Title: Bioenergetics and Enzymes
1Bioenergetics and Enzymes
Raffinose
2Carbon dioxide reduction is endergonic Glucose
oxidation is exergonic
3In the reaction 2 Na Cl2, 2 Na 2
Cl-, what is being oxidized and what is being
reduced?
- Na is being oxidized, Cl2 is being reduced
- Na is being reduced, Cl2 is being oxidized
- Both Na and Cl2 are being oxidized
- Both Na and Cl2 are being oxidized
4First law The energy content of the universe is
constant. Second law In all energy
transformations, entropy (disorder) increases
5Solar into chemical potential energy
chemical potential into kinetic energy
chemical potential into gradient energy
chemical potential into gradient energy
chemical potential into light energy
Kinetic into heat energy
6Entropy can decrease (order increase) in an open
system
7Biological organisms decrease entropy as they
develop (become more ordered), but in all energy
transformations, entropy increases! Therefore
biological organisms (cells) do not obey the
second law of thermodynamics (which says that
entropy increases).
8G Gibbs free energy H enthalpy (bond
energy) S entropy (disorder)
9Gibbs free energy (G)
- Free energy is a useful concept because it is an
easy-to-measure indicator of whether or not
chemical reactions are capable of occurring
(going to the right) spontaneously. - Free energy decreases in spontaneous (exergonic)
reactions. Energy is released by the reaction. - Free energy increases in reactions that cannot
occur spontaneously (endergonic). Energy has to
be put into the reaction to make it go forward
(to the right).
10I Heart Cell Bio
11(No Transcript)
121138 a.m. EST on Jan. 28, 1986 Space shuttle
Challenger
Space Shuttle Booster Rocket O-Ring
13- The change in free energy for an reaction can be
measured if we know - the Keq of the reaction
- the molar concentration of reactants and
products. - the temperature.
14(No Transcript)
15Standard conditions 1 M and STP
Starting at standard conditions, the reaction
will go to the right (exergonic) or to the left
(endergonic) to attain equilibrium.
16The standard free energy change for a reaction
with a Keq 1 is
17The standard free energy change for a reaction
with a Keq gt 1 is
18Exergonic Endergonic
19(No Transcript)
20Standard conditions never prevail in the cell.
The standard free energy change is used to
calculate the free energy change at non-standard
conditions.
21non-standard conditions
This is a very important equation for cell
biologists since it allows one to predict the
direction of a chemical reaction from the actual
starting conditions that prevail in the cell.
22Which equation is used to determine if a reaction
in the cell will go forward?
23What is the meaning of a positive
- Reaction goes spontaneously to the left from
standard conditions - Reaction goes spontaneously to the left from
standard conditions - Reaction goes spontaneously to the left from
prevailing conditions - Reaction goes spontaneously to the right from
prevailing conditions
24An exergonic reaction can drive an endergonic
reaction if the two reactions are coupled on the
surface of an enzyme.
The delta Gs are additive.
25The standard free energy change for the complete
oxidation of glucose is -686 kcal/mole. In
respiration, this oxidation is coupled to the
production of 30 ATPs. What is the standard free
energy change for the oxidation of glucose in the
cell?
- -686 kcal/mole
- -686 kcal/mole 30 (-7.3 kcal/mole)
- -686 kcal/mole 30 (7.3 kcal/mole)
- -686 kcal/mole - 30 (-7.3 kcal/mole)
26(No Transcript)
27(No Transcript)
28What does an enzyme do to the standard free
energy change of a reaction it catalyzes?
- Increases it
- Decreases it
- Nothing
29Product
Transition state
Substrate
Insert 5-8
30(No Transcript)
31Picasso, Woman Seated in a Chair, 1941
32In the foregoing demonstration, what did the
chair represent?
- Product
- Reactant
- Enzyme
- Transition state
33Michaelis and Menten
- Learning how enzymes work
- from observing their kinetic behavior
34Initial velocity vo
Vo
y ax2 bx c dy/dx 2ax b at x0, dy/dx b
35Initial velocity vo
Vo
36E S ES E P
k1
k3
k2
- k1, k2, and k3 are rate constants (k4 is ignored)
- k1, k2, and k3 are related to the affinity of the
enzyme for its substrate - high k1 means high affinity
- high k2 and k3 means low affinity
- KM (k2 k3)/k1 (low KM high affinity)
- k3 is the turnover number (the maximal rate of
product formation) - k3.ET VMAX
37(No Transcript)
38(No Transcript)
39saturation
40(No Transcript)
41Common sense definitions
- VMAX
- the highest rate that a given concentration of
enzyme can work - the rate of product formation when the active
site of the enzyme is saturated - KM
- the substrate concentration at which the vo is
half-maximal - the substrate concentration at which the active
site is half-saturated (filled half the time) - An approximation of the affinity of the substrate
for the active site high KM means low affinity
and vice versa
42The Michaelis-Menten equation
o
- vo increases as S increases
- at infinite S, vo equals VMAX
- as KM increases (affinity decreases), vo
decreases
43Which of the following is false?
- At VMAX, the active site is saturated
- At VMAX, the reaction is at equilibrium
- At KM, the active site is half saturated.
- KM is inversely proportional to the affinity of
the active site for its substrate.
44The affinity of the active site for the substrate
is the sum of all the bonds holding S in place
Cyclic AMP substrate
Phosphodiesterase enzyme
45Aminoacyl-tRNA synthetases add amino acids to
tRNA. Valine and threonine are two structurally
similar amino acids. What is the difference
between the bindings site of A)
valyl-tRNA-synthetase and B) threonyl-tRNA-synthet
ase?
- A has 1 polar binding site and 3 non-polar
binding sites B has 2 and 2. - A has 2 polar binding site and 2 non-polar
binding sites B has 1 and 3. - A has 2 polar binding site and 2 non-polar
binding sites B has 3 and 1. - A has 3 polar binding site and 1 non-polar
binding sites B has 2 and 2.
46Lineweaver-Burk linear transformation
47(No Transcript)
48Galactokinase catalyzes the phosphorylation of
galactose. The phosphate is from ATP. What is the
KM of galactokinase?
- 0.05 mM
- 0.01 mM
- 10 mM
- 20 mM
49Galactokinase catalyzes the phosphorylation of
galactose. The phosphate is from ATP. What is the
VMAX of galactokinase?
- 0.1 umole/min
- 0.05 umole/min
- 10 umole/min
- 20 umole/min
50Km is increased, Vmax is unchanged
Km is unchanged, Vmax is reduced
51Example of competitive inhibitors
ethanol ethylene glycol
Oxidized by alcohol dehydrogenase to pyruvate
Oxidized by alcohol dehydrogenase to toxic
oxalate which can cause kidney failure
52Example of non-competitive inhibitors
Heavy metals (lead, mercury) bind sulfhydral
groups (cysteine residues) outside of the active
site and change the conformation of the enzyme,
making it totally inactive
Remember that Vmax k3Et
A house painter affected by chronic lead
poisoning. Wasted muscles and wrist drop are
tell-tale symptoms of lead poisoning.
53Lineweaver-Burk linear transformation
Competitive inhibitor
Non-competitive inhibitor
54Two more important ways enzyme (protein) activity
can be controlled by the cell
- Allosterism Different shape. Quaternary
structure. An allosteric subunit binds an
allosteric effector and changes the shape of the
catalytic subunit. KM is changed. - Phosphorylation The addition of phosphate groups
from ATP increases or decreases the Vmax of a
protein.
55(No Transcript)
56(No Transcript)