Title: Bell work
1Bell work
- What comes to mind when you hear equilibrium?
2Chemical equilibrium
312-1 and 12-2 Chemical Equilibrium
- Equilibrium
- There is an equal amount of reactants and
products present - Total amount of particles remain the same
- Law of conservation of mass
- It is dynamic
- When a state of equilibrium is reached, the rate
of the forward process is equal to the rate of
the reverse process - As reactants are converted to products, the same
amount of products are converted back to reactants
4Chemical Equilibrium
- Reactions usually flow from left to right
- Some reactions can flow either way
- Call reversible reactions
- If the reactants and products are kept in a
closed system where nothing can escape, the
reactants may go in either direction - Write a reversible reaction with two arrows
- Explains why cold packs can be reused
- Reversing the reaction breaks apart the products
and reforms the reactants
5At chemical equilibrium
- 2SO2 (g) O2 (g) 2 SO3 (g)
- Forward rate reverse rate
- What happens to the reaction rate?
- Does the reaction stop completely?
6Liquid-vapor equilibrium
- A volatile liquid in a closed system will be in
equilibrium with its vapor above it. - H2O (l) ?? H2O (g)
- Molecules change form back and forth at the same
rate - The reaction does not stop
- Rates are the same of the opposite processes
- Amount of liquid and gas molecules will remain
constant
7How is equilibrium measured?
- The equilibrium constant Keq
- Remember at equilibrium, the reactants continue
to form the products, and the products are
reacting to re-form the reactants at the same
rate - At equilibrium, the forward rate (ratef) equals
the reverse rate (rater) - Keq Kforward product
- ----------- -------------
- Kreverse reactant
812.2 and 12.3 Keq quantitatively describes
equilibrium
- The equilibrium constant is the ratio (at
equilibrium) of the mathematical product of the
concentrations of the products to the
mathematical product of the concentrations of the
reactants - The concentrations (mols/L) are raised to the
power of the coefficients in a balanced equation - aA bB ?? cC dD
- Keq C c D d products /reactants
- -----------------------
- A a B b
9About the Keq
- Used to tell which direction the reaction is
going - Does not include solids or liquids!
- Gases and aqueous only
10What does the Keqtell us?
- Keq products / reactants
- Tells us which direction the reaction is
traveling - If the value is 1, the products and the reactant
concentrations are the same (it is at
equilibrium) - In reactions that have Keq values greater than
one, the reverse reaction is favored - More product is present than reactants
- In reactions that have Keq values less than one,
the forward reaction is favored - More reactants are present than product
11Lets do some practice using concentrations
- H2 (g) O2(g) ? H2O (g)
- Calculate the Keq if H2 1.0 M
- O2 2.0 M
- H2O 1.5 M
12Practice
- Nitrogen pentachloride decomposes at 7600C.
- NCl5(g) ?? NCl3(g) Cl2(g)
- Keq 3.00 x 10-2
- What is the concentration of each of the products
(NCl3 and Cl2) at equilibrium if the
concentration of NCl5 is 1.5 x 10-3 mol/L and the
concentration of NCl3 and Cl2 are equal?
13Answer
- NCl5(g) ? NCl3(g) Cl2(g)
- Keq 3.00 x 10-2
- Keq NCl3 Cl2
- --------------
- NCl5
- 3.00 x 10-2 x x
- --------------
- 1.5 x 10-3
14Answer continued
- 3.00 x 10-2 x2
- --------------
- 1.5 x 10-3
- x2 (3.00 x 10-2) (1.5 x 10-3)
- x2 (4.5 x 10-5)
- X 0.0067 mol/L
15Bell Work
- Calculate Keq for the synthesis of ammonia at
4000C if the following concentrations are present
at equilibrium. - N2(g) H2(g) ? NH3(g)
- N2 4.5 mol/L
- H2 1.80 mol/L
- NH3 3.28 mol/L
16practice
- Formamide, HCONH2 is used to manufacture
agricultural chemicals, dyes, and
pharmaceuticals. At 1250C formamide decomposes - HCONH2(g) ? NH3(g) CO(g)
- Keq 4.8
- if the equilibrium concentrations of NH3 and CO
are both 0.60 mol/L, what is the - equilibrium concentration of formamide?
17practice
- Example. For the reaction, CO 3H2 ? ? CH4
H2O, calculate Keq from the following equilibrium - concentrations CO 0.0613 M H2 0.1839 M
CH4 0.0387 M H2O 0.0387 M.
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19review
20Direction of reaction
- Reaction Quotient (Q)
- Same application of Keq to us so far
- Same expression
- Q products / reactants
21Characteristics about K
- Equilibrium can be approached from either
direction. - K does not depend on the initial concentrations
of reactants and products. - K does depend on temperature.
- The equilibrium constants for forward and reverse
reactions are the reciprocals of each other - K 1/K
- Example, K 11, then K 1/11 0.091
- If a reaction can be expressed as the sum of two
or more reactions, K for the overall reaction is
the product of the equilibrium constants of the
individual reactions - Reaction 3 Reaction 1 Reaction 2
- K(Reaction 3) K(reaction 1) x K(Reaction 2)
22One more thing about Keq
- Keq is the equilibrium constant
- It tells us which way the reaction is occurring
- Has other names depending on what is happening
- Also called Kc
- Constant for molar concentrations
- Also called Ka
- When the reaction involves an acidic situation
- Acid dissociation constant for weak acids
- Also called Kb
- When the reaction involves a basic situation
- Base dissocaition constant for weak bases
- Also called Kp
- When all of the reactants and products in the
reaction are gases so Keq can be expressed in
terms of partial pressure (atm) - Gases can be or pp
- Also called Ksp
- When the reaction involves solubility (solubility
product) - Note that no denominator will be used in these
types of reactions because the reactants are
solids
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24practice
- Write the expression for Kp for the following
reaction - CuO (s) H2 (g) ??Cu (s) H2O (g)
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26example
- For the reaction, 2SO2(g) O2(g) ?? 2SO3(g)
- Write the equilibrium constant expression, Kp.
