Title: University of Dayton Industrial Assessment Center
1University of DaytonIndustrial Assessment Center
2Energy Costs and CO2
3Natural Gas Price Trends
Source U.S. Dept. of Energy, Annual Energy
Review 2005, Report No. DOE/EIA-0384(2005)
4Natural Gas Price Volatility
- Source Canada National Energy Board,
http//www.neb.gc.ca/energy/EnergyPricing/HowMarke
tsWork/NG_e.htm
5Electricity Price Trends
Source U.S. Dept. of Energy, Annual Energy
Review 2005, Report No. DOE/EIA-0384(2005)
6Electricity Price Volatility
- Residential electricity prices will increase 2.6
in 2007, compared to 2.2 over the last 10 years - Those regions with States undergoing market
restructuring may experience more price
volatility. For example, residential prices in
the East North Central region are projected to
rise by nearly 6 percent in 2007, compared to the
last 10-year average of only 1 percent.
Source U.S. Dept. of Energy, Short Term Energy
Outlook, May 2007, http//www.eia.doe.gov/emeu/ste
o/pub/contents.html
7Inside Out Method
8Traditional Outside-In Approach To Energy
Efficiency
Traditional Analysis Sequence for Reducing Energy
Use
Traditional Analysis Sequence for Reducing Waste
Result Incremental improvement at high cost
9Preferred Inside-out Approach To Energy
Efficiency
Inside-Out Analysis Sequence for Reducing Energy
Use
Inside-Out Analysis Sequence for Reducing Waste
Result Significant improvement at minimal cost
10Inside-out Approach to Energy Efficiency
- Reduce end-use loads
- Reduce distribution losses and loads
- Improve primary energy conversion equipment
11Electrical System
12Power Factor and Phase Lag
- Inductive loads such as AC motors cause phase lag
between voltage and current, which converts some
supplied power (kVA) into un-useable reactive
power (kVAr) and decreases useable power (kW) - Thus, supplied power (kVA) increased by utility
to deliver required useable power (kW)
13Power Factor, kVA and kW
14Power Factor
- Inductive loads such as AC motors cause phase lag
between voltage and current, which converts some
supplied power (kVA) into un-useable reactive
power (kVAr) and decreases useable power (kW) - Thus, supplied power (kVA) increased by utility
to deliver required useable power (kW) - PF is ratio of useable power (Pa) and supplied
power (Ps) - Low PF has three adverse effects
- Utilities charge for low PF
- Increased supplied power (kVA) increases line
losses, line size, transformer size - May cause sensitive electrical equipment to
malfunction. - Good practice to maintain PF at 90 or more by
right-sizing under-loaded motors and adding
capacitors
15Reduce Peak Demand by Moving Electrical Operation
to Light Shift
Even shifts moving operation increases demand
Uneven shifts moving operation decreases demand
16Stagger Startup of Barrel Heaters
Sunday barrel pre-heat, with hydraulic motors
off, does not generally set peak demand
17Lighting
18Inside-out Approach for Lighting Efficiency
- End-Use
- Deliver required quantity of lighting
- Maximize daylighting
- Distribution System
- Position lights effectively
- Improve luminaire efficiency
- Primary Equipment
- Install high-efficiency lighting
19Paint Ceilings White
- White ceilings reflect more light onto the work
plane. - Lighting levels under identical lights were
- 30 fc under white ceiling
- 10 fc under black ceiling
- Use 1/3 as many lights under white ceilings
20Replace Colored / Fiberglass Windows with
Corrugated Polycarbonate
Corrugated polycarbonate costs about the same as
and is installed just like corrugated fiberglass,
but lets in about 10 times more light.
21Employ Skylighting
- Skylights
- Highest quality light
- Reduce lighting energy costs
- Increase heating/cooling costs
-
- To maximize cost-effectiveness
- Analyze competing costs
- Identify optimum skylight / floor area ratio
http//www.sprung.com/Product/Images/SkylightsSqua
re
22Light Levels vs. Skylight Area
23Total Cost Savings vs. Skylight Area
24Recommended Skylighting Areas
- Optimum skylight/floor area ratio
- Ranges from 1 to 6
- Increases with target lighting level
- Decreases as lights are more efficient
- Energy cost savings
- Range from 1 to 25 cents per ft2 floor area-year
- Increase with target lighting level
- Decrease as lights are more efficient
Wallmart with 5 skylight/floor ratio and lights
turned off
25Replace / Modify Inefficient Luminaires
- Acrylic to aluminum MH luminaires
- Add reflectors to fluorescent strip lighting
- Known
- Fluorescent strip lights with CU .65
- Action
- Add reflectors so CU 0.75
- Savings
- Fraction luminaires removed (1/CU1 1/CU2)
- Fraction luminaires removed 1/.65 1/.75 20
26Install Reflectors on T12 Fixtures without
Reflectors
- Reflectors push light downward onto the work
plane rather than allowing it to escape upward
onto the ceiling. - 63 fc under fixtures with reflectors and 20 fc
under fixtures without reflectors. - Installing reflectors on half of current fixtures
would provide same lighting and cut energy use in
half.
