Title: Thermochemistry
1Thermochemistry
2Energy
- The capacity to do work or transfer heat
- Potential Energy Kinetic Energy
- w F x d
3Other Forms of Energy
- Radiant Energy
- Electromagnetic Radiation
- Thermal Energy
- Associated with random motion of a molecule or
atom - Chemical Energy
- Energy stored within the structural limits of a
molecule or atom
4Units
- Joule E 1/2 mv2 kg m2/s2
- 1 Joule .239 calories
- 1 calorie 3.965 x 10-3 btu
- How many Joules 1 btu?
5Dimensional Analysis?
1 cal
1 joule
1 btu
x
x
.239 cal
3.965 x 10-3 btu
6Dimensional Analysis?
1 cal
1 joule
1 btu
x
x
.239 cal
3.965 x 10-3 btu
1060 Joules (w/ significant figures)
7First Law of Thermodynamics
- The Energy in the Universe is Constant ?E q
w - q heat w work
- But
- WHAT IS THE UNIVERSE?
8Thermochemistry
- Exothermicity
- out of a system
- ?E lt 0
- Endothermicity
- into a system
- ?E gt 0
Surroundings
Surroundings
Energy
Energy
System
System
9Thermochemistry
- Exothermicity
- out of a system
- ?H (-)
- Endothermicity
- into a system
- ?H ()
Surroundings
Surroundings
q w
q w
System
System
10Enthalpy - H
- A chemists description for heat gained () or
lost (-) by a closed system (constant
pressure) ?????????final??????initi
al? - A state function - depends only on a systems
present state, not how it got there.
11Enthalpy is an Extensive Property
- If one mole of isopropanol burns in air with ?H
- 1987 kJ, what is the change in enthalpy for
50 g of isopropanol? (Hint MW 60) - 2 C3H7OH (l) 9 O2 (g) gt 6 CO2 (g) 8 H2O (l)
12Enthalpy is an Extensive Property
- If one mole of isopropanol burns in air with ?H
- 1987 kJ, what is the change in enthalpy for
50 g of isopropanol? (Hint MW 60)
-1987 kJ
1 mole
?H
x
50.0 g
x
1 mole
60.0 g
?H
-1655 -1660 kJ
13Heat Capacity
- The heat absorbed by the system is a function of
the mass and the ability to absorb heat.
C Heat Absorbed/ Change in Temperature
Joules/Co
14Two Flavors
- Specific Heat Capacity
- Joules/ Co g
- Molar Heat Capacity
- Joules/ K mole
15Calorimetry
- By running a reaction in water, we can use the
specific heat of water and the observed
temperature change to measure ?H for the system.
16Bond Energies/Strengths
- The Bond Dissociation Energy is the ?H for the
bond breaking reaction in the gas phase. - CH4 (g) gt C (g) 4 H (g) ?H 1660 kJ
17Hesss Law
- The change in enthalpy is the same regardless
of the steps taken to get there.
2 C3H7OH (l) 9 O2 (g) gt 6 CO2 (g) 8 H2O (g)
-1659 kJ/mol
H2O (l) gt H2O (g)
130 kJ/mol
-1529 kJ/mol
2 C3H7OH (l) 9 O2 (g) H2O (l)
gt 6 CO2 (g) 9 H2O (g)
18Enthalpy Diagrams
130 kJ/mol
to surroundings
-1659 kJ/mol
-1529 kJ/mol
19The Benefits of Thermochemistry
- Enthalpy
- A means of quantifying chemical energy
- The first law of thermodynamics
- All energy must be accounted for
- Hesss Law
- Known reactions can be used to determine
energetics of composite, unknown reactions
20Oxidation of Nitrogen
- What is the enthalpy change for the reaction of
oxygen and nitrogen? - N2 (g) 2 O2 (g) gt 2 NO2 (g)
- N2 (g) O2 (g) gt 2 NO (g) ?H 180 kJ
- 2 NO (g) O2 (g) gt 2 NO2 (g) ?H -112 kJ
- N2 (g) 2 O2 (g) gt 2 NO2 (g) ?H 68 kJ
21Path Independent
NO (g), O2 (g)
NO (g), O2 (g)
-112 kJ
2NO2 (g)
2NO2 (g)
180 kJ
68 kJ
N2 (g), 2O2 (g)
N2 (g), 2O2 (g)
22Hesss Law
- Hydrogen peroxide, H2O2, is a colorless liquid.
