Title: Chapter 13 Chromatin Structure and its Effects on Transcription
1Chapter 13Chromatin Structure and its Effects on
Transcription
2Students must be positive that they
understand standard PCR.
- There is a resource on the web for this purpose.
- Warn them before this class.
3Notes
- Do not attempt to interpret figure 13.14.
- Figure 13.18. The concentration of nucleosomes
does not prevent the restriction enzyme from
finding its cut sites in many molecules (in some
the nucleosomes block the cut site).
4Eukaryotes five different Histone Classes
Histone size amino acids Molecular weight
H2A 150 14,000
H2B 150 13,770
H3 150 15,400
H4 100 11,340
H1 (H5) 200 21,500
Eukaryotes contain many copies of each histone
gene. 10-20 in mice, 100X in Drosophila
5Compaction
700 nm fiber
Beads On A string
solenoid
Snake The Solenoid PR 25
Double helix
Probably involve SARS
6(No Transcript)
7Nucleosome
DNA
Protein
Core nucleosome contains 2X H2A, 2X H2B, 2X H3
2X H4
8Beads on a string
9Histone H1
- Outside of the core
- Easiest to remove by high salt extraction
10Solenoid
30 nm solenoid
6 per turn
Packing ratio of 8
11Tetranucleosome Fig 13.7
12(No Transcript)
1345-80 kb loops
14The movie was deleted to save space. You can
download it separately.
15Evidence that histones help to regulate gene
expression
- Xenopus laevis 5s rRNA (20,000 copies)
- oocyte 5S rRNA genes, expressed only in oocytes -
98 - somatic 5S rRNA genes, expressed in both oocytes
and somatic cells - 2
16Chromatin is required for specificity
- With DNA, RNA polymerase III transcribes both
well - With oocyte chromatin, both expressed
- With somatic cell chromatin only somatic 5S rRNA
genes expressed.
17Somatic cell chromatin
- Inactive oocyte genes contained all 5 histones
- Active somatic genes contain only core histones
- Remove H1 oocyte genes turn on. Add it back and
they turn off.
pg 369 Weaver 4th ed.
18Nucleosome compete with transcription factors
- This is too simple toallow one to
modulateexpression or is it?
19mRNA encoding genes Class II genes transcribed by
RNA polymerase II
- Core histones cause mild (4X) repression of gene
expression - Activators do not affect this
- H1 increases repression (25 to 100X)
- Activators can prevent this - similar to the 5S
genes.
20Laybourne Kadonaga 1991
- Chromatin form of the Drosophila Krüppel gene
- nuclear extract transcribes it at 25 of the
maximum rate. This is 75 repression. - Interpretation1) 100 of the genes are
transcribed at a 75 rate of transcription2) 25
of the genes are transcribed at 100 of the rate. - 25 of promoters unoccupied. How was this
determined?
pg 370 Weaver 4th ed
21Histones can act as repressors
- Thus, via competition for binding sites,
transcription factors can de-repress (your book
calls it antirepression.
Histone H1 Nucleosome core
22Histone antirepression
- With respect to histone repression, Gal4 acts as
an antirepressor. In addition, it acts as an
activator. - SP1 acts as both a histone antirepressor and as
an activator. - GAGA factor seems to only act as a histone
antirepressor.
23De-repression or Anti-repression is the amount of
transcription that you get when the histone is
not interfering by hiding the promoter.
24Histone antirepression
- With respect to histone repression, Gal4 acts as
an antirepressor. In addition, it acts as an
activator. - SP1 acts as both a histone antirepressor and as
an activator. - GAGA factor seems to only act as a histone
antirepressor.
25Yaniv saw that some transcriptionally active SV40
virus DNAs had nucleosome free zones.
Fig. 13.21 Weaver 3rd ed.
Figure 13.17
26Is the promoter region of an active gene a
nucleosome free zone?
Figure 13. 18
27BamHI
BamHI
BamHI
BglII
BglII
BglII
28DNase I hypersensitivity
Transcribing SV40 virus isolated from infected
monkey cell tissue culture.
29Two fragments
Figure 13. 20
Gel electrophoresis Southern Blotting
This is a Southern Blot.
30DNase I hypersensitivity in Chromatin lectures
- Is this caused by the promoter or something else
near the promoter? Can this occur with the
promoter at a different location? Try a modified
SV40 that has a second promoter inserted. - Does transcription cause this or is it caused by
something else that binds the promoter? Do we
need to have transcription for this to occur?
Make a nuclear lysate that supports transcription
chromatin assembly. Then deplete it for RNA
polymerase II. Or starve for nucleotides. - Is this peculiar to the SV40 promoter. Try a
plasmid with a completely different type of
promoter. - Does the promoter have to be active for this to
happen? Try this with a promoter that can be
turned on and off. eg. Tet-on. - Why does the smaller band disappear?Less
intense because amount of probe that it can
collect is smaller. Test w/2 probes of the same
size.Less abundant, because transcription is
going that way and polymerarse might expand the
nucleosome clear zone to the left. Test by
reversing the direction of the plasmid. - What is the origin of the 100 band. Does it
confound our interpretation?