27Replace Incandescent with Compact Fluorescent
Lamps
- CF lamps
- Use 75 less energy
- Last 8-10 times longer
- Known
- 100 100-W I lamps, life 1,000 hours, cost
1, operating 6,000 h/yr - Action
- Replace with 23-W CF lamps, life 10,000 hours,
cost 5 - Savings
- 100 lamps x (.100 - .023) kW/lamp x 6,000 h/yr
46,200 kWh/yr - 46,200 kWh/yr x 0.10 /kWh 4,620 /yr
- 100 lamps x 6,000 h/yr x (1/1,000 5/10,000)
(h-lamp)-1 300 /yr - 4,620 /yr 300 /yr 4,920 /yr
28Replace T12 Lamps Electro-magnetic
Ballastswith T8 Lamps Electronic Ballasts
- T8 lamps with electronic ballasts
- Use 25 less energy
- Improve CRI and eliminate flicker
- Known
- 100 fixtures with four 34-W T12 lamps and
electro-magnetic ballasts operating 6,000 h/yr - Action
- Replace with four 32-W T8 lamps and electronic
ballasts - Savings
- 100 fix x (.144 - .112) kW/fix x 6,000 h/yr
19,200 kWh/yr - 19,200 kWh/yr x 0.10 /kWh 1,920 /yr
29Replace Metal Halide with High Bay Fluorescent
Lights
- High bay fluorescent (HBF) lights
- Reduce energy use by 50 or more
- Improve CRI
- Reduce maintenance costs
- Stabilize light level
- Improve light distribution
- Can be turned on/off as needed, w/ occupancy or
w/photocells
30Metal Halide to High Bay Fluorescent
31Light Output vs. Temperature
- Metal Halide
- Constant output
- T8
- Max at 77 F
- 80 at 50 F and 112 F
- T5
- Max at 93 F
- 80 at 64 F and 131 F
Source http//www.ruudlighting.com
32Replace High Pressure Sodium with High Bay
Fluorescent Lights
- Photos of lighting under HPS and HBF lights in
same facility taken with same camera.
33Motors
34Turn Off Motors When Not in Use
- Stamping press motors
- 65 of power dissipated as heat due to friction
- Use 65 of power required during stroke part of
cycle while idle - Hydraulic system motors
- Use 40 of full load power even while idle.
- Motor startup too brief to influence peak demand.
35Replace Smooth with Notched V-belts
- Example
- Notched belts are
- 3 more efficient than smooth belts
- Last 50 to 400 longer than smooth belts
- Cost only about 30 more than smooth belts
- Estimated Savings
- 25-hp motor, 91 efficient, 75 loaded
- 25 hp x 0.75 kW/hp x 75 loaded / 91 x 3 0.5
kW - 0.5 kW x 6,000 hours/yr 3,000 kWh/year
- 3,000 kWh/year x 0.10 /kWh 300 /year
- Implementation Cost
- Negligible
- Simple Payback
- Immediate
36Replace V-belt with Synchronous Belt Drive
- Example
- Synchronous belt drives are
- 5 more efficient than v-belt drives
- Last 24,000 hours
- Estimated Savings
- 100-hp motor, 91 efficient, 75 loaded
- 100 hp x 0.75 kW/hp x 75 loaded / 91 x 5 3.1
kW - 3.1 kW x 6,000 hours/yr 18,600 kWh/year
- 18,600 kWh/year x 0.10 /kWh 1,860 /year
- Implementation Cost
- 12 /hp x 100 hp 1,200
- Simple Payback
- 1,200 / 1,860 /yr 8 months
37Under-loaded Motors Efficiency Declines
- Example
- Estimated Savings
- 75-hp motor is 15 loaded. Operates at an
efficiency of about 50. The power requirement
is about - (75 hp x 15 x .746 kW/hp) / 50 16.8 kW
- 15-hp motor would be 75 loaded and 86
efficient. The power requirement would be about - (15 hp x 75 x .746 kW/hp) / 86 9.8 kW
- Total electricity savings would be about
- 16.8 kW - 9.8 kW 7 kW
- 7 kW x 48 hr/wk x 50 wk/yr 16,800 kWh/yr
- 16,800 kWh x 0.10 /kWh 1,680 /yr
- Estimated Implementation Cost and Simple Payback
