Title: Bonding and Molecular Structure:
1Chapter 10
- Bonding and Molecular Structure
- Orbital Hybridization and
- Molecular Orbitals
2Goals
- Understand the differences between valence bond
theory and molecular orbital theory. - Identify the hybridization of an atom in a
molecule or ion. - Understand the differences between bonding and
antibonding molecular orbitals. - Write the molecular orbital configuration for
simple diatomic molecules.
3Orbitals and Bonding Theories
- VSEPR Theory only explains molecular shapes.
- It says nothing about bonding in molecules
- In Valence Bond (VB) Theory (Linus Pauling)
- atoms share electron pairs by allowing their
- atomic orbitals to overlap.
- Another approach to rationalize chemical
- bonding is the Molecular Orbital (MO) Theory
- (Robert Mulliken) molecular orbitals are spread
- out or delocalized over the molecule.
4Valence Bond (VB) Theory
- Covalent bonds are formed by the overlap of
- atomic orbitals.
- Atomic orbitals on the central atom can mix and
- exchange their character with other atoms in a
- molecule.
- Process is called hybridization.
- Hybrids are common
- Pink flowers
- Mules
- Hybrid Orbitals have the same shapes as
- predicted by VSEPR.
51s
1s
H
H
? bond
61s
1s
H
H
E
1s
H
? bond
7H
H
H
E
1s
H
? bond
82p
2p
F
F
? bond
F2
92p
E
2s
1s
F
10F
2p
E
2s
1s
F
11Methane
CH4
2p
E
2s
1s
C
12Methane
CH4
H
H
2p
E
2s
1s
C
13Methane
CH4
H
H
H
2p
E
2s
1s
C
14Methane
CH4
H
H
H
H
2p
E
2s
1s
C
15Methane
CH4
H
H
H
H
2p
H
E
90
2s
H
C
H
90
H
1s
C
16Methane
CH4
H
109.5
C
H
H
H
Tetrahedral Geometry 4 Identical Bonds
17Problem and Solution
- C must have 4 identical orbitals in valence shell
for bonding - solution hybridization
18Methane
CH4
2p
E
2s
1s
19Methane
CH4
2s
2p
2p
E
E
2s
1s
1s
20Methane
CH4
2s
2p
2p
E
E
2s
1s
1s
21Methane
CH4
2s
2p
2p
E
E
2s
1s
1s
22Methane
CH4
2p
sp3
E
E
2s
1s
1s
232p
2s
242p
Three
2s
four sp3 hybrid orbitals
254 identical sp3 hybrid orbitals they are four
because there was the combination of one s and
three p atomic orbitals (25 s, 75 p)
tetrahedral geometry
26Methane
CH4
H
H
H
H
2p
sp3
E
E
2s
1s
1s
27Valence Bond (VB) Theory
28Predict the Hybridization of the Central Atom
in aluminum bromide
?
?
?
?
Br
?
?
Electron-pair shape trigonal planar
3 regions
Al
?
?
?
?
Br
Br
?
?
?
?
?
?
?
?
Hybridization sp2
29Trigonal Planar Electronic Geometry, sp2
- Electronic Structures BF3
-
1s 2s 2p B ??????????? ?
1s sp2 hybrid ??? ?????? ??? ??? ?
1s 2s 2p 2p B ?????? ????
? ?
2s 2p F He ????????????
30Trigonal Planar Electronic Geometry, sp2
31Predict the Hybridization of the Central Atom
in carbon dioxide
CO2
?
?
?
?
O
C
O
?
?
?
?
2 regions
Electron-pair shape, linear
Hybridization sp (50 s, 50 p)
32Linear Electronic Geometry, sp
- Electronic Structures BeCl2
-
1s 2s 2p Be ???????????
1s sp hybrid ? ?? ? ?
3s 3p Cl Ne ????????????
33Predict the Hybridization of the Central Atom in
Beryllium Chloride
- Two regions electron-pair shape
- sp hybridization
34Predict the Hybridization of the Central Atom in
PF5
- Five regions Trigonal Bipyramidal Electronic
- Geometry - sp3d hybridization,
- five sp3d hybrid orbitals
35Predict the Hybridization of the Central Atom
in xenon tetrafluoride
36Predict the Hybridization of the Central Atom
in xenon tetrafluoride
?
?
?
?
?
?
F
F
?
?
?
?
6 regions electron-pair shape octahedral
?
?
?
?
Xe
?
?
?
?
?
?
?
?
F
F
?
?
?
?
