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Stochastic%20Process

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Title: Stochastic%20Process


1
Stochastic Process
  • Formal definition
  • A Stochastic Process is a family of random
    variables X(t) t ? T defined on a probability
    space, indexed by the parameter t, where t varies
    over an index set T
  • You are supposed to associated T with time
  • Examples
  • Frog jumping from one lily pad to another
  • X(t) lily pad occupied by the frog at time
    t
  • Flip a coin and take one step north if heads and
    one step south if tails(discrete time , discrete
    state)
  • ??, ??

2
Queuing Systems as stochastic processes
  • Single server model
  • Arrival process
  • Queue scheduling discipline
  • Service time distribution

System
3
Some random processes associated with a queuing
system
  • X(t) of arrivals in (0, t)
  • N(t) of customs(jobs) in system at time t
  • X(tn) of customs(jobs) in system when
  • nth arrival occurs
  • U(t) amount of unfinished work in the
  • system at time t

Continuous time random processes
Discrete time random process
Continuous time random process
4
Markov ???
  • M/M/1/N
  • M
  • ArrivalPoisson
  • ServiceExponential
  • GGeneral
  • DDeterministic

Arrival process
of servers
Service time distribution
Finite waiting room
Memoryless
5
Fig 2.2
Cn-1
Cn
Cn1
Cn2
Xn1
Xn2
Xn
idle
Server
Cn
Cn1
Cn2
Wn
Wn1
Wn20
Queue
Cn
Cn1
Cn2
  • Wn nth customers waiting time(inside the
    queue)
  • Xn nth customers service time(inside the
    server)
  • System time waiting time service time

6
Littles Result ?Tn
Black box
arrivals
departures
  • Def
  • ?mean long term arrival rate
  • (no assumption about Poisson or anything else
  • -not even i.i.d. interarrival times)
  • Tmean time a customer spends in the black box
  • nmean number of customers in the box

7
Proof
customers
Err
T5
T4
T3
T2
T1
time
0
t
Err
8
  • Let
  • n(t) of cistomers in the system at time t
  • A(t) of arrivals in (0, t)
  • of customers in the system

area
9
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10
Stochastic Processes
Sample path
Distrib of initial state
t
t
0
t
t1
t2
  • Notation F(x0t0) FX(t0)(x0) PX(t0) ? x0
  • Describing stochastic processes
  • F(x1, x2,, xn t1, t2,, tn) F(x t)
  • PX(t1) ? x1, X(t2) ? x2,, X(tn) ? xn

11
  • Special case
  • Stationary
  • F(xt)F(x t t), where t t t1 t, t2 t,
    , tn t
  • Independent
  • F(x t)Fx(t1)(x1)Fx(t2)(x2)Fx(tn)(xn)

12
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13
Markov Processes
  • Future behavior does not depend on all of past
    history
  • Only depends on current state
  • PX(t) xX(t1) x1,, X(tn) xn
  • PX(t) x X(tn) xn, t1ltt2ltlttnltt
  • Concerned mostly with discrete state Markov
    Chains
  • Discrete and continuous time
  • Time homogeneous Markov processes
  • PX(t) ? x X(tn) ? xnPX(t t) ? x X(tn t)
    ? xn, for all t

14
Markov Chins --discrete state space
p12
2
p24
p23
p14
1
4
p44
p13
p31
p43
3
  • May be continuous time or discrete time

15
Markov Chain
  • For discrete parameter
  • We only consider the sequence of states and not
    the time spent in each state
  • For continuous time M.C.
  • The holding time in each state is exponential
    distributed
  • Must be if future behavior only depends on
    current state
  • Need the memoryless property of the exponential

16
  • Discrete time M.C.
  • P transition probability Matrix
  • Pi, j pX(t1) j X(t) i
  • Continuous time M.C.
  • Rate of transmission between states

17
How to select state?
  • Ex
  • Model of a shared memory multiprocessors

18
How to select state? (cont.)
  • An abstraction

19
How to select state? (cont.)
  • Parameter case
  • 2 processors
  • 2 memory modules

?????? ??????
20
Discrete Parameter Markov Chains
  • Discrete state space
  • Finite or countable infinite
  • Pjk(m, n) PXn k Xm j, 0 ? m ? n
  • For time homogeneous Markov Chains
  • Pjk(m, n) is only a function of n-m
  • In particular,Pjk Pjk(m, m1)

