INFRARED ABSORPTION SPECTROSCOPY - PowerPoint PPT Presentation

1 / 81
About This Presentation
Title:

INFRARED ABSORPTION SPECTROSCOPY

Description:

Infrared absorption only occurs when the incoming IR photon has sufficient energy for the transition to the next allowed vibrational state Note: ... – PowerPoint PPT presentation

Number of Views:2479
Avg rating:3.0/5.0
Slides: 82
Provided by: ashomarcon
Category:

less

Transcript and Presenter's Notes

Title: INFRARED ABSORPTION SPECTROSCOPY


1
INFRARED ABSORPTION SPECTROSCOPY
Semester Dec Apr 2010
2
Learning Outcomes
  • By the end of this topic, students should be able
    to
  • Explain the principles and the working mechanism
    of infrared (IR) absorption spectroscopy
  • Identify the molecular species that absorb IR
    radiation
  • Interpret IR spectrum
  • Explain stretching and bending vibrations in
    relation to IR absorption
  • Determine unknown qualitatively using IR
    absorption
  • Draw a schematic diagram of a conventional IR
    instrument and a fourier transform IR instrument
    and explain the function of each component of the
    instrument
  • Differentiate between a dispersive IR instrument
    and a FTIR spectrometer

3
Infrared spectroscopy
  • Mostly for qualitative analysis
  • Absorption spectra is recorded as transmittance
    spectra
  • Absorption in the infrared region arise from
    molecular vibrational transitions
  • Absorption at specific wavelengths
  • Thus, IR spectra provides more specific
    qualitative information
  • IR spectra is called fingerprints
  • - because no other chemical species will have
    identical IR spectrum

4
Comparison between transmittance (upper) vs
absorbance (lower) plot
The transmittance spectra provide better contrast
btw intensities of strong and weak bands compared
to absorbance spectra
5
Electromagnetic Spectrum
  • Energy of IR photon insufficient to cause
    electronic excitation but can cause vibrational
    excitation

6
INTRODUCTION
  • Comparison between UV-vis and IR
  • Energy UV gt vis gt IR
  • Frequency UV gt vis gt IR
  • Wavelength UV lt vis lt IR

7
INFRARED SPECTROSCOPY
  • Infrared (IR) spectroscopy deals with the
    interaction of infrared radiation with matter
  • IR spectrum provides
  • Important information about its chemical nature
    and molecular structure
  • IR applicability
  • Analysis of organic materials
  • Polyatomic inorganic molecules
  • Organometallic compounds

8
  • IR region of EM spectrum
  • ? 780 nm 1000 µm
  • Wavenumber 12,800 10cm-1
  • IR region subdivided into 3 subregions
  • 1. Near IR region (Nearest to the visible)
  • - 780 nm to 2.5 µm (12,800 to 4000 cm-1)
  • 2. Mid IR region
  • - 2.5 to 50 µm (4000 200 cm-1)
  • 3. Far IR region
  • - 50 to 1000 µm (200 10cm-1)

visible
NEAR
MID
infrared
FAR
8
microwave
9
  • When IR absorption occur?
  • 1. IR absorption only occurs when IR radiation
    interacts with a molecule undergoing a change in
    dipole moment as it vibrates or rotates.
  • 2. Infrared absorption only occurs when the
    incoming IR photon has sufficient energy for the
    transition to the next allowed vibrational state
  • Note If the 2 rules above are not met, no
    absorption can occur

10
What happen when a molecule absorbs infrared
radiation?
  • Absorption of IR radiation corresponds to energy
    changes on the order of 8 to 40 kJ/mole.
  • - Radiation in this energy range corresponds to
    stretching and bending vibrational frequencies of
    the bonds in most covalent molecules.
  • In the absorption process, those frequencies of
    IR radiation which match the natural vibrational
    frequencies of the molecule are absorbed.
  • The energy absorbed will increase the amplitude
    of the vibrational motions of the bonds in the
    molecule.

11
  • NOT ALL bonds in a molecule are capable of
    absorbing IR energy. Only those bonds that have
    change in dipole moment are capable to absorb IR
    radiation.
  • The larger the dipole change, the stronger the
    intensity of the band in an IR spectrum.