Solutions of H2O2 are used as bleach and
antiseptics. It can be prepared in a process
whose overall change is
H2(g) O2(g) H2O2(l)
Calculate the enthalpy change using the following
data
1
H2O2(l)
H2O(l)
O2 (g) H -98.0 kJ
2
2H2(g) O2(g)
2H2O(l) H -571.6 kJ
23Calculate the enthalpy change using the following
data
1
kJ
H2O2(l)
H2O(l)
O2 (g) ? H -98.0
2
2H2(g) O2(g)
2H2O(l) ? H -571.6
kJ
1
H2O O2
H2O2
? H (-98.0 kJ x (-1)
2
(-571.6 kJ)
1
H2 O2
H2O
? H
2
(2)
H2 O2
H2O2
? H -187.8 kJ
24Enthalpies of Formation-Heat of Formation
- In order to standardize a set of data, we have
established a set of conditions under which ?Hfo
are reported. - Standard State - most stable form of an element
at STP - STP - standard temperature and pressure
- P 105 Pascals 1 atm
- T 298 K (25 oC)
25Elemental Heats of Formation
- For an element, the heat of formation is
defined as 0.0 kJ/mol under STP conditions.
Note the standard state of an element is its
form at STP
26To Calculate ?Ho Reaction
- ?Horxn ? n?Hfo(prod) - ? m?Hfo(react)
- Remember to change the sign of ?Hfo if the
reaction is reversed. - If the formation reaction must be multiplied by
an integer, ?Hfo must be as well. - Elements in their standard states dont
contribute to ?Ho.
27An example - Alternative Automobile Fuels
- Methanol is sometimes used as a fuel alternative
to octane (gasoline) in high performance race
cars. Determine the enthalpy of combustion per
gram of each. - ?Hfo CH3OH (l) -239 kJ/mole
- ?Hfo C8H18 (l) -269 kJ/mole
- ?Hfo CO2 (g) -394 kJ/mole
- ?Hfo H2O (l) -286 kJ/mole
28Methanol Combustion
- CH3OH (l) O2 (g) gt CO2 (g) H2O (l)
29Methanol Combustion
- 2CH3OH (l) 3O2 (g) gt 2CO2 (g) 4H2O (l)
- ?Horeaction ? n?Hfo(prod) - ? m?Hfo(react)
- 2 x ?Hfo (CO2) 4 x ?Hfo (H2O) - 2 x ?Hfo
(CH3OH) - 3 x ?Hfo (H2O) -
30Methanol Combustion
- 2CH3OH (l) 3O2 (g) gt 2CO2 (g) 4H2O (l)
- ?Horeaction ? n?Hfo(prod) - ? m?Hfo(react)
- 2 x ?Hfo (CO2) 4 x ?Hfo (H2O) - 2 x
?Hfo (CH3OH) - 2 x (-394 kJ) 4 x (-286 kJ) - 2 x
(-239 kJ) - -1454 kJ/ 2 moles CH3OH
31Conversion to ?Hfo/g
- ?Horeaction/g -1454 kJ/ 2 moles CH3OH
-1454 kJ/2 moles x (32.0 g/mol)
-22.7 kJ/g
32Combustion of Octane
- C8H18 (l) O2 (g) gt CO2 (g) H2O (l)
- Complete for next time!
- HINT 2 moles of octane are consumed.
33Standard Enthalpies of Formation
- Hydrogen sulfide gas is a poisonous gas with the
odor of rotten eggs. The gas burns in oxygen as
follows Calculate the
standard enthalpy change for this reaction using
standard enthalpies of formation.
2H2S(g) 3O2(g)
2H2O(l) 2SO2(g)
34Standard Enthalpies of Formation
2H2S(g) 3O2(g)
2H2O(l) 2SO2(g)
2(-20)
3(0)
2(-285.8)
2(-296.8)
(kJ)
35Standard Enthalpies of Formation
2H2S(g) 3O2(g)
2H2O(l) 2SO2(g)
2(-20)
3(0)
2(-285.8)
2(-296.8)
(kJ)
?Ho ?n ?Ho (products) - ?m ?Ho (reactants)
2(-285.8) 2(-296.8)-2(-20) 3(0)
kJ -1125.2 -1125 kJ