Title: Bonding and Structure of Hydrocarbons
1Bonding and Structure of Hydrocarbons
22.1 Saturated Hydrocarbons 22.2 Unsaturated
Hydrocarbons 22.3 Aromatic Hydrocarbons
2Hydrocarbons
- Compounds containing carbon and hydrogen atoms
only - Raw materials for synthesizing other organic
products
3Saturated Hydrocarbons
422.1 Saturated Hydrocarbons (SB p.29)
Saturated Hydrocarbons
- Contain only C ? C and C ? H single bonds
- Carbon atom is tetravalent (i.e. able to form
four bonds) - Structures and shapes can be predicted in terms
of - ? hybridization of orbitals
- ? valence shell electron pair repulsion theory
522.1 Saturated Hydrocarbons (SB p.29)
sp3 Hybridization
- Four unpaired electrons
- ? Form four bonds with other atoms
622.1 Saturated Hydrocarbons (SB p.29)
sp3 Hybridization
- 2s and 2p orbitals with their unpaired electrons
are mixed to give four hybrid orbitals of the
same energy level
722.1 Saturated Hydrocarbons (SB p.29)
sp3 Hybridization
- The hybrid orbital formed is called sp3 hybrid
orbital - ? each hybrid orbital has one part s character
and 3 parts p character - The four hybrid orbitals have the same shape and
same energy level
822.1 Saturated Hydrocarbons (SB p.30)
sp3 Hybridization
- There is one electron in each hybrid orbital to
form a bond - ? Electrons repel one another
- ? four sp3 hybrid orbitals get as far away as
possible - ? tetrahedral arrangement
922.1 Saturated Hydrocarbons (SB p.30)
Methane (CH4)
The formation of a methane molecule
1022.1 Saturated Hydrocarbons (SB p.30)
Methane (CH4)
- Four C?H bonds are arranged tetrehedrally
- All H ? C ? H bond angles are the same, i.e.109.5o
1122.1 Saturated Hydrocarbons (SB p.31)
Methane (CH4)
An sp3 hybrid orbital
- Has two lobes of unequal sizes
1222.1 Saturated Hydrocarbons (SB p.31)
Methane (CH4)
- The large lobe overlaps with the 1s orbital of a
hydrogen atom in a head-on manner to form a C ? H
bond
Formation of a C ? H ? bond
1322.1 Saturated Hydrocarbons (SB p.31)
Methane (CH4)
- ? The larger lobe of sp3 hybrid orbitals is
relatively large in size - ? The overlap between it and 1s orbital of
hydrogen atom is large - ? C ? H bond is strong
- In a ? bond, the bonding electrons are localized
symmetrically along the internuclear axis of the
bonding atoms
1422.1 Saturated Hydrocarbons (SB p.31)
Ethane (C2H6)
- Both carbon atoms are sp3 hybridized
The formation of an ethane molecule from two
sp3-hybridized carbon atoms
1522.1 Saturated Hydrocarbons (SB p.31)
Ethane (C2H6)
The ball-and-stick model of ethane
1622.1 Saturated Hydrocarbons (SB p.32)
Valence Shell Electron Pair Repulsion Theory
- Predict the geometry of arrangement of atoms in
the molecules
1722.1 Saturated Hydrocarbons (SB p.32)
Valence Shell Electron Pair Repulsion Theory
Step 1. Focus on the central atom of the
molecule 2. Consider all of the valence electron
pairs of the central atom, i.e. bond pairs and
lone pairs
1822.1 Saturated Hydrocarbons (SB p.32)
Valence Shell Electron Pair Repulsion Theory
- Electron pairs tend to stay as far apart as
possible - ? electronic repulsion between lone pairs is
generally greater than that between bond pairs
1922.1 Saturated Hydrocarbons (SB p.32)
Valence Shell Electron Pair Repulsion Theory
- The shape of the molecule is referred to the
positions of the atoms - ? the shape has minimum repulsion between the
electron pairs
