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Bell work

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There is an equal amount of reactants and products present ... Ho is the standard enthalpy change for the forward reaction. R is the gas constant (8.31 J/mol*k) ... – PowerPoint PPT presentation

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Title: Bell work


1
Bell work
  • What comes to mind when you hear equilibrium?

2
Chemical equilibrium
3
12-1 and 12-2 Chemical Equilibrium
  • Equilibrium
  • There is an equal amount of reactants and
    products present
  • Total amount of particles remain the same
  • Law of conservation of mass
  • It is dynamic
  • When a state of equilibrium is reached, the rate
    of the forward process is equal to the rate of
    the reverse process
  • As reactants are converted to products, the same
    amount of products are converted back to reactants

4
Chemical Equilibrium
  • Reactions usually flow from left to right
  • Some reactions can flow either way
  • Call reversible reactions
  • If the reactants and products are kept in a
    closed system where nothing can escape, the
    reactants may go in either direction
  • Write a reversible reaction with two arrows
  • Explains why cold packs can be reused
  • Reversing the reaction breaks apart the products
    and reforms the reactants

5
At chemical equilibrium
  • 2SO2 (g) O2 (g) 2 SO3 (g)
  • Forward rate reverse rate
  • What happens to the reaction rate?
  • Does the reaction stop completely?

6
Liquid-vapor equilibrium
  • A volatile liquid in a closed system will be in
    equilibrium with its vapor above it.
  • H2O (l) ?? H2O (g)
  • Molecules change form back and forth at the same
    rate
  • The reaction does not stop
  • Rates are the same of the opposite processes
  • Amount of liquid and gas molecules will remain
    constant

7
How is equilibrium measured?
  • The equilibrium constant Keq
  • Remember at equilibrium, the reactants continue
    to form the products, and the products are
    reacting to re-form the reactants at the same
    rate
  • At equilibrium, the forward rate (ratef) equals
    the reverse rate (rater)
  • Keq Kforward product
  • ----------- -------------
  • Kreverse reactant

8
12.2 and 12.3 Keq quantitatively describes
equilibrium
  • The equilibrium constant is the ratio (at
    equilibrium) of the mathematical product of the
    concentrations of the products to the
    mathematical product of the concentrations of the
    reactants
  • The concentrations (mols/L) are raised to the
    power of the coefficients in a balanced equation
  • aA bB ?? cC dD
  • Keq C c D d products /reactants
  • -----------------------
  • A a B b

9
About the Keq
  • Used to tell which direction the reaction is
    going
  • Does not include solids or liquids!
  • Gases and aqueous only

10
What does the Keqtell us?
  • Keq products / reactants
  • Tells us which direction the reaction is
    traveling
  • If the value is 1, the products and the reactant
    concentrations are the same (it is at
    equilibrium)
  • In reactions that have Keq values greater than
    one, the reverse reaction is favored
  • More product is present than reactants
  • In reactions that have Keq values less than one,
    the forward reaction is favored
  • More reactants are present than product

11
Lets do some practice using concentrations
  • H2 (g) O2(g) ? H2O (g)
  • Calculate the Keq if H2 1.0 M
  • O2 2.0 M
  • H2O 1.5 M

12
Practice
  • Nitrogen pentachloride decomposes at 7600C.
  • NCl5(g) ?? NCl3(g) Cl2(g)
  • Keq 3.00 x 10-2
  • What is the concentration of each of the products
    (NCl3 and Cl2) at equilibrium if the
    concentration of NCl5 is 1.5 x 10-3 mol/L and the
    concentration of NCl3 and Cl2 are equal?