- What is the value for Kp if Kc 2.8x102 at 1000
K?
27We can use Ksp to determine solubility, s
- Solubility the concentration in a saturated
solution - Tells us the maximum amount of solute you can
dissolve - If soluble, high concentration of ions and low
concentration of reactants - Ksp is larger than 1
- The bigger the ksp, the more soluble the stuff is
- The smaller the ksp, the less soluble the stuff
28The position of equilibrium
- Equilibrium constants vary with temperatures
- At what temperature are they mostly products at
equilibrium? - T 470 oC
- N2 3H2 ?? 2 NH3 K 1.0 x 10-1
- T 25 oC
- N2 3H2 ?? 2 NH3 K 4.0 x 108
- The second temperature shows us that they are
most products at equilibrium
29Which solid dissolves the most in water (most
soluble)?
- PbCl2 (s) ?? Pb2 (aq) 2Cl- (aq)
- K 1.6 x 10-8
- PbI2 (s) ?? Pb2 (aq) 2I- (aq)
- K 8.5 x 10-9
- The first one would dissolve most number is
bigger
30Example for you
- At a temperature of 1000 K, carbon monoxide can
react with oxygen gas to form carbon dioxide - Write a balanced equation for this reaction
- Write the Keq expression for this reaction
- The equilibrium constant for this reaction is 2.2
x 1022. is this reaction expected to be at
equilibrium or to go to completion?
31Direction of reaction
- So far you have solved for the K for equations
- This tells us what is happening with the reaction
- Magnitude of K
- If the K value is large (K gtgt 1), the equilibrium
lies to the right and the reaction mixture
contains mostly products. - If the K value is small (K ltlt1), the equilibrium
lies to the left and the reaction mixture
contains mostly reactants. - If the K value is close to 1 (0.10 lt K lt 10), the
mixture contains appreciable amounts of both
reactants and products.
3212.4 - Direction of reaction
- To solve for the direction of reaction, we need a
new unit called the reaction quotient (Q) - Q has the same expression as k
- Q products/reactants
33example
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3512.5 - System equilibrium
- Equilibrium can favor the formation of reactants
or products - When a system is at equilibrium, it will stay
that way until something changes this condition - Stresses alter the equilibrium
- Change the location of the equilibrium
36Le Chateliers principle
- French chemist Henri Louis Le Chatelier
- His principle states that when a system at
equilibrium is disturbed by applying stress, it
attains a new equilibrium position to accommodate
the change and relieve the stress - What are stresses?
- Concentration, temperature, or pressure
37Changing concentration
- If you add more reactants, the system will shift
towards the products (right) - If you remove reactants (means there is more
products than reactants now), the system will
shift towards the reactants (left) - If you remove products (means there is more
reactants than products now), the system will
shift towards the products (right)
38Temperature affects equilibrium systems
- Temperature changes can cause equilibrium shifts
- An increase in temperature causes the endothermic
reaction to occur - The way the reaction shifts depends on the type
of reaction - Endothermic or exothermic
39Endothermic
- Example
- What does it look like (reaction diagram)
- If we lower the temperature, what are we doing?
- By lowering the temperature, one of the products
(energy) is being removed - As the temperature continues to drop, the system
reacts to relieve the stress
40Increase temperature
- Endothermic reaction
- Add temperature, adding heat energy
- The system will react in a way to relieve the
stress and absorbs the heat
41Exothermic reaction
- Example
- Increasing temperature
- Left shift, more product
- Decreasing temperature
- Right shift, more reactants
42Increase temperature
- Exothermic reaction
- Add temperature, adding heat energy
- The system will react in a way to relieve the
stress and absorbs the heat
43Now lets decrease temperature
44vant Hoff equation
- K2 ?Ho 1 1
- 1n ----- ------ ---- - ----
- K1 R T1
T2 - K2 and K1 are equilibrium constants at T2 and T1
- ?Ho is the standard enthalpy change for the
forward reaction - R is the gas constant (8.31 J/molk)
- If the forward reaction is exothermic, K
decreases as T increases - If the forward reaction is endothermic, K
increases as T increases
45Pressure changes
- Gaseous equilibrium systems
- Compression or expansion
- Count the number of gas moelcules on each side of
the equation - Compression
- Increase in pressure will cause the system to
shift to the side that will form less gas
moelcules - Expansion
- Decrease in pressure will cause the system to
shift to the side that will form more gas
particles
46Practice
- Answer the following questions
- What does Le Chateliers principle say?
- How does changing the concentration of the
reactants affect a reaction (according to Le
Chatelier)? - How does increasing pressure affect the reaction?
47Practice
- What will happen to the following reactions when
the various stresses are applied - 2 H2 (g) O2 (g) ? 2 H2O (l)
- 1. More hydrogen is added to the system
- 2. Oxygen is removed from the system
- 3. This is exothermic the temperature is
increased - 4. The pressure is increased
- 5. The pressure is decreased
48recap
- Out of the changes talked about with Le Chatelier
- Adding or removing
- Compressing or expanding
- Changing temperature
- The only one that changes the value of the
equilibrium constant is a change in temperature - In the other two cases, K remains constant