2022.1 Saturated Hydrocarbons (SB p.32)
Valence Shell Electron Pair Repulsion Theory
The tetrahedral shape of a methane molecule
resulting in the minimum electronic repulsion
2122.1 Saturated Hydrocarbons (SB p.33)
22Unsaturated Hydrocarbons
2322.2 Unsaturated Hydrocarbons (SB p.34)
Unsaturated Hydrocarbons
- Hydrocarbons containing multiple bonds
- Include alkenes, alkynes and aromatic hydrocarbons
2422.2 Unsaturated Hydrocarbons (SB p.34)
sp2 Hybridization
- 2s orbital and two 2p orbitals are hybridized to
form three sp2 hybrid orbitals - One 2p orbital unhybridized
2522.2 Unsaturated Hydrocarbons (SB p.34)
sp2 Hybridization
- Take up a trigonal planar arrangement
2622.2 Unsaturated Hydrocarbons (SB p.35)
sp2 Hybridization
- The unhybridized 2p orbital is at a right angle
to the plane of the three sp3 hybrid orbitals
An sp2-hybridized carbon atom
2722.2 Unsaturated Hydrocarbons (SB p.35)
Ethene (C2H4)
- The sp2 hybrid orbitals from each carbon atom
head-on overlap with each other to form a ? bond
between the carbon atoms
2822.2 Unsaturated Hydrocarbons (SB p.35)
Ethene (C2H4)
- The remaining sp2 hybrid orbitals head-on overlap
with the 1s orbitals of the hydrogen atoms to
form ? bonds
2922.2 Unsaturated Hydrocarbons (SB p.35)
Ethene (C2H4)
- Side-way overlap of orbitals is much less
effective than head-on overlap of orbitals - ? ? bond is much stronger than ? bond
3022.2 Unsaturated Hydrocarbons (SB p.35)
Ethene (C2H4)
- ? bond electron cloud consists of two lobes
- ? one above and one below the plane of the
molecular framework
3122.2 Unsaturated Hydrocarbons (SB p.35)
Ethene (C2H4)
- The bonding electrons of a ? bond are loosely
held by the carbon nuclei - ? they can easily be attacked by electrophiles
(electron-loving chemical species) - ? unsaturated hydrocarbons with double bonds
are reactive compounds - ? undergo addition reactions readily
3222.2 Unsaturated Hydrocarbons (SB p.36)
Ethene (C2H4)
3322.2 Unsaturated Hydrocarbons (SB p.36)
3422.2 Unsaturated Hydrocarbons (SB p.36)
Cyclohexene (C6H10)
- Four of the carbon atoms are sp3-hybridized
- The remaining two carbon atoms that form the
carbon-carbon double bond are sp2-hybridized
3522.2 Unsaturated Hydrocarbons (SB p.36)
Cyclohexene (C6H10)
The structure of cyclohexene
3622.2 Unsaturated Hydrocarbons (SB p.36)
3722.2 Unsaturated Hydrocarbons (SB p.38)
sp Hybridization
- 2s orbital and one 2p orbital are hybridized to
form two sp hybrid orbitals - Two 2p orbitals unhybridized
3822.2 Unsaturated Hydrocarbons (SB p.38)
sp Hybridization
- The sp hybrid orbitals are co-linear
- Orientated at an angle of 180o
3922.2 Unsaturated Hydrocarbons (SB p.38)
sp Hybridization
- The unhybridized 2p orbitals are perpendicular to
the axis that passes through the centre of two sp
hybrid orbitals
An sp-hybridized carbon atom
4022.2 Unsaturated Hydrocarbons (SB p.39)
Ethyne (C2H2)
- The sp hybrid orbitals from each carbon atom
head-on overlap with each other to form a ? bond
between the carbon atoms
4122.2 Unsaturated Hydrocarbons (SB p.39)
Ethyne (C2H2)
- The remaining sp hybrid orbitals head-on overlap
with the 1s orbitals of the hydrogen atoms to
form ? bonds
4222.2 Unsaturated Hydrocarbons (SB p.39)
Ethyne (C2H2)
- The 2py and 2pz orbitals on each carbon atom
overlap in a side-way manner to form two ? bonds
4322.2 Unsaturated Hydrocarbons (SB p.39)
