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GRAPHS

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Example--Solving Algebraically. X3 2x2 -9x 18 = 0. Factor by grouping. Separate into 2 groups. ... Set each factor to zero and solve. X 2 = 0 or x = -2 ... – PowerPoint PPT presentation

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Title: GRAPHS


1
GRAPHS
  • Chapter 1

2
Solving Equations in One Variable Using a
Graphing Utility
  • 1.3

3
Solving Equations in One Variable
  • If an equation can be solved algebraically, then
    an exact solution is found. If not, then a
    graphing calculator is used to find an
    approximate solution to TWO DECIMAL PLACES.

4
Solve Using Zero
  • Write in the form
  • Expression 0
  • Graph Y1 expression
  • Use ZERO to determine each x-intercept.

5
Solve Using Intersect
  • Graph Y1 expression on the left and
    Y2expression on the right.
  • Use INTERSECT to determine the x-coordinate of
    each point of intersection.

6
Solve Using Intersect
  • After graphing, press 2nd trace.
  • Choose intersect (5).
  • Move the cursor onto one of the graphs and press
    enter.
  • Move the cursor onto the other graph and press
    enter.
  • Move the cursor on the intersection and hit
    enter.
  • Repeat for other intersections.

7
Example--Solving with Calculator
  • 3(2-x)2x-1
  • Put 3(2-x) in
  • Y1 and 2x-1
  • In y2 and get
  • The graph on
  • The right. Then
  • find the intersection.

8
Example--Solving Algebraically
  • 3(2-x)2x-1
  • 6 3x 2x 1
  • 7 5x
  • X 7/5 1.4

9
Example--Solving with Calculator
  • X3 2x2 -9x 18 0
  • Put the equation in y1 and use the zero function
    to find the zeroes or values that make the
    equation true.
  • X 3, -2, and -3

10
Example--Solving Algebraically
  • X3 2x2 -9x 18 0
  • Factor by grouping. Separate into 2 groups.
  • (X3 2x2 ) (-9x 18) 0
  • Take out a common factor of each.
  • x2(X 2 ) - 9(x 2) 0
  • Factor out the common factor.
  • (x2)(x2 9) 0
  • Set each factor to zero and solve.
  • X2 0 or x -2
  • x2 9 0 or (x3)(x-3) 0 or x -3 or 3
  • X 3, -2, and -3
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