Title: What is powering this clock?
1- What is powering this clock?
2How much Voltage
- You can see the battery is missing and the clips
are attached to the terminals. - What is the voltage required to run the clock?
3Make a Battery
Place a drop of Copper nitrate on one end of the
paper. Place a piece of copper in the center of
the wet spot
4Make a Battery
On the other end place a drop of zinc nitrate and
place a piece of zinc in the wet solution.
5Make a Battery
Add a couple of drops of KNO3 in the middle of
the two solutions to make a salt bridge.
6Make a Battery
Touch the probe leads to the two metals as
pictured here. Record the voltage.
V
7Whats the sign?
- If the reading is negative, switch the leads to
the other metals. You want to get a positive
voltage reading. - Record the metal that is at the red lead and the
metal at the black lead.
8REDUCE RED CATS
- This is the way I remember that reduction occurs
at the cathode and it is at the red lead. - Reduction ?
- Oxidation ?
9Look at the Standard Reduction Potential Table
10Find the voltage for each pair of metals you have.
?
11- Cu2 2 e- ? Cu 0.34 volts
- Zn ? Zn2 2e- 0.76 volts
-
1.10 volts -
-
12What is the purpose of the salt bridge?
13- What is powering this clock?
14How much Voltage
- You can see the battery is missing and the clips
are attached to the terminals. - What is the voltage required to run the clock?
15- After adding the phenolphthalein around the
strip of magnesium a pink color is observed. - Also there are tiny bubbles all along the sides
of the magnesium
16Lead Battery
- AnodePb(s) HSO4- ?PbSO4(s) H(aq) 2 e-
- cathode
- PbO2(s) 3 H HSO4 2e- ? PbSO4 H2O
- 0.296 V
- 1.628 V
- 1.924 V
17Mercury Battery
STEEL cathode
HgO in KOH Zn(OH)2
Zn container anode
Watches, pacemakers, calculators
18Rechargeable Nickel-cadmium
- anode Cd OH- ? Cd(OH)2 2 e-
- cathode NiO(OH)S H2O ?Ni(OH)2 OH-
- Recharge many times because the solid products
adhere to the surface of the electrode renewing
the battery.
19Corrosion
- Corrosion is the oxidative deterioration of a
metal such at rust.
O2 from the air
Drop of water
O2 4H 4 e- ? 2 H2O cathode
Fe --gt Fe2 2 e- anode
Rust
20How can you prevent corrosion?
- Look at the equation and prevent the reaction
from happening. What can you do?
21Electrochemical Cells
- There are 2 types of cells
- Galvanic also called voltaic is a spontaneous
reaction that produces an electric current - - Electrolytic requires an outside source to
supply the current such as a battery or
electrical outlet
22Electroplating
- Example of an Electrolytic cell
- Silverplated dinnerware - Silver is a soft metal
what would happen if you used a solid silver
fork?
23Electrolysis
Black lead cathode -
Red lead anode
Graphite electrodes
Na2SO4(aq)
24What is happening??
- Reduction
- 2 H2O(l) 2 - ? H2(g) 2 H-(aq) -0.83 V
- 2 H(aq) 3 e- ? H2(g) 0.00 V
- Na(aq) e- ? Na(s) -2.71
V - Oxidation
- 2 H2O ? O2(g) 4H(aq) 4e- -1.23 V
- 2 SO42- ? S2O8 2 e-
-2.00 V
25See bubbles? What is the clue?
- Look at the data table again and see which
reactions you think took place
26What is happening??
- Reduction
- 2 H2O(l) 2 - ? H2(g) 2 H-(aq) -0.83 V
- 2 H(aq) 3 e- ? H2(g) 0.00 V
- Na(aq) e- ? Na(s) -2.71
V - Oxidation
- 2 H2O ? O2(g) 4H(aq) 4e- -1.23 V
- 2 SO42- ? S2O8 2 e-
-2.00 V
27Answer
- Reduction was water or Na
- We know is must be water for 3 reasons -
- 1. a gas was produced
- 2. sodium reacts with water violently
- 3. It became more basic
- 2H2O 2 e- --gt H2(g) 2 OH- -.83V
28- Oxidation was either water of sulfate ion
- Oxidation of water produces H and a gas. Do we
have evidence of that? - H2O --gt O2(g) 4 H 4 e- -1.23 V
29Energy Involved
- 2H2O 2 e- --gt H2(g) 2 OH- -.83V
- H2O --gt O2(g) 4 H 4 e- -1.23 V
-
- 2.06 V - What does the negative sign mean?
30Change the electrodes to Copper
Black lead cathode -
Red lead anode
Copper electrodes
Na2SO4(aq)
31What is happening??
- Reduction
- 2 H2O(l) 2 - ? H2(g) 2 H-(aq) -0.83 V
- 2 H(aq) 3 e- ? H2(g) 0.00 V
- Na(aq) e- ? Na(s) -2.71
V - Cu2 2 e- - ? Cu - 0.34 V
- Oxidation
- 2 H2O ? O2(g) 4H(aq) 4e- -1.23 V
- 2 SO42- ? S2O8 2 e-
-2.00 V - Cu(s) - ? Cu2 2 e- 0.34 V