Ethyne (C2H2)
44Aromatic Hydrocarbons
4522.3 Aromatic Hydrocarbons (SB p.40)
Aromatic Hydrocarbons
- During the latter part of the 19th century,
- Aliphatic compounds
- ? chemical behaviour was fat-like
- Aromatic compounds
- ? low hydrogen to carbon ratio
- ? fragrant
4622.3 Aromatic Hydrocarbons (SB p.40)
Aromatic Hydrocarbons
- Kekule was the first to recognize the early
aromatic compounds all contain a six-carbon unit
(i.e. benzene)
4722.3 Aromatic Hydrocarbons (SB p.40)
Benzene (C6H6)
- Benzene was highly unsaturated
- ? undergoes addition reactions readily
- Indeed, benzene hardly undergoes addition
reactions
4822.3 Aromatic Hydrocarbons (SB p.40)
Benzene (C6H6)
- When benzene undergoes substitution reactions
with chlorine - ? Only one form of chlorobenzene is formed
- ? All six hydrogen atoms are identical
- ? More stable than alkenes and alkynes
4922.3 Aromatic Hydrocarbons (SB p.41)
Benzene (C6H6)
- From X-ray crystallography,
- All C ? C bonds have the same length (0.139 nm)
- C ? C bond in cyclohexane is 0.154 nm in length
- C C bond in cyclohexene is 0.134 nm in length
5022.3 Aromatic Hydrocarbons (SB p.41)
Benzene (C6H6)
- The stability of benzene and the C ? C bond
length in benzene can be explained by a resonance
model
5122.3 Aromatic Hydrocarbons (SB p.41)
Benzene (C6H6)
- The unhybridized p orbitals sideway overlap to
form ? bonds - ? Form a delocalized ? electron cloud
5222.3 Aromatic Hydrocarbons (SB p.41)
Benzene (C6H6)
- The delocalization of ? electrons imparts extra
stability to benzene
5322.3 Aromatic Hydrocarbons (SB p.41)
Benzene (C6H6)
- For simplicity, the structure of benzene can be
written as
5422.3 Aromatic Hydrocarbons (SB p.41)
Benzene (C6H6)
- In the real structure, the ? electrons are
delocalized over the whole system - The better way to represent the structure of
benzene
5522.3 Aromatic Hydrocarbons (SB p.43)
Enthalpy Changes of Hydrogenation of Benzene and
Cyclohexene
Hydrogenation of cyclohexene
5622.3 Aromatic Hydrocarbons (SB p.43)
Enthalpy Changes of Hydrogenation of Benzene and
Cyclohexene
Hydrogenation of 1,3-cyclohexadiene
5722.3 Aromatic Hydrocarbons (SB p.44)
Enthalpy Changes of Hydrogenation of Benzene and
Cyclohexene
Hydrogenation of 1,3,5-cyclohexatriene (Kekule
structure)
5822.3 Aromatic Hydrocarbons (SB p.44)
Relative stabilities of cyclohexene,
1,3-cyclohexadiene, 1,3,5-cyclohexatriene
(hypothetical) and benzene
The real benzene molecule is more stable than the
hypothetical Kekule structure by 150.4 kJ mol-1
5922.3 Aromatic Hydrocarbons (SB p.45)
Enthalpy Changes of Formation of Benzene and
Cyclohexene
6022.3 Aromatic Hydrocarbons (SB p.45)
Enthalpy Changes of Formation of Benzene and
Cyclohexene
6122.3 Aromatic Hydrocarbons (SB p.45)
Enthalpy Changes of Formation of Benzene and
Cyclohexene
6222.3 Aromatic Hydrocarbons (SB p.46)
Enthalpy Changes of Formation of Benzene and
Cyclohexene
6322.3 Aromatic Hydrocarbons (SB p.46)
Enthalpy Changes of Formation of Benzene and
Cyclohexene
6422.3 Aromatic Hydrocarbons (SB p.46)
Enthalpy Changes of Formation of Benzene and
Cyclohexene
- Enthalpy change of formation of benzene is less
positive than that of cyclohexene - ? benzene is energetically more stable than
cyclohexene
65The END
6622.1 Saturated Hydrocarbons (SB p.33)
Check Point 22-1
(a) Draw a three-dimensional structure for
propane (C3H8).