12
  • What is a dipole moment?
  • is a measure of the extent to which a separation
    exists between the centers of positive and
    negative charge within a molecule.

d-
d
d
13
  • In heteronuclear diatomic molecule, because of
    the difference in electronegativities of the two
    atoms, one atom acquires a small positive charge
    (q), the other a negative charge (q-).
  • This molecule is then said to have a dipole
    moment whose magnitude, µ qd

distance of separation of the charge
14
Molecular Species That Absorb Infrared Radiation
  • Compound absorb in IR region
  • Organic compounds, carbon monoxide
  • Compounds DO NOT absorb in IR region
  • O2, H2, N2, Cl2

15
IR Vibrational Modes
16
Molecular vibration
divided into
back forth movement
involves change in bond angles
stretching
bending
wagging
scissoring
symmetrical
asymmetrical
rocking
twisting
in-plane vibration
out of plane vibration
17
STRETCHING
18
BENDING
19
Sample Handling Techniques
  • Gases
  • evacuated cylindrical cells equipped with
    suitable windows
  • Liquid
  • sodium chloride windows
  • neat liquid
  • Solid
  • Pellet (KBr)
  • Mull

20
LIQUID
  • a drop of the pure (neat) liquid is squeezed
    between two rock-salt plates to give a layer that
    has thickness 0.01mm or less
  • 2 plates held together by capillary mounted in
    the beam path
  • What is meant by neat liquid?
  • Neat liquid is a pure liquid that do not contain
    any solvent or water.
  • This method is applied when the amount of liquid
    is small or when a suitable solvent is
    unavailable

21
Solid sample preparation
  • There are three ways to prepare solid sample for
    IR spectroscopy.
  • Solid that is soluble in solvent can be dissolved
    in a solvent, most commonly carbon tetrachloride
    CCl4.
  • Solid that is insoluble in CCl4 or any other IR
    solvents can be prepared either by KBr pellet or
    mulls.

22
PELLETING (KBr PELLET)
  • Mixing the finely ground solid sample with
    potassium bromide (KBr) and pressing the mixture
    under high pressure (10,000 15,000 psi) in
    special dye.
  • KBr pellet can be inserted into a holder in the
    spectrometer.

23
MULLS
  • Formed by grinding 2-5 mg finely powdered sample,
    presence 1 or 2 drops of a heavy hydrocarbon oil
    (Nujol)
  • Mull examined as a film between flat salt plates
  • This method applied when solid not soluble in an
    IR transparent solvent, also not convenient
    pelleted in KBr

24
  • What is a mull
  • A thick paste formed by grinding an insoluble
    solid with an inert liquid and used for studying
    spectra of the solid
  • What is Nujol
  • A trade name for a heavy medicinal liquid
    paraffin. Extensively used as a mulling agent in
    spectroscopy

25
Instrumentation
26
IR Instrument
  • Dispersive spectrometers
  • sequential mode
  • Fourier Transform spectrometers
  • simultaneous analysis of the full spectra range
    using inferometry

27
IR Instrument (Dispersive)
  • Important components in IR dispersive spectrometer

5
1
2
3
4
signal processor readout
source lamp
sample holder
? selector
detector
Detector - Thermocouple - Pyroelectric
transducer - Thermal transducer
Source - Nernst glower - Globar
source - Incandescent wire
28
Radiation Sources
  • generate a beam with sufficient power in the ?
    region of interest to permit ready detection
    measurement
  • provide continuous radiation made up of all ?s
    with the region (continuum source)
  • stable output for the period needed to measure
    both P0 and P

29
Schematic Diagram of a Double Beam Infrared
Spectrophotometer
30
FTIRFourier Transform Infrared
31
FTIR
  • Why is it developed?
  • to overcome limitations encountered with the
    dispersive instruments
  • especially slow scanning speed due to individual
    measurement of molecules/atom
  • utilize an interferometer

32
  • Interferometer
  • Special instrument which can read IR frequencies
    simultaneously
  • faster method than dispersive instrument
  • interferograms are transformed into frequency
    spectrums by using mathematical technique called
    Fourier Transformation

FT Calculations
interferograms
IR spectrum
33
Components of Fourier Transform Instrument
- majority of commercially available Fourier
transform infrared instruments are based upon
Michelson interferometer
3
4
1
2
5
6
34
  • Advantages (over dispersive instrument)
  • high sensitivity
  • high resolution
  • speed of data acquisition ( data for an entire
    spectrum can be obtained in 1 s or less)

