Title: The Chemistry of Acids and Bases
1The Chemistry of Acids and Bases
2Acids and Bases TitrationAt the conclusion of
our time together, you should be able to
- Do a titration of an acid with a base
- Calculate the equivalence point (neutralization
point) for a titration problem - Define normality
3Familiar Saying
Failure to be present causes the vital organ to
become more enamored. Distance makes the heart
grow fonder!!
4ACID-BASE REACTIONSTitrations
- H2C2O4(aq) 2 NaOH(aq) ---gt
- acid base
- Na2C2O4(aq) 2 H2O(liq)
- Carry out this reaction using TITRATION.
5Setup For Titrating An Acid With A Base
6Titration
- 1. Add solution from the buret.
- 2. Reagent (base) reacts with compound (acid) in
solution in the flask. - Indicator shows when exact stoichiometric
reaction has occurred. (Acid Base) - This is called the NEUTRALIZATION point.
- The equivalence point has been reached
7The Formula for Titration
- Use
- M1 E V1 M2 E V2
- M molarity of acid and base
- E number of H or OH- per mole of acid or base
- M x E Normality
- V volume
8Various Protic Titration Page 561 Standardize
a solution of NaOH i.e., accurately determine
its concentration.
- 32.7 mL of 0.100 M NaOH is neutralized with 25.0
mL of HCl by titration to an equivalence point.
What is the concentration of the acid?
9How do you do this??
- Use
- M1 E V1 M2 E V2
- 0.100 M x 1 x 32.7 mL
- M x 1 x 25.0 mL
- 0.131 M HCl
- pH -log (0.131 x 1) 0.883
10A.P. TEST IN ENGLISH
- 26,000 riot-crazed aborigines are storming the
test room. You are to write an essay that will
calm them. You are then to deliver your essay to
them using only the "Shakespearean English" with
quotes from the Greek and Latin languages.
11Page 56-2 You have 50.0 mL of 0.250 M NaOH
neutralized 20.0 mL of sulfuric acid. Determine
the M of the acid?
- 0.250 M x 1 x 50.0 mL
- M x 2 x 20.0 mL
-
- 0.313 M H2SO4
- For each mole of sulfuric acid there are 2
moles of H, therefore, - pH -log (0.313 x 2) 0.203
12Bill Gates' RulesHere is a list of 11 things
that many high school and college graduates did
not learn in school. In his book, Bill Gates
talks about how feel-good, politically-correct
teachings created a full generation of kids with
no concept of reality and how this concept has
set them up for failure in the real world.
- RULE 5
- Flipping burgers is not beneath your dignity.
Your grandparents had a different word for burger
flipping they called it opportunity.
13Acids and Bases TitrationLets see if you can
- Do a titration of an acid with a base
- Calculate the equivalence point (neutralization
point) for a titration problem - Define normality
14Page 563 Various Protic
- Use
- M1 E V1 M2 E V2
- 0.0500 M x 2 x 29.6 mL
- M x 1 x 40.0 mL
- 0.0740 M HNO3
- pOH -log (0.0500 x 2) 1.00
15Page 581 Titration with Grams
- Use
- M1 E V1 M2 E V2
- Moles of base (1)
- .800 M x 1 x 0.1000 L
-
- 0.0800 M HCl
- grams (1 mol/MM) (E) 0.0800 mol
- grams 56.11 (0.0800)
- 4.49 g KOH
16Page 594 Titration with Grams
- Use
- M1 E V1 M2 E V2
- 3 x Moles of acid
- 0.623 M x 1 x 0.074 L
-
- 0.0461 M KOH
- multiply both sides by MM and divide by MEV
- 3 x 2.73 g
- 0.0461 mol Molar Mass
- 178 g/mol
17Pass the Clicker!!!
18Normality is defined as
- M V
- E V
- M E
- M E V
- Not listed
19A method used to determine the concentration of
an unknown acid or base.
- Equivalence point
- Neutralization point
- Titration
- Titrant
- Normality
- Flask
- Buret
- Not listed
20The titrant is usually added to a(n)
- Equivalence point
- Neutralization point
- Titration
- Titrant
- Normality
- Flask
- Buret
- Not listed
21The indicator is usually added to the
- Equivalence point
- Neutralization point
- Titration
- Titrant
- Normality
- Flask
- Buret
- Not listed
22Going Down!!
233 M sulfuric acid would have a normality of
- 3 N
- 2 N
- 5 N
- 6 N
- 9 N
- Not listed
24100.0 mL of 3.0 M sulfuric acid neutralizes 50.0
mL of sodium hydroxide. What is the molarity of
the base?
- 12 M
- 6.0 M
- 3.0 M
- 1.5 M
- 0.33 M
- Not listed
25100.0 mL of 3.000 M nitric acid neutralizes 3.000
M of aluminum hydroxide. How many mL of the base
did you use?
- 100.0 mL
- 50.00 mL
- 33.33 mL
- 16.67 mL
- 8.333 mL
- Not listed
26Murphy's LawsofScience and Technology
Whenever a system becomes completely defined,
some fool discovers something which either
abolishes the system or expands it beyond
recognition.
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28The Chemistry of Acids and Bases
29Acids and Bases TitrationAt the conclusion of
our time together, you should be able to
- Do a titration of an acid with a base
- Calculate the equivalence point (neutralization
point) for a titration problem - Define normality
- Determine the percent acid with a titration
problem
30You will pay, I guarantee it!!!
31During a titration, the indicator goes in the
- Erlenmyer flask
- Beaker
- Buret
32During a titration, the substance of unknown
concentration goes in the
- Erlenmyer flask
- Beaker
- Buret
33Lemonade Titration Problem
- MEV (base) MEV (acid)
- 0.100 M x 1 x 8.70 mL
- M x 3 x 10.0 mL
-
- 0.0290 M citric acid
34Lemonade Titration Problem
- M mol/L
- 0.0290 M x 0.010 L
- x g
- 192.14 g/mol
-
- 0.0557 g in 10 mL
35Lemonade Titration Problem
- Using the density of citric acid in lemonade
- 10.0 mL x 0.960 g/mL
- 9.60 g lemonade in 10.0 mL of solution
-
- 0.0557 g citric acid in 10.0 mL x 100
- 9.60 g lemonade in 10.0 mL
- 0.580
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