Answer
6722.1 Saturated Hydrocarbons (SB p.33)
Check Point 22-1
(b) How many s bonds are there in a molecule
of (i) propane? (ii) butane? (iii)
methylpropane?
Answer
- (i) 10 ? bonds
- (ii) 13 ? bonds
- (iii) 13 ? bonds
Back
6822.1 Saturated Hydrocarbons (SB p.33)
Let's Think 1
Are ball-and-stick models good representations of
organic molecules? Are there any other models
available?
Answer
6922.1 Saturated Hydrocarbons (SB p.33)
Back
Let's Think 1
The ball-and-stick model has the following
disadvantages The sizes, bond lengths and
bond angles are restricted to fixed
classifications. It cannot represent important
small variations, especially in angles. When
we pick it up to look at the model, bonds tend to
rotate to unintended positions. For big
molecules, it is practically impossible to pick
it up without distorting it. We can only guess
at steric repulsions, pbonding hindrance to
rotation, etc. There are many other molecular
models, one of them is the computer model which
makes use of visualization softwares (e.g. Chime)
to view the structure of molecules. It overcomes
the disadvantages of the ball-and-stick model and
provides much more information about the
structure of molecules.
7022.2 Unsaturated Hydrocarbons (SB p.35)
Back
Let's Think 2
Which is a stronger bond, a carbon-carbon single
bond or a carbon-carbon double bond? Why?
Answer
A carbon-carbon double bond is stronger than a
carbon-carbon single bond, as the carbon-carbon
double bond contains one sbond and one pbond
whereas the carbon-carbon single bond contains
only one sbond.
7122.2 Unsaturated Hydrocarbons (SB p.35)
Let's Think 3
Is the ball-and-stick model of ethene in Fig.
22-10 a good model of ethene?
Answer
It is not a good representation of the ethene
molecule as it fails to represent the s bond
between the two carbon atoms.
Back
7222.2 Unsaturated Hydrocarbons (SB p.36)
Example 22-2
The bond enthalpy of the carbon-carbon double
bond in ethene is 612 kJ mol1 while the bond
enthalpy of the carbon-carbon single bond in
ethane is 348 kJ mol1. Explain briefly why the
bond enthalpy of the carbon-carbon double bond is
less than twice that of the carbon-carbon single
bond.
Answer
7322.2 Unsaturated Hydrocarbons (SB p.36)
Back
Example 22-2
A carbon-carbon double bond is composed of a
sbond and a p bond. The sbond is formed by the
head-on overlap of orbitals. The electrons of the
sbond are distributed along the internuclear axis
of the two bonded atoms. sbond is a strong bond
and has a high bond enthalpy. On the other hand,
a pbond is formed by the side-way overlap of
orbitals. As the side-way overlap of orbitals is
less effective than the head-on overlap of
orbitals, a pbond is weaker than a sbond. Hence,
the bond enthalpy of the carbon-carbon double
bond (i.e. a sbond and a pbond) is less than
twice that of the carbon-carbon single bond (i.e.
a sbond).
7422.2 Unsaturated Hydrocarbons (SB p.37)
Check Point 22-2A
(a) State the difference between the s bond and
the p bond in the carbon-carbon double bond.