- Cost of straight drive, 15-hp motor and labor
would be about 500. Simple payback would be
about - SP 500 / 1,680 /yr x 12 months/yr 4 months
38Under-loaded Motors Power Factor Declines
39Power Factor
- Inductive loads such as AC motors cause phase lag
between voltage and current, which converts some
supplied power (kVA) into un-useable reactive
power (kVAr) and decreases useable power (kW) - Thus, supplied power (kVA) increased by utility
to deliver required useable power (kW) - PF is ratio of useable power (Pa) and supplied
power (Ps) - Low PF has three adverse effects
- Utilities charge for low PF
- Increased supplied power (kVA) increases line
losses, line size, transformer size - May cause sensitive electrical equipment to
malfunction. - Good practice to maintain PF at 90 or more by
- Right-sizing under-loaded motors
- Adding capacitors
40Motor Efficiency and Costs
Source US DOE Motor Master 2.0
41Motor Lifecycle Cost Dominated by Energy
- Consider
- 20 hp motor, 93 efficient, 80 loaded, 6,000
hr/yr, 10 years - Cost of electricity
- 20 hp x 80 x 0.75 kW/hp / 0.93 x 6,000 hr/yr
77,500 kWh/yr - 77,500 kWh/yr x 10 yr x 0.10 /kWh 77,500
- Cost of motor
- Purchase cost 1,000
- Ratio of energy to purchase cost
- 77,500 / 1,000 77 to 1
- Thus,
- Use efficient motors!
421 Improvement in Efficiency Equals Purchase Cost
- Consider
- 20 hp motor, 93 efficient, 80 loaded, 6,000
hr/yr, 10 years - Cost of electricity
- If efficiency 93, then 10 year electricity
cost 77,500 - If efficiency 94, then 10 year electricity
cost 76,600 - Savings 77,500 - 76,600 900
- Cost of motor
- Purchase cost 1,000
- Thus,
- Purchase premium efficiency motors!
43Replace Rather than Repair Old Motors
Assuming 80 loaded, 6,000 hr/yr, 0.10 /kWh
44Fluid Flow
45Fluid Flow Systems
- Inside is work required to move fluid
- Reduce friction
- Smooth pipes/ducts (PVC, Copper, Steel)
- Large diameter pipe/ducts (P k D5)
- Low pressure drop fittings /valves (long radius
elbows) - Maintain proper inlet/outlet conditions
- Unrestricted flow for 6 duct diameters
- Pump slow, pump long
46Minimize Pipe Friction
- Use large diameter pipes
- DP headloss C / D5
- Doubling pipe diameter reduces pumping costs by
97 - Use smooth plastic pipes
- fsteel 0.021 fplastic 0.018
- Pumping savings from plastic pipe
- (0.021 0.018) / 0.018 17
- Less friction reduces pumping costs and cooling
load
47Employ Energy-Efficient Flow Control
- Most pump and fan systems
- Sized for peak flow, but
- Operate at lower flows
- Or require variable flows
- Use energy-efficient methods to control flow
48Old Inefficient Flow Control
By-pass loop (No savings)
By-pass damper (No savings)
Outlet valve/damper (Small savings)
Inlet vanes (Moderate savings)
49New Efficient Flow Control
Trim impellor for constant-volume pumps
Slow fan for constant-volume fans
VFD for variable-volume pumps or fans
50 Inefficient and Efficient Flow Control
51Install VFD on Process Cooling Loop Pump
- W2 W1 (V2/V1)3
- Reducing flow by 50 reduces pumping costs by 87
52 Variable Frequency Drive Costs
53 Variable-Speed Cooling Tower Fans
Variable speed cooling tower fans save the most
energy on year-round loads with high set-point
temperatures characteristic of industrial process
cooling applications.
