Title: Gas chromatography.
1Gas Chromatography
- M.Prasad Naidu
- MSc Medical Biochemistry, Ph.D,.
2Gas Chromatography Acetates
- Gas Chromatography, Refractive Index
Distillation - The next two (2) experiments introduce Gas
Chromatography and Simple Fractional
Distillation. - They are then tied together along with the
Refractive Index technique in a third experiment.
- This Week
- Gas Chromatography Acetates
- Pavia ? p. 837 855
- Slayden ? p. 45-47
- 2nd Week
- Distillation of a Mixture
- Slayden ? p. 41 - 27
- 3rd Week
- Gas Chromatography and Refractive Index of
Distillates from Distillation of Mixture
Experiment - Slayden p. 39
3Gas Chromatography Acetates
- Gas Chromatography
- Uses
- Separation and analysis of organic compounds
- Testing purity of compounds
- Determine relative amounts of components in
mixture - Compound identification
- Isolation of pure compounds (microscale work)
- Similar to column chromatography, but differs in
3 ways - Partitioning process carried out between Moving
Gas Phase and Stationary Liquid Phase - Temperature of gas can be controlled
- Concentration of compound in gas phase is a
function of the vapor pressure only. - GC also known as Vapor-Phase Chromatography (VPC)
and Gas-Liquid Partition Chromatography (GLPC)
4Gas Chromatography Acetates
- Gas Chromatograph
- Microliter Syringe
- Heated injection port with rubber septum for
inserting sample - Heating chamber with carrier gas injection port
- Oven containing copper, stainless steel, or glass
column. - Column packed with the Stationary Liquid Phase ?
a non-volatile liquid, wax, or low melting
solid-high boiling hydrocarbons, silicone oils,
waxes or polymeric esters, ethers, and amides - Liquid phase is coated onto a support material,
generally crushed firebrick
5Gas Chromatography Acetates
- Principals of Separation
- Column is selected, packed with Liquid Phase, and
installed. - Sample injected with microliter syringe into the
injection port where it is vaporized and mixed
into the Carrier Gas stream (helium, nitrogen,
argon). - Sample vapor becomes partitioned between Moving
Gas Phase and Stationary Liquid Phase. - The time the different compounds in the sample
spend in the Vapor Phase is a function of their
Vapor Pressure. - The more volatile (Low Boiling Point / Higher
Vapor Pressure) compounds arrive at the end of
the column first and pass into the detector
6Gas Chromatography Acetates
- Principals of Detection
- Two Detector Types
- Thermal Conductivity Detector (TCD) (we use this)
- Flame Ionization
- TCD is electrically heated Hot Wire placed in
carrier gas stream - Thermal conductivity of carrier gas (helium in
our case) is higher than most organic substances.
- Presence of sample compounds in gas stream
reduces thermal conductivity of stream - Wire heats up and resistance decreases.
- Two detectors used one exposed to sample gas and
the other exposed to reference flow of carrier
gas. - Detectors form arms of Wheatstone Bridge, which
becomes unbalanced by sample gas. - Unbalanced bridge generates electrical signal,
which is amplified and sent to recorder
7Gas Chromatography Acetates
- Factors Affecting Separation
- Boiling Points of Components in Sample
- Low boiling point compounds have higher vapor
pressures. - High boiling point compounds have lower vapor
pressures requiring more energy to reach
equilibrium vapor pressure, i.e., atmospheric
pressure. - Boiling point increases as molecular weight
increases. - Flow Rate of Carrier Gas
- Choice of Liquid Phase
- Molecular weights, functional groups, and
polarities of component molecules are factors in
selecting liquid phase. - Length of Column
- Similar compounds require longer columns than
dissimilar compounds. Isomeric mixtures often
require quite long columns
8Gas Chromatography Acetates
- The Experiment
- Purpose Introduce the theory and technique of
gas chromatography. - Identify a compound by it retention time.
- From the relationship between peak area and
mole content calculate the mole fraction and
mole percent of a compound in a mixture. - Approach
- Obtain chromatograph of a known equimolar mixture
of four (4) esters. - (Ethyl, Propyl, Butyl, Hexyl Acetate)
- Obtain chromatograph of unknown mixture (one or
more compounds in the known mixture). - Determine Retention Times.
