Title: Chemistry, The Central Science, 10th edition
1Chapter 13Properties of Solutions
- Chemistry, The Central Science, 10th edition
- Theodore L. Brown H. Eugene LeMay, Jr.
- and Bruce E. Bursten
Troy Wood University of Buffalo Buffalo, NY ?
2006, Prentice Hall
2From weakest to strongest, rank the following
solutions in terms of solventsolute
interactions NaCl in water, butane (C4H10) in
benzene (C6H6), water in ethanol.
- NaCl in water lt C4H10 in C6H6 lt water in ethanol
- Water in ethanol lt NaCl in water lt C4H10 in C6H6
- C4H10 in C6H6 lt water in ethanol lt NaCl in water
3Correct Answer
- NaCl in water lt C4H10 in C6H6 lt water in ethanol
- Water in ethanol lt NaCl in water lt C4H10 in C6H6
- C4H10 in C6H6 lt water in ethanol lt NaCl in water
Butane in benzene will have only weak dispersion
force interactions. Water in ethanol will
exhibit much stronger hydrogen-bonding
interactions. However, NaCl in water will show
iondipole interactions because NaCl will
dissolve into ions.
4At a certain temperature, the Henrys law
constant for N2 is 6.0 ? 10?4 M/atm. If N2 is
present at 3.0 atm, what is the solubility of N2?
- 6.0 ? 10?4 M
- 1.8 ? 10?3 M
- 2.0 ? 10?4 M
- 5.0 ? 10?5 M
5Correct Answer
- 6.0 ? 10?4 M
- 1.8 ? 10?3 M
- 2.0 ? 10?4 M
- 5.0 ? 10?5 M
Henrys law,
Sg (6.0 ? 10?4 M/atm)(3.0 atm) Sg 1.8 ? 10?3 M
6Determine the mass percentage of hexane in a
solution containing 11 g of butane in 110 g of
hexane.
- 9.0
- 10.
- 90.
- 91
7Correct Answer
- 9.0
- 10.
- 90.
- 91
solution
in
component
of
mass
?
100
component
of
mass
solution
of
mass
total
Thus, 110 g (110 g 11 g)
? 100 91
8If 3.6 mg of Na is detected in a 200. g sample
of water from Lake Erie, what is its
concentration in ppm?
- 7.2 ppm
- 1.8 ppm
- 18 ppm
- 72 ppm
9Correct Answer
- 7.2 ppm
- 1.8 ppm
- 18 ppm
- 72 ppm
solution
in
component
of
mass
?
6
10
component
of
ppm
solution
of
mass
total
g
0.0036
mg
3.6
?
6
ppm
18
10
g
200.
g
200.
10What is the molality of 6.4 g of methanol (CH3OH)
dissolved in 50. moles of water?
- 0.040 m
- 0.22 m
- 0.064 m
- 0.11 m
11Correct Answer
- 0.040 m
- 0.22 m
- 0.064 m
- 0.11 m
12- How many moles of solute are there in 240 g of a
solution that is 5.0 glucose (C6H12O6) by mass?
- 0.033 moles
- 0.067 moles
- 0.10 moles
- 0.12 moles
- 0.20 moles
13Correct Answer
- 0.033 moles
- 0.067 moles
- 0.10 moles
- 0.12 moles
- 0.20 moles
5.0 glucose means 5.0 g glucose/100 g
solution (5.0 g glucose/100 g solution)(240 g
solution) 12 g (12 g glucose) ? (1 mol
glucose/180 g glucose) 0.067 moles glucose
14At a certain temperature, water has a vapor
pressure of 90.0 torr. Calculate the vapor
pressure of a water solution containing 0.080
mole sucrose and 0.72 mole water.
- 9.0 torr
- 10. torr
- 80. torr
- 81. torr
- 90. torr
15Correct Answer
- 9.0 torr
- 10. torr
- 80. torr
- 81. torr
- 90. torr
?
P
P
total
i
i
Pi XiPtotal Pi (0.72 mol/0.72 0.080
mol)(90.0 torr) Pi (0.90)(90.0 torr) 81. torr
16- Ethanol normally boils at 78.4C. The boiling
point elevation constant for ethanol is 1.22C/m.
What is the boiling point of a 1.0 m solution of
CaCl2 in ethanol?
- 77.2C
- 79.6C
- 80.8C
- 82.1C
- 83.3C
17Correct Answer
- 77.2C
- 79.6C
- 80.8C
- 82.1C
- 83.3C
m
K
T
?
b
b
The increase in boiling point is determined by
the molality of total particles in the solution.
Thus, a 1.0 m solution of CaCl2 contains 1.0 m
Ca2 and 2.0 m Cl? for a total of 3.0 m. Thus,
the boiling point is elevated 3.7C, so it is
78.4C 3.7C 82.1C.
18- At 300 K, the osmotic pressure of a solution is
0.246 atm. What is its concentration of the
solute?
- 1.0 M
- 0.50 M
- 0.25 M
- 0.10 M
19Correct Answer
(
)
- 1.0 M
- 0.50 M
- 0.25 M
- 0.10 M
n
MRT
RT
?
V
M ? /RT M (0.246 atm)/(0.0821
L-atm/mol-K)(300K) M (0.246 atm)/(0.2463
L-atm/mol) 1.0 M
20- Which of the following is not an example of a
colloid?
- Fog
- Smoke
- Paint
- Milk
- Carbonated water
21Correct Answer
- Fog
- Smoke
- Paint
- Milk
- Carbonated water
Carbonated water is a solution all the other
substances in the list are excellent examples of
colloids.