Chapter 9: Chemical quantities - PowerPoint PPT Presentation

About This Presentation
Title:

Chapter 9: Chemical quantities

Description:

Mass calculations ... Percent yield. All calculations so far have given theoretical yields of products ... Percent yield: measure of experimental efficiency ... – PowerPoint PPT presentation

Number of Views:39
Avg rating:3.0/5.0
Slides: 10
Provided by: Hoye
Category:

less

Transcript and Presenter's Notes

Title: Chapter 9: Chemical quantities


1
Chapter 9 Chemical quantities
Chemistry 1020 Interpretive chemistry Andy
Aspaas, Instructor
2
Interpreting chemical equations
  • The coefficients in a chemical equation indicate
    relative numbers of molecules involved in the
    equation
  • 2H2(g) O2(g) ? 2H2O(g)
  • This equation can be interpreted many ways
  • 2 molecules H2 gas react with 1 molecule O2 gas
    to form 2 molecules H2O gas
  • 2 dozen molecules H2 gas react with 1 dozen
    molecules O2 gas to form 2 dozen molecules H2O
    gas
  • 2 mol H2 gas react with 1 mol O2 gas to form 2
    mol H2O gas

3
Mole-mole relationships in reactions
  • 2H2(g) O2(g) ? 2H2O(g)
  • If you want to produce 15.7 mol H2O, how many
    moles of O2 gas are required in this reaction?
  • Use the coefficients in the balanced chemical
    reaction to convert between moles of any
    components in a reaction
  • Mole ratio 1 mol O2(g) for every 2 mol H2O(g)
    from the equation
  • Use that mole ratio as a dimensional analysis
    conversion factor

4
Mass calculations
  • In chemistry, number of moles is the only unit
    that can be used to convert between quantities of
    constituents in a chemical reaction
  • Stoichiometry conversion of masses of different
    reactants and products in a chemical reaction
  • If youre given the mass of a reactant or
    product, you must first convert mass to moles
  • If youre looking to find the mass of a reactant
    or product, you must first find the moles, and
    then convert to mass

5
Practice mass calculation problems
  • CO(g) 2H2(g) ? CH3OH(l)
  • What masses of carbon monoxide gas and hydrogen
    gas are required to produce 6.0 kg of methanol?
  • LiOH(s) CO2(g) ? Li2CO3(s) H2O(l)
  • What mass of CO2 gas can 1.00 kg of lithium
    hydroxide react with?

6
Limiting reagent
  • Whenever you are given quantities of more than
    one reactant, you must decide which will be
    consumed first (the limiting reactant)
  • The cheese sandwich analogy
  • Decide quantity of products that each individual
    reactant is able to produce
  • The reactant that produces the smallest quantity
    of product is the limiting reactant

7
Limiting reactant
  • Convert each reactant to moles
  • Use mole ratios to convert each to moles of
    product
  • Reactant which produces smallest value of product
    moles is limiting reactant
  • Use limiting reactant to calculate product moles
    and finally product mass

8
Limiting reactant practice
  • N2(g) 3H2(g) ? 2NH3(g)
  • Say 25.0 g nitrogen gas and 5 g hydrogen gas are
    reacted to form ammonia. What mass of ammonia can
    be produced?
  • Convert reactants to moles
  • Convert each to moles products
  • Identify limiting reagent
  • Product moles from limiting reagent
  • Convert to mass of product

9
Percent yield
  • All calculations so far have given theoretical
    yields of products
  • The maximum amount of product that can be formed,
    assuming all of the limiting reagent reacts, and
    all product can be collected
  • In reality, actual yield is almost always lower
  • Percent yield measure of experimental efficiency
  • (actual yield) / (theoretical yield) x 100
Write a Comment
User Comments (0)
About PowerShow.com