Problems Using
the Ideal Gas Equation 1
- Example 1 Consider the following balanced
chemical equation - 2 KClO3 (s) ? 2 KCl (s) 3 O2 (g)
- If 2.56g of KClO3 decomposes at 55.0ºC and
752.3torr, how many mL of oxygen gas are
produced? - If 75.0mL of KClO3 decomposes at 55.0ºC and
752.3torr, how many grams of oxygen gas are
produced? - If a 2.563g impure sample of KClO3 decomposes to
give 305mL of O2 at 55.0ºC and 752.3torr, with
2.002g of residue left behind, calculate the
following - What is the gas constant, R?
- How many grams of pure KClO3 are present in the
impure sample? - What is the percentage of KClO3 in the impure
sample?
26THE END