Title: 010'141 Engineering Mathematics II Lecture 4 Continuous Distributions
1010.141 Engineering Mathematics IILecture
4Continuous Distributions
- Bob McKay
- School of Computer Science and Engineering
- College of Engineering
- Seoul National University
- Partly based on
- Sheldon Ross A First Course in Probability
2Outline
- Continuous Random Variables
- Continuous Distributions
- Uniform
- Normal
- Exponential
- Other Discrete Distributions
- Gamma
- Weibull
- Cauchy
- Beta
- Functions of a Random Variable
3Continuous Random Variables
- Discrete random variables cover many important
problems, but there are also many problems which
cannot be conveniently represented in this way - Recall that a random variable over a probability
space (?, ?,P) is a measurable function X ? ? S
for some set S - If ? is a continuous space - for example R, the
real numbers, we call X a continuous random
variable - In the case of R, this is equivalent to an
alternative definition, that there exists a
non-negative function f defined over R, such that
for any measurable B ? R, - PX ?B ?B f(x) dx
- f is known as the probability density function
4Properties ofContinuous Random Variables
- Of course, for the case B R
- ?R f(x) dx PX ? R 1
- For intervals of R, we have the equivalent
- PX ? a,b ?ab f(x) dx
- So PX ? a,a ?aa f(x) dx 0
- That is, the probability of any specific value is
zero - PX lt a ?-?a f(x) dx
5Continuous Example (Ross)
- The amount of time, in hours, that a computer
functions before breaking down is a continuous
random variable with probability density function
given by - f(x) ?e-x/100 x ? 0
- 0 x lt 0
- What is the probability that a computer will
function between 50 and 150 hours before breaking
down?
6Continuous Example
- We have
- ?-?? f(x) dx ? ?0? e-x/100 dx 1
- From which
- ? 1/100
- So
- PX ? 50,150 ?50150 1/100 e-x/100 dx
e-1/2 - e-3/2 0.633
7Uniform Distribution
- The probability density function
- f(x) 1 0 lt x lt 1 0 otherwise
- generates a uniform distribution over the
interval (0,1) - That is, any value between 0 and 1 is equally
likely - This may be generalised to an arbitrary interval
(a,b) - f(x) 1/b-a a lt x lt b 0 otherwise
8Normal Distribution
- The probability density function
- f(x) 1/?(2??) e-(x-?)2/2?2
- generates a normal distribution with mean ? and
standard deviation ? - If X is normally distributed with mean ? and
standard deviation ?, then Y ?X? is normally
distributed with mean ??? and standard deviation
?? - In particular, setting Z (X - ?)/? generates
the unit normal distribution
9Properties of the Normal Distribution
- The cumulative distribution function
- ?(x) 1/?(2?) ?-?x e-y2/2 dy
- Satisfies the symmetry condition
- ?(-x) 1 - ?(x)
- The distribution function for a normally
distributed random variable with mean ? and
standard deviation ? can be written - Fx(a) ?((a - ?) / ?)
- ?(x) 1 - 1/x?(2?) e-x2/2 for large x
10Normal Distribution Example (Ross)
- An instructor gives an A to those whose test
score is greater than ??, B for between ? and
??, C for ?-? to ?, D for ?-2? to ?-?, and F for
less than ?-2? - What is the probability of an A? Of an F?
- Probability of A 1 - ?(1) 0.1587
- Probability of F ?(-2) 0.0288
11Normal and Binomial Distributions
- If Sn denotes the number of successes that occur
when n independent trials, each resulting in a
success with probability p, are performed then
for any a lt b - P a ? (Sn-np) / ?(np(1-p)) ? b ? ?(b) - ?(a)
- as n ? ?
- Thus we have two good approximations to the
binomial distribution - the Poisson approximation
for when np is moderate, and the Normal for when
np(1-p) is large
12Normal / Binomial Example
- To determine the effectiveness of a certain diet
in reducing the amount of cholesterol in the
blood stream, 100 people are put on the diet.
After they have been on the diet for a sufficient
time, their cholesterol count will be taken. The
nutritionist running the experiment has decided
to endorse the diet if at least 65 of the people
have a lower cholesterol count after the diet.
What is the probability that the nutritionist
endorses the new diet if, in fact, it has no
effect on the cholesterol level?
13Normal / Binomial Example
- We assume that each persons probability of a
random reduction is 0.5, independent of any other
person - Thus we want to compute the probability that,
given only random reductions, more than 65
successes are seen - PX ? 65
- Transforming as required, this is
- P 3 ? (X-(1000.5) / ?(1000.50.5)
- Which we can approximate as
- 1 - ?(3) 0.0013
- Since n 100 is sufficiently large
14Normal / Binomial Example cont.