54Compressed Air
55Inside-out Approach to Compressed Air Efficiency
- End use
- Install solenoid valves to shut off air
- Install air saver nozzles
- Install differential pressure switches on bag
houses - Use blower for low-pressure applications
- Distribution
- Fix leaks
- Starve leaks
- Install no-loss drains
- Decrease pressure drop in distribution system
- Compressor System
- Compress outside air
- Use refrigerated dryer
- Direct warm air into building during winter
- Use load/unload control with auto shutoff or VSD
for lag compressor - Stage compressors with pressure settings or
controller - Add compressed air storage to increase auto
shutoff
56Eliminate Continuous Blowoff with Solenoid Valves
- Known
- Open tube air loss V (scfm) 11.6 x ID (in)2
x P (psia) - Solenoid valves cost between 30 - 350
- Operate up to 600 cycles per minute from 50-150
psig - Controlled by process machines, photo sensors,
etc. - Action
- Replace continuous blowoff from 100 psig, 3/8-in
pipe with solenoid valve open 20 of time - Savings
- V tube 11.6 x 3/8 (in)2 x 115 (psia) 188
scfm - 188 scfm x 80 x 0.75 kW/hp / (4.2 scfm/hp x
0.90) 30 kW - 30 kW x 6,000 hr/yr x 0.10 /kWh 18,000 /yr
- If load/unload at 60 6,200 /yr x 40 7,200
/yr
57Reduce Blow-off with Air-Saver Nozzles
- Known
- Open tube air loss V (scfm) 11.6 x ID (in)2
x P (psia) - 3/8-in tube, 100 psig, 2000 hr/yr, 4.2 scfm/hp
comp - 3/8-in vortex nozzle consumes 31 scfm
- Action
- Add nozzle to tube
- Savings
- V tube 11.6 x 3/8 (in)2 x 115 (psia) 188
scfm - V nozzel 31 scfm
- (188 31) scfm x 0.75 kW/hp / (4.2 scfm/hp x
0.90) 31 kW - 31 kW x 2,000 hr/yr x 0.10 /kWh 6,200 /yr
- If load/unload at 60 6,200 /yr x 40 2,480
/yr
58Control Bag House Air Pulses with Differential
Pressure Sensor
- Known
- Timed pulse uses 34 scfm at peak production
- Production is currently 60 of peak
- Action
- Install differential pressure control
- Savings
- 34 scfm x 40 x 0.75 kW/hp / (4.2 scfm/hp x
0.90) 2.7 kW - 2.7 kW x 6,000 hr/yr x 0.10 /kWh 1,620 /yr
- If load/unload at 60 1,620 /yr x 40 648
/yr
59Use Blower For Low-pressure Applications
- Known
- Air compressor at 100 psig 4.2 scfm/hp
- Low-pressure blowers at 20 psig 7.2 scfm /hp
- Tank currently uses 140 scfm of comp air
- Action
- Install low-pressure blower
- Savings
- 140 scfm x 0.75 kW/hp x (1/4.2 1/7.2) hp/scfm
/ 0.90 11.6 kW - 11.6 kW x 6,000 hr/yr x 0.10 /kWh 6,960 /yr
- If load/unload at 60 6,960 /yr x 40
2,780 /yr
60Purchase Ultrasonic Sensor and Fix Leaks
- Known
- Most compressed air systems lose between 5 and
20 of compressed air to leaks. - To find leaks
- listen with the unaided ear or ultrasonic
sensor. - monitor compressor power when all production
machinery is off. - Inspect system for leaks once a week
- Action
- Fix single 1/32-inch leak
- Savings
- 1 scfm x 0.75 kW/hp / (4.2 scfm/hp x 0.90) 0.2
kW - 0.2 kW x 6,000 hr/yr x 0.10 /kWh 120 /yr
- If load/unload at 60 120 /yr x 40 48 /yr
61Starve Leaks in Unoccupied Areas by Shutting Off
Branch Headers
- Known
- Total plant leak load 200 cfm
- Half of plant operates 6,000 hr/yr and half of
plant operates 2,000 hr/yr - Action
- Install solenoid valve to shut off air to unused
area - Savings
- 200 scfm x 50 x 0.75 kW/hp / (4.2 scfm/hp x
0.90) 20 kW - 20 kW x 4,000 hr/yr x 0.10 /kWh 8,000 /yr
- If load/unload at 60 8,000 /yr x 40 3,200
/yr
62Replace Timed Solenoid with No-loss Drains
- Known
- 3/8-inch drain with timed solenoid opens 3
seconds every 30 seconds to discharge condensate. - 3/8-inch no-loss float-type drains eliminates
