Thorie Financire 20052006 2' Valeur actuelle

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Thorie Financire 20052006 2' Valeur actuelle

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Suppose that the price of a 5-year zero-coupon with face value equal to 100 is 75. ... Example: 20-year mortgage. Annual payment = 25,000. Borrowing rate = 10 ... – PowerPoint PPT presentation

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Title: Thorie Financire 20052006 2' Valeur actuelle


1
Théorie Financière2005-20062. Valeur actuelle
  • Professeur André Farber

2
Present Value general formula
  • Cash flows C1, C2, C3, ,Ct, CT
  • Discount factors DF1, DF2, ,DFt, , DFT
  • Present value PV C1 DF1 C2 DF2
    CT DFT
  • An example
  • Year 0 1 2 3
  • Cash flow -100 40 60 30
  • Discount factor 1.000 0.9803 0.9465 0.9044
  • Present value -100 39.21 56.79 27.13
  • NPV - 100 123.13 23.13

3
Using prices of U.S. Treasury STRIPS
  • Separate Trading of Registered Interest and
    Principal of Securities
  • Prices of zero-coupons
  • Example Suppose you observe the following prices
  • Maturity Price for 100 face value
  • 1 98.03
  • 2 94.65
  • 3 90.44
  • 4 86.48
  • 5 80.00
  • The market price of 1 in 5 years is DF5 0.80
  • NPV - 100 150 0.80 - 100 120 20

4
Present value and discounting
  • How much would an investor pay today to receive
    Ct in t years given market interest rate rt?
  • We know that 1 0 gt (1rt)t t
  • Hence PV ? (1rt)t Ct gt PV Ct/(1rt)t
    Ct ? DFt
  • The process of calculating the present value of
    future cash flows is called discounting.
  • The present value of a future cash flow is
    obtained by multiplying this cash flow by a
    discount factor (or present value factor) DFt
  • The general formula for the t-year discount
    factor is

5
Spot interest rates
  • Back to STRIPS. Suppose that the price of a
    5-year zero-coupon with face value equal to 100
    is 75.
  • What is the underlying interest rate?
  • The yield-to-maturity on a zero-coupon is the
    discount rate such that the market value is equal
    to the present value of future cash flows.
  • We know that 75 100 DF5 and DF5
    1/(1r5)5
  • The YTM r5 is the solution of
  • The solution is
  • This is the 5-year spot interest rate

6
Term structure of interest rate
  • Relationship between spot interest rate and
    maturity.
  • Example
  • Maturity Price for 100 face value YTM (Spot
    rate)
  • 1 98.03 r1 2.00
  • 2 94.65 r2 2.79
  • 3 90.44 r3 3.41
  • 4 86.48 r4 3.70
  • 5 80.00 r5 4.56
  • Term structure is
  • Upward sloping if rt gt rt-1 for all t
  • Flat if rt rt-1 for all t
  • Downward sloping (or inverted) if rt lt rt-1 for
    all t

7
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8
Using one single discount rate
  • When analyzing risk-free cash flows, it is
    important to capture the current term structure
    of interest rates discount rates should vary
    with maturity.
  • When dealing with risky cash flows, the term
    structure is often ignored.
  • Present value are calculated using a single
    discount rate r, the same for all maturities.
  • Remember this discount rate represents the
    expected return.
  • Risk-free interest rate Risk premium
  • This simplifying assumption leads to a few useful
    formulas for
  • Perpetuities (constant or growing at a constant
    rate)
  • Annuities (constant or growing at a constant
    rate)

9
Constant perpetuity
Proof PV C d C d² C d3 PV(1r) C C
d C d² PV(1r) PV C PV C/r
  • Ct C for t 1, 2, 3, .....
  • Examples Preferred stock (Stock paying a fixed
    dividend)
  • Suppose r 10 Yearly dividend 50
  • Market value P0?
  • Note expected price next year
  • Expected return

10
Growing perpetuity
  • Ct C1 (1g)t-1 for t1, 2, 3, .....
    rgtg
  • Example Stock valuation based on
  • Next dividend div1, long term growth of dividend
    g
  • If r 10, div1 50, g 5
  • Note expected price next year
  • Expected return

11
Constant annuity
  • A level stream of cash flows for a fixed numbers
    of periods
  • C1 C2 CT C
  • Examples
  • Equal-payment house mortgage
  • Installment credit agreements
  • PV C DF1 C DF2 C DFT
  • C DF1 DF2 DFT
  • C Annuity Factor
  • Annuity Factor present value of 1 paid at the
    end of each T periods.

12
Constant Annuity
  • Ct C for t 1, 2, ,T
  • Difference between two annuities
  • Starting at t 1 PVC/r
  • Starting at t T1 PV C/r 1/(1r)T
  • Example 20-year mortgage
  • Annual payment 25,000
  • Borrowing rate 10
  • PV ( 25,000/0.10)1-1/(1.10)20 25,000 10
    (1 0.1486)
  • 25,000 8.5136
  • 212,839

13
Growing annuity
  • Ct C1 (1g)t-1 for t 1, 2, , T r ? g
  • This is again the difference between two growing
    annuities
  • Starting at t 1, first cash flow C1
  • Starting at t T1 with first cash flow C1
    (1g)T
  • Example What is the NPV of the following project
    if r 10?
  • Initial investment 100, C1 20, g 8, T 10
  • NPV 100 20/(10 - 8)1 (1.08/1.10)10
  • 100 167.64
  • 67.64

14
Useful formulas summary
  • Constant perpetuity Ct C for all t
  • Growing perpetuity Ct Ct-1(1g)
  • rgtg t 1 to 8
  • Constant annuity CtC t1 to T
  • Growing annuity Ct Ct-1(1g)
  • t 1 to T