35
Interpretation Infrared Spectra
36
Infrared Spectra
  • IR spectrum is due to specific structural
    features, a specific bond, within the molecule,
    since the vibrational states of individual bonds
    represent 1 vibrational transition.
  • e.g. IR spectrum can tell the molecule has an O-H
    bond or a CO or an aromatic ring

37
Infrared Spectra
38
How to Interpret Infrared Spectra?
39
How to analyze IR spectra
  • Begin by looking in the region from 4000-1300.
  • Look at the CH stretching bands around 3000

Indicates
Are any or all to the right of 3000? alkyl groups (present in most organic molecules)
Are any or all to the left of 3000? a CC bond or aromatic group in the molecule
40
2. Look for a carbonyl in the region 1760-1690.
If there is such a band
Indicates
Is an OH band also present? a carboxylic acid group
Is a CO band also present? an ester
Is an aldehyde CH band also present? an aldehyde
Is an NH band also present? an amide
Are none of the above present? a ketone
(also check the exact position of the carbonyl
band for clues as to the type of carbonyl
compound it is)
41
3. Look for a broad OH band in the region
3500-3200 cm-1. If there is such a band
Indicates
Is an OH band present? an alcohol or phenol
4. Look for a single or double sharp NH band in
the region 3400-3250 cm-1. If there is such
a band
Indicates
Are there two bands? a primary amine
Is there only one band? a secondary amine
42
5. Other structural features to check for
Indicates
Are there CO stretches? an ether (or an ester if there is a carbonyl band too)
Is there a CC stretching band? an alkene
Are there aromatic stretching bands? an aromatic
Is there a CC band? an alkyne
Are there -NO2 bands? a nitro compound
43
How to analyze IR spectra
  • If there is an absence of major functional group
    bands in the region 4000-1300 cm-1 (other than
    CH stretches), the compound is probably a strict
    hydrocarbon.
  • Also check the region from 900-650 cm-1.
    Aromatics, alkyl halides, carboxylic acids,
    amines, and amides show moderate or strong
    absorption bands (bending vibrations) in this
    region.
  • As a beginning student, you should not try to
    assign or interpret every peak in the spectrum.
    Concentrate on learning the major bands and
    recognizing their presence and absence in any
    given spectrum.

44
(No Transcript)
45
(No Transcript)
46
ALKANE
47
C-H Stretch for sp3 C-H around 3000 2840
cm-1. CH2 Methylene groups have a characteristic
bending absorption at approx 1465
cm-1 CH3 Methyl groups have a characteristic
bending absorption at approx 1375 cm-1 CH2 The
bending (rocking) motion associated with four or
more CH2 groups in an open chain occurs at
about 720 cm-1
48
ALKENE
49
ALKENE
C-H Stretch for sp2 C-H occurs at values greater
than 3000 cm-1. C-H out-of-plane (oop) bending
occurs in the range 1000 650 cm-1 CC stretch
occurs at 1660 1600 cm-1 often conjugation
moves CC stretch to lower frequencies and
increases the intensity
50
ALKYNE
51
ALKYNE
Stretch for sp C - H occurs near 3300 cm-1.
Stretch occurs near 2150 cm-1 conjugation moves
stretch to lower frequency.
52
AROMATIC RINGS
Stretch for sp2 C-H occurs at values greater than
3000 cm-1.
Ring stretch absorptions occur in pairs at 1600
cm-1 and 1475 cm-1.
Bending occurs at 900 - 690cm-1.
53
AROMATIC RINGS
54
  • C-H Bending ( for Aromatic Ring)
  • The out-of-plane (oop) C-H bending is useful in
    order to assign the positions of substituents on
    the aromatic ring.
  • Monosubstituted rings
  • this substitution pattern always gives a strong
    absorption near 690 cm-1. If this band is absent,
    no monosubstituted ring is present. A second
    strong band usually appears near 750 cm-1.
  • Ortho-Disubstituted rings
  • one strong band near 750 cm-1.
  • Meta- Disubstituted rings
  • gives one absorption band near 690 cm-1 plus one
    near 780 cm-1. A third band of medium intensity
    is often found near 880 cm-1.
  • Para- Disubstituted rings
  • - one strong band appears in the region from 800
    to 850 cm-1.