90 of air losses. - 3/8-inch no-loss float-type drains costs about
600 - Action
- Replace timed solenoid drain with no-loss drain
- Savings
- V drain 11.6 x 3/8 (in)2 x 115 (psia) 188
scfm - Fraction time open (3 sec / 30 sec) 10
- 188 scfm x 10 x 0.75 kW/hp / (4.2 scfm/hp x
0.90) 3.7 kW - 3.7 kW x 90 x 6,000 hr/yr x 0.10 /kWh 2,000
/yr - If load/unload at 60 2,000 /yr x 40 800
/yr
63Use Looped Piping to Decrease System Pressure
Drop
- Use looped rather than linear design
- Main line size from average cfm to get DP 3
psi - Branch line size from cfm peak to get DP 3psi
- Feed lines size from peak cfm to get DP - 1 psi
- Hose can generate DP 4 to 5 psi (proper
selection of hoses is important!) - Total DP lt 10 psig
64Avoid Deadhead Connections
65Properly Size Supply Piping / Hoses
66Properly Size and Maintain Filters and Dryers
- Place filter upstream of dryer to protect dryer
- DP filter lt 1 psid
- DP refrigerated dryer lt 5 psid ( 90 F inlet and
40 F outlet)
67Reduce Compressor Operating Pressure
Fractional Savings
0.5 per psi
- Known
- Compressor draws 20 kW while producing 120 psig
air - Action
- Reduce pressure setting to from 110 to 100 psig
- Savings
- (P2high/P1)0.286 (110 psig 14.7 psia) / 14.7
psia0.286 1.84 - (P2low/P1)0.286 (100 psig 14.7 psia) / 14.7
psia0.286 1.80 - Frac savings (1.84 1.80) / (1.84 1) 4.8
- 20 kW x 4.8 x 6,000 hr/yr x 0.10 /kWh 580
/yr
68Compress Outdoor Air
- Known
- Compressing cooler outside air reduces
compressor work - Fractional Savings (Thi - Tlow) / Thi 2 per
10 F - Compressor draws 20 kW, Tin 80 F, Tout 50 F
- Action
- Install PVC piping to duct outside air to
compressor - Savings
- Frac Savings ((80 460) - (50 460)) / (80
460) 5.5 - 20 kW x 5.5 x 6,000 hr/yr x 0.10 /kWh 660
/yr - If load/unload at 60 660 /yr x 40 264
/yr
69Replace Desiccant Dryer with Refrigerated Dryer
- Known
- Refrigerated dryer cools to Tdew-point 35 F,
and use 4-6 W/scfm - Desiccant dryer cools air to Tdew-point -40 F,
but use 15 of compressed air for purging - Current use 840 scfm from compressor at 4.2
scfm/hp - Action
- Install refrigerated dryer
- Savings
- Purge power
- 840 scfm x 15 x 0.75 kW/hp / (4.2 scfm/hp x
90) 25 kW - Refrigerated dryer power
- (840 scfm x 85 x 0.006 kW/scfm 4.3 kW
- (25 kW 4.3 kW) x 6,000 hr/yr x 0.10 /kWh
12,420 /yr
70Direct Warm Air Into Plant During Winter
Winter
- Known
- gt75 of compressor input power lost as heat
- Compressors draws 105 kW, heating system 80
efficient, operates 2,000 hours per year - Action
- Change ventilation or add duct work to direct
warm air into plant during winter - Savings
- 105 kW x 75 x 3,413 Btu/kWh x 2,000 hours/year
540 mmBtu/yr - 540 mmBtu/year / 80 x 10 /mmBtu 6,750 /year
71Compressor Power vs Capacity By Control Mode
FP (FC x (1 FPNL) FPNL
72Power Characteristics of Load/unload and
Modulation Control
73Modulation vs Load/Unload with Auto Shutoff
74Modulation to Load/Unload with Auto Shutoff
Savings
- Known
- Power draw measured at 79 kW in modulation 51 kW
in load/unload with auto shutoff - Action
- Switch from modulation to load/unload with auto
shutoff - Savings
- (79 51) kW x 6,000 hr/yr x 0.10 /kWh
16,800 /yr
75Stage Compressors
- If the same load/unload pressures for two
compressors are the same, both compressors will
operate at part-load.
- Stage compressors into a lead and lag
compressor by setting the load/unload pressures
of the lag compressor 5 psi less than the lead
compressor.
- Staging allows the Lead compressor to run fully
loaded and the Lag compressor to turn off or run
at minimal load, increasing efficiency.
