Loop Analysis 3.2 Circuits with OpAmps 3.3 - PowerPoint PPT Presentation

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Loop Analysis 3.2 Circuits with OpAmps 3.3

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Op Amp is short for operational amplifier. ... A Mixer Circuit. v2. vout. R2. Rf. R1. v1. lecture 9. 22. KCL at the Inverting Input. v2. vout ... – PowerPoint PPT presentation

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Title: Loop Analysis 3.2 Circuits with OpAmps 3.3


1
Loop Analysis (3.2)Circuits with Op-Amps (3.3)
  • Prof. Phillips
  • February 19, 2003

2
Op Amps
  • Op Amp is short for operational amplifier.
  • An operational amplifier is modeled as a voltage
    controlled voltage source.
  • An operational amplifier has a very high input
    impedance and a very high gain.

3
Use of Op Amps
  • Op amps can be configured in many different ways
    using resistors and other components.
  • Most configurations use feedback.

4
Applications of Op Amps
  • Amplifiers provide gains in voltage or current.
  • Op amps can convert current to voltage.
  • Op amps can provide a buffer between two
    circuits.
  • Op amps can be used to implement integrators and
    differentiators.
  • Lowpass and bandpass filters.

5
The Op Amp Symbol
High Supply
Non-inverting input
Output
Inverting input
Ground
Low Supply
6
The Op Amp Model
v
Non-inverting input

vo
Rin


Inverting input
A(v -v- )
v-
7
Typical Op Amp
  • The input resistance Rin is very large
    (practically infinite).
  • The voltage gain A is very large (practically
    infinite).

8
Ideal Op Amp
  • The input resistance is infinite.
  • The gain is infinite.
  • The op amp is in a negative feedback
    configuration.

9
The Basic Inverting Amplifier
R2
R1




Vin
Vout

10
Consequences of the Ideal
  • Infinite input resistance means the current into
    the inverting input is zero
  • i- 0
  • Infinite gain means the difference between v and
    v- is zero
  • v - v- 0

11
Solving the Amplifier Circuit
  • Apply KCL at the inverting input
  • i1 i2 i-0

R2
i2
R1

i1
i-
12
KCL
13
Solve for vout
  • Amplifier gain

14
Recap
  • The ideal op-amp model leads to the following
    conditions
  • i- 0 i
  • v v-
  • These conditions are used, along with KCL and
    other analysis techniques, to solve for the
    output voltage in terms of the input(s).

15
Where is the Feedback?
R2
R1




Vin
Vout

16
Review
  • To solve an op-amp circuit, we usually apply KCL
    at one or both of the inputs.
  • We then invoke the consequences of the ideal
    model.
  • The op amp will provide whatever output voltage
    is necessary to make both input voltages equal.
  • We solve for the op-amp output voltage.

17
The Non-Inverting Amplifier




vin
vout
R2
R1

18
KCL at the Inverting Input




i-
vin
vout
i1
i2
R2
R1

19
KCL
20
Solve for Vout
21
A Mixer Circuit
Rf
R1
R2

v1




v2
vout

22
KCL at the Inverting Input
Rf
R1
i1
if
R2

v1
i2

i-



v2
vout

23
KCL
24
KCL
25
Solve for Vout
26
Class Example
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