21
  • Transition probability matrix
  • P Pj, k (stochastic matrix)
  • All elements ? 0 and row sums 1
  • p(0) initial state probability vector
  • pi(0) ith component of p(0) prob. system
    starts in state i

22
State-transition diagram
  • Example Random walk
  • N-step Transition Probabilities
  • Def

n-step transition prob. matrix
23
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24
Type of states types of Markov Chains
  • Transient states
  • no way to go back
  • 1 is a transient state
  • Pji(n) ? 0, as n ? 8

25
  • Recurrent states
  • ??? transient
  • State i is recurrent iff starting from any state
    j, state i is visited eventually with probability
    1. Pji(n) ? 1, as n ? 8
  • Expectation is 8
  • Recurrent-null
  • Mean time between visits is 8
  • Recurrent-non-null
  • Mean time between visits is lt 8
  • Periodic
  • dig.c.d of all n such that Pii(n) ? 0
  • aperiodic if di 1

26
  • Absorbing states
  • trap states
  • 4 is an absorbing state, so is 5

p
4
7
5
1-p
27
Irreducible Markov Chain
  • Any state is reachable from any other state in a
    finite number of transition,
  • i.e. vi, j, Pij(n) gt 0 for some finite n
  • For an irreducible Markov chain
  • All states are aperiodic or all are periodic with
    the same period
  • All states are transient or none are
  • All states are recurrent or none are

28
  • Let p(0) vector of initial state probabilities
  • i.e. pi(0) prob. start in state i
  • pi(0) prob. in state i at time 1

29
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30
  • Thm.
  • For any aperiodic chain, the limit
  • Thm.
  • For an irreducible, aperiodic M.C., the limit of
    pexists and is independent of the initial state
    probability distribution
  • Thm.
  • For an irreducible, aperiodic M.C. with all
    states recurrent non-null, pis the unique
    stationary state probability vector

31
Example
  • Limit does not exist for a periodic chain
  • p(0) (1, 0, 0)
  • p(3k ) (1, 0, 0)
  • p(3k1) (0, 1, 0)
  • p(3k2) (0, 0, 1) no limit

32
Example
  • Reducible M.C
  • Solution to p pP is not independent of initial
    state prob. Vector
  • p(0) (1, 0, 0, 0) Or p(0) (0, 0, 1, 0)

B
D
A
C
33
Recall problem before --2 memory modules case
and 2 processors
q1
m1
P1p2
q2
m2
  • Step 1 select state
  • (2, 0) (1, 1) (0, 2)
  • Step 2 transition P

  • gt

q2
34
  • Step 3 ?p
  • p pP
  • S pi 1
  • ?p(p1, p2, p3)
  • (p1, p2, p3) (p1, p2, p3)

35
  • Performance measure
  • Usually expressed as reward functions
  • E.q. memory bandwidth
  • i.e.expected of references completed per cycle
  • p(2, 0)?1 p(0, 2)?1 p(1, 1)?2

36
Discrete Parameter Birth-Death Process
  • bi prob. of a birth in state i
  • di prob. of a death in state i
  • ai prob. of a neither in state I
  • p pP
  • Straight form above eqn

37
  • Substitute imploes.

38
  • Messy with all the b.d.a. arbitrary

39
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40
  • ??
  • p pP (by balance equation)

41
  • pjPji
  • rate at which state i is entered from state j
  • ? Sj pjPji total rate into state i
  • pj fraction of visits to state i
  • rate at which state i is exited
  • pi Sj pjPji (p pP )

42
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43
  • Another way of solving
  • --sometimes were convenient
  • pi bi pi1 di1
  • pi1 ( bi/ di1)pi

44
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45
  • Examples
  • An infinite stack
  • A finite stack
  • Two stacks growing toward each other

46
Some properties of Poisson processes
  • Alternate Def.
  • N(0) 0
  • Independence of non-overlapping intervals
  • Time homogeneity
  • P1 event in (t, th) ?h o(h)
  • P0 event in (t, th) 1- ?h o(h)
  • P gt 1 event in (t, th) o(h)

47
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48
  1. Merging independent Poisson processes

49
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50
  1. Splitting a Poisson process

51
  • Look at stream A

52
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54
Examples
  • 1 component can be operational or failed
  • When it is operational, it fails with a rate a
  • When it has failed, it is repaired at rate ß