76Stage Compressor Savings
- Known
- Two 100-hp, compressors operating between 95
105 psig at 70 capacity - FP (FC x (1 FPNL) FPNL
- Action
- Set base between 95 105 psig and lag between
90-100 psig - Savings
- Current
- FP (.7 x (1 .6) .6 .88
- Power 2 x 100 hp x .88 / .90 x .75 kW/hp 147
kW - Proposed
- Base 100 hp x 1.00 / .90 x .75 kW/hp 83 kW
- Lag FP (.2 x (1 .6) .6 .68 P 100 hp
x .68 / .90 x .75 kW/hp 57 kW - Base Lag 83 kW 57 kW 140 kW
- Savings (147 140) kW x 6,000 hr/yr x 0.10
/kWh 4,200 /yr - Savings if auto shutoff (147 100) kW x 6,000
hr/yr x 0.10 /kWh 28,200 /yr
77Add Compressed Air Storage
Minimal storage causes frequent cycling
Adding storage decreases cycling and enables
auto-shutoff
- Savings
- Add 500 gallons of storage
- Average power draw from 17 to 14.5 kW after
adding storage - (17 14.5) kW x 6,000 hr/yr x 0.10 /kWh
1,500 /yr
78Add Local Storage w/ Valve and Reduce Compressed
Air Pressure
79Summary of Key Equations and Relations
- Input power (kW) Voltage (V) x Current (A) x
1.73 x Power factor (kW/kVA) / 1,000 VA/kVA - Peak input power (kW) Rated motor power (hp) x
Service factor x 0.75 kW/hp / Motor efficiency - Annual energy use (kWh/yr) Input power (kW) x
Operating hours (hr/yr) - Annual electricity cost (/yr) Annual energy
use (kWh/yr) x Unit electricity cost (/kWh) - Flow from open tube (scfm) 11.6 (scfm/lbf) x
Pressure (psig) x Diameter (in) 2 - Input power from flow (kW) Flow (scfm) x 0.75
kW/hp / (Specific output (scfm/hp) x Motor
efficiency) - Typical compressor/blower specific output 4.5
scfm/hp at 100 psig 7.2 scfm at 20 psig - Savings from reducing operating pressure 0.5
per psi - Savings from reducing intake air temperature 2
per 10 F - Refrigerated dryer electricity use 0.006
kW/scfm Unheated desiccant dryer air use 15
of flow - Recoverable heat from air compressors 75 of
electrical power (kW) x 3,412 (Btu/kWh) - Fraction Power (Fraction Capacity x (1
Fraction Power at No Load) Fraction Power at
No Load - Typical Fraction Power at No Load (Modulation
Control) 0.70 - Typical Fraction Power at No Load (Load/unload
Control) 0.50 - 0.60 - Typical Fraction Power at No Load (Variable Speed
Drive) 0.10 - Typical Fraction Power at No Load (On/Off) 0.0
80Process Cooling
81Match Cooling Source to End Use
Near order of magnitude difference in costs!
82Cooling Tower
- 500 ton tower delivers 7.5 mmBtu/hr
- Ppump 18 kW Pfan 20 kW Water 120
gal/mmBtu - Unit cost of cooling 1.22 /mmBtu
83Water-Cooled Chiller
- E/Q 0.8 kW/ton 67 kWh/mmBtu
- Unit cost of cooling 6.70 /mmBtu
84Air-Cooled Chiller
- E/Q 1.0 kW/ton 83 kWh/mmBtu
- Unit cost of cooling 8.30 /mmBtu
85Absorption Chiller
- E/Q 1 Btu-heat / Btu-cooling Eff-boiler 80
- Unit cost of cooling 12.50 /mmBtu
86Open-Loop Water Cooling
- DT 10 F V 12,000 gallons / 1 mmBtu
- Unit cost of cooling 72 /mmBtu
87Compressed Air Cooling
- Vortex cooler uses 150 scfm at 100 psig to
produce 10,200 Btu/hr cooling - 4.5 scfm per hp
- Unit cost of cooling 272 /mmBtu
88Add Heat Exchanger in Continuous Process with
Sequential Heating and Cooling
89Add Heat Exchanger When Cooled Tank is Warmer
than Heated Tank
T 145 F Requires Cooling
T 120 F Requires Heating
90Avoid Mixing
Separate hot and cold water tanks
91Cooling Tower Performance
92Use Cooling Tower Instead of Chiller When
Possible
Fraction of year cooling tower can deliver water
at Tc (Assume Tr 10 F in Dayton OH)
93Air-Cooled Chiller
- E/Q 1.0 kW/ton 83 kWh/mmBtu
- Unit cost of cooling 8.30 /mmBtu
94Water-Cooled Chillers
- E/Q 0.8 kW/ton 67 kWh/mmBtu
- Unit cost of cooling 6.70 /mmBtu
95Air-Cooled Chiller Performance
96Water-Cooled Chiller Performance
97Process Heating
98Heat Balance on Furnace
99Energy Saving Opportunities From Heat Balance
- Reduce flue losses
- Reduce wall losses
- Reduce opening losses
- Reduce cooling losses
- Reduce storage losses
-
- Reclaim heat from flue to
- Pre-heat combustion air
- Pre-heat load
100Natural Gas Combustion with Stoichiometric Air
CH4 2 (O2 3.8 N2) CO2 2 H2O 7.6
N2
HEAT
- Oxygen breaks CH4 into CO2 and H2O
- Nitrogen doesnt react
- Heat absorbed by products CO2, H2O and N2
101Natural Gas Combustion with Excess Air
CH4 3 (O2 3.8 N2) CO2 2 H2O 7.6
N2 02 3.8 N2
HEAT
- With excess air, heat absorbed by excess O2 and
N2 - Lowers flame temperature, heat transfer and
efficiency.