55
Ortho-Disubstituted rings
Bending observed as one strong band near 750 cm-1.
56
Meta- Disubstituted rings
- gives one absorption band near 690 cm-1 plus
one near 780 cm-1. A third band of medium
intensity is often found near 880 cm-1.
57
Para- Disubstituted rings
- one strong band appears in the region from 800
to 850 cm-1.
58
ALCOHOL
Primary alcohol 10
Secondary alcohol 20
Tertiary alcohol 30
59
ALCOHOL
O-H The hydrogen-bonded O-H band is a broad peak
at 3400 3300 cm-1. This band is usually the
only one present in an alcohol that has not
been dissolved in a solvent (neat liquid).
C-O-H Bending appears as a broad and weak peak
at 1440 1220 cm-1 often obscured by the CH3
bendings. C-O Stretching vibration usually occurs
in the range 1260 1000 cm-1. This band can be
used to assign a primary, secondary or tertiary
structure to an alcohol.
60
PHENOL
61
PHENOL
62
(No Transcript)
63
ETHER
C-O The most prominent band is that due to C-O
stretch, 1300 1000 cm-1. Absence of CO
and O-H is required to ensure that C-O stretch
is not due to an ester or an alcohol.
Phenyl alkyl ethers give two strong bands at
about 1250 1040 cm-1, while aliphatic ethers
give one strong band at about 1120 cm-1.
64
(No Transcript)
65
CARBONYL COMPOUNDS
cm-1 1810 1800 1760 1735
1725 1715 1710
1690 Anhydride Acid Anhydride Ester
Aldehyde Ketone Carboxylic
Amide (band 1) Chloride (band 2)
acid
Normal base values for the CO stretching
vibrations for carbonyl groups
66
A. ALDEHYDE
CO stretch appear in range 1740-1725 cm-1 for
normal aliphatic aldehydes
Conjugation of CO with phenyl 1700 1660 cm-1
for CO and 1600 1450 cm-1 for ring (CC)
C-H Stretch, aldehyde hydrogen (-CHO),
consists of weak bands, one at 2860 - 2800
cm-1 and the other at 2760 2700 cm-1.
67
(No Transcript)
68
B. KETONE
CO stretch appear in range 1720-1708 cm-1 for
normal aliphatic ketones
Conjugation of CO with phenyl 1700 1680 cm-1
for CO and 1600 1450 cm-1 for ring (CC)
69
(No Transcript)
70
C. CARBOXYLIC ACID
71
(No Transcript)
72
D. ESTER
CO stretch appear in range 1750-1735 cm-1 for
normal aliphatic esters
Conjugation of CO with phenyl 1740 1715 cm-1
for CO and 1600 1450 cm-1 for ring (CC)
C O Stretch in two or more bands, one stronger
and broader than the other, occurs in the range
1300 1000 cm-1
73
(No Transcript)
74
E. AMIDE
10
20
30
75
AMIDE
76
F. ACID CHLORIDE
Stretch appear in range 1810 -1775 cm-1 in
conjugated chlorides. Conjugation lowers the
frequency to 1780 1760 cm-1
Stretch occurs in the range 730 -550 cm-1
Acid chloride show a very strong band for the CO
group.
77
F. ANHYDRIDE
Stretch always has two bands, 1830 -1800 cm-1 and
1775 1740 cm-1, with variable relative
intensity. Conjugation moves the absorption to a
lower frequency. Ring strain (cyclic anhydride)
moves absorptions to a higher frequency.
Stretch (multiple bands) occurs in the range 1300
-900 cm-1
78
AMINE
20
10
30
79
AMINE
Stretching occurs in the range 3500 3300 cm-1.
Primary amines have two bands. Secondary amines
have one band a vanishingly weak one for
aliphatic compounds and a stronger one for
aromatic secondary amines. Tertiary amines have
no N H stretch.
N H
Bending in primary amines results in a broad band
in the range 1640 1560 cm-1. Secondary amines
absorb near 1500 cm-1
N H
Out-of-plane bending absorption can sometimes be
observed near 800 cm-1
N H
Stretch occurs in the range 1350 1000 cm-1
C N
80
Primary Amine
Secondary Amine
81
Tertiary Amine
Aromatic Amine
Write a Comment
User Comments (0)
About PowerShow.com