31Histone acetylation
- amino groups of lysine side chains
- unacetylated histones tend to repress
transcription - acetylated histones tend to activate
transcription - Histone acetyl transferase (HAT)- see Figure
13.23 for how to detect them. - Histone deacetylase
32Histone acetylation
- First discovered by Vincent Allfrey in 1964 takes
till 1996 (Brownell Allis) to purify a HAT - Tetrahymena has heavily acetylated histones.
- Take macronuclei extracts. SDS gel
electrophoresis in gel impregnated with histones.
Soak in radiolabeled acetyl-CoA. Wash.
Fluorography.
You dont have this slide.
33How to purify a HAT
heated chemical inactivation
BSA no histones no
protein
Acetylates histones
A way to assay for its presence
Demonstrates that one is detecting the presence
of a single enzyme. Tells you the relative size
of the enzyme.
34Now purify it.
- Standard biochemical techniques to purify p55.
- Can use the assay to tell where it is.
- Once pure get partial amino acid sequence. Very
small number of amino acids.
35Degenerate PCR
mRNA
mRNA
mRNA
DNA
36Degenerate PCR
mRNA
DNA
37Degenerate PCR
mRNA
AAAAAAA
38Degenerate PCR
39Degenerate PCR
UPPER STRAND Primer cocktail K G W
M D I M 5' AA(AG) GG(N) TGG
ATG GA(TC) AT(TCA) ATG 3' 2 X 4 X
1 X 1 X 2 X 3 X 1 48 A 21 mer
primer with 48 fold degeneracy.
40Degenerate PCR
LOWER STRAND Primer cocktail N M V
T M M V 5' AA(TC) ATG GT(N)
AC(N) ATG ATG GT(N) 3' Take the reverse
complement for the lower strand. The reverse
complement is merely the opposite strand in a DNA
helix also written in the 5' to 3 direction. 5'
(N)AC CAT CAT (N)GT (N)AC CAT (AG)TT 3'
4 X 1 X 1 X 4 X 4 X 1 X 2 128
41Degenerate PCR
LOWER STRAND Primer cocktail N M V
T M M V 5' AA(TC) ATG GT(N)
AC(N) ATG ATG GT(N) 3' Take the reverse
complement for the lower strand. The reverse
complement is merely the opposite strand in a DNA
helix also written in the 5' to 3 direction. 5'
(N)AC CAT CAT (N)GT (N)AC CAT (AG)TT 3'
4 X 1 X 1 X 4 X 4 X 1 X 2
128 If we wish to have a less degenerate
cocktail what can we do? Let's shave off the 5'
end by one base to reduce the degeneracy to 32
fold. 5' AC CAT CAT (N)GT (N)AC CAT
(AG)TT 3' Degeneracy is 1 X 1 X 1 X 4 X
4 X 1 X 2 32 fold degeneracy.
42Degenerate PCR
D N F N R Q K Q K L G G E D L F
M T E E Q K K Y Y N A M K K L G S
K K GAYAAYTTYAAYMGNCARAARCARAARYTNGGNGGNGARGAYY
TNTTYATGACNGARGARCARAARAARTAYTAYAAYGCNATGAARAARYTN
GGNWSNAARAARG 2 2 2 2 6 2 2 2 2 6 4 4
2 2 6 2 1 4 2 2 2 2 2 2 2 2 4 1
2 2 6 4 6 2 2
L G G E D L F
YTNGGNGGNGARGAYYTNTTY
6 4 4 2 2 6 2 4608 D N F N R Q K
...........................................K K
Y Y N A M GAYAAYTTYAAYMGNCARAAR..............
............................AARAARTAYTAYAAYGCNATG
2 2 2 2 6 2 2 384.......................
..............2 2 2 2 2 4 1 128
Ambiguous Bases
A-adenine B-not A C-cytosine G-guanine H-not G
K-G or T M-A or C N-A, C, G or T R-A or G S-C or G
T-thymine U-uracilT V-not T W-A or T Y-C or T -
gap
43Screen a cDNA library
- DNA copies of every mRNA made by a cell are
produced and cloned into a bacterial vector. - Screening.
- Google.
445-RACE
Figure 4.16
45HAT type A
- Have bromodomain
- Binds aceylated lysines. So HAT As can recoginze
partially acetylated histone tails. - Examples p55, Gcn5p CBP/p300, TAF250
46Acetylation continued
- Acetylation of histone tails neutralizes some of
the positive charge, causing them to relax their
grip on the DNA. - Reduces nucleosome cross-linking. That is the
interaction between histones in neighboring
nucleosome. eg. basic n-terminal tail of H4 in
one nucleosome and an acidic pocket in H2A-H2B
dimer in the next nucleosome
47Acetylation continued
- Also some TFs recognize acetylated histones. eg.
TAFII250 has a double bromodomain and recognizes
low level acetylated histones. Once bound it is a
HAT and increases acetylation. - low level acetylation of histones occurs in
inactive chromatin.
48END
49(No Transcript)
50Take home
- The presence of nucleosomes can interfere with
the binding of TFs to enhancers and with the
preinitiation complex to the promoter.
Repression - When other proteins (simple TFs) are bound to the
DNA they can prevent the histones from binding.
This is competitive inhibition of histone
binding. Called de-repression or antirepression
in your book.