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CHAPTERS 7

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Title: CHAPTERS 7


1
CHAPTERS 7 8
  • NETWORKS 1 0909201-01
  • 19 October 2004 Lecture 6b
  • ROWAN UNIVERSITY
  • College of Engineering
  • Dr Peter Mark Jansson, PP PE
  • DEPARTMENT OF ELECTRICAL COMPUTER ENGINEERING
  • Autumn Semester 2005 Quarter One

2
test II
  • Historic means
  • 2004 69.6 (75.4 Adjusted)
  • 2003 63
  • This Year mean

3
networks I
  • Todays learning objectives
  • build an understanding of
  • First (1st) Order Circuits

4
admin
  • less than 28 hours remain.
  • All previous homework 1-6
  • due Friday by 5 p.m. for final grade
  • new homework
  • hw 7 due Thursday (15 Take Home)
  • final test this Thurs 315pm
  • Rowan Hall Auditorium

5
HANDY CHART
ELEMENT CURRENT VOLTAGE
6
OP-AMP CIRCUITS WITH C L
7
QUIZ Find vo f(vs)
8
ANSWER TO QUIZ
9
Handier Charts for studying
  • see Table 7.9-1
  • Characteristics of Energy Storage Elements
  • Page 266
  • and Table 7.14-2
  • Parallel and Series Capacitors and Inductors
  • Page 281
  • Inductance
  • Behaves as a short to constant DC current
  • Capacitance
  • Behaves as an open circuit to constant DC voltage

10
Table 7.9-1 (p. 266) Characteristics of Energy
Storage Elements
11
Initial conditions of switched circuits
  • switch changes
  • t0, at time of switching
  • t0-, just prior to switching
  • t0, just after switching
  • t8, a long time after switching, steady state
  • Instantaneously
  • Capacitor current can change, voltage cant
  • Inductor voltage can change, current cant

12
  • steady state circuit conditions just before the
    switching change and again a very long period
    after the switching change
  • inductor in a steady DC current acts as a short
    circuit with no voltage drop
  • vL L (di/dt) if di/dt0 so does v
  • capacitor in a constant DC voltage acts as an
    open circuit with no current flow
  • iC C (dv/dt) if dv/dt0 so does i

13
simple illustrations of switching
  • an inductor example
  • If R1R21? What is i1 and iL at t(0-) t(0)
  • a capacitor and inductor example
  • LC1 What is vC and iL at t(0-) t(0)

14
HW problem 7.9-2
  • page 286

LC2 What is total resistance the 12V source sees
in the circuit at t(0-) t(0), answer is two
(2) numbers Rt(0-) Rt(0),
15
Circuit for Example 7.9-1 Switch 1 closes at t
0 and switch 2 opens at t 0, Find iL(0),
vc(0), dVc(0)/dt, and diL(0)/dt, assume switch
2 has been closed for a long time.
16
Circuit for Example 7.9-1 at t(0-) Switch 1 is
not closed yet, and switch 2 has been closed for
a long time, all current flows through 1?
resistor. Find iL(0-) and voltage across
capacitor vc(0-) is ?
Show your answers as Learning check 3
17
Once you found out what iL(0-) and voltage across
capacitor vc(0-) is, how do these quantities
relate to
  • The instant afterwards?
  • iL(0-) and iL(0) current in inductor
  • vc(0-) and vc(0) voltage across capacitor
  • why?

Show your answers as Learning check 4
18
Circuit for Example 7.9-1 at t(0) Switch 1 has
just closed, and switch 2 has just opened. To
solve for diL(0)/dt we need a KVL in right hand
mesh, to solve for dvc(0)/dt we need a KCL at
node a.
KVL in right hand mesh vL vC 1iL 0 so
diL(0)/dt -2A/s KCL at node a (vc-10)/2 ic
iL 0 so dvc(0)/dt 12V/s
19
What did we learn here?
  • at switching time (t0) current in inductor and
    voltage in capacitor remained constant
  • but voltage in inductor changed instantaneously
    from 0V to -2V with diL(0)/dt -2A/s
  • and
  • current through capacitor changed instantaneously
    from 0 to 6 A with
  • dvc(0)/dt 12V/s

20
LAST STEP What are final conditions at t t(8)
for vc, ic, vL and iL ?
CURRENT IN CAPACITOR is Zero VOLTAGE ACROSS
INDUCTOR is Zero SHOW vc and iL as LEARNING CHECK
5
21
IMPORTANT CONCEPTS FROM CH. 7
  • I/V Characteristics of C L.
  • Energy storage in C L.
  • Writing KCL KVL for circuits with C L.
  • Solving op-amp circuits with C or L in feedback
    loop.
  • Solving op-amp circuits with C or L at the
    input.