- Calculate Peak Areas
- Calculate Total Area
- Calculate Mole Fraction
- Calculate Mole Percentage
9Gas Chromatography Acetates
- The Experiment (Cont)
- Groups Work in groups of three (3).
- Each group will use the same standard
chromatogram. - Each Student will run their own unknown
- Samples
- The Standard has 4 esters
- Ethyl Acetate, Propyl Acetate, Butyl Acetate,
Hexyl Acetate - The Unknowns have 1 to 4 of the compounds in the
standard
10Gas Chromatography Acetates
- The Report
- The Gas Chromatograph instrument settings and the
processing of the samples to get the
chromatograms are considered one (1) procedure. - When multiple samples or sub-samples are
processed with the same procedure, it is not
necessary to set up a separate procedure for each
sample. Setup a suitable template in Results to
report all of the results obtained. - Thus, the process to obtain Gas Chromatograms of
the Known mixture of 4 acetates and the
Unknown mixture utilize the same procedure. - The computation of the Peak Areas and the Total
Peak area are considered separate procedures. - The computation of Mole Fraction and Mole are
considered separate procedures
11Gas Chromatography Acetates
- Summarize in paragraph form, all of the results
obtained in the experiment. Use a logical
organization and order of the results. - The Conclusion for the Gas Chromatography of
Acetates experiment must present arguments, using
applicable results, that support the
identification of compounds in the Unknown
mixture. - The known mixture was an equimolar mixture of
four (4) acetates. Comment on the equivalency of
the peak areas in the known mixture and the
application of the Thermal Response Correction
Factor to adjust the peak areas and the computed
mole percent of the unknown mixture
12Gas Chromatography Acetates
Note all three temperatures are the same
- Record Instrument readings
- Injection Port Temp
- Column Temp
- Detector Temp
- Gas Flow Rate (65 mL / min)
- Chart Speed (5 cm / min)
- Injecting the Sample
- Sample is injected into the B port with the
microsyringe - The Microsyringe is fragile and expensive BE
CAREFUL - Mark Starting Point on chart short vertical
line - Insert needle fully into rubber septum or until
resistance is met maybe a ¼ inch remains. - Inject sample quickly and remove needle.
- Start chart recorder simultaneously with sample
injection
13Gas Chromatography Acetates
- Determine the Retention Time
- The period following injection that is required
for a compound to pass through the column to the
point where the detector current is maximum, i.e.
maximum pen deflection or maximum peak height. - For a given set of constant conditions (carrier
gas, flow rate of carrier gas, column
temperature, column length, liquid phase,
injection port temperature), the retention time
of any compound is always constant. - Retention Time is similar to the Retardation
Factor, Rf in Thin Layer Chromatography. - Compute Retention Time from the Chart Speed (5
cm/min) and the distance on the chart from the
time of injection to the point on the chart where
the perpendicular line drawn from the peak height
intersects the base line
14Gas Chromatography Acetates
- Determination of Retention Time
- Since Velocity (v) Distance / Time d / t
- Ret Time (t) Distance(cm) / Velocity(cm/min)
d / v
Starting Point On Chart
15Gas Chromatography Acetates
- Quantitative Analysis
- The area under a gas chromatograph peak is
proportional to the amount (moles) of the
compounds eluted. - The molar percentage composition of a mixture can
be approximated by comparing the relative areas
of the peaks in the chromatogram. - This approach assumes that the detector is
equally sensitive to all compounds and its
response is linear - This assumption is usually not valid and will be
addressed in the Thermal Response Adjustment
section starting on slide 17
16Gas Chromatography Acetates
- Triangulation Method of Determining Area Under
Peak - Multiply the height of peak (in mm) above the
baseline by the width of the peak at half the
height. - Baseline is a straight line connecting side arms
of the peak. Best if peaks are symmetrical. - Add areas to get total.