?
?
37Predict the Hybridization of the Central Atom
in xenon tetrafluoride
?
?
?
?
?
?
F
F
?
?
?
?
6 regions electron-pair shape octahedral
?
?
?
?
Xe
?
?
?
?
?
?
?
?
F
F
?
?
?
?
?
?
sp3d2
38Predict the Hybridization of the Central Atom in
SF6
- Six regions Octahedral Electronic Geometry
- - sp3d2 hybridization,
- six sp3d2 hybrid orbitals
39Consider Ethylene, C2H4
40Consider Ethylene, C2H4
H
H
C
C
H
H
41Consider Ethylene, C2H4
H
H
C
C
H
H
3 regions
trigonal planar
42Consider Ethylene, C2H4
H
H
C
C
H
H
3 regions
trigonal planar
sp2
43Consider Ethylene, C2H4
H
H
C
C
H
H
3 regions
trigonal planar
sp2
442p
E
2s
1s
452s
2p
2p
E
E
2s
1s
1s
462p
2p
sp2
E
E
2s
1s
1s
47sp2
2p
sp2
sp2
482p
sp2
sp2
sp2
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51? bond framework
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54? bond
55? bond
56Compounds Containing Double Bonds
- Thus a CC bond looks like this and is made
- of two parts, one ? and one ? bond.
57Consider Acetylene, C2H2
C
H
H
C
58Consider Acetylene, C2H2
C
H
H
C
2 regions
linear
59Consider Acetylene, C2H2
C
H
H
C
2 regions
linear
sp hybridization
60Consider Acetylene, C2H2
C
H
H
C
2 regions
linear
sp hybridization
612s
2p
2p
E
E
2s
1s
1s
622p
2p
sp
E
E
2s
1s
1s
632p
sp
sp
2p
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65? bond framework
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67? bonds
68Compounds Containing Triple Bonds
- A ? bond results from the head-on overlap of
- two sp hybrid orbitals.
- The unhybridized p orbitals form two p bonds
(side-on overlap of atomic orbitals.) - Note that a triple bond consists of one ? and
- two p bonds.
69? bonds
70Generally
- single bond is a ? bond
- double bond consists of 1 ? and 1 ? bond
- triple bond consists of 1 ? and 2 ? bonds
71Molecular Orbital (MO) Theory
- when atoms combine to form molecules, atomic
orbitals overlap and are then combined to form
molecular orbitals - of orbitals are conserved
- a molecular orbital is an orbital associated with
more than 1 nucleus - like any other orbital, an MO can hold 2
electrons - consider hydrogen atoms bonding to form H2
72Molecular Orbital Theory
- Combination of atomic orbitals on different atoms
forms molecular orbitals (MOs) so that electrons
in MOs belong to the molecule as a whole. - Waves that describe atomic orbitals have both
positive and negative phases or amplitudes. - As MOs are formed the phases can interact
constructively or destructively.
73Molecular Orbitals
- There are two simple types of molecular
- orbitals that can be produced by the overlap
- of atomic orbitals.
- Head-on overlap of atomic orbitals
- produces ? (sigma) orbitals.
- Side-on overlap of atomic orbitals
- produces ? (pi) orbitals.
- Two 1s atomic orbitals that overlap produce
- two molecular orbitals designated as
- ?1s or bonding molecular orbital
- ?1s or antibonding molecular orbital.
74H
H
75subtract
add
76subtract
antibonding
add
bonding
77subtract
antibonding
??1s
add
?1s
bonding
78Molecular Orbital Energy Level Diagram
- Now that we have seen what these MOs look
- like and a little of their energetics, how are
- the orbitals filled with electrons?
- Order of filling of MOs obeys same rules as
- for atomic orbitals.
- Including
- Aufbau principle increasing energy
- Hunds Rule two unaligned e- per orbital
- Thus the following energy level diagram
- results for the homonuclear diatomic
- molecules H2 and He2.
79??1s
E
E
1s
1s
?1s
H
H2
H
80??1s
E
E
1s
1s
?1s
H
H2
H
81??1s
E
E
1s
1s
?1s
H
H2
H
82??1s
E
E
1s
1s
?1s
H
H2
H
83(?1s ) 2
??1s
E
E
1s
1s
?1s
H
H2
H
84(?1s ) 2
total spin 0
??1s
E
E
1s
1s
?1s
H
H2
H
85- Diamagnetic slightly repelled by a magnetic
field - total spin 0
- paramagnetic attracted to a magnetic field
- total spin not 0
- (bonding e
antibonding e) - Bond Order --------------------
-
2
86Bond Order and Bond Stability
- The larger the bond order, the more stable the
- molecule or ion is.
