Chapter One - PowerPoint PPT Presentation

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Chapter One

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What is the molarity of the original acetic acid solution? 6. Example 5 (continued) ... The acidic substance in vinegar is acetic acid, HC2H3O2. ... – PowerPoint PPT presentation

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Title: Chapter One


1
Example 1
  • How many mL of 0.200 M NaOH will completely
    neutralize 100 mL 0.250 M H2SO4?

2
Example 2
  • If 40.0 mL of 1.60 M HCl and 60.0 mL of 2.00 M
    NaOH are mixed, what are the molar concentrations
    of Na, Cl, and OH in the resulting solution?

3
Example 3
  • If 100. mL of 1.00 M H3PO4 solution is mixed with
    200. mL of 1.00 M NaOH, what salt is produced,
    and what is its molarity?

4
Example 4 Titration
  • What is the molarity of NaOH solution if 92.0 mL
    of this solution was completely neutralized with
    138 mL of 0.4 M H2SO4 solution?

5
Example 5 Back Titration
  • 74.5 ml of 2.61 M sodium hydroxide is added to
    99.2 ml of acetic acid, and the resulting
    solution is found to be basic. It required 12.7
    ml of 1.25 M sulfuric acid to reach neutrality.
    What is the molarity of the original acetic acid
    solution?

6
Example 5 (continued)
7
Example 6 Titration
  • The acidic substance in vinegar is acetic acid,
    HC2H3O2. When 6.00 g of a certain vinegar was
    titrated with 0.100 M NaOH, 40.11 mL of base had
    to be added to reach the equivalence point. What
    percent by mass of this sample of vinegar is
    acetic acid?

8
Eqivalent Weight
  • One equivalent weight, or equivalent, of acid
    contains 1 mol of hydrogen ions
  • One equivalent weight, or equivalent, of base
    contains 1 mol of hydroxide ions
  • Examples
  • NaOH
  • Ba(OH)2
  • HCl
  • H2SO4

9
Normality
10
Example 7
  • 666 g of Ba(OH)2 is dissolved in 3 L of water.
    Calculate the normality of the solution.

11
Example 8
  • Calculate the normality of a solution of H3PO4 if
    500 mL of the solution react completely with 30 g
    of NaOH.

12
Normality
  • The neutralization (acid-base) reaction can
    typically be presented by the net ionic equation
  • H OH ? H2O
  • Therefore, one equivalent of acid always reacts
    with one equivalent of base, and vice versa
  • equivs. acid equivs. base
  • Vacid Nacid Vbase Nbase

13
Example 9
  • What volume of 3.00N solution of H3PO4 will react
    completely with 750 ml of 2.00N solution of
    Ba(OH)2?

14
Assignments Reminders
  • Read Chapter 11 completely
  • Read Section 4-7 of Chapter 4
  • Extra Review Session 5 to 7 pm on Thursday in
    105 Heldenfels
  • Review Session for Exam 3 515 to 715 pm on
    Sunday in 100 Heldenfels
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