- Divide each area by total area to get mole
fraction - See next slide
17Gas Chromatography Acetates
- Peak Area by the Triangulation Method
- Peak Area h w½
- Where h Peak Height
- w½ width of peak at
½ the peak height - Total Peak Area(TA) A B
- Mole Fraction(MF) A/TA, B/TA
- Mole Percent MF x 100
18Gas Chromatography Acetates
- Thermal Response Factor
- Equimolar mixtures each compound in the mixture
has the same number of moles should produce
chromatograms in which all peaks have the same
area - Compounds with different functional groups or
widely varying molecular weights do not all have
the same thermal conductivity. This can cause
the instrument to produce response variations,
which result in unequal peak areas. - A correction factor called The Thermal Response
Factor for a given compound is determined from
the relative peak areas of an equimolar solution
19Gas Chromatography Acetates
- Thermal Response Calculations For GC Analysis
- For the analysis of the Alkyl Acetates in the
table below, the subscript i stands for the
number of carbons in the alkyl group, so that i
2, 3, 4, 6 for this experiment. Thus, subscript
2 stands for Ethyl Acetate subscript 3 stands
for Propyl Acetate, etc. - Note In the table below any of the compounds can
be used as the basis for the calculations, i.e.,
s can be 2, 3, 4, or 5 for our mixture of 4
Acetates. - From the Chromatogram of your Standard Equimolar
Mixture of Alkyl Acetates fill in the blanks
below.
20Gas Chromatography Acetates
- Thermal Response Ratios a correction factor
- The area ratios under the GC peaks are
proportional, but not equal, to the molar ratios
of the components in the mixture. - Let TR be the thermal response of a component,
generally - The thermal response ratio of the different
components, TRx/TRy, a constant, could be
simplified to a single term, but we will continue
to express it as a ratio
.
21Gas Chromatography Acetates
- Thermal Response Ratios (Cont)
- For the analysis of the Alkyl Acetates in the
equations below, the subscript i stands for the
number of carbons in the alkyl group, so that - i 2(Ethyl), 3(Propyl), 4(Butyl), 5(Hexyl)
- In the derivation and examples that follow, Ethyl
Acetate will be used as the basis for the
calculations, but any of the other compounds
could also be used, such as in the case where the
unknown mixture does not contain any Ethyl Acetate
22Gas Chromatography Acetates
- Thermal Response Ratios (Cont)
- The mole ratio of each component relative to
Ethyl Acetate in the unknown mixture is
calculated from - Since we will need the TRs/TRi ratios from the
above equation, they will be calculated from the
areas under the peaks in the standard equimolar
mixture - For an equimolar mixture molei/moles 1
- Thus, substitution in equation 2 gives
23Gas Chromatography Acetates
.
- Thermal Response Ratios (Cont)
- Adjusting the Peak Areas of the Unknown Mixture
- From equation (3), each individual TRs/TRi ratio
is calculated from the peak areas in the GC trace
of the standard equimolar mixture - Using each TRs/TRi ratio, the mole ratio of each
component in the unknown mixture, relative to the
base compound, is calculated from equation (2) - The Molei/Moles values from equation 2 now
represent the adjusted peak areas, and thus are
proportional to the molar content of the unknown
mixture - The adjusted Molei/Moles values are summed
- The new Mole Fractions are computed by dividing
each Molei/Moles value by the total
24Gas Chromatography Acetates
- Thermal Response Ratios (Cont)
- Example Ethyl Acetate (S2) is used as basis
for calculations
EtAc (2) ProAc (3) BuAc (4) HexAc (6)
Standard Equimolar Mixture Measured Peak Area 1.44 1.09 1.16 0.98
Standard Equimolar Mixture TRs/TRi (s2) 1.44 1.00 1.44 1.44 1.33 1.09 1.44 1.24 1.16 1.44 1.48 0.98
Unknown Mixture Measured Peak Area 2.14 2.18 2.12 1.54
Unknown Mixture moli/mols (s2) 2.14 ? 1.00 1.00 2.14 2.18 ? 1.33 1.35 2.14 2.12 ? 1.24 1.23 2.14 1.54 ? 1.48 1.07 2.14
Unknown Mixture molei percent 21.5 29.0 26.5 23.0
EtAc / EtAc mol2 / mol2 area2 /
area2 ? TR2 / TR2 2.14 / 2.14 ? 1.00
1.00 ProAc / EtAc mol3 / mol2 area3 /
area2 ? TR2 / TR3 2.18 / 2.14 ? 1.33
1.35 BuAc / EtAc mol4 / mol2 area4 /
area2 ? TR2 / TR4 2.12 / 2.14 ? 1.24 1.23
HexAc / EtAc mol6 / mol2 area6 / area2 ?
