Title: Using Computational Chemistry to Study a Reaction Pathway
1Using Computational Chemistry to Study a Reaction
Pathway
- Jessica L. Case
- Super Chem II
- April 30, 2002
2Goals of the Project
- Utilize Gaussian 98 and WebMO for various
computational calculations - Geometry Optimizations
- Frequency Calculations
- Transition State Determination
- IRC Calculations to find Intermediate Structures
- Determine the energies of the reactants,
intermediates, transition state, and product - Use these methods to determine a reaction pathway
- Draw a calculated reaction coordinate diagram
3Reaction Under Study
- Why this reaction?
- Studied it last summer as a possible monomer unit
to form ladder polymers
4Geometry Optimization2-methoxyfuran
Method Basis Set Energy (H) Energy (kcal/mol)
AM1 3-21G -0.055206032 -34.64230929
AM1 6-31G(d) -0.055206032 -34.64230929
AM1 6-311G(d,p) -0.055206032 -34.64230929
HF 3-21G -340.6059668 -2.13734105
HF 6-31G(d) -342.5083676 -2.14927105
HF 6-311G(d,p) -342.5987805 -2.14984105
B3LYP 3-21G -342.6481147 -2.15015105
B3LYP 6-31G(d) -344.5377379 -2.14945105
5Geometry Optimizationcyclobutylbenzyne
Method Basis Set Energy (H) Energy (kcal/mol)
AM1 3-21G 0.273878653 171.8614568
AM1 6-31G(d) 0.273878653 171.8614568
AM1 6-311G(d,p) 0.273878653 171.8614568
HF 3-21G -304.5375532 -1.91100105
HF 6-31G(d) -306.2532483 -1.92177105
HF 6-311G(d,p) -306.3209326 -1.92219105
B3LYP 3-21G -306.5968457 -1.92393105
B3LYP 6-31G(d) -308.2918719 -1.93456105
6Geometry Optimizationproduct
Method Basis Set Energy (H) Energy (kcal/mol)
AM1 3-21G 0.171341699 107.5185441
AM1 6-31G(d) 0.171341699 107.5185441
AM1 6-311G(d,p) 0.171341699 107.5185441
HF 3-21G -645.1633345 -4.04846105
HF 6-31G(d) -648.7899777 -4.07122105
B3LYP 3-21G -649.2513117 -4.07412105
B3LYP 6-31G(d) -652.8390400 -4.09663105
7Frequency Calculations
Molecule Method Basis Set ZPE (H)
2-MF HF 3-21G 0.108346
2-MF HF 6-31G(d) 0.108148
2-MF B3LYP 6-31G(d) 0.101644
CBB HF 3-21G 0.116369
CBB HF 6-31G(d) 0.115783
CBB B3LYP 6-31G(d) 0.109457
Product HF 3-21G 0.230598
Product HF 6-31G(d) 0.230935
Product B3LYP 6-31G(d) 0.215880
8Locating the Transition State
- First, combine the numbering of the atoms in the
two reactant structures - Second, combine the Z-matrices of the two
geometry optimized reactants - Third, determine the approximate approach of the
two molecules will take to react together to form
the product - Vary distance between reactants
- Vary intermolecular angles
- Vary dihedral angles
9Lining Up the ReactantsHF / 6-31G(d)
- R 3 Angstroms
- E -648.6805142 H
- R 10 Angstroms
- E -648.7616681 H
- R 20 Angstroms
- E -648.7615803 H
- R 80 Angstroms
- E -648.7615669 H
- 2-methoxyfuran
- E -342.5083676 H
- cyclobutylbenzyne
- E -306.2532483 H
- sum of reactants
- E -648.7616159 H
10Determining the Transition State Structure
- Use the combined Z-matrix of the two reactants
and the Z-matrix of the product as input - The STQN method locates a transition structure
with the QST2 keyword - Utilizes the input structures to determine a
structure of maximum energy in between the
reactants and products structures
11The Transition State
- Two different inputs yielded very similar
structures - E1 -648.752134712 H -4.07098452053105
kcal/mol - E2 -648.752134717 H -4.07098452056105
kcal/mol - The transition state occurred at R 2.999
Angstroms - Frequency calculations yielded a zero point
energy of 0.229644 H and one negative vibrational
mode, which is expected for a transition state
structure
12Locating the Intermediates
- IRC Calculations
- Takes the calculated structure and force field
from the optimized transition state and
determines intermediate structures along the
reaction path - Varied the number of steps away from the
transition state - 2 steps E -648.7522613 H
- 10 steps E -648.7555564 H
- 40 steps E -648.7571191 H
13The Intermediate Structures
14Reaction Coordinate Diagram
15And with that, my academic career at Hope College
is complete!!!
Booyah!