102Natural Gas Combustion with Correct Amount of
Excess Air
CH4 2.2 (O2 3.8 N2) CO2 2 H2O
7.6 N2 0.2 02 0.8 N2
HEAT
- About 10 excess air, insures complete
combustion - 10 excess air 2 O2 in exhaust gasses
103Natural Gas Combustion Products
104Fraction Heat Available to Furnace(Combustion
Efficiency)
105Fraction Heat Lost Up Stack
106Natural Gas Combustion with Oxygen
HEAT
CH4 2 (O2) CO2 2 H2O
- Oxygen doesnt contain N2
- Heat absorbed by less product gasses CO2, H2O
- Increases flame temperature, heat transfer,
efficiency
107Flame Temperature with Oxygen Enhancement
108Available Heat (Combustion Efficiency) with
Oxygen Enhancement
109CO Formation
7000
6000
No Air Leakage into furnace
5000
4000
CO - PPM
3000
2000
1000
0
0
1
2
3
4
5
Oxygen
1100.5 Oxygen
1 Oxygen
2 Oxygen
4 Oxygen
111Insulate Injection Molding Barrels and Heads
112Turn Off Heat to IMM Barrels When Not in Use
113Minimize Air Leakage Into Furnaces
Heat in Flue Gases
Air Leaks
Combustion Air
Fuel
114Seal Furnace Openings
- Openings
- Usually enable air leakage into furnace
- Always enable radiation loss
115Use Draft Control to Balance Pressure
116Reduce Air Leakage in Continuous Ovens By
Modifying Entrance/Exit
117Cover Charge Wells
- 2 ft x 4 ft open charge well radiates and
convects heat - Cover charge well with mineral fiber insulation
75 of time - Savings 1,500 /yr
118Preheat Combustion Air with Recuperator
119Preheat Combustion Air with Tubein-Tube Heat
Exchanger
120Preheat Combustion Air with Regenerators
121Preheat Load with Preheating Shed
122Preheat Continuous Load with Counter-flow Heat
Exchange
123Recover Flue Gas Heat with Waste Heat Boiler
124Boilers and Steam
125Inside Out Approach to Boiler/Steam Efficiency
- End use
- Insulate hot surfaces
- Cover open tanks
- Distribution system
- Fix leaky steam traps
- Insulate steam and condensate pipes
- Boiler system
- Reduce excess air
- Switch from On/Off to Modulate control
- Run multiple boilers at part load
- Add recuperator to preheat feed water
126Insulation Properties
Rule of thumb insulate all surfaces over 120 F
127Insulate Open Tanks
- Heat loss from open tanks occurs via convection,
radiation and evaporation - Losses reduced by covering surface or adding
floats.
128Steam Traps
- Inverted Bucket Traps Condensate discharged
intermittently. - Float and Thermostatic Traps Condensate
discharged continuously - Thermostatic Traps Condensate discharged
continuously - Thermodynamic Traps Condensate discharged
intermittently - Intermittent traps detect leaks by listening for
continuous discharge with ultrasonic sensor - Continuous traps detect leaks by measuring
temperature on both sides
129Steam Trap Orifice Size and Leakage Rate
- Orifice size is function of design pressure and
pipe diameter (NPT)
- Steam flow (lb/hr) 24.24 lb/(hr-psia-in2) x P
psia x D inch2 x FracOpen
130Fix Leaky Steam Traps
- Known
- Failed 0.5-inch inverted bucket trap rated at 180
psi, actual steam pressure is 120 psig. - Savings
- From table orifice size is 1/32-inch. Assuming
that the orifice is 50 open, the steam loss
through the leaking trap is about - 24.24 lb/(hr-psia-in2) x 135 psia x 3/32 inch2
x 50 14.5 lb/hr - The latent heat of steam at 120 psig is about 872
Btu/lb and the saturation temperature is about
350 F. Assuming that 100 of the condensate is
returned at 200 F, and that the boiler is 80
efficient, the natural gas savings from fixing
the steam trap would be about - 14.5 lb/hr x 872 Btu/lb 1 Btu/lb-F x (350
200) F x 6,000 hr/yr / 80 111 mmBtu/yr - 111 mmBtu/yr x 10 /mmBtu 1,110 /yr
- Implementation Cost and Simple Payback
- Inverted-bucket steam traps for ½-inch pipe
connections with a max operating pressure of 125
psig cost about 92 each with installation cost
of 30 per trap. If so, the cost of replacing
the trap would be about 122. - Simple Payback 122 / 1,110 /yr x 12 months/yr
1 month
131Insulate Steam and Condensate Return Pipes
- Known
- Insulate 100 ft x 6-in steam pipe carrying 100
psig - Savings
- 125,870 Btu/hr x 8,000 hr/yr / 80 1,260
mmBtu/yr - 1,260 mmBtu/yr x 10 /mmBtu 12,600 /yr
- Implementation Cost
- 1,800
- Simple Payback
- 1,800 / 12,600 /yr 0.15 years
132Close Condensate Return System
Open system
Closed System
Open systems lose 25 of steam energy as flash,
return colder condensate