- Actually, we should allow for the fact that a
result of 64.8 will be measured as 65, so what we
really want is - PX ? 64.5
- Transforming as required, this is
- P 2.9 ? (X-(1000.5) / ?(1000.50.5)
- Which we can approximate as
- 1 - ?(2.9) 0.0019
- Since n 100 is still sufficiently large
15Exponential Distribution
- The probability density function
- f(x) ?e-?x x ? 0
- 0 x lt 0
- generates an exponential distribution with
parameter ? - The cumulative distribution function may be found
by integration as - F(a) 1 - e-?x
- The exponential distribution arises frequently as
the time until some event occurs
16Exponential Distribution Properties
- We define a random variable X to be memoryless if
- P X gt st X gt t P X gt s
- (that is, if you have already waited until t, the
probability that you will have to wait a further
s is the same as the initial probability that you
will have to wait s - The exponential distribution is the only
memoryless distribution
17Exponential Distribution Example (Ross)
- Consider a bank with two tellers. Suppose that
when Mr Smith enters the bank, he discovers that
Ms Jones is being served by one of the tellers,
and Mr Brown by the other - Suppose also that Mr Smith is told that his
service will begin as soon as either Jones or
Brown leaves - If the amount of time spent with a teller is
exponentially distributed with parameter ?, what
is the probability that, of the three customers,
Mr smith is the last to leave?
18Exponential Distribution Example (Ross)
- Clearly, one of Brown and Jones must leave first,
at which time Smith starts to be served - At that point, since the exponential distribution
is memoryless, both Smith and the remaining
customer have the same distribution of
probability of length of service - Thus Smiths probability of being the last to
leave is 0.5 - Since Jones and Brown have equal distributions
when Smith arrives, they each have probability
0.25 of being last to leave
19Gamma Distribution
- The gamma distribution with parameters (t, ?) is
given by the probability density function - f(x) ?e-?x(?x)t-1 / ?(t) x ? 0
- 0 x lt 0
- where ? is defined as
- ?(t) ?0? e-yyt-1dy
- The gamma distribution arises frequently as the
time until n occurrences of some event occur - The special case in which ? 0.5 and tn/2 is
known as the ?n2 distribution, and arises
particularly as the error distribution of an n
dimensional problem, where the error in each
coordinate is normally distributed
20Weibull Distribution
- The Weibull distribution with parameters (?, ?,
?) is given by the probability density function - f(x) (?/?)??-1e-?? x gt ?
- 0 x? ?
- where ? is defined as
- ? (x - ?) / ?
- Its cumulative density distribution is
- f(x) 1 - e-?? x gt ?
- 0 x? ?
21Weibull Distribution
- The Weibull distribution is used to approximate
the failure of items composed of many parts,
where failure of any of the parts causes the
whole assembly to fail - For example, a computer fails when any of its
components fail - Hard drive
- Memory
- Cpu
- Bus
- Cache
- Etc.
22Cauchy Distribution
- The Cauchy distribution with parameters ? is
given by the probability density function - f(x) 1 / (? 1 (x - ?)2
- It has a similar shape to the normal
distribution, but with fatter tails - Values far from the mean are more likely to be
found than with the normal distribution
23Beta Distribution
- The Beta distribution with parameters (a, b) is
given by the probability density function - f(x) 1/B(a,b) xa-1(1-x)b-1 0 lt x 1
- 0 otherwise
- where B is defined as
- B(a,b) ?01 xa-1(1-x)b-1dx
24Beta Distribution
- The Beta distribution gives controllable
distributions - representing prior knowledge about the shape of
solutions - b controls the symmetry of the distribution
- When b lt a, the distribution is skewed to the
left - I.e. small values are more likely
- When b a, the distribution is symmetric
- When b gt a, the distribution is skewed to the
right - a controls the general shape of the distribution
for a b - When a 1, we get a uniform distribution
- When a lt 1, the distribution is concave upwards
- When a gt1, the distribution is convex upwards
25Functions of a Random Variable
- We often know about the relationship between two
random variables - In particular, for two random variables X and Y,
we may know that Y g(X) - If we also know the probability density function
of X, we would like to know the provability
density function of Y - To know about the probability density of Y at a
particular value y, we will have to work from the
probability density of the x that gives rise to
y, ie of g-1(y) - (for this to be well-defined, we will need to
restrict the form of g)
26Functions of a Random Variable
- Let X be a continuous random variable with
probability density function fX. Suppose that
g(x) is a strictly increasing (or strictly
decreasing) function of x. Then the variable Y
defined by Y g(X) has a probability density
function fY given by - fY(y) fXg-1(y) d/dy g-1(y) when
g-1(y) is defined 0 when g-1(y) is
undefined
27Summary
- Continuous Random Variables
- Continuous Distributions
- Uniform
- Normal
- Exponential
- Other Discrete Distributions
- Gamma
- Weibull
- Cauchy
- Beta
- Functions of a Random Variable
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