13
Answer
  • NCl5(g) ? NCl3(g) Cl2(g)
  • Keq 3.00 x 10-2
  • Keq NCl3 Cl2
  • --------------
  • NCl5
  • 3.00 x 10-2 x x
  • --------------
  • 1.5 x 10-3

14
Answer continued
  • 3.00 x 10-2 x2
  • --------------
  • 1.5 x 10-3
  • x2 (3.00 x 10-2) (1.5 x 10-3)
  • x2 (4.5 x 10-5)
  • X 0.0067 mol/L

15
Bell Work
  • Calculate Keq for the synthesis of ammonia at
    4000C if the following concentrations are present
    at equilibrium.
  • N2(g) H2(g) ? NH3(g)
  • N2 4.5 mol/L
  • H2 1.80 mol/L
  • NH3 3.28 mol/L

16
practice
  • Formamide, HCONH2 is used to manufacture
    agricultural chemicals, dyes, and
    pharmaceuticals. At 1250C formamide decomposes
  • HCONH2(g) ? NH3(g) CO(g)
  • Keq 4.8
  • if the equilibrium concentrations of NH3 and CO
    are both 0.60 mol/L, what is the
  • equilibrium concentration of formamide?

17
practice
  • Example. For the reaction, CO 3H2 ? ? CH4
    H2O, calculate Keq from the following equilibrium
  • concentrations CO 0.0613 M H2 0.1839 M
    CH4 0.0387 M H2O 0.0387 M.

18
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19
review
20
Direction of reaction
  • Reaction Quotient (Q)
  • Same application of Keq to us so far
  • Same expression
  • Q products / reactants

21
Characteristics about K
  • Equilibrium can be approached from either
    direction.
  • K does not depend on the initial concentrations
    of reactants and products.
  • K does depend on temperature.
  • The equilibrium constants for forward and reverse
    reactions are the reciprocals of each other
  • K 1/K
  • Example, K 11, then K 1/11 0.091
  • If a reaction can be expressed as the sum of two
    or more reactions, K for the overall reaction is
    the product of the equilibrium constants of the
    individual reactions
  • Reaction 3 Reaction 1 Reaction 2
  • K(Reaction 3) K(reaction 1) x K(Reaction 2)

22
One more thing about Keq
  • Keq is the equilibrium constant
  • It tells us which way the reaction is occurring
  • Has other names depending on what is happening
  • Also called Kc
  • Constant for molar concentrations
  • Also called Ka
  • When the reaction involves an acidic situation
  • Acid dissociation constant for weak acids
  • Also called Kb
  • When the reaction involves a basic situation
  • Base dissocaition constant for weak bases
  • Also called Kp
  • When all of the reactants and products in the
    reaction are gases so Keq can be expressed in
    terms of partial pressure (atm)
  • Gases can be or pp
  • Also called Ksp
  • When the reaction involves solubility (solubility
    product)
  • Note that no denominator will be used in these
    types of reactions because the reactants are
    solids

23
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24
practice
  • Write the expression for Kp for the following
    reaction
  • CuO (s) H2 (g) ??Cu (s) H2O (g)

25
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26
example
  • For the reaction, 2SO2(g) O2(g) ?? 2SO3(g)
  • Write the equilibrium constant expression, Kp.
  • What is the value for Kp if Kc 2.8x102 at 1000
    K?

27
We can use Ksp to determine solubility, s
  • Solubility the concentration in a saturated
    solution
  • Tells us the maximum amount of solute you can
    dissolve
  • If soluble, high concentration of ions and low
    concentration of reactants
  • Ksp is larger than 1
  • The bigger the ksp, the more soluble the stuff is
  • The smaller the ksp, the less soluble the stuff

28
The position of equilibrium
  • Equilibrium constants vary with temperatures
  • At what temperature are they mostly products at
    equilibrium?
  • T 470 oC
  • N2 3H2 ?? 2 NH3 K 1.0 x 10-1
  • T 25 oC
  • N2 3H2 ?? 2 NH3 K 4.0 x 108
  • The second temperature shows us that they are
    most products at equilibrium

29
Which solid dissolves the most in water (most
soluble)?
  • PbCl2 (s) ?? Pb2 (aq) 2Cl- (aq)
  • K 1.6 x 10-8
  • PbI2 (s) ?? Pb2 (aq) 2I- (aq)
  • K 8.5 x 10-9
  • The first one would dissolve most number is
    bigger

30
Example for you
  • At a temperature of 1000 K, carbon monoxide can
    react with oxygen gas to form carbon dioxide
  • Write a balanced equation for this reaction
  • Write the Keq expression for this reaction
  • The equilibrium constant for this reaction is 2.2
    x 1022. is this reaction expected to be at
    equilibrium or to go to completion?