133Close Condensate Return System
- Known
- Closed system returns 100 lb/hr at 200 F compared
to 150 F for open system - Boiler is 80 efficient
- Savings
- 100 lb/hr x 1 Btu/lb-F x (200 150) F x 8,000
hr/yr / 80 50 mmBtu/yr - 50 mmBtu/yr x 10 /mmBtu 500 /yr
134Excess Air and Boiler Efficiency
- Combustion air generally controlled by dampers
- Simple recalibration of dampers can reduce excess
excess air
135Combustion with 10 Excess Air Guarantees
Complete Combustion
136Boiler Control
- Most boilers have
- Modulating burners
- Single-point positioning control
- Inconsistent excess air levels over firing range
- Typically greater at low fire than high fire by
30 or more - Excess air calibrated at high fire, then too much
at reduced firing
137Single-Point Positioning Control
- Controls based on signals from steam or hot water
gauge - Combustion controls are usually calibrated by
technicians at high fire
Burner with Single-Point Positioning
Burners Linking Mechanism
138O2 Trim System
- Can be programmed to maintain a desired excess
air level (10). - Eliminates the need to calibrate to slightly
higher levels than desired. - System should be calibrated 3 to 4 times per
year, which results in a 1,500 - 2,000 annual
maintenance cost. - Purchase cost is 20,000 - 30,000 per system.
139Preheat Water With Economizer
- Air-to-water heat exchangers called economizers
- Forces water through finned tubes in exhaust
stack - Best pay-backs for full-year heating with low
condensate return
140HVAC
141Inside-out Approach to HVAC Efficiency
- Minimize heating/cooling load
- Improve distribution system
- Improve efficiency of heating/cooling plant
142Use Programmable Thermostats
- Lower/increase interior set-point temp during
unoccupied periods - Important because heating/cooling load
proportional to (Tia Toa) - Example If Toa 50 F, then reducing Tia from
70 F to 60 F decreases heating load by 50 - However, thermal mass limits temperature drop
and reduces savings
143Close Doors and Openings
- Install garage-door openers on lift-trucks
- Observation Heating energy varies by 3X at same
temp! - Discovery Didnt close shipping doors!
144Turn Off Dust Collectors When Not Needed
- Reduce ventilation load with
- VAV
- On/off control
- Filter air with HEPA filter if both heating and
cooling
145Balance Supply / Exhaust Air
146Employ DP Control to Balance Plant Air
- Manometer measures DP between inside and outside,
and adjusts air flow of MAU - Good choice if ventilation requirements change
frequently - Paint booths
- Large combustion air demands
147Reverse Direction of Exhaust Fan During Winter
Months
- Exhausting air drives infiltration and internal
heat gains dont displace space heating - Supplying air eliminates infiltration and
internal heat gains displace space heating
148Insulate Under-insulated Walls / Ceilings
- Example Add 3.5-in fg batt insulation (R 3.2
/inch) to R 3 brick wall - Qh,sav (1/R1 1/R2) x A x (Tbal Toa)
- Qh,sav (1/3 1/13) Btu/hr-ft2-F x (65 30) F
9 Btu/hr-ft2 - Qng,sav 9 Btu/hr-ft2 x 4,000 hr/yr / 0.80 x 10
/mmBtu 0.45 /ft2-yr - Cost 3-in fiberglass batt insulation 0.35 /ft2
- SP 0.35 / 0.45 /yr
- SP 0.8 yr
Diminishing returns for adding R-10 insulation
149Insulate Under-insulated Walls / Ceilings
- 4 inches of spray on cellulose
- 1.30 per ft2
150Deliver Heat Effectively
- Problems
- Warm air pulled out of facility by exhaust fans
or openings - Excess temperature stratification
- Solutions
- Install radiant heaters in high ventilation areas
- Install destratification fans
151Use Outside Air Requirement to Select Unit
Heater or MAU
- Unit heaters
- 80 efficient
- Recirculate inside air
- Make-up air units
- 100 efficient
- Supply outside air
- Selection
- If dont need outside air, use unit heaters to
avoid heating cold outside air - If need outside air, use makeup air units for
high efficiency
152Convert from CAV to VAV Systems
- Constant-Air-Volume (CAV) system, air supply
constant and zone temperature regulated with
reheat - Variable-Air-Volume (VAV) system, air supply to
zones is varied and reheat is minimized - Thus, VAV systems use less fan, cooling and
heating energy
153Reheat/VAV Box Control
154CAV-VAV Whole Building Electric Savings
155CAV to VAV Cooling Savings
156CAV to VAV Heating Savings