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Drill Problem 7'8'1

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... 1011011 is received, what is the decoded codeword based on the minimum Hamming distance. ... dij = w(si sj) Also thought of as the number of differences ... – PowerPoint PPT presentation

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Title: Drill Problem 7'8'1


1
Drill Problem 7.8.1
  • John Alamia

2
Problem
  • A given code consists of the codewords 0000000,
    0011110, 0101101, 0111000, 1001100, 1011001,
    1101010, 1110100. If 1011011 is received, what is
    the decoded codeword based on the minimum Hamming
    distance.

3
Hamming Distance
  • dij w(si Ä sj)
  • Also thought of as the number of differences or
    errors
  • Minimum Hamming distance between two different
    signals is 1

4
Solution
  • 0000000 Ä 1011011 5
  • 0011110 Ä 1011011 3
  • 0101101 Ä 1011011 5
  • 0111000 Ä 1011011 4
  • 1001100 Ä 1011011 4
  • 1011001 Ä 1011011 1
  • 1101010 Ä 1011011 3
  • 1110100 Ä 1011011 5
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