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ESI 6912: Dynamic Programming

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Algorithm: bisection ... Bisection will find one of the values corresponding to a consumption of L, and ... Bisection: Potential problems ... – PowerPoint PPT presentation

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Title: ESI 6912: Dynamic Programming


1
ESI 6912Dynamic Programming
  • Resource Allocation problems - 3

2
Resource allocation with multiple resources
  • Recall the resource allocation problem with 2
    resource constraints.

3
Multiple Resources
4
Using Lagrange relaxation
  • Relax the 2nd capacity constraint and penalize
    the violation in the objective function (with
    penalty parameter ??0)

5
Using Lagrange relaxation
  • Note that we can rewrite this problem as

6
Using Lagrange relaxation
  • So, for fixed ?, we obtain a single resource
    allocation problem with profit functions
  • So we can solve this problem using e.g. recursive
    fixing

7
Property 1
  • The optimal allocation for a given ? (say x ?) is
    the best solution to the original problem among
    all allocations that use no more of the 2nd
    resource.

8
Proof of Property 1
  • Since x ? is the optimal solution to the relaxed
    problem, we have
  • This implies
  • Therefore, if then

9
Property 1
  • This property implies that if, for some ?, we
    have d (x ?)L, then x ? is the optimal solution
    to the original problem.

10
Property 2
  • The amount used of the 2nd resource is
    non-increasing in ?.

11
Proof of Property 2
  • Let 0??1??2. Then
  • and
  • Thus
  • and therefore

12
Property 2
  • This property implies that, if d (x
    0)?L, then this solution is optimal and the 2nd
    resource constraint is redundant.
  • Otherwise, we can use property 2 to search for a
    value of ? for which d (x ?)L.

13
Algorithm bisection
  • Find two values of ? (0??1??2) whose
    corresponding consumption of the 2nd resource
    bracket the value L
  • Solve the relaxed problem with
  • If d (x ?)L, STOP.
  • If d (x ?)gtL, set ?1? otherwise set ?2?.
    REPEAT.

14
Algorithm graphical
p(x)
5
p(x)-?d(x)c
p(x)c
4
3
2
1
d(x)
1
2
3
4
5
6
7
15
Algorithm bisection
  • The bisection algorithm works if the profit as
    function of the amount of resource 2 exhibits
    strictly decreasing marginal return.
  • In this case, there is a continuum of values for
    ? that correspond with each value for the
    resource consumption.
  • Bisection will find one of the values
    corresponding to a consumption of L, and
    therefore the optimal solution, in finite time.

16
Bisection Potential problems
  • There are no solutions for which exactly L units
    of resource 2 are consumed

p(x)
5
p(x)-?d(x)c
p(x)c
4
3
2
1
d(x)
1
2
3
4
5
6
7
17
Bisection Potential problems
  • The marginal returns are decreasing, but not
    strictly at L

p(x)
p(x)-?d(x)c
p(x)-?d(x)c
5
p(x)-?d(x)c
4
3
2
1
d(x)
1
2
3
4
5
6
7
18
Bisection Potential problems
  • The marginal returns are not everywhere decreasing

p(x)-?d(x)c
p(x)
p(x)-?d(x)c
5
4
3
2
1
d(x)
1
2
3
4
5
6
7
19
Another resource allocation problem (1)
  • Consider the problem of allocating two types of
    resources to N activities.
  • There are K units of resource 1 available, and L
    units of resource 2.
  • The profit associated with allocating xn units of
    resource type 1 and yn units of resource type 2
    to activity n is pn(xn,yn).

20
NLP formulation
  • Formulate this problem as a dynamic programming
    problem.

21
Dynamic Programming formulation
  • State
  • (n,x,y) (first activity to be considered, total
    resources remaining)
  • Initial states (N1,x,y)
  • Ending state (1,K,L)
  • Decision
  • Amount of resources to allocate to activity n

22
Another resource allocation problem (1)
  • Optimal value function
  • f(n,x,y) the maximum profit obtainable from
    activities n,,N using x units of resource 1 and
    y units of resource 2
  • We wish to find f(1,K,L)
  • Boundary conditions
  • f(N1,x,y) 0, x0,,K, y0,,L

23
Another resource allocation problem (1)
  • Recurrence relation
  • for x0,,K y0,,L n1,,N
  • Running time
  • The network has O(NKL) nodes and O(N(KL)2) arcs
  • The costs of each arc can be determined in
    constant time
  • The running time is O(N(KL)2)

24
Another resource allocation problem (2)
  • Reconsider the previous problem.
  • However, now assume that we have Z dollars
    available, that we can spend on resources.
  • One unit of resource i costs ri (i 1,2).
  • How many units of each resource should we buy?

25
NLP formulation
  • Solve this problem using dynamic programming.

26
Another resource allocation problem (2)
  • Approach 1
  • The DP formulation of the problem with fixed
    values of K and L in fact solves all problems
    with smaller resource capacities
  • Solve the original problem with KZ/r1 and
    LZ/r2.
  • Choose the combination that yields the highest
    profit
  • Running time O(NZ4/(r1r2))

27
Another resource allocation problem (2)
  • Approach 2
  • First, find the optimal profit for a given budget
    assigned to activity n
  • Then solve a dynamic programming problem find the
    optimal amount of money to spend on resources for
    each activity

28
Dynamic Programming formulation
  • State
  • (n,z) (first activity to be considered, total
    budget available)
  • Initial states (N1,z)
  • Ending state (1,Z)
  • Decision
  • Budget to allocate to resources for activity n

29
Another resource allocation problem (2)
  • Optimal value function
  • f(n,z) the maximum profit obtainable from
    activities n,,N with a budget of z
  • We wish to find f(1,Z)
  • Boundary conditions
  • f(N1,z) 0, z0,,Z

30
Another resource allocation problem (2)
  • Recurrence relation
  • for z0,,Z n1,,N
  • Running time
  • The network has O(NZ) nodes and O(NZ2) arcs
  • The costs of all arcs can be determined in O(NZ2)
  • The running time is O(NZ2)
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