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5.4

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5.4 Use Medians and Altitudes CE = BF = AD = Length of segment from vertex to midpoint of opposite side CP = BP = AP = Length of segment from vertex to P – PowerPoint PPT presentation

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Title: 5.4


1
5.4 Use Medians and Altitudes
Length of segment from vertex to midpoint of opposite side AD BF CE
Length of segment from vertex to P AP BP CP
Length of segment from P to midpoint PD PF PE
2
5.4 Use Medians and Altitudes
  • As shown by the activity, a triangle will balance
    at a particular point. This point is the
    intersection of the medians of the triangle.

3
5.4 Use Medians and Altitudes
  • A median of a triangle is a segment from a vertex
    to the midpoint of the opposite side. The three
    medians of a triangle are concurrent. The point
    of concurrency, called the centroid, is inside
    the triangle.

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5.4 Use Medians and Altitudes
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5.4 Use Medians and Altitudes
  • Example 1 Use the centroid of a triangle
  • In Triangle RST, Q is the centroid and
  • SQ 8. Find QW and SW.

6
5.4 Use Medians and Altitudes
  • Example 2 Use the centroid of a triangle
  • In Triangle HJK, P is the centroid and
  • JP 12. Find PT and JT.

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5.4 Use Medians and Altitudes
  • Example 3 Use the centroid of a triangle
  • The vertices of Triangle FGH are F(2, 5),
  • G(4, 9), and H(6, 1). Which ordered pair gives
    the coordinates of the centroid P of Triangle
    FGH?

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5.4 Use Medians and Altitudes
  • An altitude of a triangle is the perpendicular
    segment from a vertex to the opposite side or to
    the line that contains the opposite side.

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5.4 Use Medians and Altitudes
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5.4 Use Medians and Altitudes
  • The point at which the lines containing the three
    altitudes of a triangle intersect is called the
    orthocenter of the triangle.

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5.4 Use Medians and Altitudes
  • The orthocenter is located in different areas
    depending on what type of triangle you have.

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5.4 Use Medians and Altitudes
  • Isosceles Triangle
  • In an isosceles triangle, the perpendicular
    bisector, angle bisector, and altitude from the
    vertex angle to the base are all the same
    segment. In an equilateral triangle, this is
    true for the special segment from any vertex.
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