TR2 / TR6 1.54 / 2.14 ? 1.48 1.07 ?
moli/mol2 1.00 1.35 1.23 1.07
4.65 ? mole EtAc 1.00 / 4.65 100
21.5 ? mole ProAc
1.35 / 4.65 100 29.0 ? mole BuAc 1.23
/ 4.65 100 26.5 ? mole HexAc 1.07 /
4.65 100 23.0
25Gas Chromatography Acetates
Thermal Response Ratios (Cont) Example 2
Ethyl Acetate (S2) is used as basis for
calculations
EtAc (2) ProAc (3) BuAc (4) HexAc (6)
Standard Equimolar Mixture Measured Peak Area 128 186 208 210
Standard Equimolar Mixture TRs/Tri (s2) 128 1.00 128 128 0.69 186 128 0.62 208 128 0.61 210
Unknown Mixture Measured Peak Area 2.14 2.18 2.12 1.54
Unknown Mixture moli/mols (s2) 2.14 ? 1.00 1.00 2.14 2.18 ? 0.69 0.70 2.14 2.12 ? 0.62 0.61 2.14 1.54 ? 0.61 0.44 2.14
Unknown Mixture molei percent 36.4 25.4 22.2 16.0
EtAc / EtAc mol2 / mol2 area2 / area2 ? TR2
/ TR2 2.14 / 2.14 ? 1.00 1.00 ProAc /
EtAc mol3 / mol2 area3 / area2 ? TR2 /
TR3 2.18 / 2.14 ? 0.69 0.70 BuAc /
EtAc mol4 / mol2 area4 / area2 ? TR2 /
TR4 2.12 / 2.14 ? 0.62 0.61 HexAc /
EtAc mol6 / mol2 area6 / area2 ? TR2 /
TR6 1.54 / 2.14 ? 0.61 0.44 ?
moli/mol2 1.00 0.70 0.61 0.44
2.75 ? mole EtAc 1.00 / 2.75 100
36.4 ? mole ProAc 0.70 / 2.75 100
25.4 ? mole BuAc 0.61 / 2.75 100
22.2 ? mole HexAc 0.44 / 2.75 100 16.0
26Thermal Response Ratios (Cont) Ex. 3 - (Assumes
the unknown is missing Ethyl Acetate and
Propyl Acetate (S3) is used as basis for
calculations)
EtAc (2) ProAc (3) BuAc (4) HexAc (6)
Standard Equimolar Mixture Measured Peak Area 128 186 208 210
Standard Equimolar Mixture TRs/Tri (s3) 186 1.45 128 186 1.0 186 186 0.89 208 186 0.89 210
Unknown Mixture Measured Peak Area 0.0 2.18 2.12 1.54
Unknown Mixture moli/mol2 (s3) 0.0 2.18 1.0 2.18 2.12 0.87 2.18 1.54 0.63 2.18
Unknown Mixture molei percent 0.0 40.0 34.8 25.2
ProAc / EtAc mol3 / mol3 area3 / area3 ?
TR3 / TR3 2.18 / 2.18 ? 1.00 1.00 BuAc
/ EtAc mol4 / mol3 area4 / area3 ? TR3 /
TR4 2.12 / 2.18 ? 0.89 0.87 HexAc /
EtAc mol6 / mol3 area6 / area3 ? TR3 /
TR6 1.54 / 2.18 ? 0.89 0.63 ?
moli/mol3 1.00 0.87 0.63 2.50 ? mole
ProAc 1.00 / 2.50 100 40.0 ? mole
BuAc 0.87 / 2.50 100 34.8 ? mole
PexAc 0.63 / 2.50 100 25.2
27Thank you