Answer
7522.2 Unsaturated Hydrocarbons (SB p.37)
Check Point 22-2A
- The differences between the s bond and the p bond
in the carbon-carbon double bond are - 1. The s bond is formed by the head-on overlap
of the sp2 hybrid orbitals of two carbon atoms,
while the p bond is formed by the side-way
overlap of the vacant p orbitals of two carbon
atoms. - 2. The bonding electrons in the s bond are
localized symmetrically along the internuclear
axis of two bonded carbon atoms. However, the
electrons in the p bond appear as two lobes, one
above and one below the internuclear axis of the
two bonded atoms. - 3. The s bond is much stronger than the p bond
as the side-way overlap of orbitals which
results in the p bond is much less effective
than the head-on overlap of orbitals which
results in the s bond. - 4. The s bond is free to rotate, whereas the p
bond is not.
7622.2 Unsaturated Hydrocarbons (SB p.37)
Back
Check Point 22-2A
(b) How many s and p bonds are present in a
molecule of (i) propene? (ii) but-1-ene? (iii)
but-2-ene?
Answer
(b) (i) 8 s bonds and 1 p bond (ii) 11 s bonds
and 1 p bond (iii) 11 s bonds and 1 p bond
7722.2 Unsaturated Hydrocarbons (SB p.40)
Check Point 22-2B
(a) How many s and p bonds are present in a
molecule of (i) propyne? (ii) but-1-yne? (iii)
but-2-yne?
Answer
(a) (i) 6 s bonds and 2 p bonds (ii) 9 s bonds
and 2 p bonds (iii) 9 s bonds and 2 p bonds
7822.2 Unsaturated Hydrocarbons (SB p.40)
Check Point 22-2B
(b) What is the hybridization of each carbon atom
in ethanenitrile?
Answer
(b) Carbon 1 is sp3-hybridized, whereas carbon 2
is sp-hybridized.
7922.2 Unsaturated Hydrocarbons (SB p.40)
Back
Check Point 22-2B
(c) State the bond angles indicated in the
compound below
Answer
(c) x 109.5o y 120o z 180o
8022.3 Aromatic Hydrocarbons (SB p.41)
Let's Think 4
What leads to the extra stability observed in
benzene?
Answer
In the six-member ring of benzene, six p orbitals
of carbon atoms sideway overlap with each other
to form six p bonds. The p electron clouds are
delocalized in the ring, linking the six carbon
atoms together. This imparts extra stability to
the benzene molecule.
Back
8122.3 Aromatic Hydrocarbons (SB p.42)
Example 22-3A
Classify the following compounds as saturated,
unsaturated or aromatic hydrocarbons.
A B C
D E
Answer
8222.3 Aromatic Hydrocarbons (SB p.42)
Example 22-3A
A Unsaturated hydrocarbon B Aromatic
hydrocarbon C Unsaturated hydrocarbon D
Saturated hydrocarbon E Saturated hydrocarbon
Back
8322.3 Aromatic Hydrocarbons (SB p.42)
Example 22-3B
Give the approximate values of the indicated bond
angles of the following compound
Answer
a 180o b 109.5o c 120o d 120o
Back
8422.3 Aromatic Hydrocarbons (SB p.46)
Check Point 22-3
(a) Name the following compounds
Answer
(a) A cyclohexane B benzene
8522.3 Aromatic Hydrocarbons (SB p.46)
Check Point 22-3
(b) State the hybridization of the carbon atoms
in each of the above compounds.
Answer
(b) A sp3 hybridization B sp2 hybridization
8622.3 Aromatic Hydrocarbons (SB p.46)
Check Point 22-3
(c) State the C ? C ? C bond angle in each of the
above compounds.
Answer
(c) A 109.5o B 120
8722.3 Aromatic Hydrocarbons (SB p.46)
Check Point 22-3
(d) Which one is an aromatic compound? Explain
your answer.
Answer
(d) B. This is because it possesses the aromatic
ring of benzene.
Back