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ECE 1100 Introduction to Electrical and Computer Engineering

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Substituting this into the equation for Ey yields the result. Multiply by ... Therefore, only a z component of the curl exists. We next prove that this must be zero. ... – PowerPoint PPT presentation

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Title: ECE 1100 Introduction to Electrical and Computer Engineering


1
ECE 6340 Intermediate EM Waves
Fall 2005
Prof. Donald R. Wilton ECE Dept.
Notes 9 (Notes based on those of D. R. Jackson)
2
Fields of a Guided Wave
z
Assume
Then
3
Fields of a Guided Wave (cont.)
Proof (for Ey)
or
Now solve for Hx
4
Fields of a Guided Wave (cont.)
Substituting this into the equation for Ey
yields the result
Multiply by
5
Fields of a Guided Wave (cont.)
or
The other components may be found similarly.
6
TEM Wave
Wavenumber property
To avoid having a completely zero field,
so
Use
Note
7
TEM Wave (cont.)
Lossless TL
so
The phase velocity is equal to the speed of light
in the dielectric.
8
TEM Wave (cont.)
Static property
and are 2D static field
functions.
9
TEM Wave (cont.)
Proof
Therefore, only a z component of the curl
exists. We next prove that this must be zero.
10
TEM Wave (cont.)
Now use
Also,
11
TEM Wave (cont.)
Hence
Therefore,
12
TEM Wave (cont.)
( No charge density in the time-harmonic steady
state, for a homogeneous medium)
Also,
Therefore,
Hence,
13
TEM Wave (cont.)
transmission line
14
TEM Wave (cont.)
A
B
The potential function is therefore unique, and
is the same as the static potential function.
15
TEM Wave (cont.)
Similarly,
so
16
TEM Mode Magnetic Field
so
17
TEM Magnetic Field (cont.)
Also,
so
This can be written as
18
TEM Mode Charge Density
TEM mode
y
x
19
TEM Charge Density (cont.)
so
Hence
Note ?? ? ?c
20
Example Microstrip Line
Ignore substrate and ground plane
21
Example (cont.)
Line in free space with a static charge density
(This was first derived by Maxwell using
conformal mapping.)
Hence
In this result, I0 is the total current Amps
on the strip.
22
Example Coaxial Cable
Find E, H
23
Example (cont.)
Boundary conditions
so
Hence
Therefore
24
Example (cont.)
25
Example (cont.)
This result is valid at any frequency.
26
Example (cont.)
27
TEM Mode Telegraphers Eqs.
TEM mode (lossless conductors)
28
Telegraphers Eqs. (cont.)
Note v is path independent in the (x,y) plane
29
Telegraphers Eqs. (cont.)
Use
So
30
Telegraphers Eqs. (cont.)
-?
But
so
Note L is the magnetostatic (DC) value.
or
31
Telegraphers Eqs. (cont.)
If we add R into the equation
This is justifiable if the mode is approximately
a TEM mode (small conductor loss).
32
Telegraphers Eqs. (cont.)
Amperes law
so
33
Telegraphers Eqs. (cont.)
Now use
34
Telegraphers Eqs. (cont.)
Hence
35
Telegraphers Eqs. (cont.)
36
Telegraphers Eqs. (cont.)
Hence
or
37
Telegraphers Eqs. (alternate derivation)
38
Telegraphers Eqs. (alternate derivation)
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