Multiple integrals - PowerPoint PPT Presentation

1 / 64
About This Presentation
Title:

Multiple integrals

Description:

The graph of function of two variables f(x,y) is surface, plotted in 3-D. The ... If G is the region in the first octant bounded by y = x2, z y = 1, xy-plane ... – PowerPoint PPT presentation

Number of Views:617
Avg rating:3.0/5.0
Slides: 65
Provided by: Owne8
Category:

less

Transcript and Presenter's Notes

Title: Multiple integrals


1
Multiple integrals
  • BET2533 Eng. Math. III
  • R. M. Taufika R. Ismail
  • FKEE, UMP

2
Introduction
  • The integration of multivariable functions are
    denoted as

Double integrals of two variables functions
Triple integrals of three variables functions
3
Double Integrals
  • The graph of function of two variables f(x,y) is
    surface, plotted in 3-D. The integral of f(x,y)
    over the region R is the volume between the graph
    and the region R.

4
If f(x,y) 1, then the numerical value of the
volume is equal to value of the area of the
region R. Thus,
5
Iterated integral
  • If f(x,y) is continuous in a rectangular region
  • then

6
  • Usually the bracket are not shown, and these are
    done with the understanding that the inner
    integrations should be performed first
  • We also deal with the inner integrations with
    variables limits

7
Example 1
  • Evaluate the iterated integrals.
  • (i)
  • (ii)

8
Solution
  • (i) Using the definition of iterated integrals,
    we obtain

?
9
  • (ii) Using the definition of iterated integrals,
    we obtain

?
10
Double integrals Fubinis theorem
  • According to Gaudio Fubini (1879-1943), the
    double integrals of any continuous function can
    be calculated as an iterated integrals Fubinis
    theorem

11
  • Fubinis theorem on a rectangular region
  • if
  • then

R
12
  • Fubinis theorem on any region

Type I
Type II
13
Example 2
  • Evaluate
  • (i)
  • (ii)
  • (iii)

14
Solution
  • (i) The region R is illustrated as

R
15
  • Hence

?
16
  • (ii) The region R is illustrated as

R
?
17
  • (iii) The region R is illustrated as

R
?
18
Example 3
  • Find the volume of the solid bounded by

19
Solution
The solid is described as
R
20
The base of the solid is the region R
R
21
Thus, the volume V is given by
22
Now let .
Hence,
?
23
Example 4
  • Evaluate
  • (i)
  • (ii)

24
Solution
  • (i) The region R is illustrated as

R
25
  • But the inner integral cannot be
    integrated.
  • However, we can reverse the order of integration
    dydx to dxdy. Then the region become

R
26
  • Hence

?
27
  • (ii) The region R is illustrated as

R
28
  • But the inner integral cannot be
    integrated.
  • However, we can reverse the order of integration
    dxdy to dydx. Then the region become

R
29
  • Hence

?
30
Review Polar coordinates
Polar coordinates
y
r
?
x
31
Cylindrical polar coordinates
32
Spherical polar coordinates
33
Double integrals in polar coordinates
  • When involving circular shape, it is easier to
    evaluate in the polar coordinates
  • Suppose that we can convert a function z(x,y) to
    z f(r,?) then we may evaluate the integral of
    f(r,?) in the polar coordinates

34
z f (r,?)
V
dV
z f (r,?)
R
dA
A
35
y
dr
dA
r
rd?
d?
?
x
36
Example 5
  • Evaluate the following integrals by changing to
    polar coordinates.
  • (i)
  • (ii)

37
Solution
(i) The region of integration R is described as
38
  • Therefore

?
39
(ii) The region of integration R is described as
R
40
Therefore
?
41
  • Therefore

42
Example 6
  • Use the polar coordinates to solve Example 4.

43
Solution
The solid and its base is described as
R
R
44
Thus, the volume V is given by
?
45
Triple integrals Cartesian coordinates
  • Triple integrals in Cartesian coordinates is an
    integration of a function of three variables
    f(x,y,z) on a 3-D closed region G

46
(No Transcript)
47
G
R
48
Example 7
  • If G is the region in the first octant bounded
    by y x2, z y 1, xy-plane and yz-plane,
    evaluate
  • (i) where
  • (ii) The volume of the region G

49
Solution
  • The region G and its projection R on the
    xy-plane is as shown below

50
  • (i)In this case we have f(x,y,z) 6z, z1(x,y)
    0 and z2(x,y) 1 y. The projection of G on the
    xy-plane is a region R bounded by x 0, x 1, y
    x2 and y 1. Thus we obtain

51
?
52
  • (ii)

?
53
Triple integrals Cylindrical coordinates
54
Example 8
  • Use cylindrical coordinates to find the volume
    of the solid bounded by
  • and
    .

55
Solution
  • The solid of the region G and its projection R
    on the xy-plane are

56
  • Using relation x2 y2 r2, we obtain
  • z2 v(25 r2). We also have z1 0. Thus,

?
57
Example 9
  • Use cylindrical coordinates to find the volume
    of the solid bounded by the paraboloid
    and the plane .

58
Solution
  • The solid of the region G and its projection R
    on the xy-plane are

z
y
3
G
R
x
3
-3
3
y
R
3
-3
x
59
  • Thus, the required volume is

?
60
Triple integrals Spherical coordinates
z
? sin f d?
? sin f
d?
d?
d?
?
f
? df
?
df
y
?
x
61
? sin f d?
d?
? df
62
Example 10
  • Find the volume of the solid that lies above the
    cone and inside the sphere .

63
Solution
  • The solid of the region G as illustrated below

64
  • Thus, the required volume is

?
Write a Comment
User Comments (0)
About PowerShow.com