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Chapter 9: Elasticity and Fracture

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1st condition for equilibrium: The sum of all forces is zero: SFx ... for consideration, and make a careful free-body diagram to show all forces acting on it ... – PowerPoint PPT presentation

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Title: Chapter 9: Elasticity and Fracture


1
Chapter 9 Elasticity and Fracture
  • Christopher Chui

2
Statics Forces in Equilibrium
  • 1st condition for equilibrium The sum of all
    forces is zero SFx 0, SFy 0, SFz 0
  • 2nd condition for equilibrium The sum of all
    torques is zero St 0

3
Problem Solving in Statics
  • Choose one body at a time for consideration, and
    make a careful free-body diagram to show all
    forces acting on it
  • Choose a coordinate system and resolve the forces
    into their components
  • Using letters to represent unknowns, write down
    the equation for SFx 0, SFy 0, SFz 0
  • For St 0 equation, choose any axis
    perpendicular to the xy plane. Pay attention to
    the sign of the torque
  • Solve these equations for the unknowns

4
Stability and Balance
  • If an object is displaced slightly, 3 possible
    outcomes 1) the object returns to its original
    positionstable equilibrium 2) the object moves
    even fartherunstable equilibrium 3) the object
    remains in its new positionneutral equilibrium
  • A body whose CG is above its base of support will
    be stable if a vertical line projected downward
    from the CG falls within the base of support

5
Elasticity, Stress and Strain
  • Hookes law DL is proportional to applied force
  • There is a limit of elasticity plasticity
    follows and finally breaking
  • DL (1/E)(F/A)Lo E is elastic or Youngs modulus
  • Stress force / area F/A
  • Strain change in length / original length DL
    / Lo
  • E stress / strain

6
Three Types of Stresses
  • Tensile stress
  • Compressive stress
  • Shear stress
  • Shear strain DL (1/G)(F/A) Lo where G is
    shear modulus ½ to 1/3 of the elastic modulus
  • DV/Vo -(1/B) DP, where B is the bulk modulus
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