- Bond order 0 implies there are equal numbers of
electrons in bonding and antibonding orbitals, - same stability as separate atoms no bond
formed - Bond order gt 0 implies there are more electrons
in bonding than antibonding orbitals. - Molecule is more stable than separate atoms.
- The greater the bond order, the shorter the bond
- length and the greater the bond energy.
87(?1s ) 2
total spin 0
diamagnetic
??1s
E
E
1s
1s
?1s
H
H2
H
88BO 1/2 ( 2 0) 1
??1s
E
E
1s
1s
?1s
H
H2
H
89Consider He2
90??1s
E
E
1s
1s
?1s
He
He2
He
91??1s
E
E
1s
1s
?1s
He
He2
He
92(?1s ) 2
(? 1s ) 2
??1s
E
E
1s
1s
?1s
He
He2
He
93diamagnetic
??1s
E
E
1s
1s
?1s
He
He2
He
94BO 1/2 ( 2 2 ) 0 He2 does not exist
??1s
E
E
1s
1s
?1s
He
He2
He
95Combination of p Atomic Orbitals
96Molecular Orbitals
- The head-on overlap of two corresponding p
- atomic orbitals on different atoms, say 2px
- with 2px produces
- ?2px bonding orbital
- ?2px antibonding orbital
972p
2p
98subtract
add
99antibonding MO
subtract
add
bonding MO
100antibonding MO
? 2p
subtract
add
bonding MO
? 2p
101Molecular Orbitals
- Side-on overlap of two corresponding p
- atomic orbitals on different atoms (say 2py
- with 2py or 2pz with 2pz) produces
- or (both are bonding orbitals)
- or (both are nonbonding orbitals)
1022p
2p
103subtract
add
104subtract
antibonding MO
add
bonding MO
105subtract
??2p
add
?2p
106subtract
??2p
add
?2p
107Consider Li2
108??2p
?2p
2p
2p
?2p
E
E
?2p
??2s
2s
2s
?2s
Li
Li
Li2
109??2p
?2p
2p
2p
?2p
E
E
?2p
??2s
2s
2s
?2s
Li
Li
Li2
110??2p
?2p
2p
2p
?2p
E
E
?2p
??2s
2s
2s
?2s
Be
Be
Be2
111??2p
?2p
2p
2p
?2p
E
E
?2p
??2s
2s
2s
?2s
Be
Be
Be2
112??2p
?2p
2p
2p
?2p
E
E
?2p
??2s
2s
2s
?2s
B
B
B2
113??2p
?2p
2p
2p
?2p
E
E
?2p
??2s
2s
2s
?2s
B
B
B2
114??2p
?2p
2p
2p
?2p
E
E
?2p
??2s
2s
2s
?2s
C
C
C2
115??2p
?2p
2p
2p
?2p
E
E
?2p
??2s
2s
2s
?2s
N
N
N2
116Homonuclear Diatomic Molecules
- In shorthand notation we represent the
- configuration of N2 as
117Bond Order of N2
- The greater the bond order of a bond the
- more stable we predict it to be.
- For N2 the bond order is
118??2p
?2p
2p
2p
E
E
?2p
??2s
2s
2s
?2s
O
O
O2
119Homonuclear Diatomic Molecules
- In shorthand notation we represent the
- configuration of O2 as
- We can see that O2 is a paramagnetic
- molecule (two unpaired electrons).
120??2p
?2p
2p
2p
E
E
?2p
??2s
2s
2s
?2s
F
F
F2
121??2p
?2p
2p
2p
E
E
?2p
??2s
2s
2s
?2s
Ne
Ne
Ne2
122Bond Order for Ne2
- 2?4 - 2?4
- BO ------- 0
- 2
- We can see that Ne2 is not stable. It does not
- exist
123Delocalization and Shapes of Molecular Orbitals
- Molecular orbital theory describes
- shapes in terms of delocalization of
- electrons.
- Carbonate ion (CO32-) is a good example.
- VB Theory MO Theory
124Delocalization and Shapes of Molecular Orbitals
- Benzene, C6H6, Resonance structure - VB theory
125Delocalization and Shapes of Molecular Orbitals
- This is the picture of the valence bond
- (VB) theory
126Delocalization and Shapes of Molecular Orbitals
- The structure of benzene is described
- well by molecular orbital theory.