55
  • 2 components

56
  • 2 components
  • Both have same failure rate a and repair rate ß

57
Exponentially distribution n v
  • fx(t) ?e-?t
  • Fx(x? t) 1 e-?t
  • P(t ? x ? t?t) ??t
  • e.q. 2 components
  • Both have exponential lifetimes before failure
  • Parameters a1, a2
  • Starts with both components operational

58
  • Repair times are exponential distribution with
    parameters ß1, ß2

59
  • Cases
  • A) component 1 has preemptive priority
  • B) repairman shares his time when both
    components failed in any ?t length interval
    (repair man spends ½ ?t on component 1 and ½ ?t
    on component 2)
  • What is the prob. of repair of comp. 1 in next
    ?t?
  • (½ ß1?t )

60
  • C) now suppose 2 repairmen

61
Continuous time Markov Chains
62
(Forward)Chapman-Kolmogorov Equations (C.K.E)
  • Idea
  • t t?t
  • u t

63
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64
  • C.K. equation
  • Aside there is a backward C-K equation
  • Turns out

65
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66
  • For time homogeneous M.C.
  • Q(t)Q
  • Not a function of time
  • (initial condition p(0))
  • For an irreducible aperiodic M.C.
  • pj(t) exists and is independent of initial state

67
M/M/1 Queue
Poisson arrivals
1 srver
Exponential service time dist.
  • ?
  • mean arrival rate or inter-arrival times are
    exponential distr.
  • µ

68
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69
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70
Whats concerned
  • Mean of customers in system

71
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72
  • Mean response time
  • Littles result

73
  • Mean waiting time
  • Length of time between arrival and start of
    service
  • Assume FCFS
  • Mean waiting time
  • mean system time mean service time

74
  • Assume FCFS, what is distribution of response
    time?
  • L.T.(Laplace Transform) of distribution
  • PnPwhen arriving, see n customers in
    system
  • PASTA Poisson Arrivals See Time Averages

75
M/M/1/N(Finite Waiting Room)
  • What fraction of customers are lost?
  • PNpN

76
M/M/2
77
M/M/8
78
Discourage Arrival
79
Discourage Arrival(cont.)
80
  • Discrete time M.C.
  • state
  • Continuous time M.C.
  • holding time in a state
  • Semi-M.C.
  • both the discrete and continuous times property

81
Discrete Time M.C.
  • No notion of how much time is spent in a state
    between Jumps
  • p pP, Spi 1
  • Interpret pi as the relative frequency with which
    state i is visited
  • E.q. one of N visits approximatelypiN are to
    state i
  • only really valid in the limit as N ? 8

82
Semi-Markov Chain
  • Transition probabilities as in discrete time
    states and have holding time
  • Let ti mean holding time for state i
  • Consider observing a semi-Markov Chain
  • For N state visits, the time interval will be
    approximately Sjpjtj
  • Fraction of time in state i
  • Supposeti tj ,for all i, j
  • Then fraction of time in state i

83
Relationship to continuous time M.C.
  • Example
  • Consider as a semi-Markov Chain,
  • what are the state holding times?
  • What are the transition probabilities?

84
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86
Finite Population(M/M/1s variation)
  • N customers, sometimes referred to as the
    machine-repairman model
  • Each is operational for a period of time, which
    is exponential distribution(?) between failures
  • When a machine fails, it joins a queue for repair
  • There is a single repairman, the time for the
    repairman to repair a broken machine is an
    exponential distributed(µ) random variable

Parameter ?in above figure
Parameter µin above figure
87
  • Define state
  • State space of customer in queue
  • Transition (as M/M/1/N)
  • Solve p
  • (see next slide)

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89
  • Suppose wanted repair time distribution(use L.T.)
  • If machine arrives finds k machines ahead of
    it,
  • Then L.T. for time to repair
  • Unconditional
  • Need prob. Machine arrives to see k machines
    ahead of it pk

90
Markov Chains with Absorbing states
  • Example
  • Two components system (fault tolerance system)
  • Failure rate for of both components ?
  • Repair rate µ
  • State space?
  • Transition rate diagram?

91
  • Differential equations for time dependent
    solution
  • ,time-homogeneous,
    ?Q

92
  • Apply Laplace Transform to each equation

93
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