15
Compounding interval
  • Up to now, interest paid annually
  • If n payments per year, compounded value after 1
    year
  • Example Monthly payment
  • r 12, n 12
  • Compounded value after 1 year (1 0.12/12)12
    1.1268
  • Effective Annual Interest Rate 12.68
  • Continuous compounding
  • 1(r/n)n?er (e 2.7183)
  • Example r 12 e12 1.1275
  • Effective Annual Interest Rate 12.75

16
Juggling with compounding intervals
  • The effective annual interest rate is 10
  • Consider a perpetuity with annual cash flow C
    12
  • If this cash flow is paid once a year PV 12 /
    0.10 120
  • Suppose know that the cash flow is paid once a
    month (the monthly cash flow is 12/12 1 each
    month). What is the present value?
  • Solution 1
  • Calculate the monthly interest rate (keeping EAR
    constant)
  • (1rmonthly)12 1.10 ? rmonthly 0.7974
  • Use perpetuity formula
  • PV 1 / 0.007974 125.40
  • Solution 2
  • Calculate stated annual interest rate 0.7974
    12 9.568
  • Use perpetuity formula PV 12 / 0.09568
    125.40

17
Interest rates and inflation real interest rate
  • Nominal interest rate 10 Date 0 Date 1
  • Individual invests 1,000
  • Individual receives 1,100
  • Hamburger sells for 1 1.06
  • Inflation rate 6
  • Purchasing power ( hamburgers) H1,000 H1,038
  • Real interest rate 3.8
  • (1Nominal interest rate) (1Real interest
    rate)(1Inflation rate)
  • Approximation
  • Real interest rate Nominal interest rate -
    Inflation rate

18
Bond Valuation
  • Objectives for this session
  • 1.Introduce the main categories of bonds
  • 2.Understand bond valuation
  • 3.Analyse the link between interest rates and
    bond prices
  • 4.Introduce the term structure of interest rates
  • 5.Examine why interest rates might vary according
    to maturity

19
Zero-coupon bond
  • Pure discount bond - Bullet bond
  • The bondholder has a right to receive
  • one future payment (the face value) F
  • at a future date (the maturity) T
  • Example a 10-year zero-coupon bond with face
    value 1,000
  • Value of a zero-coupon bond
  • Example
  • If the 1-year interest rate is 5 and is assumed
    to remain constant
  • the zero of the previous example would sell for

20
Level-coupon bond
  • Periodic interest payments (coupons)
  • Europe most often once a year
  • US every 6 months
  • Coupon usually expressed as of principal
  • At maturity, repayment of principal
  • Example Government bond issued on March 31,2000
  • Coupon 6.50
  • Face value 100
  • Final maturity 2005
  • 2000 2001 2002 2003 2004 2005
  • 6.50 6.50 6.50 6.50 106.50

21
Valuing a level coupon bond
  • Example If r 5
  • Note If P0 gt F the bond is sold at a premium
  • If P0 ltF the bond is sold at a
    discount
  • Expected price one year later P1 105.32
  • Expected return 6.50 (105.32
    106.49)/106.49 5

22
When does a bond sell at a premium?
  • Notations C coupon, F face value, P price
  • Suppose C / F gt r
  • 1-year to maturity
  • 2-years to maturity
  • As P1 gt F

with
23
A level coupon bond as a portfolio of zero-coupons
  • Cut level coupon bond into 5 zero-coupon
  • Face value Maturity Value
  • Zero 1 6.50 1 6.19
  • Zero 2 6.50 2 5.89
  • Zero 3 6.50 3 5.61
  • Zero 4 6.50 4 5.35
  • Zero 5 106.50 5 83.44
  • Total 106.49

24
Law of one price
  • Suppose that you observe the following data

What are the underlying discount factors?
Bootstrap method
100.97 DF1 104105.72 DF1 7 DF2
107101.56 DF1 5.5 DF2 5.5 DF3
105.5
25
Bond prices and interest rates
Bond prices fall with a rise in interest rates
and rise with a fall in interest rates
26
Sensitivity of zero-coupons to interest rate
27
Duration for Zero-coupons
  • Consider a zero-coupon with t years to maturity
  • What happens if r changes?
  • For given P, the change is proportional to the
    maturity.
  • As a first approximation (for small change of r)

Duration Maturity
28
Duration for coupon bonds
  • Consider now a bond with cash flows C1, ...,CT
  • View as a portfolio of T zero-coupons.
  • The value of the bond is P PV(C1) PV(C2)
    ... PV(CT)
  • Fraction invested in zero-coupon t wt PV(Ct) /
    P
  • Duration weighted average maturity of
    zero-coupons
  • D w1 1 w2 2 w3 3wt t wT T

29
Duration - example
  • Back to our 5-year 6.50 coupon bond.
  • Face value Value wt
  • Zero 1 6.50 6.19 5.81
  • Zero 2 6.50 5.89 5.53
  • Zero 3 6.50 5.61 5.27
  • Zero 4 6.50 5.35 5.02
  • Zero 5 106.50 83.44 78.35
  • Total 106.49
  • Duration D .05811 0.05532 .0527 3
    .0502 4 .7835 5
  • 4.44
  • For coupon bonds, duration lt maturity

30
Price change calculation based on duration
  • General formula
  • In example Duration 4.44 (when r5)
  • If ?r 1 ? 4.44 1 - 4.23
  • Check If r 6, P 102.11
  • ?P/P (102.11 106.49)/106.49 - 4.11

Difference due to convexity
31
Duration -mathematics
  • If the interest rate changes
  • Divide both terms by P to calculate a percentage
    change
  • As
  • we get

32
Yield to maturity
  • Suppose that the bond price is known.
  • Yield to maturity implicit discount rate
  • Solution of following equation
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