31
Direction of reaction
  • So far you have solved for the K for equations
  • This tells us what is happening with the reaction
  • Magnitude of K
  • If the K value is large (K gtgt 1), the equilibrium
    lies to the right and the reaction mixture
    contains mostly products.
  • If the K value is small (K ltlt1), the equilibrium
    lies to the left and the reaction mixture
    contains mostly reactants.
  • If the K value is close to 1 (0.10 lt K lt 10), the
    mixture contains appreciable amounts of both
    reactants and products.

32
12.4 - Direction of reaction
  • To solve for the direction of reaction, we need a
    new unit called the reaction quotient (Q)
  • Q has the same expression as k
  • Q products/reactants

33
example
34
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35
12.5 - System equilibrium
  • Equilibrium can favor the formation of reactants
    or products
  • When a system is at equilibrium, it will stay
    that way until something changes this condition
  • Stresses alter the equilibrium
  • Change the location of the equilibrium

36
Le Chateliers principle
  • French chemist Henri Louis Le Chatelier
  • His principle states that when a system at
    equilibrium is disturbed by applying stress, it
    attains a new equilibrium position to accommodate
    the change and relieve the stress
  • What are stresses?
  • Concentration, temperature, or pressure

37
Changing concentration
  • If you add more reactants, the system will shift
    towards the products (right)
  • If you remove reactants (means there is more
    products than reactants now), the system will
    shift towards the reactants (left)
  • If you remove products (means there is more
    reactants than products now), the system will
    shift towards the products (right)

38
Temperature affects equilibrium systems
  • Temperature changes can cause equilibrium shifts
  • An increase in temperature causes the endothermic
    reaction to occur
  • The way the reaction shifts depends on the type
    of reaction
  • Endothermic or exothermic

39
Endothermic
  • Example
  • What does it look like (reaction diagram)
  • If we lower the temperature, what are we doing?
  • By lowering the temperature, one of the products
    (energy) is being removed
  • As the temperature continues to drop, the system
    reacts to relieve the stress

40
Increase temperature
  • Endothermic reaction
  • Add temperature, adding heat energy
  • The system will react in a way to relieve the
    stress and absorbs the heat

41
Exothermic reaction
  • Example
  • Increasing temperature
  • Left shift, more product
  • Decreasing temperature
  • Right shift, more reactants

42
Increase temperature
  • Exothermic reaction
  • Add temperature, adding heat energy
  • The system will react in a way to relieve the
    stress and absorbs the heat

43
Now lets decrease temperature
  • Exothermic
  • Endothermic

44
vant Hoff equation
  • K2 ?Ho 1 1
  • 1n ----- ------ ---- - ----
  • K1 R T1
    T2
  • K2 and K1 are equilibrium constants at T2 and T1
  • ?Ho is the standard enthalpy change for the
    forward reaction
  • R is the gas constant (8.31 J/molk)
  • If the forward reaction is exothermic, K
    decreases as T increases
  • If the forward reaction is endothermic, K
    increases as T increases

45
Pressure changes
  • Gaseous equilibrium systems
  • Compression or expansion
  • Count the number of gas moelcules on each side of
    the equation
  • Compression
  • Increase in pressure will cause the system to
    shift to the side that will form less gas
    moelcules
  • Expansion
  • Decrease in pressure will cause the system to
    shift to the side that will form more gas
    particles

46
Practice
  • Answer the following questions
  • What does Le Chateliers principle say?
  • How does changing the concentration of the
    reactants affect a reaction (according to Le
    Chatelier)?
  • How does increasing pressure affect the reaction?

47
Practice
  • What will happen to the following reactions when
    the various stresses are applied
  • 2 H2 (g) O2 (g) ? 2 H2O (l)
  • 1. More hydrogen is added to the system
  • 2. Oxygen is removed from the system
  • 3. This is exothermic the temperature is
    increased
  • 4. The pressure is increased
  • 5. The pressure is decreased

48
recap
  • Out of the changes talked about with Le Chatelier
  • Adding or removing
  • Compressing or expanding
  • Changing temperature
  • The only one that changes the value of the
    equilibrium constant is a change in temperature
  • In the other two cases, K remains constant
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