22
new concepts from ch. 8
  • response of first-order circuits
  • to a constant input
  • the complete response
  • stability of first order circuits
  • response of first-order circuits
  • to a nonconstant (sinusoidal) source

23
What does First Order mean?
  • circuits that contain capacitors and inductors
    can be defined by differential equations
  • circuits with ONLY ONE capacitor OR ONLY ONE
    inductor can be defined by a first order
    differential equation
  • such circuits are called First Order Circuits

24
whats the complete response (CR)?
  • Complete response transient response steady
    state response
  • OR.
  • Complete response natural response forced
    response

25
finding the CR of 1st Order Circuit
  • Find the forced response before the disturbance.
    Evaluate at t t(0-) to determine initial
    conditions v(0-) or i(0-)
  • Find forced response (steady state) after the
    disturbance t t(8) Voc or Isc
  • Add the natural response (Ke-t/?) to the new
    forced response. Use initial conditions to
    calculate K

26
Figure 8.0-1 (p. 290)A plan for analyzing
first-order circuits. (a) First, separate the
energy storage element from the rest of the
circuit. (b) Next, replace the circuit connected
to a capacitor by its Thévenin equivalent
circuit, or replace the circuit connected to an
inductor by its Norton equivalent circuit.
27
RC and RL circuits
  • RC circuit complete response
  • RL circuit complete response

28
simplifying for analysis
  • Using Thevenin and Norton Equivalent circuits
    can greatly simplify the analysis of first order
    circuits
  • We use a Thevenin with a Capacitor
  • and a Norton with an Inductor

29
Thevenin Equivalent at t0
i(t)
-
30
Norton equivalent at t0
31
1st ORDER CIRCUITS WITH CONSTANT INPUT
32
Example (before switch closes)
  • If vs 4V, R1 20k?,
  • R2 20 k?
  • R3 40 k?
  • What is v(0-) ?

LC6 Write down vsource at t(0-) t(0)
33
as the switch closes
  • THREE PERIODS emerge..
  • 1. system change (switch closure)
  • 2. (immediately after) capacitor or inductor in
    system will store / release energy (adjust and/or
    oscillate) as system moves its new level of
    steady state (a.k.a. transient or natural
    response) . WHY???
  • 3. new steady state is then achieved (a.k.a. the
    forced response)

34
Thevenin Equivalent at t0
i(t)
-
KVL
35
SOLUTION OF 1st ORDER EQUATION
36
SOLUTION CONTINUED
37
SOLUTION CONTINUED
38
so complete response is
  • complete response v(t)
  • forced response (steady state) Voc
  • natural response (transient)
  • (v(0-) Voc) e-t/RtC) NOTE ? RtC

39
Figure 8.3-4 (a) A first-order circuit and (b) an
equivalent circuit that is valid after the switch
opens. (c) A plot of the complete response.
LC7 What is Rt(0) and VOC?
40
Lets Build the Complete Response for the circuit
1) Find the forced response before the
disturbance. Evaluate at t t(0-) to determine
initial conditions v(0-) or i(0-) in our case
v(0-) 2V 2) Find forced response (steady
state) after the disturbance t t(8) Voc or
Isc in our case VOC 8V 3) Add the natural
response (Ke-t/?) to the new forced response. Use
initial conditions to calculate K in our case Rt
10,000 and C2?F so RtC has value of 20 and
units of milliseconds
41
What is meaning of this new equation?
  • Lets plot a few points.

When does steady state occur With respect to RtC?
42
WITH AN INDUCTOR
t 0
R1
R2
R3
i(t)
L
vs
Why ?
LC8 Give your answer
43
Norton equivalent at t0
Why ?
KCL
44
SOLUTION
45
so complete response is
  • complete response i(t)
  • forced response (steady state) Isc
  • natural response (transient)
  • (i(0-) isc) et(Rt/L)) NOTE ?L/Rt

46
Figure 8.3-5(a) A first-order circuit and (b) an
equivalent circuit that is valid after the switch
closes. (c) A plot of the complete response.
47
Lets Practice getting the CR
  • Determine what equation to use
  • Determine initial condition
  • Determine steady state condition
  • Determine Rt
  • Solve

48
Figure E8.3-1 (p. 308)
49
Figure E8.3-2 (p. 309)
50
Figure E8.3-3 (p. 309)
51
Figure E8.3-4 (p. 309)
52
Figure E8.3-5 (p. 309)
53
Stability of 1st order circuits
  • when ?gt0 the natural response vanishes as t ?8
  • THIS IS A STABLE CIRCUIT
  • when ?lt0 the natural response grows without bound
    as t?8
  • THIS IS AN UNSTABLE CIRCUIT

54
forced response summary
55
Unit step or pulse signal
  • vo(t) A Be-at
  • for t gt 0

56
Example
  • 8.6-2, p. 321-323

57
Figure 8.6-12 (p. 322) The circuit considered
in Example 8.6-2
58
Figure 8.6-13 (p. 322) Circuits used to
calculate the steady-state response (a) before t
0 and (b) after t 0.
59
HANDY CHART
ELEMENT CURRENT VOLTAGE
60
IMPORTANT CONCEPTS FROM CHAPTER 8
  • determining Initial Conditions
  • determining T or N equivalent to simplify
  • setting up differential equations
  • solving for v(t) or i(t)

61
Dont forget HW 7 (test takehome)
  • due tomorrow - Thursday
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